CAT Past Year Question Paper Solution - 2004 | Additional Study Material for CAT PDF Download

 Page 1


Scoring table
    Section
DI 1 to 38 38
Quant 39 to 73 35
EU + RC 74 to 123 50
T otal 123
T otal
questions
T otal
attempted
T otal
correct
T otal
wrong
Net
Score
 Time
T aken
Question
number
1 1 2 4 3 2 4 3 5 3 6 4 7 4 8 1 9 1 10 3
11 1 12 2 13 2 14 2 15 4 16 1 17 4 18 1 19 2 20 4
21 1 22 1 23 1 24 2 25 3 26 4 27 3 28 1 29 2 30 2
31 4 32 3 33 3 34 4 35 4 36 2 37 4 38 4 39 3 40 2
41 1 42 2 43 1 44 2 45 1 46 1 47 3 48 4 49 4 50 2
51 3 52 4 53 2 54 2 55 3 56 4 57 4 58 3 59 4 60 3
61 3 62 2 63 3 64 2 65 1 66 2 67 2 68 4 69 4 70 1
71 3 72 3 73 1 74 2 75 1 76 4 77 3 78 2 79 4 80 3
81 1 82 4 83 1 84 3 85 2 86 1 87 3 88 3 89 4 90 2
91 4 92 2 93 1 94 2 95 4 96 1 97 2 98 2 99 3 100 3
101 1 102 1 103 2 104 4 105 2 106 1 107 1 108 3 109 4 110 4
111 3 112 3 113 3 114 3 115 2 116 3 117 2 118 2 119 3 120 1
121 3 122 2 123 4

	


	
Page 2


Scoring table
    Section
DI 1 to 38 38
Quant 39 to 73 35
EU + RC 74 to 123 50
T otal 123
T otal
questions
T otal
attempted
T otal
correct
T otal
wrong
Net
Score
 Time
T aken
Question
number
1 1 2 4 3 2 4 3 5 3 6 4 7 4 8 1 9 1 10 3
11 1 12 2 13 2 14 2 15 4 16 1 17 4 18 1 19 2 20 4
21 1 22 1 23 1 24 2 25 3 26 4 27 3 28 1 29 2 30 2
31 4 32 3 33 3 34 4 35 4 36 2 37 4 38 4 39 3 40 2
41 1 42 2 43 1 44 2 45 1 46 1 47 3 48 4 49 4 50 2
51 3 52 4 53 2 54 2 55 3 56 4 57 4 58 3 59 4 60 3
61 3 62 2 63 3 64 2 65 1 66 2 67 2 68 4 69 4 70 1
71 3 72 3 73 1 74 2 75 1 76 4 77 3 78 2 79 4 80 3
81 1 82 4 83 1 84 3 85 2 86 1 87 3 88 3 89 4 90 2
91 4 92 2 93 1 94 2 95 4 96 1 97 2 98 2 99 3 100 3
101 1 102 1 103 2 104 4 105 2 106 1 107 1 108 3 109 4 110 4
111 3 112 3 113 3 114 3 115 2 116 3 117 2 118 2 119 3 120 1
121 3 122 2 123 4

	


	
1. 1 GPA of Preeti = 3.2
i.e.,  
FD x D y
3.2
5
++ ++
=
? 0 + 2 + x + 2 + y = 16
? x + y = 12
The only possible combination is A, A.
Hence, Preeti obtained A grade in Statistics.
2. 4 Total points scored by Tara = 2.4 × 5 = 12
She scored same grade in three of the subjects, so
her score is of the form 3x + y + z = 12
She cannot have scored 3 A’s as her total points will
exceed 12.
She can score 3 B’s and 2 F’s which will make her
total points 3 × 4 + 2 × 0 = 12.
She cannot score 3 C’s as the points in remaining two
will be 12 – 3 × 3 = 3 and only possible breakup is (3,
0). This will contradict the fact that she had same
grade in only three courses.
For a similar reason, she cannot score 3 D’s.
She cannot score 3 F’s, because for the remaining
two courses she has to amass 12 points which is
possible if she score A in both – a contradiction.
Hence, Tara could have scored a B or F grade in
Operations.
3. 2 GPA of Gowri is 3.8
i.e. 3 + 3 + 6 + x + 4 = 3.8 × 5
16 + x = 19
x = 3
So in Strategy, Gowri's grade is C.
Rahul's grade in strategy = (4.2 × 5) – 15 = 6, i.e., A.
Fazal's grade in strategy = (2.4 × 5) – 8 = 4, i.e., B.
Hence, Gowri's grade will be higher than that of Hari.
4. 3 As Fazal’s GPA = 2.4
So D + F + B + X + D = 2.4 × 5
? 2 + 0 + 4 + X + 2 = 12
? X = 4
So his grade in Strategy is B.
So grade of Utkarsh in Marketing is also B.
So for Utkarsh, Y + B + F + C + A = 3 × 5
? Y + 4 + 0 + 3 + 6 = 15
? Y = 2
So grade of Utkarsh in Finance = D.
5. 3 Average incomes of Ahuja family
=
3200 3000 2800 9000
3000;
33
++
==
Bose family=
2300 2100 2800 7200
2400;
33
++
==
Coomar family =
1200 2200 1600 5000
1667
33
++
=˜ and Dubey
family = 
1200 3200 4400
2200.
22
+
==
Hence, Coomar family has the lowest average
income.
6.4 The average expenditures (approximately) for the
families:
Ahuja = 
700 1700 2700
1733;
3
++
˜
Bose = 
800 1750 2300
1617;
3
++
˜
Coomar = 
500 1100 1900
1167
3
++
˜ and
Dubey = 
1200 2800
2000.
2
+
=
Hence, Dubey family has the highest average
expenditure.
7. 4 The average savings (approximately) for the
families:
Ahuja = 
2500 1300 100
1300;
3
++
=
Bose = 
1500 350 500
783;
3
++
˜
Coomar = 
700 1100 300
700
3
++
=
and
Dubey = 
0400
200.
2
+
=
Hence, Dubey family has the lowest average
savings.
8. 1 The savings of a person is maximum if he/she has
high income but less expenditure. From the graph, a
member of Ahuja family has Rs.3200 as income and
Rs.700 as expenditure. Hence, he/she will have the
maximum savings among all.
For questions 9 to 12:
On day 3, there were 2 visitors from UK and 1 from USA. On
the same day, the site was visited by 2 persons from Univer-
sity 4 and 1 from University 6. So University 4 is located in UK
and University 6 is in USA.
Similar reasoning for day 2 gives us the conclusion that Uni-
versity 3 is located in Netherlands and University 8 is in India.
On day 1, the number of visitors from USA is 1 and that from
University 6 is 1. University 6 is in USA (derived above), which
implies no other university is in USA.
The number of visitors from India on day 1 is 1. Also, no visitor
from University 8, which is in India has visited the site on day
1. This implies that one of University 1 and University 5 is in
India and the other in Netherlands. A similar logic gives us that
one of University 2 and University 6 is in UK and the other in
Canada.
Page 3


Scoring table
    Section
DI 1 to 38 38
Quant 39 to 73 35
EU + RC 74 to 123 50
T otal 123
T otal
questions
T otal
attempted
T otal
correct
T otal
wrong
Net
Score
 Time
T aken
Question
number
1 1 2 4 3 2 4 3 5 3 6 4 7 4 8 1 9 1 10 3
11 1 12 2 13 2 14 2 15 4 16 1 17 4 18 1 19 2 20 4
21 1 22 1 23 1 24 2 25 3 26 4 27 3 28 1 29 2 30 2
31 4 32 3 33 3 34 4 35 4 36 2 37 4 38 4 39 3 40 2
41 1 42 2 43 1 44 2 45 1 46 1 47 3 48 4 49 4 50 2
51 3 52 4 53 2 54 2 55 3 56 4 57 4 58 3 59 4 60 3
61 3 62 2 63 3 64 2 65 1 66 2 67 2 68 4 69 4 70 1
71 3 72 3 73 1 74 2 75 1 76 4 77 3 78 2 79 4 80 3
81 1 82 4 83 1 84 3 85 2 86 1 87 3 88 3 89 4 90 2
91 4 92 2 93 1 94 2 95 4 96 1 97 2 98 2 99 3 100 3
101 1 102 1 103 2 104 4 105 2 106 1 107 1 108 3 109 4 110 4
111 3 112 3 113 3 114 3 115 2 116 3 117 2 118 2 119 3 120 1
121 3 122 2 123 4

	


	
1. 1 GPA of Preeti = 3.2
i.e.,  
FD x D y
3.2
5
++ ++
=
? 0 + 2 + x + 2 + y = 16
? x + y = 12
The only possible combination is A, A.
Hence, Preeti obtained A grade in Statistics.
2. 4 Total points scored by Tara = 2.4 × 5 = 12
She scored same grade in three of the subjects, so
her score is of the form 3x + y + z = 12
She cannot have scored 3 A’s as her total points will
exceed 12.
She can score 3 B’s and 2 F’s which will make her
total points 3 × 4 + 2 × 0 = 12.
She cannot score 3 C’s as the points in remaining two
will be 12 – 3 × 3 = 3 and only possible breakup is (3,
0). This will contradict the fact that she had same
grade in only three courses.
For a similar reason, she cannot score 3 D’s.
She cannot score 3 F’s, because for the remaining
two courses she has to amass 12 points which is
possible if she score A in both – a contradiction.
Hence, Tara could have scored a B or F grade in
Operations.
3. 2 GPA of Gowri is 3.8
i.e. 3 + 3 + 6 + x + 4 = 3.8 × 5
16 + x = 19
x = 3
So in Strategy, Gowri's grade is C.
Rahul's grade in strategy = (4.2 × 5) – 15 = 6, i.e., A.
Fazal's grade in strategy = (2.4 × 5) – 8 = 4, i.e., B.
Hence, Gowri's grade will be higher than that of Hari.
4. 3 As Fazal’s GPA = 2.4
So D + F + B + X + D = 2.4 × 5
? 2 + 0 + 4 + X + 2 = 12
? X = 4
So his grade in Strategy is B.
So grade of Utkarsh in Marketing is also B.
So for Utkarsh, Y + B + F + C + A = 3 × 5
? Y + 4 + 0 + 3 + 6 = 15
? Y = 2
So grade of Utkarsh in Finance = D.
5. 3 Average incomes of Ahuja family
=
3200 3000 2800 9000
3000;
33
++
==
Bose family=
2300 2100 2800 7200
2400;
33
++
==
Coomar family =
1200 2200 1600 5000
1667
33
++
=˜ and Dubey
family = 
1200 3200 4400
2200.
22
+
==
Hence, Coomar family has the lowest average
income.
6.4 The average expenditures (approximately) for the
families:
Ahuja = 
700 1700 2700
1733;
3
++
˜
Bose = 
800 1750 2300
1617;
3
++
˜
Coomar = 
500 1100 1900
1167
3
++
˜ and
Dubey = 
1200 2800
2000.
2
+
=
Hence, Dubey family has the highest average
expenditure.
7. 4 The average savings (approximately) for the
families:
Ahuja = 
2500 1300 100
1300;
3
++
=
Bose = 
1500 350 500
783;
3
++
˜
Coomar = 
700 1100 300
700
3
++
=
and
Dubey = 
0400
200.
2
+
=
Hence, Dubey family has the lowest average
savings.
8. 1 The savings of a person is maximum if he/she has
high income but less expenditure. From the graph, a
member of Ahuja family has Rs.3200 as income and
Rs.700 as expenditure. Hence, he/she will have the
maximum savings among all.
For questions 9 to 12:
On day 3, there were 2 visitors from UK and 1 from USA. On
the same day, the site was visited by 2 persons from Univer-
sity 4 and 1 from University 6. So University 4 is located in UK
and University 6 is in USA.
Similar reasoning for day 2 gives us the conclusion that Uni-
versity 3 is located in Netherlands and University 8 is in India.
On day 1, the number of visitors from USA is 1 and that from
University 6 is 1. University 6 is in USA (derived above), which
implies no other university is in USA.
The number of visitors from India on day 1 is 1. Also, no visitor
from University 8, which is in India has visited the site on day
1. This implies that one of University 1 and University 5 is in
India and the other in Netherlands. A similar logic gives us that
one of University 2 and University 6 is in UK and the other in
Canada.
9. 1 10. 3 11. 1
12. 2
13. 2 Number of Naya mixer-grinders disposed off in 1999
= 20% of 30 = 6
So the number of Naya mixer-grinders in 1999, i.e.
124 is inclusive of those mixer grinders produced in
1997 and 1998 and still in operation. The numbers
are (30 – 6)= 24 and (80 – 30) = 50 respectively.
Therefore, number of new Naya mixer-grinders
purchased in 1999 = 124 – (50 + 24) = 50.
14. 2 Number of Naya mixer-grinders disposed off in 1999
= 20% of 30 = 6
Number of Naya mixer-grinders disposed off in 2000
= 20% of (80 – 30) = 10
Therefore, total number of Naya mixer-grinders
disposed by end of 2000 = 6 + 10 = 16.
15. 4 Sine information regarding the number of Purana
mixer-grinders for the years prior to 1995 is not
known, it cannot be ascertained as to how many of
them were disposed off in 2000.
16. 1 It is given that 10 Purana mixer-grinders were
disposed off as junk in 1997. So the number of
mixer-grinders in operation in 1997 must have been
162 – 10 = 152. But it is given to be 182.
?Number of newly purchased Purana mixer-
grinder in 1997 = 182 – 152 = 30
20% of this, i.e. 6 were disposed off in 1999. So the
number of mixer-grinders in operation in 1999 must
have been 222 – 6 = 216. But it is given to be 236.
?Number of newly purchased Purana mixer-
grinder in 1999 = 236 – 216 = 20.
17. 4 Thailand and Japan (Maximum difference of 4 ranks
(5 – 1)
= 4.
18. 1 China (Maximum difference of 2 between 2 parameter’s
2)
19. 2 Japan (Maximum difference of 4.)
20. 4 Japan and Malaysia (Inferring from question 17)
21. 1 Let incomes of Zakib and Supriyo be Z and S
respectively
Statement A: 20% of Z > 25% of S
? Z > 
5
S
4
Now, Zakia spent 30% of his income on education =
30% of Z > 
30 5
S0.375S
100 4
×=
From this we cannot say if 0.3 Z is greater than or
less than 0.4 S.
Hence, statement A alone is not sufficient.
Statement B: 13% of S > 10% of Z
Multiplying both sides by 3, we get,
39% of S > 30 % of Z
So 40% of S is definitely more than 30% of Z.
Hence, statement B alone is sufficient.
22. 1 Assume A, B, C, D gets score 10, 8, 6, 4 respectively.
A    B   C    D
10   8   6   4
Statement A:
With the conditions, A will give vote to B
With the conditions, B will give vote to A
With the conditions, C will give vote to A
Even if D gives to A/B/C - 2 situation arises.
Either A will win or there will a tie when D gives vote to
B.
Even then A will win.
So we are getting the answer.
Statement B: Nothing concrete can be derived.
23. 1 Statement A: Nothing can be said.
Statement B: Since there are 3 boys in the top 5 rank
holders, the other two are girls and Rashmi is not one
of them. As Kumar is ranked sixth, Rashmi is either
seventh or below. Hence, statement II alone is suffi-
cient.
24. 2
Statement A: To reach the Red mark, Tarak needs to
take even number of steps and to reach the Blue
mark, he needs to take odd number of steps. Given
that the number of steps taken by him is 21. Therefore,
Tarak stops at the Blue mark.
Hence, statement A alone is sufficient.
Statement B: If the number of tails is 3 more than the
heads, then the effective movement will be 3 steps to
the left, i.e. Tarak will reach Blue mark.
Hence, statement B alone is sufficient.
25. 3 Statement A: 2 kg potato cost + 1 kg gourd cost < 1 kg
potato cost + 1 kg gourd cost
? 1 kg potato cost < 1 kg gourd cost.
Hence, statement A is not sufficient.
Statement B: 1 kg potato cost + 2 kg onion cost = 1 kg
Page 4


Scoring table
    Section
DI 1 to 38 38
Quant 39 to 73 35
EU + RC 74 to 123 50
T otal 123
T otal
questions
T otal
attempted
T otal
correct
T otal
wrong
Net
Score
 Time
T aken
Question
number
1 1 2 4 3 2 4 3 5 3 6 4 7 4 8 1 9 1 10 3
11 1 12 2 13 2 14 2 15 4 16 1 17 4 18 1 19 2 20 4
21 1 22 1 23 1 24 2 25 3 26 4 27 3 28 1 29 2 30 2
31 4 32 3 33 3 34 4 35 4 36 2 37 4 38 4 39 3 40 2
41 1 42 2 43 1 44 2 45 1 46 1 47 3 48 4 49 4 50 2
51 3 52 4 53 2 54 2 55 3 56 4 57 4 58 3 59 4 60 3
61 3 62 2 63 3 64 2 65 1 66 2 67 2 68 4 69 4 70 1
71 3 72 3 73 1 74 2 75 1 76 4 77 3 78 2 79 4 80 3
81 1 82 4 83 1 84 3 85 2 86 1 87 3 88 3 89 4 90 2
91 4 92 2 93 1 94 2 95 4 96 1 97 2 98 2 99 3 100 3
101 1 102 1 103 2 104 4 105 2 106 1 107 1 108 3 109 4 110 4
111 3 112 3 113 3 114 3 115 2 116 3 117 2 118 2 119 3 120 1
121 3 122 2 123 4

	


	
1. 1 GPA of Preeti = 3.2
i.e.,  
FD x D y
3.2
5
++ ++
=
? 0 + 2 + x + 2 + y = 16
? x + y = 12
The only possible combination is A, A.
Hence, Preeti obtained A grade in Statistics.
2. 4 Total points scored by Tara = 2.4 × 5 = 12
She scored same grade in three of the subjects, so
her score is of the form 3x + y + z = 12
She cannot have scored 3 A’s as her total points will
exceed 12.
She can score 3 B’s and 2 F’s which will make her
total points 3 × 4 + 2 × 0 = 12.
She cannot score 3 C’s as the points in remaining two
will be 12 – 3 × 3 = 3 and only possible breakup is (3,
0). This will contradict the fact that she had same
grade in only three courses.
For a similar reason, she cannot score 3 D’s.
She cannot score 3 F’s, because for the remaining
two courses she has to amass 12 points which is
possible if she score A in both – a contradiction.
Hence, Tara could have scored a B or F grade in
Operations.
3. 2 GPA of Gowri is 3.8
i.e. 3 + 3 + 6 + x + 4 = 3.8 × 5
16 + x = 19
x = 3
So in Strategy, Gowri's grade is C.
Rahul's grade in strategy = (4.2 × 5) – 15 = 6, i.e., A.
Fazal's grade in strategy = (2.4 × 5) – 8 = 4, i.e., B.
Hence, Gowri's grade will be higher than that of Hari.
4. 3 As Fazal’s GPA = 2.4
So D + F + B + X + D = 2.4 × 5
? 2 + 0 + 4 + X + 2 = 12
? X = 4
So his grade in Strategy is B.
So grade of Utkarsh in Marketing is also B.
So for Utkarsh, Y + B + F + C + A = 3 × 5
? Y + 4 + 0 + 3 + 6 = 15
? Y = 2
So grade of Utkarsh in Finance = D.
5. 3 Average incomes of Ahuja family
=
3200 3000 2800 9000
3000;
33
++
==
Bose family=
2300 2100 2800 7200
2400;
33
++
==
Coomar family =
1200 2200 1600 5000
1667
33
++
=˜ and Dubey
family = 
1200 3200 4400
2200.
22
+
==
Hence, Coomar family has the lowest average
income.
6.4 The average expenditures (approximately) for the
families:
Ahuja = 
700 1700 2700
1733;
3
++
˜
Bose = 
800 1750 2300
1617;
3
++
˜
Coomar = 
500 1100 1900
1167
3
++
˜ and
Dubey = 
1200 2800
2000.
2
+
=
Hence, Dubey family has the highest average
expenditure.
7. 4 The average savings (approximately) for the
families:
Ahuja = 
2500 1300 100
1300;
3
++
=
Bose = 
1500 350 500
783;
3
++
˜
Coomar = 
700 1100 300
700
3
++
=
and
Dubey = 
0400
200.
2
+
=
Hence, Dubey family has the lowest average
savings.
8. 1 The savings of a person is maximum if he/she has
high income but less expenditure. From the graph, a
member of Ahuja family has Rs.3200 as income and
Rs.700 as expenditure. Hence, he/she will have the
maximum savings among all.
For questions 9 to 12:
On day 3, there were 2 visitors from UK and 1 from USA. On
the same day, the site was visited by 2 persons from Univer-
sity 4 and 1 from University 6. So University 4 is located in UK
and University 6 is in USA.
Similar reasoning for day 2 gives us the conclusion that Uni-
versity 3 is located in Netherlands and University 8 is in India.
On day 1, the number of visitors from USA is 1 and that from
University 6 is 1. University 6 is in USA (derived above), which
implies no other university is in USA.
The number of visitors from India on day 1 is 1. Also, no visitor
from University 8, which is in India has visited the site on day
1. This implies that one of University 1 and University 5 is in
India and the other in Netherlands. A similar logic gives us that
one of University 2 and University 6 is in UK and the other in
Canada.
9. 1 10. 3 11. 1
12. 2
13. 2 Number of Naya mixer-grinders disposed off in 1999
= 20% of 30 = 6
So the number of Naya mixer-grinders in 1999, i.e.
124 is inclusive of those mixer grinders produced in
1997 and 1998 and still in operation. The numbers
are (30 – 6)= 24 and (80 – 30) = 50 respectively.
Therefore, number of new Naya mixer-grinders
purchased in 1999 = 124 – (50 + 24) = 50.
14. 2 Number of Naya mixer-grinders disposed off in 1999
= 20% of 30 = 6
Number of Naya mixer-grinders disposed off in 2000
= 20% of (80 – 30) = 10
Therefore, total number of Naya mixer-grinders
disposed by end of 2000 = 6 + 10 = 16.
15. 4 Sine information regarding the number of Purana
mixer-grinders for the years prior to 1995 is not
known, it cannot be ascertained as to how many of
them were disposed off in 2000.
16. 1 It is given that 10 Purana mixer-grinders were
disposed off as junk in 1997. So the number of
mixer-grinders in operation in 1997 must have been
162 – 10 = 152. But it is given to be 182.
?Number of newly purchased Purana mixer-
grinder in 1997 = 182 – 152 = 30
20% of this, i.e. 6 were disposed off in 1999. So the
number of mixer-grinders in operation in 1999 must
have been 222 – 6 = 216. But it is given to be 236.
?Number of newly purchased Purana mixer-
grinder in 1999 = 236 – 216 = 20.
17. 4 Thailand and Japan (Maximum difference of 4 ranks
(5 – 1)
= 4.
18. 1 China (Maximum difference of 2 between 2 parameter’s
2)
19. 2 Japan (Maximum difference of 4.)
20. 4 Japan and Malaysia (Inferring from question 17)
21. 1 Let incomes of Zakib and Supriyo be Z and S
respectively
Statement A: 20% of Z > 25% of S
? Z > 
5
S
4
Now, Zakia spent 30% of his income on education =
30% of Z > 
30 5
S0.375S
100 4
×=
From this we cannot say if 0.3 Z is greater than or
less than 0.4 S.
Hence, statement A alone is not sufficient.
Statement B: 13% of S > 10% of Z
Multiplying both sides by 3, we get,
39% of S > 30 % of Z
So 40% of S is definitely more than 30% of Z.
Hence, statement B alone is sufficient.
22. 1 Assume A, B, C, D gets score 10, 8, 6, 4 respectively.
A    B   C    D
10   8   6   4
Statement A:
With the conditions, A will give vote to B
With the conditions, B will give vote to A
With the conditions, C will give vote to A
Even if D gives to A/B/C - 2 situation arises.
Either A will win or there will a tie when D gives vote to
B.
Even then A will win.
So we are getting the answer.
Statement B: Nothing concrete can be derived.
23. 1 Statement A: Nothing can be said.
Statement B: Since there are 3 boys in the top 5 rank
holders, the other two are girls and Rashmi is not one
of them. As Kumar is ranked sixth, Rashmi is either
seventh or below. Hence, statement II alone is suffi-
cient.
24. 2
Statement A: To reach the Red mark, Tarak needs to
take even number of steps and to reach the Blue
mark, he needs to take odd number of steps. Given
that the number of steps taken by him is 21. Therefore,
Tarak stops at the Blue mark.
Hence, statement A alone is sufficient.
Statement B: If the number of tails is 3 more than the
heads, then the effective movement will be 3 steps to
the left, i.e. Tarak will reach Blue mark.
Hence, statement B alone is sufficient.
25. 3 Statement A: 2 kg potato cost + 1 kg gourd cost < 1 kg
potato cost + 1 kg gourd cost
? 1 kg potato cost < 1 kg gourd cost.
Hence, statement A is not sufficient.
Statement B: 1 kg potato cost + 2 kg onion cost = 1 kg
onion cost + 2 kg gourd cost   1 kg potato cost + 1 kg
onion cost = 2 kg gourd cost.
Hence, statement B is also not sufficient.
Combining both statements we get
1 kg potato cost < 1 kg gourd cost …(i)
1 kg potato cost + 1 kg onion cost
= 2 kg gourd cost …(ii)
Hence, onion is the costliest.
26. 4 Statement A: 13 currency notes will give diff. Values.
Statement B: Multiple of 10 and by many.
Even if you combine the statement, we can have
various values.
Answer is (4).
For questions 27 to 30: Go through the following table.
 Pakistan South Africa Australia 
K 28 51 < 48 
R < 22 49 55 
S < 22 75 50 
V 130 < 49 < 48 
Y 40 < 49 87 
Top 3 batsmen 198 175 192 
India Total 220 250 240 
27. 3 28. 1
29. 2 30. 2
Solutions for questions 31 to 34: For solving these
questions make a table like this:
           
 Africa America Australasia Europe  
L 0 1 1 1 3 
H   1 1 6 
P   2 1 6 
R   1 1 6 
 4 8 5 4 21 
(i) As the labour expert is half of each of the other, so the
only possible combination is:
H
L – 3
P
R
6 each
(ii) Statement (d): If the number of Australasia expert is 1
less, i.e. total export are 20 American be twice as
each of other. The only combined possible is Americas
= 8.
Australasia = 4 + 1 = 5
Europe = 4
Africa = 4
Now, we need to workout the various options possible
in the blank cells.
 Africa America Australasia Europe  
L 0 1 1 1 3 
H 2 2 1 1 6 
P 1 2 2 1 6 
R 1 3 1 1 6 
 4 8 5 4 21 
 Africa America Australasia Europe  
L 0 1 1 1 3 
H 1 3 1 1 6 
P 1 2 2 1 6 
R 2 2 1 1 6 
 4 8 5 4 21 
 Africa America Australasia Europe  
L 0 1 1 1 3 
H 1 3 1 1 6 
P 2 1 2 1 6 
R 1 3 1 1 6 
 4 8 5 4 21 
31. 4 32. 3 33. 3
34. 4
For questions 35 to 38:
Germany has won both their matches, so possible winning
combinations in first two rounds is
R1 : Won 1 - 0 and R2: Won 2 - 1
Or
R1 : Won 2 - 1 and R2: Won 1 - 0.
Argentina must have won R1 and R2 by 1 - 0.
If Germany won by 2 - 1 in R1 vs Spain, Spain won in R2 by 4
- 0, and if Germany won 1 - 0 in R1, then Spain won 5 - 1 in R2.
Since only New Zealand and South Africa conceded 4 or more
than 4 goals, then Spain must have played either one in R2.
If Spain won 4 - 0 in R2 vs South Africa, then South Africa must
win R1 by 1 - 0, which is a contradiction to the fact that South
Africa has lost both R1 and R2. Also, Spain can never win 5 -
1 vs South Africa in R2 (goals conceded by South Africa is 4).
Therefore, Spain won against New Zealand in R2.
Germany:
R1 vs Spain Won 2 -1 or
1 - 0
R2 vs SA/Pak Won 1 - 0 or
2 - 1
R3 vs Arg Draw
Spain:
R1 vs Germany Lost 1 - 2 or
0 - 1
Page 5


Scoring table
    Section
DI 1 to 38 38
Quant 39 to 73 35
EU + RC 74 to 123 50
T otal 123
T otal
questions
T otal
attempted
T otal
correct
T otal
wrong
Net
Score
 Time
T aken
Question
number
1 1 2 4 3 2 4 3 5 3 6 4 7 4 8 1 9 1 10 3
11 1 12 2 13 2 14 2 15 4 16 1 17 4 18 1 19 2 20 4
21 1 22 1 23 1 24 2 25 3 26 4 27 3 28 1 29 2 30 2
31 4 32 3 33 3 34 4 35 4 36 2 37 4 38 4 39 3 40 2
41 1 42 2 43 1 44 2 45 1 46 1 47 3 48 4 49 4 50 2
51 3 52 4 53 2 54 2 55 3 56 4 57 4 58 3 59 4 60 3
61 3 62 2 63 3 64 2 65 1 66 2 67 2 68 4 69 4 70 1
71 3 72 3 73 1 74 2 75 1 76 4 77 3 78 2 79 4 80 3
81 1 82 4 83 1 84 3 85 2 86 1 87 3 88 3 89 4 90 2
91 4 92 2 93 1 94 2 95 4 96 1 97 2 98 2 99 3 100 3
101 1 102 1 103 2 104 4 105 2 106 1 107 1 108 3 109 4 110 4
111 3 112 3 113 3 114 3 115 2 116 3 117 2 118 2 119 3 120 1
121 3 122 2 123 4

	


	
1. 1 GPA of Preeti = 3.2
i.e.,  
FD x D y
3.2
5
++ ++
=
? 0 + 2 + x + 2 + y = 16
? x + y = 12
The only possible combination is A, A.
Hence, Preeti obtained A grade in Statistics.
2. 4 Total points scored by Tara = 2.4 × 5 = 12
She scored same grade in three of the subjects, so
her score is of the form 3x + y + z = 12
She cannot have scored 3 A’s as her total points will
exceed 12.
She can score 3 B’s and 2 F’s which will make her
total points 3 × 4 + 2 × 0 = 12.
She cannot score 3 C’s as the points in remaining two
will be 12 – 3 × 3 = 3 and only possible breakup is (3,
0). This will contradict the fact that she had same
grade in only three courses.
For a similar reason, she cannot score 3 D’s.
She cannot score 3 F’s, because for the remaining
two courses she has to amass 12 points which is
possible if she score A in both – a contradiction.
Hence, Tara could have scored a B or F grade in
Operations.
3. 2 GPA of Gowri is 3.8
i.e. 3 + 3 + 6 + x + 4 = 3.8 × 5
16 + x = 19
x = 3
So in Strategy, Gowri's grade is C.
Rahul's grade in strategy = (4.2 × 5) – 15 = 6, i.e., A.
Fazal's grade in strategy = (2.4 × 5) – 8 = 4, i.e., B.
Hence, Gowri's grade will be higher than that of Hari.
4. 3 As Fazal’s GPA = 2.4
So D + F + B + X + D = 2.4 × 5
? 2 + 0 + 4 + X + 2 = 12
? X = 4
So his grade in Strategy is B.
So grade of Utkarsh in Marketing is also B.
So for Utkarsh, Y + B + F + C + A = 3 × 5
? Y + 4 + 0 + 3 + 6 = 15
? Y = 2
So grade of Utkarsh in Finance = D.
5. 3 Average incomes of Ahuja family
=
3200 3000 2800 9000
3000;
33
++
==
Bose family=
2300 2100 2800 7200
2400;
33
++
==
Coomar family =
1200 2200 1600 5000
1667
33
++
=˜ and Dubey
family = 
1200 3200 4400
2200.
22
+
==
Hence, Coomar family has the lowest average
income.
6.4 The average expenditures (approximately) for the
families:
Ahuja = 
700 1700 2700
1733;
3
++
˜
Bose = 
800 1750 2300
1617;
3
++
˜
Coomar = 
500 1100 1900
1167
3
++
˜ and
Dubey = 
1200 2800
2000.
2
+
=
Hence, Dubey family has the highest average
expenditure.
7. 4 The average savings (approximately) for the
families:
Ahuja = 
2500 1300 100
1300;
3
++
=
Bose = 
1500 350 500
783;
3
++
˜
Coomar = 
700 1100 300
700
3
++
=
and
Dubey = 
0400
200.
2
+
=
Hence, Dubey family has the lowest average
savings.
8. 1 The savings of a person is maximum if he/she has
high income but less expenditure. From the graph, a
member of Ahuja family has Rs.3200 as income and
Rs.700 as expenditure. Hence, he/she will have the
maximum savings among all.
For questions 9 to 12:
On day 3, there were 2 visitors from UK and 1 from USA. On
the same day, the site was visited by 2 persons from Univer-
sity 4 and 1 from University 6. So University 4 is located in UK
and University 6 is in USA.
Similar reasoning for day 2 gives us the conclusion that Uni-
versity 3 is located in Netherlands and University 8 is in India.
On day 1, the number of visitors from USA is 1 and that from
University 6 is 1. University 6 is in USA (derived above), which
implies no other university is in USA.
The number of visitors from India on day 1 is 1. Also, no visitor
from University 8, which is in India has visited the site on day
1. This implies that one of University 1 and University 5 is in
India and the other in Netherlands. A similar logic gives us that
one of University 2 and University 6 is in UK and the other in
Canada.
9. 1 10. 3 11. 1
12. 2
13. 2 Number of Naya mixer-grinders disposed off in 1999
= 20% of 30 = 6
So the number of Naya mixer-grinders in 1999, i.e.
124 is inclusive of those mixer grinders produced in
1997 and 1998 and still in operation. The numbers
are (30 – 6)= 24 and (80 – 30) = 50 respectively.
Therefore, number of new Naya mixer-grinders
purchased in 1999 = 124 – (50 + 24) = 50.
14. 2 Number of Naya mixer-grinders disposed off in 1999
= 20% of 30 = 6
Number of Naya mixer-grinders disposed off in 2000
= 20% of (80 – 30) = 10
Therefore, total number of Naya mixer-grinders
disposed by end of 2000 = 6 + 10 = 16.
15. 4 Sine information regarding the number of Purana
mixer-grinders for the years prior to 1995 is not
known, it cannot be ascertained as to how many of
them were disposed off in 2000.
16. 1 It is given that 10 Purana mixer-grinders were
disposed off as junk in 1997. So the number of
mixer-grinders in operation in 1997 must have been
162 – 10 = 152. But it is given to be 182.
?Number of newly purchased Purana mixer-
grinder in 1997 = 182 – 152 = 30
20% of this, i.e. 6 were disposed off in 1999. So the
number of mixer-grinders in operation in 1999 must
have been 222 – 6 = 216. But it is given to be 236.
?Number of newly purchased Purana mixer-
grinder in 1999 = 236 – 216 = 20.
17. 4 Thailand and Japan (Maximum difference of 4 ranks
(5 – 1)
= 4.
18. 1 China (Maximum difference of 2 between 2 parameter’s
2)
19. 2 Japan (Maximum difference of 4.)
20. 4 Japan and Malaysia (Inferring from question 17)
21. 1 Let incomes of Zakib and Supriyo be Z and S
respectively
Statement A: 20% of Z > 25% of S
? Z > 
5
S
4
Now, Zakia spent 30% of his income on education =
30% of Z > 
30 5
S0.375S
100 4
×=
From this we cannot say if 0.3 Z is greater than or
less than 0.4 S.
Hence, statement A alone is not sufficient.
Statement B: 13% of S > 10% of Z
Multiplying both sides by 3, we get,
39% of S > 30 % of Z
So 40% of S is definitely more than 30% of Z.
Hence, statement B alone is sufficient.
22. 1 Assume A, B, C, D gets score 10, 8, 6, 4 respectively.
A    B   C    D
10   8   6   4
Statement A:
With the conditions, A will give vote to B
With the conditions, B will give vote to A
With the conditions, C will give vote to A
Even if D gives to A/B/C - 2 situation arises.
Either A will win or there will a tie when D gives vote to
B.
Even then A will win.
So we are getting the answer.
Statement B: Nothing concrete can be derived.
23. 1 Statement A: Nothing can be said.
Statement B: Since there are 3 boys in the top 5 rank
holders, the other two are girls and Rashmi is not one
of them. As Kumar is ranked sixth, Rashmi is either
seventh or below. Hence, statement II alone is suffi-
cient.
24. 2
Statement A: To reach the Red mark, Tarak needs to
take even number of steps and to reach the Blue
mark, he needs to take odd number of steps. Given
that the number of steps taken by him is 21. Therefore,
Tarak stops at the Blue mark.
Hence, statement A alone is sufficient.
Statement B: If the number of tails is 3 more than the
heads, then the effective movement will be 3 steps to
the left, i.e. Tarak will reach Blue mark.
Hence, statement B alone is sufficient.
25. 3 Statement A: 2 kg potato cost + 1 kg gourd cost < 1 kg
potato cost + 1 kg gourd cost
? 1 kg potato cost < 1 kg gourd cost.
Hence, statement A is not sufficient.
Statement B: 1 kg potato cost + 2 kg onion cost = 1 kg
onion cost + 2 kg gourd cost   1 kg potato cost + 1 kg
onion cost = 2 kg gourd cost.
Hence, statement B is also not sufficient.
Combining both statements we get
1 kg potato cost < 1 kg gourd cost …(i)
1 kg potato cost + 1 kg onion cost
= 2 kg gourd cost …(ii)
Hence, onion is the costliest.
26. 4 Statement A: 13 currency notes will give diff. Values.
Statement B: Multiple of 10 and by many.
Even if you combine the statement, we can have
various values.
Answer is (4).
For questions 27 to 30: Go through the following table.
 Pakistan South Africa Australia 
K 28 51 < 48 
R < 22 49 55 
S < 22 75 50 
V 130 < 49 < 48 
Y 40 < 49 87 
Top 3 batsmen 198 175 192 
India Total 220 250 240 
27. 3 28. 1
29. 2 30. 2
Solutions for questions 31 to 34: For solving these
questions make a table like this:
           
 Africa America Australasia Europe  
L 0 1 1 1 3 
H   1 1 6 
P   2 1 6 
R   1 1 6 
 4 8 5 4 21 
(i) As the labour expert is half of each of the other, so the
only possible combination is:
H
L – 3
P
R
6 each
(ii) Statement (d): If the number of Australasia expert is 1
less, i.e. total export are 20 American be twice as
each of other. The only combined possible is Americas
= 8.
Australasia = 4 + 1 = 5
Europe = 4
Africa = 4
Now, we need to workout the various options possible
in the blank cells.
 Africa America Australasia Europe  
L 0 1 1 1 3 
H 2 2 1 1 6 
P 1 2 2 1 6 
R 1 3 1 1 6 
 4 8 5 4 21 
 Africa America Australasia Europe  
L 0 1 1 1 3 
H 1 3 1 1 6 
P 1 2 2 1 6 
R 2 2 1 1 6 
 4 8 5 4 21 
 Africa America Australasia Europe  
L 0 1 1 1 3 
H 1 3 1 1 6 
P 2 1 2 1 6 
R 1 3 1 1 6 
 4 8 5 4 21 
31. 4 32. 3 33. 3
34. 4
For questions 35 to 38:
Germany has won both their matches, so possible winning
combinations in first two rounds is
R1 : Won 1 - 0 and R2: Won 2 - 1
Or
R1 : Won 2 - 1 and R2: Won 1 - 0.
Argentina must have won R1 and R2 by 1 - 0.
If Germany won by 2 - 1 in R1 vs Spain, Spain won in R2 by 4
- 0, and if Germany won 1 - 0 in R1, then Spain won 5 - 1 in R2.
Since only New Zealand and South Africa conceded 4 or more
than 4 goals, then Spain must have played either one in R2.
If Spain won 4 - 0 in R2 vs South Africa, then South Africa must
win R1 by 1 - 0, which is a contradiction to the fact that South
Africa has lost both R1 and R2. Also, Spain can never win 5 -
1 vs South Africa in R2 (goals conceded by South Africa is 4).
Therefore, Spain won against New Zealand in R2.
Germany:
R1 vs Spain Won 2 -1 or
1 - 0
R2 vs SA/Pak Won 1 - 0 or
2 - 1
R3 vs Arg Draw
Spain:
R1 vs Germany Lost 1 - 2 or
0 - 1
R2 vs NZ Won 4 - 0 or
5 - 1
R3 vs Pak Draw
New Zealand:
R1 vs Arg/Pak Lost 1 - 2 or
0 - 1
R2 vs Spain Lost 0 - 4 or
1 - 5 R3 vs SA Draw
Looking at the table, the only possible outcomes for Pakistan in
the first two rounds are 2 -0 win and 0 - 1 loss.
In R1, New Zealand cannot lose 1 - 2 since Argentina conceded
no goals and Pakistan's only loss was by a margin 0 - 1.
Therefore, NZ lost R1 0 - 1. This score is possible only if its
opponent is Argentina. Consequently, NZ lost 1 - 5 in R2 vs
Spain. Hence, Spain must have lost 0 - 1 to Germany.
The above information can be finally summarised as:
Germany: R1 vs Spain Won 1 -
0
R2 vs SA Won 2 -
1
R3 vs Arg Draw
Spain: R1 vs Germany Lost  0 -
1
R2 vs NZ Won 5 -
1
R3 vs Pak Draw
New Zealand: R1 v s Arg Lost 0 - 1
R2 vs Spain Lost 1 - 5
R3 vs SA Draw
Pakistan: R1 vs SA Won 2 -0
R2 v s Arg Lost 0 - 1
R3 vs Spain Draw
Argentina: R1 vs NZ Won 1 -
0
R2 vs Pak Won 1 -
0
R3 vs Germany Draw
South Africa: R1 v s Pak Lost 0 - 2
R2 v s Germany Lost 1 - 2
R3 vs NZ Draw
35. 4
36. 2
Additional information for Q.37-38:
* The given data set for rounds 4 and 5 appears to be
inconsistent because from statements (a), (b) and (c) it is
evident that four teams namely Spain, Argentina, Germany and
Pakistan won their fifth round matches whereas the maximum
possible wins in any round is only 3.
37. 4 38. 4
39. 3 The boats will be colliding after a time which is given
by
 
20 4
t hours 80 minutes
510 3
== =
+
.
After this time of 80 minutes, boat (1) has covered
520
80 kms kms
60 3
×=
, whereas boat (2) has
covered 
10
80 kms
60
×
=
40
kms.
3
After 79 minutes, distance covered by the first boat =
d
1
 = 
20 5
– kms
360
??
??
??
After 79 minutes, distance covered by the second
boat = d
2
 = 
40 10
– kms
360
??
??
??
So the separation between the two boats
= 20 – ()
12
dd + = 
1
kms
4
Alternative method:
Relative speed of two boats = 5 + 10 = 15 km/hr
i.e. in 60 min they cover (together) = 15 km
?in 1 min they will cover (together) 
=
15 1
km
60 4
40. 2
2
x/2
x
In original rectangle ratio = 
x
2
In Smaller rectangle ratio = 
2
x
2
??
??
??
Given 
x2
x22
x 2
2
=? =
Area of smaller rectangle = 
x
2 x 2 2 sq. units
2
×= =