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**1. What day of the week does May 28 2006 fall on**

**A. Saturday B. Monday C. Sunday D. Thursday**

**Answer**: Option C

Explanation:

28th May 2006 = (2005 years + period from 1-Jan-2006 to 28-May-2006)

We know that number of odd days in 400 years = 0

Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)

Number of odd days in the period 2001-2005

= 4 normal years + 1 leap year

= 4 x 1 + 1 x 2 = 6

Days from 1-Jan-2006 to 28-May-2006 = 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 28(may)

= 148

148 days = 21 weeks + 1 day = 1 odd day

Total number of odd days = (0 + 6 + 1) = 7 odd days = 0 odd day

0 odd day = Sunday

Hence May 28 2006 is Sunday.

**2. What will be the day of the week 15th August, 2010?**

**A. Thursday B. Sunday C. Monday D. Saturday**

**Answer: **Option B

Explanation:

15th Aug 2010 = (2009 years + period from 1-Jan-2010 to 15-Aug-2010)

We know that number of odd days in 400 years = 0

Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)

Number of odd days in the period 2001-2009

= 7 normal years + 2 leap year

= 7 x 1 + 2 x 2 = 11 = (11 - 7x1) odd day = 4 odd day

Days from 1-Jan-2010 to 15-Aug-2010

= 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 31(may) + 30(Jun) + 31(Jul) + 15(Aug)

= 227

227 days = 32 weeks + 3 day = 3 odd day

Total number of odd days = (0 + 4 + 3) = 7 odd days = 0 odd day

0 odd day = Sunday

Hence 15th August, 2010 is Sunday.

**3. Today is Monday. After 61 days, it will be**

**A. Thursday B. Sunday C. Monday D. Saturday**

**Answer: **Option D

Explanation:

61 days = 8 weeks 5 days = 5 odd days

Hence if today is Monday, After 61 days, it will be = (Monday + 5 odd days)

= Saturday

**4. On what dates of April, 2001 did Wednesday fall?**

**A. 2 ^{nd}, 9^{th}, 16^{th}, 23^{rd}**

**B. 4 ^{th}, 11^{th}, 18^{th}, 25^{th}**

**C. 3 ^{rd}, 10^{th}, 17^{th}, 24^{th}**

**D. 1 ^{st}, 8^{th}, 15^{th}, 22^{nd}, 29^{th}**

**Answer: **Option B

Explanation:

We need to find out the day of 01-Apr-2001

01-Apr-2001 = (2000 years + period from 1-Jan-2001 to 01-Apr-2001)

We know that number of odd days in 400 years = 0

Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)

Days from 1-Jan-2001 to 01-Apr-2001 = 31 (Jan) + 28 (Feb) + 31 (Mar) + 1(Apr) = 91

91 days = 13 weeks = 0 odd day

Total number of odd days = (0 + 0) = 0 odd days

0 odd day = Sunday. Hence 01-Apr-2001 is Sunday.

Hence first Wednesday of Apr 2011 comes in 04^{th} and successive Wednesdays come in 11^{th}, 18^{th} and 25^{th}

**5. How many days are there in x weeks x days**

**A. 14x**

**B. 8x**

**C. 7x ^{2}**

**D. 7**

**Answer:** Option B

Explanation:

x weeks x days =(7×x)+x=7x+x=8x=(7×x)+x=7x+x=8x days

**6. The calendar for the year 2007 will be the same for the year**

**A. 2017**

**B. 2018**

**C. 2014**

**D. 2016**

**Answer:** Option B

Explanation:

For a year to have the same calendar with 2007 ,the total odd days from 2007 should be 0.

**7. Which of the following is not a leap year?**

**A. 1200**

**B. 800**

**C. 700**

**D. 2000**

**Answer:** Option C

Explanation:

Remember the leap year rule (Given in the formulas)

1. Every year divisible by 4 is a leap year, if it is not a century.

2. Every 4th century is a leap year, but no other century is a leap year.

800,1200 and 2000 comes in the category of 4th century (such as 400,800,1200,1600,2000 etc).

Hence 800,1200 and 2000 are leap years

700 is not a 4th century, but it is a century. Hence it is not a leap year

**8. 01-Jan-2007 was Monday. What day of the week lies on 01-Jan-2008?**

**A. Wednesday**

**B. Sunday**

**C. Friday**

**D. Tuesday**

**Answer: **Option D

Explanation:

Given that January 1, 2007 was Monday.

Odd days in 2007 = 1 (we have taken the complete year 2007 because we need to find out the odd days from 01-Jan-2007 to 31-Dec-2007, that is the whole year 2007)

Hence January 1, 2008 = (Monday + 1 Odd day) = Tuesday

**9. 8th Dec 2007 was Saturday, what day of the week was it on 8th Dec, 2006?**

**A. Sunday**

**B. Tuesday**

**C. Friday**

**D. Tuesday**

**Answer: **Option C

Explanation:

Given that 8th Dec 2007 was Saturday

Number of days from 8th Dec, 2006 to 7th Dec 2007 = 365 days

365 days = 1 odd day

Hence 8th Dec 2006 was = (Saturday - 1 odd day) = Friday

**10. On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?**

**A. Sunday**

**B. Friday**

**C. Saturday**

**D. Monday**

**Answer: **Option A

Explanation:

Given that 8th Feb, 2005 was Tuesday

Number of days from 8th Feb, 2004 to 7th Feb, 2005 = 366 *(Since Feb 2004 has 29 days as it is a leap year)*

366 days = 2 odd days

Hence 8th Feb, 2004 = (Tuesday - 2 odd days) = Sunday

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