1. What day of the week does May 28 2006 fall on
A. Saturday B. Monday C. Sunday D. Thursday
Answer: Option C
Explanation:
28th May 2006 = (2005 years + period from 1Jan2006 to 28May2006)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)
Number of odd days in the period 20012005
= 4 normal years + 1 leap year
= 4 x 1 + 1 x 2 = 6
Days from 1Jan2006 to 28May2006 = 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 28(may)
= 148
148 days = 21 weeks + 1 day = 1 odd day
Total number of odd days = (0 + 6 + 1) = 7 odd days = 0 odd day
0 odd day = Sunday
Hence May 28 2006 is Sunday.
2. What will be the day of the week 15th August, 2010?
A. Thursday B. Sunday C. Monday D. Saturday
Answer: Option B
Explanation:
15th Aug 2010 = (2009 years + period from 1Jan2010 to 15Aug2010)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)
Number of odd days in the period 20012009
= 7 normal years + 2 leap year
= 7 x 1 + 2 x 2 = 11 = (11  7x1) odd day = 4 odd day
Days from 1Jan2010 to 15Aug2010
= 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 31(may) + 30(Jun) + 31(Jul) + 15(Aug)
= 227
227 days = 32 weeks + 3 day = 3 odd day
Total number of odd days = (0 + 4 + 3) = 7 odd days = 0 odd day
0 odd day = Sunday
Hence 15th August, 2010 is Sunday.
3. Today is Monday. After 61 days, it will be
A. Thursday B. Sunday C. Monday D. Saturday
Answer: Option D
Explanation:
61 days = 8 weeks 5 days = 5 odd days
Hence if today is Monday, After 61 days, it will be = (Monday + 5 odd days)
= Saturday
4. On what dates of April, 2001 did Wednesday fall?
A. 2^{nd}, 9^{th}, 16^{th}, 23^{rd}
B. 4^{th}, 11^{th}, 18^{th}, 25^{th}
C. 3^{rd}, 10^{th}, 17^{th}, 24^{th}
D. 1^{st}, 8^{th}, 15^{th}, 22^{nd}, 29^{th}
Answer: Option B
Explanation:
We need to find out the day of 01Apr2001
01Apr2001 = (2000 years + period from 1Jan2001 to 01Apr2001)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)
Days from 1Jan2001 to 01Apr2001 = 31 (Jan) + 28 (Feb) + 31 (Mar) + 1(Apr) = 91
91 days = 13 weeks = 0 odd day
Total number of odd days = (0 + 0) = 0 odd days
0 odd day = Sunday. Hence 01Apr2001 is Sunday.
Hence first Wednesday of Apr 2011 comes in 04^{th} and successive Wednesdays come in 11^{th}, 18^{th} and 25^{th}
5. How many days are there in x weeks x days
A. 14x
B. 8x
C. 7x^{2}
D. 7
Answer: Option B
Explanation:
x weeks x days =(7×x)+x=7x+x=8x=(7×x)+x=7x+x=8x days
6. The calendar for the year 2007 will be the same for the year
A. 2017
B. 2018
C. 2014
D. 2016
Answer: Option B
Explanation:
For a year to have the same calendar with 2007 ,the total odd days from 2007 should be 0.
7. Which of the following is not a leap year?
A. 1200
B. 800
C. 700
D. 2000
Answer: Option C
Explanation:
Remember the leap year rule (Given in the formulas)
1. Every year divisible by 4 is a leap year, if it is not a century.
2. Every 4th century is a leap year, but no other century is a leap year.
800,1200 and 2000 comes in the category of 4th century (such as 400,800,1200,1600,2000 etc).
Hence 800,1200 and 2000 are leap years
700 is not a 4th century, but it is a century. Hence it is not a leap year
8. 01Jan2007 was Monday. What day of the week lies on 01Jan2008?
A. Wednesday
B. Sunday
C. Friday
D. Tuesday
Answer: Option D
Explanation:
Given that January 1, 2007 was Monday.
Odd days in 2007 = 1 (we have taken the complete year 2007 because we need to find out the odd days from 01Jan2007 to 31Dec2007, that is the whole year 2007)
Hence January 1, 2008 = (Monday + 1 Odd day) = Tuesday
9. 8th Dec 2007 was Saturday, what day of the week was it on 8th Dec, 2006?
A. Sunday
B. Tuesday
C. Friday
D. Tuesday
Answer: Option C
Explanation:
Given that 8th Dec 2007 was Saturday
Number of days from 8th Dec, 2006 to 7th Dec 2007 = 365 days
365 days = 1 odd day
Hence 8th Dec 2006 was = (Saturday  1 odd day) = Friday
10. On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?
A. Sunday
B. Friday
C. Saturday
D. Monday
Answer: Option A
Explanation:
Given that 8th Feb, 2005 was Tuesday
Number of days from 8th Feb, 2004 to 7th Feb, 2005 = 366 (Since Feb 2004 has 29 days as it is a leap year)
366 days = 2 odd days
Hence 8th Feb, 2004 = (Tuesday  2 odd days) = Sunday
125 videos168 docs117 tests

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4. Is it possible to customize a calendar according to my preferences? 
5. How can I use a calendar to stay organized and improve time management? 
125 videos168 docs117 tests


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