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Page 1 G e n e r a l I n s t r u c t i o n s : • T h i s q u e s t i o n p a p e r h a s 3 1 q u e s t i o n s . • S e c t i o n A c o n s i s t s o f 4 q u e s t i o n s o f 1 m a r k e a c h . • S e c t i o n B c o n s i s t s o f 6 q u e s t i o n s o f 2 m a r k s e a c h . • S e c t i o n C c o n s i s t s o f 1 0 q u e s t i o n s o f 3 m a r k s e a c h . • S e c t i o n D c o n s i s t s o f 1 1 q u e s t i o n s o f 4 m a r k s e a c h . • A l l q u e s t i o n s a r e c o m p u l s o r y t o a t t e m p t . • A t t e m p t t h e p a p e r n e a t l y a n d l e g i b l y . S E C T I O N - A 1 . F i n d t h e e s t i m a t e d d i f f e r e n c e o f 4 8 9 3 4 8 a n d 4 8 3 6 5 . A n s . 4 8 9 3 4 8 r o u n d e d o f f t o n e a r e s t t e n t h o u s a n d s = 4 9 0 0 0 0 4 8 3 6 5 r o u n d e d o f f t o n e a r e s t t e n t h o u s a n d s = 5 0 0 0 0 E s t i m a t e d d i f f e r e n c e = 4 4 0 0 0 0 2 . I n a p i c t o g r a p h , i f t h e s y m b o l r e p r e s e n t s 2 0 s t u d e n t s , t h e n h o w m a n y s t u d e n t s w i l l b e r e p r e s e n t e d b y t h e s y m b o l ? A n s . 3 5 . 3 . S o l v e a n d w r i t e t h e a n s w e r i n t h e H i n d u A r a b i c N u m e r a l : D - C D X L = _ _ _ _ _ _ A n s . D - C D X L = 5 0 0 – 4 4 0 = 6 0 = L X 4 . H o w m a n y d e g r e e s a r e t h e r e i n t h e a n g l e b e t w e e n t h e h a n d s o f a c l o c k w h e n i t i s 6 o ’ c l o c k ? A n s . 1 8 0 d e g r e e s = s t r a i g h t a n g l e Page 2 G e n e r a l I n s t r u c t i o n s : • T h i s q u e s t i o n p a p e r h a s 3 1 q u e s t i o n s . • S e c t i o n A c o n s i s t s o f 4 q u e s t i o n s o f 1 m a r k e a c h . • S e c t i o n B c o n s i s t s o f 6 q u e s t i o n s o f 2 m a r k s e a c h . • S e c t i o n C c o n s i s t s o f 1 0 q u e s t i o n s o f 3 m a r k s e a c h . • S e c t i o n D c o n s i s t s o f 1 1 q u e s t i o n s o f 4 m a r k s e a c h . • A l l q u e s t i o n s a r e c o m p u l s o r y t o a t t e m p t . • A t t e m p t t h e p a p e r n e a t l y a n d l e g i b l y . S E C T I O N - A 1 . F i n d t h e e s t i m a t e d d i f f e r e n c e o f 4 8 9 3 4 8 a n d 4 8 3 6 5 . A n s . 4 8 9 3 4 8 r o u n d e d o f f t o n e a r e s t t e n t h o u s a n d s = 4 9 0 0 0 0 4 8 3 6 5 r o u n d e d o f f t o n e a r e s t t e n t h o u s a n d s = 5 0 0 0 0 E s t i m a t e d d i f f e r e n c e = 4 4 0 0 0 0 2 . I n a p i c t o g r a p h , i f t h e s y m b o l r e p r e s e n t s 2 0 s t u d e n t s , t h e n h o w m a n y s t u d e n t s w i l l b e r e p r e s e n t e d b y t h e s y m b o l ? A n s . 3 5 . 3 . S o l v e a n d w r i t e t h e a n s w e r i n t h e H i n d u A r a b i c N u m e r a l : D - C D X L = _ _ _ _ _ _ A n s . D - C D X L = 5 0 0 – 4 4 0 = 6 0 = L X 4 . H o w m a n y d e g r e e s a r e t h e r e i n t h e a n g l e b e t w e e n t h e h a n d s o f a c l o c k w h e n i t i s 6 o ’ c l o c k ? A n s . 1 8 0 d e g r e e s = s t r a i g h t a n g l e S E C T I O N - B 5 . F i n d t h e p r o d u c t o f t h e p l a c e v a l u e s o f t w o 7 s i n 1 9 7 0 4 7 . A n s . P l a c e v a l u e o f 7 i n 1 9 7 0 4 7 i s 7 0 0 0 a n d 7 P r o d u c t = 4 9 0 0 0 6 . S i m p l i f y u s i n g d i s t r i b u t i v e p r o p e r t y o f w h o l e n u m b e r s : 8 3 5 x 1 0 5 A n s . 8 3 5 × 1 0 5 = 8 3 5 × ( 1 0 0 + 5 ) = 8 3 5 × 1 0 0 + 8 3 5 × 5 ( u s i n g d i s t r i b u t i v e p r o p e r t y ) = 8 3 5 0 0 + 4 1 7 5 = 8 7 6 7 5 7 . I s 2 8 a p e r f e c t n u m b e r ? S h o w t h e w o r k i n g . A n s . F a c t o r s o f 2 8 a r e 1 , 2 , 4 , 7 , 1 4 a n d 2 8 S u m o f f a c t o r s = 1 + 2 + 4 + 7 + 1 4 + 2 8 = 5 6 w h i c h i s 2 × 2 8 T h e r e f o r e , Y e s 2 8 i s a p e r f e c t n u m b e r 8 . F i n d t h e d i a m e t e r o f a c i r c l e i f i t s r a d i u s i s 4 . 5 c m . A n s . D i a m e t e r = 2 x 4 . 5 c m = 9 c m 9 . T h e f o l l o w i n g a r e t h e m a r k s s c o r e d b y 2 0 s t u d e n t s o f V I A i n M a t h e m a t i c s e x a m : 5 7 , 6 5 , 8 0 , 5 7 , 8 0 , 6 5 , 8 5 , 3 4 , 5 7 , 4 1 , 5 4 , 8 0 , 4 1 , 5 4 , 3 4 , 4 1 , 8 5 , 5 7 , 8 0 , 6 5 P r e p a r e a f r e q u e n c y d i s t r i b u t i o n t a b l e . A n s . F r e q u e n c y d i s t r i b u t i o n t a b l e n e a t l y d r a w n 1 0 . S t a t e t h e c o m m u t a t i v e p r o p e r t y o f a d d i t i o n o f w h o l e n u m b e r s . G i v e a n e x a m p l e . A n s . a + b = b + a F o r e g : 3 + 5 = 5 + 3 = 8 S E C T I O N - C Page 3 G e n e r a l I n s t r u c t i o n s : • T h i s q u e s t i o n p a p e r h a s 3 1 q u e s t i o n s . • S e c t i o n A c o n s i s t s o f 4 q u e s t i o n s o f 1 m a r k e a c h . • S e c t i o n B c o n s i s t s o f 6 q u e s t i o n s o f 2 m a r k s e a c h . • S e c t i o n C c o n s i s t s o f 1 0 q u e s t i o n s o f 3 m a r k s e a c h . • S e c t i o n D c o n s i s t s o f 1 1 q u e s t i o n s o f 4 m a r k s e a c h . • A l l q u e s t i o n s a r e c o m p u l s o r y t o a t t e m p t . • A t t e m p t t h e p a p e r n e a t l y a n d l e g i b l y . S E C T I O N - A 1 . F i n d t h e e s t i m a t e d d i f f e r e n c e o f 4 8 9 3 4 8 a n d 4 8 3 6 5 . A n s . 4 8 9 3 4 8 r o u n d e d o f f t o n e a r e s t t e n t h o u s a n d s = 4 9 0 0 0 0 4 8 3 6 5 r o u n d e d o f f t o n e a r e s t t e n t h o u s a n d s = 5 0 0 0 0 E s t i m a t e d d i f f e r e n c e = 4 4 0 0 0 0 2 . I n a p i c t o g r a p h , i f t h e s y m b o l r e p r e s e n t s 2 0 s t u d e n t s , t h e n h o w m a n y s t u d e n t s w i l l b e r e p r e s e n t e d b y t h e s y m b o l ? A n s . 3 5 . 3 . S o l v e a n d w r i t e t h e a n s w e r i n t h e H i n d u A r a b i c N u m e r a l : D - C D X L = _ _ _ _ _ _ A n s . D - C D X L = 5 0 0 – 4 4 0 = 6 0 = L X 4 . H o w m a n y d e g r e e s a r e t h e r e i n t h e a n g l e b e t w e e n t h e h a n d s o f a c l o c k w h e n i t i s 6 o ’ c l o c k ? A n s . 1 8 0 d e g r e e s = s t r a i g h t a n g l e S E C T I O N - B 5 . F i n d t h e p r o d u c t o f t h e p l a c e v a l u e s o f t w o 7 s i n 1 9 7 0 4 7 . A n s . P l a c e v a l u e o f 7 i n 1 9 7 0 4 7 i s 7 0 0 0 a n d 7 P r o d u c t = 4 9 0 0 0 6 . S i m p l i f y u s i n g d i s t r i b u t i v e p r o p e r t y o f w h o l e n u m b e r s : 8 3 5 x 1 0 5 A n s . 8 3 5 × 1 0 5 = 8 3 5 × ( 1 0 0 + 5 ) = 8 3 5 × 1 0 0 + 8 3 5 × 5 ( u s i n g d i s t r i b u t i v e p r o p e r t y ) = 8 3 5 0 0 + 4 1 7 5 = 8 7 6 7 5 7 . I s 2 8 a p e r f e c t n u m b e r ? S h o w t h e w o r k i n g . A n s . F a c t o r s o f 2 8 a r e 1 , 2 , 4 , 7 , 1 4 a n d 2 8 S u m o f f a c t o r s = 1 + 2 + 4 + 7 + 1 4 + 2 8 = 5 6 w h i c h i s 2 × 2 8 T h e r e f o r e , Y e s 2 8 i s a p e r f e c t n u m b e r 8 . F i n d t h e d i a m e t e r o f a c i r c l e i f i t s r a d i u s i s 4 . 5 c m . A n s . D i a m e t e r = 2 x 4 . 5 c m = 9 c m 9 . T h e f o l l o w i n g a r e t h e m a r k s s c o r e d b y 2 0 s t u d e n t s o f V I A i n M a t h e m a t i c s e x a m : 5 7 , 6 5 , 8 0 , 5 7 , 8 0 , 6 5 , 8 5 , 3 4 , 5 7 , 4 1 , 5 4 , 8 0 , 4 1 , 5 4 , 3 4 , 4 1 , 8 5 , 5 7 , 8 0 , 6 5 P r e p a r e a f r e q u e n c y d i s t r i b u t i o n t a b l e . A n s . F r e q u e n c y d i s t r i b u t i o n t a b l e n e a t l y d r a w n 1 0 . S t a t e t h e c o m m u t a t i v e p r o p e r t y o f a d d i t i o n o f w h o l e n u m b e r s . G i v e a n e x a m p l e . A n s . a + b = b + a F o r e g : 3 + 5 = 5 + 3 = 8 S E C T I O N - C 1 1 . S u b t r a c t 2 5 2 7 0 5 3 f r o m 2 7 2 5 3 5 0 a n d w r i t e t h e n u m b e r s e n t e n c e . A n s . S u b t r a c t i o n s h o w n N u m b e r s e n t e n c e : 2 7 2 5 3 5 0 – 2 5 2 7 0 5 3 = 1 9 8 2 9 1 2 . F i n d t h e g r e a t e s t 4 - d i g i t n u m b e r w h i c h i s e x a c t l y d i v i s i b l e b y 3 7 . A n s . G r e a t e s t 4 - d i g i t n u m b e r = 9 9 9 9 D i v i d e 9 9 9 9 b y 3 7 R e m a i n d e r = 9 N o w , r e q u i r e d n u m b e r = 9 9 9 9 – 9 = 9 9 9 0 1 3 . I n 5 6 * 8 9 1 r e p l a c e * b y ( a ) b y 3 . A n s . A c c o r d i n g t o d i v i s i b i l i t y t e s t o f 3 , S u m o f d i g i t s = 5 + 6 + * + 8 + 9 + 1 = 2 9 + * ( a ) S m a l l e s t d i g i t = 1 ( b ) L a r g e s t d i g i t = 7 1 4 . F i n d t h e H C F o f 3 8 5 a n d 6 2 1 . A r e t h e y c o p r i m e A n s . H C F o f 3 8 5 a n d 6 2 1 = 1 Y e s t h e y a r e C o p r i m e 1 5 . N a m e a n y s i x a n g l e s i n t h e g i v e n f i g u r e : A n s . A B C , B A C , A C B , B D C , D C B , D B C , A B D a n d A C D ( a t l e a s t 6 ) 1 6 . D r a w a r o u g h s k e t c h o f a q u a d r i l a t e r a l E F G H a n d n a m e a . a p a i r o f o p p o s i t e s i d e s . b . a p a i r o f a d j a c e n t a n g l e s c . t w o d i a g o n a l s . Page 4 G e n e r a l I n s t r u c t i o n s : • T h i s q u e s t i o n p a p e r h a s 3 1 q u e s t i o n s . • S e c t i o n A c o n s i s t s o f 4 q u e s t i o n s o f 1 m a r k e a c h . • S e c t i o n B c o n s i s t s o f 6 q u e s t i o n s o f 2 m a r k s e a c h . • S e c t i o n C c o n s i s t s o f 1 0 q u e s t i o n s o f 3 m a r k s e a c h . • S e c t i o n D c o n s i s t s o f 1 1 q u e s t i o n s o f 4 m a r k s e a c h . • A l l q u e s t i o n s a r e c o m p u l s o r y t o a t t e m p t . • A t t e m p t t h e p a p e r n e a t l y a n d l e g i b l y . S E C T I O N - A 1 . F i n d t h e e s t i m a t e d d i f f e r e n c e o f 4 8 9 3 4 8 a n d 4 8 3 6 5 . A n s . 4 8 9 3 4 8 r o u n d e d o f f t o n e a r e s t t e n t h o u s a n d s = 4 9 0 0 0 0 4 8 3 6 5 r o u n d e d o f f t o n e a r e s t t e n t h o u s a n d s = 5 0 0 0 0 E s t i m a t e d d i f f e r e n c e = 4 4 0 0 0 0 2 . I n a p i c t o g r a p h , i f t h e s y m b o l r e p r e s e n t s 2 0 s t u d e n t s , t h e n h o w m a n y s t u d e n t s w i l l b e r e p r e s e n t e d b y t h e s y m b o l ? A n s . 3 5 . 3 . S o l v e a n d w r i t e t h e a n s w e r i n t h e H i n d u A r a b i c N u m e r a l : D - C D X L = _ _ _ _ _ _ A n s . D - C D X L = 5 0 0 – 4 4 0 = 6 0 = L X 4 . H o w m a n y d e g r e e s a r e t h e r e i n t h e a n g l e b e t w e e n t h e h a n d s o f a c l o c k w h e n i t i s 6 o ’ c l o c k ? A n s . 1 8 0 d e g r e e s = s t r a i g h t a n g l e S E C T I O N - B 5 . F i n d t h e p r o d u c t o f t h e p l a c e v a l u e s o f t w o 7 s i n 1 9 7 0 4 7 . A n s . P l a c e v a l u e o f 7 i n 1 9 7 0 4 7 i s 7 0 0 0 a n d 7 P r o d u c t = 4 9 0 0 0 6 . S i m p l i f y u s i n g d i s t r i b u t i v e p r o p e r t y o f w h o l e n u m b e r s : 8 3 5 x 1 0 5 A n s . 8 3 5 × 1 0 5 = 8 3 5 × ( 1 0 0 + 5 ) = 8 3 5 × 1 0 0 + 8 3 5 × 5 ( u s i n g d i s t r i b u t i v e p r o p e r t y ) = 8 3 5 0 0 + 4 1 7 5 = 8 7 6 7 5 7 . I s 2 8 a p e r f e c t n u m b e r ? S h o w t h e w o r k i n g . A n s . F a c t o r s o f 2 8 a r e 1 , 2 , 4 , 7 , 1 4 a n d 2 8 S u m o f f a c t o r s = 1 + 2 + 4 + 7 + 1 4 + 2 8 = 5 6 w h i c h i s 2 × 2 8 T h e r e f o r e , Y e s 2 8 i s a p e r f e c t n u m b e r 8 . F i n d t h e d i a m e t e r o f a c i r c l e i f i t s r a d i u s i s 4 . 5 c m . A n s . D i a m e t e r = 2 x 4 . 5 c m = 9 c m 9 . T h e f o l l o w i n g a r e t h e m a r k s s c o r e d b y 2 0 s t u d e n t s o f V I A i n M a t h e m a t i c s e x a m : 5 7 , 6 5 , 8 0 , 5 7 , 8 0 , 6 5 , 8 5 , 3 4 , 5 7 , 4 1 , 5 4 , 8 0 , 4 1 , 5 4 , 3 4 , 4 1 , 8 5 , 5 7 , 8 0 , 6 5 P r e p a r e a f r e q u e n c y d i s t r i b u t i o n t a b l e . A n s . F r e q u e n c y d i s t r i b u t i o n t a b l e n e a t l y d r a w n 1 0 . S t a t e t h e c o m m u t a t i v e p r o p e r t y o f a d d i t i o n o f w h o l e n u m b e r s . G i v e a n e x a m p l e . A n s . a + b = b + a F o r e g : 3 + 5 = 5 + 3 = 8 S E C T I O N - C 1 1 . S u b t r a c t 2 5 2 7 0 5 3 f r o m 2 7 2 5 3 5 0 a n d w r i t e t h e n u m b e r s e n t e n c e . A n s . S u b t r a c t i o n s h o w n N u m b e r s e n t e n c e : 2 7 2 5 3 5 0 – 2 5 2 7 0 5 3 = 1 9 8 2 9 1 2 . F i n d t h e g r e a t e s t 4 - d i g i t n u m b e r w h i c h i s e x a c t l y d i v i s i b l e b y 3 7 . A n s . G r e a t e s t 4 - d i g i t n u m b e r = 9 9 9 9 D i v i d e 9 9 9 9 b y 3 7 R e m a i n d e r = 9 N o w , r e q u i r e d n u m b e r = 9 9 9 9 – 9 = 9 9 9 0 1 3 . I n 5 6 * 8 9 1 r e p l a c e * b y ( a ) b y 3 . A n s . A c c o r d i n g t o d i v i s i b i l i t y t e s t o f 3 , S u m o f d i g i t s = 5 + 6 + * + 8 + 9 + 1 = 2 9 + * ( a ) S m a l l e s t d i g i t = 1 ( b ) L a r g e s t d i g i t = 7 1 4 . F i n d t h e H C F o f 3 8 5 a n d 6 2 1 . A r e t h e y c o p r i m e A n s . H C F o f 3 8 5 a n d 6 2 1 = 1 Y e s t h e y a r e C o p r i m e 1 5 . N a m e a n y s i x a n g l e s i n t h e g i v e n f i g u r e : A n s . A B C , B A C , A C B , B D C , D C B , D B C , A B D a n d A C D ( a t l e a s t 6 ) 1 6 . D r a w a r o u g h s k e t c h o f a q u a d r i l a t e r a l E F G H a n d n a m e a . a p a i r o f o p p o s i t e s i d e s . b . a p a i r o f a d j a c e n t a n g l e s c . t w o d i a g o n a l s . A n s . a . A p a i r o f o p p o s i t e s i d e s – E F a n d G H b . A p a i r o f a d j a c e n t a n g l e s - E a n d G c . T w o d i a g o n a l s – E G a n d F H 1 7 . C l a s s i f y t h e t r i a n g l e s o n t h e b a s i s o f a n g l e s . A n s . A c u t e a n g l e d t r i a n g l e , O b t u s e a n g l e d t r i a n g l e a n d R i g h t a n g l e d t r i a n g l e 1 8 . L o o k a t t h e f i g u r e b e l o w a . W r i t e a n o t h e r w a y o f n a m i n g l i n e b . b . W r i t e a n o t h e r w a y o f n a m i n g l i n e a . c . W r i t e a s e t o f c o l l i n e a r p o i n t s . A n s . a . A n o t h e r w a y o f n a m i n g l i n e b . - Q S b . A n o t h e r w a y o f n a m i n g l i n e a . – P R c . A s e t o f c o l l i n e a r p o i n t s . – P , Q a n d T o r R , S a n d T 1 9 . T h e d a t a g i v e n b e l o w p r o v i d e s i n f o r m a t i o n a b o u t t h e n u m b e r o f b o o k s o n d i f f e r e n t s u b j e c t s i n a l i b r a r y . R e p r e s e n t t h e d a t a u s i n g a p i c t o g r a p h u s i n g a s u i t a b l e s c a l e S u b j e c t E n g l i s h H i n d i M a t h e m a t i c s S c i e n c e N o . o f b o o k s 1 0 0 0 6 5 0 8 0 0 4 5 0 A n s . P i c t o g r a p h n e a t l y d r a w n S c a l e s h o w n 2 0 . T h e c o l o u r s o f c a r s p r e f e r r e d b y p e o p l e l i v i n g i n a l o c a l i t y a r e s h o w n b y t h e Page 5 G e n e r a l I n s t r u c t i o n s : • T h i s q u e s t i o n p a p e r h a s 3 1 q u e s t i o n s . • S e c t i o n A c o n s i s t s o f 4 q u e s t i o n s o f 1 m a r k e a c h . • S e c t i o n B c o n s i s t s o f 6 q u e s t i o n s o f 2 m a r k s e a c h . • S e c t i o n C c o n s i s t s o f 1 0 q u e s t i o n s o f 3 m a r k s e a c h . • S e c t i o n D c o n s i s t s o f 1 1 q u e s t i o n s o f 4 m a r k s e a c h . • A l l q u e s t i o n s a r e c o m p u l s o r y t o a t t e m p t . • A t t e m p t t h e p a p e r n e a t l y a n d l e g i b l y . S E C T I O N - A 1 . F i n d t h e e s t i m a t e d d i f f e r e n c e o f 4 8 9 3 4 8 a n d 4 8 3 6 5 . A n s . 4 8 9 3 4 8 r o u n d e d o f f t o n e a r e s t t e n t h o u s a n d s = 4 9 0 0 0 0 4 8 3 6 5 r o u n d e d o f f t o n e a r e s t t e n t h o u s a n d s = 5 0 0 0 0 E s t i m a t e d d i f f e r e n c e = 4 4 0 0 0 0 2 . I n a p i c t o g r a p h , i f t h e s y m b o l r e p r e s e n t s 2 0 s t u d e n t s , t h e n h o w m a n y s t u d e n t s w i l l b e r e p r e s e n t e d b y t h e s y m b o l ? A n s . 3 5 . 3 . S o l v e a n d w r i t e t h e a n s w e r i n t h e H i n d u A r a b i c N u m e r a l : D - C D X L = _ _ _ _ _ _ A n s . D - C D X L = 5 0 0 – 4 4 0 = 6 0 = L X 4 . H o w m a n y d e g r e e s a r e t h e r e i n t h e a n g l e b e t w e e n t h e h a n d s o f a c l o c k w h e n i t i s 6 o ’ c l o c k ? A n s . 1 8 0 d e g r e e s = s t r a i g h t a n g l e S E C T I O N - B 5 . F i n d t h e p r o d u c t o f t h e p l a c e v a l u e s o f t w o 7 s i n 1 9 7 0 4 7 . A n s . P l a c e v a l u e o f 7 i n 1 9 7 0 4 7 i s 7 0 0 0 a n d 7 P r o d u c t = 4 9 0 0 0 6 . S i m p l i f y u s i n g d i s t r i b u t i v e p r o p e r t y o f w h o l e n u m b e r s : 8 3 5 x 1 0 5 A n s . 8 3 5 × 1 0 5 = 8 3 5 × ( 1 0 0 + 5 ) = 8 3 5 × 1 0 0 + 8 3 5 × 5 ( u s i n g d i s t r i b u t i v e p r o p e r t y ) = 8 3 5 0 0 + 4 1 7 5 = 8 7 6 7 5 7 . I s 2 8 a p e r f e c t n u m b e r ? S h o w t h e w o r k i n g . A n s . F a c t o r s o f 2 8 a r e 1 , 2 , 4 , 7 , 1 4 a n d 2 8 S u m o f f a c t o r s = 1 + 2 + 4 + 7 + 1 4 + 2 8 = 5 6 w h i c h i s 2 × 2 8 T h e r e f o r e , Y e s 2 8 i s a p e r f e c t n u m b e r 8 . F i n d t h e d i a m e t e r o f a c i r c l e i f i t s r a d i u s i s 4 . 5 c m . A n s . D i a m e t e r = 2 x 4 . 5 c m = 9 c m 9 . T h e f o l l o w i n g a r e t h e m a r k s s c o r e d b y 2 0 s t u d e n t s o f V I A i n M a t h e m a t i c s e x a m : 5 7 , 6 5 , 8 0 , 5 7 , 8 0 , 6 5 , 8 5 , 3 4 , 5 7 , 4 1 , 5 4 , 8 0 , 4 1 , 5 4 , 3 4 , 4 1 , 8 5 , 5 7 , 8 0 , 6 5 P r e p a r e a f r e q u e n c y d i s t r i b u t i o n t a b l e . A n s . F r e q u e n c y d i s t r i b u t i o n t a b l e n e a t l y d r a w n 1 0 . S t a t e t h e c o m m u t a t i v e p r o p e r t y o f a d d i t i o n o f w h o l e n u m b e r s . G i v e a n e x a m p l e . A n s . a + b = b + a F o r e g : 3 + 5 = 5 + 3 = 8 S E C T I O N - C 1 1 . S u b t r a c t 2 5 2 7 0 5 3 f r o m 2 7 2 5 3 5 0 a n d w r i t e t h e n u m b e r s e n t e n c e . A n s . S u b t r a c t i o n s h o w n N u m b e r s e n t e n c e : 2 7 2 5 3 5 0 – 2 5 2 7 0 5 3 = 1 9 8 2 9 1 2 . F i n d t h e g r e a t e s t 4 - d i g i t n u m b e r w h i c h i s e x a c t l y d i v i s i b l e b y 3 7 . A n s . G r e a t e s t 4 - d i g i t n u m b e r = 9 9 9 9 D i v i d e 9 9 9 9 b y 3 7 R e m a i n d e r = 9 N o w , r e q u i r e d n u m b e r = 9 9 9 9 – 9 = 9 9 9 0 1 3 . I n 5 6 * 8 9 1 r e p l a c e * b y ( a ) b y 3 . A n s . A c c o r d i n g t o d i v i s i b i l i t y t e s t o f 3 , S u m o f d i g i t s = 5 + 6 + * + 8 + 9 + 1 = 2 9 + * ( a ) S m a l l e s t d i g i t = 1 ( b ) L a r g e s t d i g i t = 7 1 4 . F i n d t h e H C F o f 3 8 5 a n d 6 2 1 . A r e t h e y c o p r i m e A n s . H C F o f 3 8 5 a n d 6 2 1 = 1 Y e s t h e y a r e C o p r i m e 1 5 . N a m e a n y s i x a n g l e s i n t h e g i v e n f i g u r e : A n s . A B C , B A C , A C B , B D C , D C B , D B C , A B D a n d A C D ( a t l e a s t 6 ) 1 6 . D r a w a r o u g h s k e t c h o f a q u a d r i l a t e r a l E F G H a n d n a m e a . a p a i r o f o p p o s i t e s i d e s . b . a p a i r o f a d j a c e n t a n g l e s c . t w o d i a g o n a l s . A n s . a . A p a i r o f o p p o s i t e s i d e s – E F a n d G H b . A p a i r o f a d j a c e n t a n g l e s - E a n d G c . T w o d i a g o n a l s – E G a n d F H 1 7 . C l a s s i f y t h e t r i a n g l e s o n t h e b a s i s o f a n g l e s . A n s . A c u t e a n g l e d t r i a n g l e , O b t u s e a n g l e d t r i a n g l e a n d R i g h t a n g l e d t r i a n g l e 1 8 . L o o k a t t h e f i g u r e b e l o w a . W r i t e a n o t h e r w a y o f n a m i n g l i n e b . b . W r i t e a n o t h e r w a y o f n a m i n g l i n e a . c . W r i t e a s e t o f c o l l i n e a r p o i n t s . A n s . a . A n o t h e r w a y o f n a m i n g l i n e b . - Q S b . A n o t h e r w a y o f n a m i n g l i n e a . – P R c . A s e t o f c o l l i n e a r p o i n t s . – P , Q a n d T o r R , S a n d T 1 9 . T h e d a t a g i v e n b e l o w p r o v i d e s i n f o r m a t i o n a b o u t t h e n u m b e r o f b o o k s o n d i f f e r e n t s u b j e c t s i n a l i b r a r y . R e p r e s e n t t h e d a t a u s i n g a p i c t o g r a p h u s i n g a s u i t a b l e s c a l e S u b j e c t E n g l i s h H i n d i M a t h e m a t i c s S c i e n c e N o . o f b o o k s 1 0 0 0 6 5 0 8 0 0 4 5 0 A n s . P i c t o g r a p h n e a t l y d r a w n S c a l e s h o w n 2 0 . T h e c o l o u r s o f c a r s p r e f e r r e d b y p e o p l e l i v i n g i n a l o c a l i t y a r e s h o w n b y t h e f o l l o w i n g p i c t o g r a p h . A n s w e r t h e q u e s t i o n s t h a t f o l l o w : C o l o u r o f c a r N o . o f p e o p l e ( 1 $ = 1 5 p e o p l e ) B l a c k $ S i l v e r R e d $ W h i t e a . F i n d t h e n u m b e r o f p e o p l e p r e f e r r i n g s i l v e r c a r s . b . H o w m a n y l e s s p e o p l e p r e f e r r e d c a r s t h a n w h i t e c a r s ? c . W h i c h c o l o u r i s m o s t l i k e d b y t h e p e o p l e ? A n s . a . - 6 0 b . - 4 5 c . - W h i t e S E C T I O N D 2 1 . U s i n g t h e d i g i t s 7 , 0 , 3 , 5 a n d 2 , m a k e a n y f o u r 7 d i g i t n u m b e r s . I n s e r t c o m m a s u s i n g I n t e r n a t i o n a l s y s t e m o f n u m e r a t i o n . A r r a n g e t h e m i n a s c e n d i n g o r d e r . A n s . A n y f o u r 7 - d i g i t n u m b e r s u s i n g 7 , 0 , 3 , 5 a n d 2 I n s e r t c o m m a s u s i n g I n t e r n a t i o n a l s y s t e m o f n u m e r a t i o n . A s c e n d i n g o r d e r 2 2 . T h e f o l l o w i n g t a b l e s h o w s t h e y e a r l y p r o d u c t i o n o f c y c l e s b y a c o m p a n y . D r a w a b a r g r a p h f o r t h e g i v e n d a t a . A n s . B a r g r a p h f o r t h e g i v e n d a t a n e a t l y d r a w n . T i t l e , S c a l e , L a b e l s 2 3 . A V o l v o b u s d r i v e r o f f e r s f r e e s e r v i c e t o a p i l g r i m a g e ( h o l y p l a c e ) w h i c h i s 2 1 k m 4 5 m a w a y f r o m a c i t y . T h e b u s m a k e s 5 r o u n d t r i p s e v e r y d a y . H o w m u c h d i s t a n c e d o e s i t c o v e r i n t h e m o n t h o f A p r i l ? W h a t v a l u e d o w e l e a r n f r o m t h i s ?Read More
FAQs on Class 6 Math: CBSE Past Year Paper - 5
| 1. What is the CBSE Class 6 Math Past Year Paper - 5? |  |
Ans. The CBSE Class 6 Math Past Year Paper - 5 is a previous year's question paper for the Class 6 Math examination conducted by the Central Board of Secondary Education (CBSE) in India. It is used for practice and revision purposes by students preparing for their exams.
| 2. How can solving the CBSE Class 6 Math Past Year Paper - 5 benefit students? | |
Ans. Solving the CBSE Class 6 Math Past Year Paper - 5 can benefit students in several ways. It helps them understand the exam pattern, familiarize themselves with the types of questions asked, and assess their preparation level. By solving the paper, students can identify their strengths and weaknesses and focus on areas that need improvement.
| 3. Are the questions in the CBSE Class 6 Math Past Year Paper - 5 similar to the actual exam? | |
Ans. Yes, the questions in the CBSE Class 6 Math Past Year Paper - 5 are designed to be similar to the ones asked in the actual exam. These papers are created by experts who have a good understanding of the exam pattern and syllabus. However, it is important to note that the actual exam may have variations in terms of difficulty level and question distribution.
| 4. Can solving the CBSE Class 6 Math Past Year Paper - 5 guarantee good marks in the exam? | |
Ans. Solving the CBSE Class 6 Math Past Year Paper - 5 can certainly improve the chances of scoring well in the exam. It helps students become familiar with the question format, manage time effectively, and gain confidence. However, achieving good marks also depends on regular study, understanding concepts, and practicing additional questions beyond the past year paper.
| 5. Where can I find the CBSE Class 6 Math Past Year Paper - 5? | |
Ans. The CBSE Class 6 Math Past Year Paper - 5 can be found on various educational websites, online platforms, or in preparation books specifically designed for CBSE exams. These resources are easily accessible and often provide solutions or answer keys to help students evaluate their performance. Additionally, schools or coaching centers may also provide students with the past year papers for practice.
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