CBSE Past Year Paper Session (2016-17) Set- 3, Mathematics Class 7 Class 7 Notes | EduRev

Past Year Papers For Class 7

Created by: Praveen Kumar

Class 7 : CBSE Past Year Paper Session (2016-17) Set- 3, Mathematics Class 7 Class 7 Notes | EduRev

 Page 1


Q u e s t i o n 	 p a p e r 	 2 0 1 6 - 2 0 1 7
C B S E 	 C l a s s 	 V I I 	 M a t h e m a t i c s 	 S e t 	 A
G e n e r a l 	 I n s t r u c t i o n :
T h i s 	 q u e s t i o n 	 p a p e r 	 c o n t a i n s 	 8 	 q u e s t i o n s
A l l 	 t h e 	 q u e s t i o n s 	 a r e 	 c o m p u l s o r y .
S e c t i o n 	 A
1 . 	 I f 	 t w o 	 i n t e g e r s 	 a r e 	 o f 	 u n l i k e 	 s i g n s , 	 t h e n 	 w h a t 	 i s 	 t h e 	 s i g n 	 o f 	 t h e i r 	 p r o d u c t ?
S o l . 	 N e g a t i v e
2 . 	 W h a t 	 i s 	 t h e 	 c h a n c e 	 o f 	 y o u r 	 b e i n g 	 y o u n g e r 	 t o m o r r o w 	 t h a n 	 t o d a y ?
S o l . 	 N o 	 c h a n g e
3 . 	 S i m p l i f y : 	 ( - 8 0 3 ) 	 × 	 1 0 1 	 + 	 8 0 3 	 × 	 ( - 1 ) .
S o l . 	 ( - 8 0 3 ) 	 × 	 1 0 1 	 + 	 1 )
- 8 0 3 	 × 	 ( 1 0 1 	 + 	 1 )
- 8 0 3 	 × 	 ( 1 0 1 	 + 	 1 )
- 8 0 3 	 × 	 1 0 2
- 8 1 9 0 6
4 . 	 A 	 d i e 	 i s 	 t h r o w n 	 2 0 	 t i m e s . 	 T h e 	 n u m b e r 	 4 	 a p p e a r s 	 6 	 t i m e s . 	 W h a t 	 i s 	 t h e 	 p r o b a b i l i t y
o f 	 n o t 	 g e t t i n g 	 n u m b e r 	 4 ?
S o l . 	 P r o b a b i l i t y
P r o b a b i l i t y 	 o f 	 g e t t i n g
P r o b a b i l i t y 	 o f 	 n o t 	 g e t t i n g 	 4 	 	
= 	 0 . 7
Page 2


Q u e s t i o n 	 p a p e r 	 2 0 1 6 - 2 0 1 7
C B S E 	 C l a s s 	 V I I 	 M a t h e m a t i c s 	 S e t 	 A
G e n e r a l 	 I n s t r u c t i o n :
T h i s 	 q u e s t i o n 	 p a p e r 	 c o n t a i n s 	 8 	 q u e s t i o n s
A l l 	 t h e 	 q u e s t i o n s 	 a r e 	 c o m p u l s o r y .
S e c t i o n 	 A
1 . 	 I f 	 t w o 	 i n t e g e r s 	 a r e 	 o f 	 u n l i k e 	 s i g n s , 	 t h e n 	 w h a t 	 i s 	 t h e 	 s i g n 	 o f 	 t h e i r 	 p r o d u c t ?
S o l . 	 N e g a t i v e
2 . 	 W h a t 	 i s 	 t h e 	 c h a n c e 	 o f 	 y o u r 	 b e i n g 	 y o u n g e r 	 t o m o r r o w 	 t h a n 	 t o d a y ?
S o l . 	 N o 	 c h a n g e
3 . 	 S i m p l i f y : 	 ( - 8 0 3 ) 	 × 	 1 0 1 	 + 	 8 0 3 	 × 	 ( - 1 ) .
S o l . 	 ( - 8 0 3 ) 	 × 	 1 0 1 	 + 	 1 )
- 8 0 3 	 × 	 ( 1 0 1 	 + 	 1 )
- 8 0 3 	 × 	 ( 1 0 1 	 + 	 1 )
- 8 0 3 	 × 	 1 0 2
- 8 1 9 0 6
4 . 	 A 	 d i e 	 i s 	 t h r o w n 	 2 0 	 t i m e s . 	 T h e 	 n u m b e r 	 4 	 a p p e a r s 	 6 	 t i m e s . 	 W h a t 	 i s 	 t h e 	 p r o b a b i l i t y
o f 	 n o t 	 g e t t i n g 	 n u m b e r 	 4 ?
S o l . 	 P r o b a b i l i t y
P r o b a b i l i t y 	 o f 	 g e t t i n g
P r o b a b i l i t y 	 o f 	 n o t 	 g e t t i n g 	 4 	 	
= 	 0 . 7
5 . 	 a . 	 T h e 	 m e a n 	 o f 	 1 5 	 o b s e r v a t i o n s 	 i s 	 3 8 . 2 . 	 I t 	 w a s 	 f o u n d 	 l a t e r 	 o n , 	 t h a t 	 t h e 	 n u m b e r 	 2 5 	 w a s
m i s r e a d 	 a s 	 5 2 . 	 F i n d 	 t h e 	 a c t u a l 	 m e a n .
b . 	 1 3 	 s t u d e n t s 	 w e r e 	 g i v e n 	 a 	 c r o s s w o r d 	 p u z z l e . 	 T h e 	 t i m e 	 t a k e n 	 ( i n 	 m i n u t e s ) 	 b y 	 t h e m 	 t o
c o m p l e t e 	 t h e 	 c r o s s w o r d 	 i s 	 g i v e n 	 b e l o w :
1 0 , 	 1 2 , 	 1 5 , 	 8 , 	 1 0 , 	 1 2 , 	 1 2 , 	 8 , 	 1 0 , 	 8 , 	 1 2 , 	 1 1 , 	 1 1
F i n d 	 t h e 	 m e d i a n 	 a n d 	 m o d e 	 f o r 	 t h e 	 a b o v e 	 d a t a .
S o l . 	 ( a ) 	 M e a n 	 = 	 3 8 . 2
N o . 	 o f 	 o b s e r v a t i o n 	 = 	 1 5
C o r r e c t 	 m e a n
B u t 	
C o r r e c t 	 m e a n 	 	
	 	 = 3 6 . 4
( b ) 	 A r r a n g e 	 o b s . 	 I n 	 a s c e n d i n g 	 o r d e r
8 , 	 8 , 	 8 , 	 1 0 , 	 1 0 , 	 1 0 , 	 1 1 , 	 1 1 , 	 1 2 , 	 1 2 , 	 1 2 , 	 1 5
N o . 	 o f 	 o b s e r v a t i o n 	 = 	 1 3 	 ( o d d )
M e a d i a n
= 	 1 1 	 	 M o d e 	 = 	 1 2
6 . 	 S i m p l i f y :
[ 	 - 	 4 2 	 – 	 { 	 2 4 	 ÷ ( 	 - 	 1 5 	 + 	 3 	 ) 	 + 	 ( 7 ) 	 } 	 – 	 ( 	 - 	 3 0 ) 	 ÷ 	 ( - 	 6 ) ]
S o l . 	 [ - 4 2 	 – 	 { 2 4 	 ÷ 	 ( - 1 5 	 + 	 3 ) 	 + 	 7 } 	 – ( - 3 0 ) 	 ÷ 	 ( - 	 6 ) ]
[ - 4 2 	 – 	 { 2 4 	 ÷ 	 ( - 1 2 ) 	 + 	 7 } 	 – 5 ]
[ - 4 2 	 – 	 { - 2 	 + 	 7 } 	 – 5 ]
[ - 4 2 	 – 	 { 5 } 	 – 5 ]
Page 3


Q u e s t i o n 	 p a p e r 	 2 0 1 6 - 2 0 1 7
C B S E 	 C l a s s 	 V I I 	 M a t h e m a t i c s 	 S e t 	 A
G e n e r a l 	 I n s t r u c t i o n :
T h i s 	 q u e s t i o n 	 p a p e r 	 c o n t a i n s 	 8 	 q u e s t i o n s
A l l 	 t h e 	 q u e s t i o n s 	 a r e 	 c o m p u l s o r y .
S e c t i o n 	 A
1 . 	 I f 	 t w o 	 i n t e g e r s 	 a r e 	 o f 	 u n l i k e 	 s i g n s , 	 t h e n 	 w h a t 	 i s 	 t h e 	 s i g n 	 o f 	 t h e i r 	 p r o d u c t ?
S o l . 	 N e g a t i v e
2 . 	 W h a t 	 i s 	 t h e 	 c h a n c e 	 o f 	 y o u r 	 b e i n g 	 y o u n g e r 	 t o m o r r o w 	 t h a n 	 t o d a y ?
S o l . 	 N o 	 c h a n g e
3 . 	 S i m p l i f y : 	 ( - 8 0 3 ) 	 × 	 1 0 1 	 + 	 8 0 3 	 × 	 ( - 1 ) .
S o l . 	 ( - 8 0 3 ) 	 × 	 1 0 1 	 + 	 1 )
- 8 0 3 	 × 	 ( 1 0 1 	 + 	 1 )
- 8 0 3 	 × 	 ( 1 0 1 	 + 	 1 )
- 8 0 3 	 × 	 1 0 2
- 8 1 9 0 6
4 . 	 A 	 d i e 	 i s 	 t h r o w n 	 2 0 	 t i m e s . 	 T h e 	 n u m b e r 	 4 	 a p p e a r s 	 6 	 t i m e s . 	 W h a t 	 i s 	 t h e 	 p r o b a b i l i t y
o f 	 n o t 	 g e t t i n g 	 n u m b e r 	 4 ?
S o l . 	 P r o b a b i l i t y
P r o b a b i l i t y 	 o f 	 g e t t i n g
P r o b a b i l i t y 	 o f 	 n o t 	 g e t t i n g 	 4 	 	
= 	 0 . 7
5 . 	 a . 	 T h e 	 m e a n 	 o f 	 1 5 	 o b s e r v a t i o n s 	 i s 	 3 8 . 2 . 	 I t 	 w a s 	 f o u n d 	 l a t e r 	 o n , 	 t h a t 	 t h e 	 n u m b e r 	 2 5 	 w a s
m i s r e a d 	 a s 	 5 2 . 	 F i n d 	 t h e 	 a c t u a l 	 m e a n .
b . 	 1 3 	 s t u d e n t s 	 w e r e 	 g i v e n 	 a 	 c r o s s w o r d 	 p u z z l e . 	 T h e 	 t i m e 	 t a k e n 	 ( i n 	 m i n u t e s ) 	 b y 	 t h e m 	 t o
c o m p l e t e 	 t h e 	 c r o s s w o r d 	 i s 	 g i v e n 	 b e l o w :
1 0 , 	 1 2 , 	 1 5 , 	 8 , 	 1 0 , 	 1 2 , 	 1 2 , 	 8 , 	 1 0 , 	 8 , 	 1 2 , 	 1 1 , 	 1 1
F i n d 	 t h e 	 m e d i a n 	 a n d 	 m o d e 	 f o r 	 t h e 	 a b o v e 	 d a t a .
S o l . 	 ( a ) 	 M e a n 	 = 	 3 8 . 2
N o . 	 o f 	 o b s e r v a t i o n 	 = 	 1 5
C o r r e c t 	 m e a n
B u t 	
C o r r e c t 	 m e a n 	 	
	 	 = 3 6 . 4
( b ) 	 A r r a n g e 	 o b s . 	 I n 	 a s c e n d i n g 	 o r d e r
8 , 	 8 , 	 8 , 	 1 0 , 	 1 0 , 	 1 0 , 	 1 1 , 	 1 1 , 	 1 2 , 	 1 2 , 	 1 2 , 	 1 5
N o . 	 o f 	 o b s e r v a t i o n 	 = 	 1 3 	 ( o d d )
M e a d i a n
= 	 1 1 	 	 M o d e 	 = 	 1 2
6 . 	 S i m p l i f y :
[ 	 - 	 4 2 	 – 	 { 	 2 4 	 ÷ ( 	 - 	 1 5 	 + 	 3 	 ) 	 + 	 ( 7 ) 	 } 	 – 	 ( 	 - 	 3 0 ) 	 ÷ 	 ( - 	 6 ) ]
S o l . 	 [ - 4 2 	 – 	 { 2 4 	 ÷ 	 ( - 1 5 	 + 	 3 ) 	 + 	 7 } 	 – ( - 3 0 ) 	 ÷ 	 ( - 	 6 ) ]
[ - 4 2 	 – 	 { 2 4 	 ÷ 	 ( - 1 2 ) 	 + 	 7 } 	 – 5 ]
[ - 4 2 	 – 	 { - 2 	 + 	 7 } 	 – 5 ]
[ - 4 2 	 – 	 { 5 } 	 – 5 ]
[ - 4 2 	 – 	 5 	 – 	 5 ]
- 5
7 . 	 S e e i n g 	 t h e 	 p o o r 	 a n d 	 u n d e r p r i v i l e g e d 	 c h i l d r e n 	 i n 	 t h e 	 n e i g h b o u r h o o d , 	 t h e 	 r e s i d e n t s 	 o f
D w a r k a 	 d e c i d e 	 t o 	 d i s t r i b u t e 	 8 0 	 t a b l e 	 f a n s 	 d u r i n g 	 s u m m e r . 	 T h e 	 c o s t 	 o f 	 o n e 	 f a n 	 i s 	 R s 	 6 5 0 .
F i n d 	 t h e 	 t o t a l 	 c o s t 	 o f 	 f a n s 	 a n d 	 w r i t e 	 t w o 	 v a l u e s 	 t h a t 	 y o u 	 l e a r n 	 f r o m 	 i t .
S o l . 	 C o s t 	 o f 	 1 	 t a b l e 	 f a n 	 = 	 R s 	 6 5 0
C o s t 	 o f 	 8 0 	 t a b l e 	 f a n 	 = R s 	 6 5 0 	 × 	 8 0
T o t a l 	 c o s t 	 o f 	 t a b l e 	 f a n 	 = 	 	 R s 	 5 2 0 0 0
8 . 	 T h e 	 f o l l o w i n g 	 d a t a 	 s h o w s 	 t h e 	 n u m b e r 	 o f 	 c a r s 	 p r o d u c e d 	 i n 	 a 	 f a c t o r y 	 f o r 	 t h e 	 f i r s t 	 s i x
m o n t h s 	 o f 	 t h e 	 y e a r s 	 2 0 1 4 	 a n d 	 2 0 1 5 .
J a n F e b M a r c h A p r i l M a y J u n 	
2 0 1 4 8 6 0 0 9 6 0 0 7 6 0 0 4 4 0 0 3 2 0 0 8 0 0
2 0 1 5 8 6 0 0 9 4 0 0 8 0 0 0 6 4 0 0 4 0 0 0 1 2 0 0
P l o t 	 a 	 d o u b l e 	 b a r 	 g r a p h 	 u s i n g 	 t h e 	 d a t a 	 g i v e n 	 a b o v e .
S o l . 	 C o r r e c t 	 B a r 	 G r a p h
W i t h 	 s c a l e , 	 a x i s ,
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