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# Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev

## Mechanical Engineering : Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev

The document Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev is a part of the Mechanical Engineering Course Mechanical Engineering SSC JE (Technical).
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IMPULSE OF JETS

• Jet Strikes normal to the flat stationary plate Force exerted by the jet normal to the plate
P= ρaV2
a = area of jet
V = velocity of jet 

• Jet strikes on a inclined stationary plate • Force exerted by the jet normal to the plate    •  Force exerted by jet on moving flat plate normal to jet. u = plate velocity
Pn  = ρa(V – u)2
Work done per second (W) = Pn × u = ra[V – u]2 × u 

• Jet strikes on series of flat plat mounted on the periphery of wheel P= ρaV(V – u)
Work done by the jet = Pn × U
W = ρaV(V – u)u

Efficiency of the work done of wheel h = at , •  Jet striking on a symmetrical stationary curved plate Pn = ρaV2 (1 + cos q)
Force exerted by a jet in its direction of flow on a curved vane is always greater than that exerted on a flat plate.
Force Exerted By a jet on a Hinged Plate •  Force due to jet of water, normal to the plate
Pn = ρaV2 sin (90º –θ) 
• For equilibrium of plate Offer running on EduRev: Apply code STAYHOME200 to get INR 200 off on our premium plan EduRev Infinity!

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