Civil Engineering Beams Civil Engineering (CE) Notes | EduRev

Topic wise GATE Past Year Papers for Civil Engineering

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Civil Engineering (CE) : Civil Engineering Beams Civil Engineering (CE) Notes | EduRev

The document Civil Engineering Beams Civil Engineering (CE) Notes | EduRev is a part of the Civil Engineering (CE) Course Topic wise GATE Past Year Papers for Civil Engineering.

Q.1  A rolled I-section beam is supported on a 75 mm wide bearing plate as shown in the figure. Thicknesses of flange and web of the I-section are 20 mm and 8 mm, respectively. Root radius of the I-section is 10 mm. Assume: material yield stress, fy = 250 MPa and partial safety factor for material. γmo = 1.10.
Civil Engineering Beams Civil Engineering (CE) Notes | EduRev
As per IS: 800-2007, the web bearing strengt (in kN, round off to 2 decimal places) of the beam is_____.    [2019 : 2 Marks, Set-II]
Solution:

Web bearing strength
Civil Engineering Beams Civil Engineering (CE) Notes | EduRev
Civil Engineering Beams Civil Engineering (CE) Notes | EduRev
Civil Engineering Beams Civil Engineering (CE) Notes | EduRev

Q.2  Assuming that there is no possibility of shear buckling in the web, the maximum reduction permitted by IS 800-2007 in the (low-shear) design bending strength of a semi-compact steel section due to high shear is    [2019 : 1 Mark, Set-I]
(a) Zero
(b) governed by the area of the flange
(c) 50%
(d) 25%
Ans.
(A)
Solution:
As per IS 800 : 2007
For semi compact section
Civil Engineering Beams Civil Engineering (CE) Notes | EduRev
So reduction is zero.

Q.3 A steel column of ISHB 350 @ 72.4 kg/m is subjected to a factored axial compressive load of 2000 kN. The load is transferred to a concrete pedestal of grade M20 through a square base plate. Consider bearing of concrete as 0.45 fck, where fck is the characteristic strength of concrete. Using limit state method and neglecting the self weight of base plate and steel column, the length of a side of the base plate to be provided is    [2018 : 1 Mark, Set-I]
(a) 39 cm
(b) 42 cm
(c) 45 cm
(d) 48 cm
Ans.
(B)
Solution:
Area required for base plate
Civil Engineering Beams Civil Engineering (CE) Notes | EduRev
= 48.24 mm
= 40.8 cm
Since, provided area must be more than required so answer should be 42 cm.

Q.4 The semi-compact section of a laterally unsupported steel beam has an elastic section modulus, plastic section modulus and design bending compressive stress of 500 cm3, 650 cm3 and 200 MPa respectively. The design flexural capacity (expressed in kNm) of the section is______.   [2016 : 1 Mark, Set-I]
Solution:

Design flexural capacity,
Civil Engineering Beams Civil Engineering (CE) Notes | EduRev
zp = plastic section modulus
ze = elastic section modulus
fy = yeild stress of steel provided
γm0 = material factor of safety of steel against yeilding
As, design bending stress is directly given,
Civil Engineering Beams Civil Engineering (CE) Notes | EduRev
Civil Engineering Beams Civil Engineering (CE) Notes | EduRev

Q.5 A steel section is subjected to a combination of shear and bending actions. The applied shear force is V'and the shear capacity of the section is Vs. For such a section, high shear force (as per IS 800 : 2007) is defined as    [2014 : 1 Mark, Set-I]
(a) V>0.6 Vs 
(b) V>0.7 VS 
(c) V > 0.8 Vs 
(d) V > 0.9 Vs
Ans.
(A)
Solution:
According to IS 800 : 2007, clause 9.2.1 No reduction in moment capacity of the section is necessary as long as the cross-section is not subjected to high shear force (factored value of shear force in less than or equal to 60 percent of the shear strength of the section)

Q.6  The adjoining figure shows a schematic representation of a steel plate girder to be used as a simply supported beam with a concentrated load. For stiffeners, PQ (running along the beam axis) and RS(running between the top and bottom flanges) which of the following pairs of statements will be TRUE?    [2011 : 2 Marks]
Civil Engineering Beams Civil Engineering (CE) Notes | EduRev
(a) (i) RS should be provided under the concentrated load only
(ii) PQ should be placed in the tension side of the flange.
(b) (i) RS helps to prevent local buckling of the web.
(ii) PQ should be placed in the compression side of the flange.
(c) (i) RS should be provided at supports.
(ii) PQ should be placed along the neutral axis
(d) (i) RS should be provided away from points of action of concentrated loads.
(ii) PQ should be provided on the compression side of the flange.
Ans. 
(B)
Solution:
PQ is a horizontal stiffener in the given plate girder. Horizontal stiffeners are also called longitudinal stiffeners. The horizontal stiffener are provided in the compression zone of the web. The first horizontal stiffener is provided at one-fifth of the distance from the compression flange to the tension flange. If required another stiffener is provided at the neutral axis. Horizontal stiffeners are not continuous and are provided between vertical stiffeners.
RS is a vertical stiffener in the given plate girder. Vertical stiffeners are also called transverse stiffeners. It is assumed that the vertical stiffener is not subjected to any load and is selected to provide necessary lateral stiffness only and can there fore , be crimped or joggled for tight fittings . Such stiffeners increase the buckling resistance of the web caused by shear. 

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