Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev

Mathematics for Class 5

Class 5 : Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev

The document Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev is a part of the Class 5 Course Mathematics for Class 5.
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Arithmetic Operations on Large Numbers

Large numbers are technically described as numbers bigger than what is used in daily life. As like normal numbers, it is possible to apply the arithmetic operations on the large numbers, such as:

Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev

  • Addition of Large numbers
  • Subtraction of Large Numbers
  • Multiplication of Large Numbers
  • Division of Large Numbers

Addition

Two or more numbers called the addends are added to give an answer called the sum.

Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev

Example 1: The statistics on the Internet suggests that the estimated population of Russia and Mexico is 14,39,64,709 and 13,07,59,074 respectively. If the population of USA is 32,67,66,748, find out whether the population of Russia and Mexico taken together is more than that of USA or not.

Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev
Population of Russia and Mexico = 27,47,23,783
Population of USA = 32,67,66,748
Since, 3 ten crores > 2 ten crores, so the population of USA is more than the population of Russia and Mexico taken together.


Subtraction

When a number called subtrahend is subtracted from another number called minuend, the result is called their difference.

Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev


Example 1: The population of Greater Mumbai and Chennai as per 2011 census was 1,63,68,084 and 64,24,624 respectively. How much more is Greater Mumbai’s population as compared to Chennai?

Population of Greater Mumbai = 1,63,68,084
Population of Chennai = 64,24,624
Population difference  = 1,63,68,084 – 64,24,624
= 99,43,460
Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev
Thus, population of Greater Mumbai is 99,43,460 more than that of Chennai.
You can check subtraction by adding the subtrahend to the difference. If the sum is equal to the minuend, then the subtraction has been carried out correctly.
Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev


Multiplication

You know that multiplication is repeated addition.
The number which is to be repeated or multiplied is called the multiplicand.
The number which expresses how often the multiplicand is repeated is called the multiplier.

Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev
Multiplier times the multiplicand = Product

For example:
Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev2 added repeatedly five times.
Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRevChapter Notes: Operations on Large Numbers Class 5 Notes | EduRev


Edurev Tips: The multiplier and the multiplicand are also called the factors.

Properties of Multiplication

  1. Changing the order of factors does not change the product.
    Example: 12 × 7 = 7 × 12 = 84
  2. The product of any number and 1 is the number itself.
    Example: 345 × 1 = 1 × 345 = 345
  3. Changing the grouping of factors does not change the product.
    Example: 2 × (4 × 9) = 2 × 36 = 72; (2 × 4) × 9 = 8 × 9 = 72
    ∴ 2 × (4 × 9) = (2 × 4) × 9 = 72.
  4. The product of any number and 0 is 0.
    Example: 79014 × 0 = 0

Multiplication by Multiples of 10

When one or both factors are multiples of 10, you can multiply mentally. Look at the following patterns to revise how
Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev


  • 7 × 1 ten = 7 tens = 70
    4 × 2 hundreds = 8 hundreds
    = 800
  • To multiply by the multiples of 10, first find the product of the front non-zero digits. Then, write as many zeros after the product as there are zeros in both the factors.

Following the same pattern, we can mentally multiply a number by 10000 or 100000 and write the product.
Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev


Example 1: Find the products.
(a) 5078 × 200
(b) 1294 × 7000
(c) 71950 × 40000

(a) 5078 × 200 = 5078 × (2 × 100)
= (5078 × 2) × 100
= 10156 × 100 = 1015600
(b) 1294 × 7000 = 1294 × (7 × 1000)
= (1294 × 7) × 1000
= 9058 × 1000
= 9058000
(c) 71950 × 40000 = 71950 × (4 × 10000)
= (71950 × 4) × 10000
= 287800 × 10000
= 2878000000


Multiplying Large Numbers

Example 1: Multiply:
(a) 70935 by 36
(b) 32893 by 975

(a)
Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev

∴ 70,935 × 36 = 25,53,660.

(b)
Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev
∴ 32,893 × 975 = 3,20,70,675.


Example 2: Multiply 2892 by 9760.

Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev
∴ 2892 × 9760 = 2,82,25,920.

Try yourself:Multiply 39567 by 6094.
View Solution


Edurev Tips: As shown below, if care is taken in placing the numerals, the zeros may be dropped without changing the product.
Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev


Division

You know that division is the opposite of multiplication. The number to be divided is called the dividend. The number which divides is called the divisor and the result obtained is called the quotient. The number remaining, in the end, is called the remainder.

Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRevParts of a Division

Example 1: Divide 333 by 15.

Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev
∴ 333 ÷ 15 = 22 R 3
So, we can check division as under:
15 × 22 + 3 = 330 + 3 = 333


Properties of Division

  1. Dividing a number by itself is equal to 1.
    Example: 7876 ÷ 7876 = 1
  2. Dividing zero by any number is equal to 0.
    Example: 0 ÷ 38765 = 0
  3. Dividing a number by 1 is equal to the number itself.
    Example: 76208 ÷ 1 = 76208
  4. Dividing any number by zero is not defined.
    Example: 3893 ÷ 0 (not defined)

Division by Multiples of 10

You have studied about division by multiples of 10 in class 4 in detail. Let us revise the same here.
376 ÷ 10 ⇒ Quotient = 37; Remainder =   6
3594 ÷ 100 ⇒ Quotient = 35; Remainder =  94
7894 ÷ 1000 ⇒ Quotient =  7; Remainder = 894
Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev
Thus, we have,
Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev
Similarly,
Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev


Division by a 2-Digit Divisor

Example 1: Divide 6590898 by 95.

Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev
∴ 6590898 ÷ 95 = 69377 R 83.
Take the first digit 9 of the divisor and divide 65 by 9. 9 sevens are 63 but 7 × 95 = 665, which is greater than 659. So, we take 6 in the quotient and subtract 6 × 95 = 570 from 659. Now, bring down 0. Take the first two digits of 890, i.e., 89. Divide by 9. 9 nines are 81 and 9 × 95 = 855. Subtract 855 from 890. Bring down 8. Now, proceed further in a similar manner till the remainder is less than 95.


Division by a 3-Digit Divisor

Example 1: Divide 371654 by 968.

Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev
∴ 371654 ÷ 968 = 383 R 910.
The divisor contains 3 digits, so we should consider 3 digits of the dividend, that is, 371. But since 371 is smaller than 968, we have to consider 4 digits, that is, 3716. Take the first digit 9 of the divisor and divide  37 by 9. The trial quotient is 4. But 4 × 968 gives 3872 which is greater than 3716, so take 3 as the quotient, 3 × 968 = 2904. Subtract 2904 from 3716 and bring down the next digit 5. Now, complete the division as shown.


Example 2: Divide 212588 by 697.

Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev
∴ 212588 ÷ 697 = 305 R 3.
Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev
We bring down 8 but the divisor 697 cannot divide 348 even once, so we put    0 after 3 in the quotient and bring down 8. Complete as shown.

Try yourself:Dividing 1886416 by 627. The Remainder we will get is:
View Solution


Operations on Numbers using Estimation

  • An estimate is a number close to an exact number which may be obtained by rounding off the exact number.
  • We have already learned rounding off numbers in Chapter 3. It helps us to get to a number that is near the actual number. 
  • We can make use of rounding off the numbers to estimate the sums, differences, products, and quotients.

Estimating Sums

Example: The population of town X is 616817 and that of town Y is 293402. Estimate the total population of both towns to the nearest thousand.

Rounding off the numbers to the nearest thousand, we get,
616817 → 617000 and 293402 → 293000
∴ Estimated sum = 617000 + 293000 = 910000


Estimating Differences

Example: There were 67853 spectators in the stadium, out of which 15229 were children. Estimate the number of adults in the stadium to the nearest thousand.

Total number of spectators in the stadium = 68000 (Rounded off to the nearest thousand)
Total number of children in the stadium = 15000
∴ Number of adults in the stadium = 68000 – 15000 = 53000
So, there were about 53000 adults in the stadium.


Estimating Products

Example: A factory produces 19272 bulbs every month. About how many bulbs will be produced in a year? Also, find the actual answer.

Here, we need to find the product of number of bulbs produced in a month and the number of months.
Chapter Notes: Operations on Large Numbers Class 5 Notes | EduRev


Edurev Tips: While estimating an operation with two numbers with different number of digits, always round off the numbers to the highest place value.


Estimating Quotients

To estimate the quotient, we find the compatible numbers (a multiple of divisor). For example, to estimate the quotient of 72 and 432.

We round off 72 → 70 and 432 → 420.
∴ 7 × 6 = 42.
So, the estimated quotient is 6.

Example: The cost of 28 jackets is ₹ 41,580. Find the estimated cost of one jacket.

28 is rounded off to 30 and ₹ 41581 is rounded off to ₹ 42000 as 30 and 42000 are compatible numbers.
∴ Estimated quotient = 42000 ÷ 30 = 1400.
So, the estimated cost of one jacket is ₹ 1400.

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