Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev

Mechanical Engineering SSC JE (Technical)

Mechanical Engineering : Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev

The document Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev is a part of the Mechanical Engineering Course Mechanical Engineering SSC JE (Technical).
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Chapter 14

IMPULSE OF JETS

  • Jet Strikes normal to the flat stationary plate

Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev

Force exerted by the jet normal to the plate
P= ρaV2
a = area of jet
V = velocity of jet 

  • Jet strikes on a inclined stationary plate

Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev

  • Force exerted by the jet normal to the plate

Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev

Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev

Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev

Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev

  •  Force exerted by jet on moving flat plate normal to jet.

Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev

u = plate velocity
Pn  = ρa(V – u)2
Work done per second (W) = Pn × u = ra[V – u]2 × u 

  • Jet strikes on series of flat plat mounted on the periphery of wheel

Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev

P= ρaV(V – u)
Work done by the jet = Pn × U
W = ρaV(V – u)u

Efficiency of the work done of wheel h =Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev
at ,Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev

  •  Jet striking on a symmetrical stationary curved plate

Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev

Pn = ρaV2 (1 + cos q)
Force exerted by a jet in its direction of flow on a curved vane is always greater than that exerted on a flat plate.
Force Exerted By a jet on a Hinged Plate

Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev

  •  Force due to jet of water, normal to the plate
    Pn = ρaV2 sin (90º –θ) 
  • For equilibrium of plate

Chapter 14 Impulse of Jets - Fluid Mechanics, Mechanical Engineering Mechanical Engineering Notes | EduRev

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