Class 9 Exam  >  Class 9 Notes  >  Mathematics (Maths) Class 9  >  Very Short Answer Type Questions: Circles

Class 9 Maths Question Answers - Circles

Q1. In the figure, if ∠ ACB = 35°, then find the measure of ∠ OAB.

Class 9 Maths Question Answers - Circles

Solution: ∠AOB = 180° -  (∠1 + ∠2)
= 180° - (35° + 35°)                     [∵ AO = OB ∴ ∠1 = ∠2]
= 110°
∠ACB = (1/2)(∠AOB) = (1/2) (110°) = 55°


Q2. If points A, B and C are such that AB ⊥ BC and AB = 12 cm, BC = 16 cm. Find the radius of the circle passing through the points A, B and C.
 Solution:
∵ AB ⊥ BC
∴ ∠B = 90°                  [Angle in a semicircle]
⇒ AC is a diameter 

Class 9 Maths Question Answers - Circles

Class 9 Maths Question Answers - Circles

AC = 20

Radius = 10cm

Q3. The angles subtended by a chord at any two points of a circle are equal. Write true or false for the above statement and justify your answer.
 Solution:
False. If two points lie in the same segment only, then the angles will be equal otherwise they are not equal.


Q4. Two chords of a circle of length 10 cm and 8 cm are at the distance 8.0 cm and 3.5 cm, respectively from the centre, state true and false for the above statement.
 Solution
: False. As the larger chord is at a smaller distance from the centre.

Q4. If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is 

Solution: 

Class 9 Maths Question Answers - Circles

Assuming that AB = 12 cm and BC = 16 cm

If BC and AB are in a circle, then AC will be the circle's diameter.

[circular's diameter forms a right angle to the circle]

Apply the Pythagorean theorem to the ABC right angle.

AC2=AB2+BC2

AC2=(12)2+(16)2

AC2=144+256⇒ AC2=400

⇒ AC2=√400=20 cm

[using the square root of a positive number since the diameter is always positive]

∴ Circle radius = 1/2(AC)=1/220=10 cm

As a result, the circle's radius is 10 cm.

Q5. In Figure, if ∠ABC = 20º, then ∠AOC is equal to:  

Class 9 Maths Question Answers - CirclesSolution: Assumed: ABC = 20°...(1)

We are aware that an arc's angle at the circle's center is twice as large as its angle at the rest of the circle.

= ∠AOC = 2(20°) (From (1))

=  ∠AOC = 40°

AOC thus equals 40°

Q6. Two chords AB and AC of a circle with center O are on the opposite sides of OA. Then ∠OAB = ∠OAC. 

Write true or false for the above statement and justify your answer.

Class 9 Maths Question Answers - Circles

Solution:

Two chords are used: AB and AC.

Join us, OB and OC.

Specifically, triangle OAC and OAB

OA (common side) = OA

Triangles OAB and OAC are not congruent, therefore it is impossible to prove that any third side or angle is equivalent. OC = OB (radius of the circle).

<OAC and <OAB

The claim is untrue as a result.


Q7. ABCD is a cyclic quadrilateral such that ∠A = 90°, ∠B = 70°, ∠C = 95° and∠D = 105°.
Write true or false for the above statement and justify your answer.

Solution: Given that ABCD is a cyclic quadrilateral with angles of 90°, 70°, 95°, and 105°,

We are aware that the sum of the opposite angles in a cyclic quadrilateral is 180°.

It can be expressed mathematically as follows: A + C = 90° + 95° = 185° 180°

B + D = 70° + 105° = 175° 

The sum of the opposing angles in this situation is not 180°.

It is therefore not a cyclic quadrilateral.

The claim is false as a result.

Q8. In Fig, if AOB is the diameter of the circle and AC = BC, then ∠CAB is equal to: 

Class 9 Maths Question Answers - Circles

Solution: We are aware that the circle's diameter forms a right angle.

∠BCA = 90∘ ......(i)

AC = BC, and (ii) <ABC=<CAB (the angle opposite to equal sides is equal)

In △ ABC, ∠CBA+∠ABC+∠BCA=180∘ [Triangle's angle-sum attribute]]
 ∠CAB+∠CAB+90∘=180∘
 2 ∠CAB=90∘
 ∠CAB=45∘. 

Q9.  Two chords AB and CD of a circle are each at distances 4 cm from the center. Then AB = CD.

Write true or false for the above statement and justify your answer. 

Class 9 Maths Question Answers - Circles

Solution: The right answer is True.

The above assertion is accurate since chords that are equally spaced from a circle's center have equal lengths.

AB=CD 

Q10.  If A, B, C, and D are four points such that ∠BAC = 30° and ∠BDC = 60°, then D is the center of the circle through A, B and C. 

Write true or false for the above statement and justify your answer. 

Solution: 

False

Because there are numerous places D where ∠BDC=60°, none of which can be the center of the circle formed by points A, B, and C.

The document Class 9 Maths Question Answers - Circles is a part of the Class 9 Course Mathematics (Maths) Class 9.
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FAQs on Class 9 Maths Question Answers - Circles

1. What is the formula for the circumference of a circle?
Ans. The formula for the circumference of a circle is \( C = 2\pi r \), where \( r \) is the radius of the circle.
2. How do you calculate the area of a circle?
Ans. The area of a circle can be calculated using the formula \( A = \pi r^2 \), where \( r \) is the radius.
3. What is the relationship between the diameter and the radius of a circle?
Ans. The diameter of a circle is twice the length of the radius. It can be expressed as \( d = 2r \), where \( d \) is the diameter and \( r \) is the radius.
4. Can a circle have a maximum and minimum radius?
Ans. No, a circle has a constant radius, and all points on the circle are equidistant from the center. Therefore, it does not have maximum or minimum radii.
5. What is the significance of π (pi) in circle geometry?
Ans. π (pi) is a mathematical constant that represents the ratio of the circumference of any circle to its diameter. It is approximately equal to 3.14159 and is essential in calculations involving circles.
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