Mechanical Engineering Exam > Mechanical Engineering Videos > Topper Handwritten Notes & Videos for GATE ME > Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE
Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE Video Lecture | Topper Handwritten Notes & Videos for GATE ME
|
59 videos|204 docs
|
FAQs on Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE Video Lecture - Topper Handwritten Notes & Videos for GATE ME
| 1. What is conduction and how does it contribute to heat transfer? |  |
Ans. Conduction is a mode of heat transfer where heat is transferred through a solid material without any bulk movement of the material itself. It occurs due to the collision of molecules within the material. When there is a temperature gradient in a solid, the higher energy molecules collide with the lower energy molecules, transferring heat in the process. Conduction is an important mechanism of heat transfer in solids.
| 2. What is a composite wall and how does it affect heat transfer? | |
Ans. A composite wall is a wall made up of multiple layers of different materials with varying thermal conductivities. Each layer in the wall has a different resistance to heat transfer, and this affects the overall heat transfer through the wall. The thermal conductivity of each layer determines how easily heat can pass through it. The presence of multiple layers with different thermal conductivities in a composite wall can significantly impact the overall heat transfer rate.
| 3. How does the thickness of a composite wall affect heat transfer? | |
Ans. The thickness of a composite wall plays a crucial role in determining the heat transfer rate. A thicker wall generally offers higher resistance to heat transfer, resulting in a slower transfer of heat. This is because a thicker wall provides a longer path for heat to flow through, increasing the thermal resistance. Therefore, increasing the thickness of a composite wall would decrease the heat transfer rate, while reducing the thickness would enhance the heat transfer.
| 4. What is the difference between heat transfer and mass transfer? | |
Ans. Heat transfer and mass transfer are both mechanisms of transferring energy, but they involve different properties. Heat transfer involves the transfer of thermal energy from a region of higher temperature to a region of lower temperature. On the other hand, mass transfer involves the transfer of mass or material from one place to another, typically driven by a concentration gradient. While heat transfer deals with the transfer of energy, mass transfer deals with the transfer of matter.
| 5. How does conduction through a composite wall affect the overall heat transfer rate? | |
Ans. Conduction through a composite wall affects the overall heat transfer rate by introducing different thermal resistances in the path of heat flow. Each layer in the composite wall has its own thermal conductivity and thickness, which contribute to the overall resistance to heat transfer. The heat transfer rate through the composite wall depends on the combination of thermal conductivities and thicknesses of the individual layers. A higher thermal conductivity or thinner layer will facilitate faster heat transfer, while a lower thermal conductivity or thicker layer will hinder heat transfer.
Text Transcript from Video
all right Maria so in this video I am
going to share with you conduction of
heat transfer through a composite slab
well if you are be bearing for any
university examination or maybe gate
examination then this topic is most
important alright so let me share with
you what what is that the mission we are
going to take for deriving the equation
what equation we require to solve
numerical problems right so for the
assumption is a complete state is
complete condition and the state will be
one dimensional complete state will be
one dimensional this is the summation we
are taking for solving the problem you
know let me first draw the circuit the
circuit which is really important for
this portion right this is the circuit
and here t1 is the temperature and here
you can see this one one resistance t2
is the intermediate temperature and t3
is here now as you can you know this is
thermal resistance rth one or pH two
let's say this right now as you know
according to four years law of heat
transfer what we know he was equal to
minus ka DT by DX right again we know
what DT DX DX is equal to V we have
already I have already share with you so
DT means t2 minus t1 so because we will
just multiply this minus here so things
will change so we can write B by K T so
we can write this equation like this T 1
minus T 2 B by K D so this B by K a is
the thermal resistance so here if we see
the first slab first slab this is the
first lab and this is the second slab if
we will see this first slab then RT h1
is equal to k1 k1 a and the same that
should be seen for this second slab RTS
2 is equal to B 2 K 2 a so this is this
is all about thermal resistance now once
we get the thermal resistance for this
lab we can easily find out the heat
transfer or rate of heat transfer
through this slab right so we know Q is
equal to Q is equal to D 1 minus D
things by the total resistance B 1 K 1 a
plus P 2 K 2 a right so this is the
total heat transfer rate now if it is
heat transfer rate and the unit of this
is what all right now cushion may be
asked that heat transfer rate okay let
me write first heat transfer rate per
unit area that means what per meter
square or sometimes we said W per meter
square right
so if quotient in the question is like
this what we should do we'll have to
transfer this area to this side that
means Q by a is equal to t1 minus t2 by
B 1 by K 1 plus B 2 by K 2 that's it
so this is the formula for finding out
heat transfer rate per area and this is
the formula for finding out heat
transfer rate for any composite slab for
composite slab only you need to invert
this and this is all about finding out
heat transfer rate through composite
slab well in my next in the last I mean
in this video only I'm going to share
with you a question which questions
already asked engaged 2006 I hope you
can read the question right so that's it
2006 okay
so in this portion what we have given
exactly we need to understand first we
are we have given a composite slab that
is important because we need to think
about composite slab
I have already shared with you what is
composite slab and now I will I'm going
to share with you how to solve the
question right away that's why if
anywhere you will get cushion related to
these you can solve the question quite
easily so first of all we have to draw a
composite slab so I have already to the
position so you need to read the
question first right so because you know
you don't know what about this tempo is
level now on that right so already they
have been asked that this side is W so
so this is David I'm just marking with
red line that's what you can identify
this is that we thought they said is
double and this side is single right now
the temperature is like this t1 and T I
and t2 here in the question will have
given di is equal to t1 plus DP by P
that means average average of these two
right so based on this diagram based on
this diagram what we have to do we have
to draw the resistance I mean the metal
diagram you must say okay Network once
you will come to know how to tow a
thermal circuit or you can social
network diagram the thermal circuit I
must say that because this is the
technical name of this thermal circuit
once you will come to know how to draw a
thermal circuit then the solve the
problem solve in a lawsuit or thinking
all much better for you ok I mean the
you can easily solve the question you
don't have any problem not this problem
once you will come to know how to draw a
thermal circuit so it's simple first
start here because you are having one
only one resistance here one type of
okay now second and then another
material because this is a composite
slab of two two that's why we have drawn
thermal circuit like this
here temperature one here temperature I
say temperature fridge here here we are
having something right
you know Q is equal to minus ka DT by DX
right this is the formula for four years
ago I mean this is a four tips law and
we have been studied couple of times
maybe have also gone through this
formula okay but here D X is me and all
those things are same here changing
temperature that means if I would say
from here to here what I have to write
for here for in this case T 1 minus TI
by be a by K a so the resistance would
be like this here to be because
thickness is here to be by K B K is
thermal conduction so suppose that this
is K 1 this is K 2 so k1 a right now for
this is B by K 2 a B by K 2 a okay now
let's go I'll go for the question okay
so this quotient will have given that
will have already a month off some dr.
we have to find out a relation like this
okay
so for this we don't need to find out
any numerical values so the thing is
that we the probability of doing mistake
is very less but here what is the case
here heat transfer it here in the first
lab is equal to it does parade in the
second slab so we can write the equation
like this Q is equal to t1 minus TI y to
be k1 K is equal to TI minus t2 by B by
K 2
okay now as we know T I is equal to t1
plus t2 by two because we have all day
live in this condition in the question
right so we have to put values TI and TI
here only
so let's write e1 minus TI t 1 plus t 2
by 2 and here also to be by k1 is equal
to t1 plus t2 by 2 minus t2 by b k2 e
now we will solve this quotient but we
caught here would be caught here that is
important that is important right so
what we got here after solving this we
can say I mean this down this idea to t1
minus t1 plus t2 right and t1 plus t2
minus 2 D 2 y 2 right so this is the
question I mean you know after what we
are getting here what we are getting
here these terms these two terms are
same okay so so what happened what
happen okay so and as you know if we
solve case and this what we want to get
this let me write so clapping will
happen to t1 minus T 1 minus T 2 by 2 so
here what will be meaning T 1 minus T 2
by 2 so let me first okay on the face
that's what we share with you
it's not so what we can write here that
is 1 minus T 2 T 1 minus T 2 by 2 B so
to give to be by K 1 a for the first or
a second second one is what here this
let me share with you so this is the we
have to simplify this one right so T 1
plus T 2 minus 2 T 2 by 2 so it will
happen T 1 minus T 2 by 2 so I can write
the same equation here T 1 minus T 2 by
2 divided by 2 so it will be by K 2 e so
this will this will cancel out now what
we can write to be 1 K 1 e and V by K 2
cross multiplication it will go cross
multiplication we are going to get like
this right now
AE cancel out be we cancel out so what
we can write Q 1 is equal to 2 K 2 what
we can write k 1 is equal to 2 K 2 so
this is how we can solve quotient if you
will get quotient come for composite
slab ok I hope you understand the
question as well as concept behind it
thanks for watching see you soon in my
next video bye
going to share with you conduction of
heat transfer through a composite slab
well if you are be bearing for any
university examination or maybe gate
examination then this topic is most
important alright so let me share with
you what what is that the mission we are
going to take for deriving the equation
what equation we require to solve
numerical problems right so for the
assumption is a complete state is
complete condition and the state will be
one dimensional complete state will be
one dimensional this is the summation we
are taking for solving the problem you
know let me first draw the circuit the
circuit which is really important for
this portion right this is the circuit
and here t1 is the temperature and here
you can see this one one resistance t2
is the intermediate temperature and t3
is here now as you can you know this is
thermal resistance rth one or pH two
let's say this right now as you know
according to four years law of heat
transfer what we know he was equal to
minus ka DT by DX right again we know
what DT DX DX is equal to V we have
already I have already share with you so
DT means t2 minus t1 so because we will
just multiply this minus here so things
will change so we can write B by K T so
we can write this equation like this T 1
minus T 2 B by K D so this B by K a is
the thermal resistance so here if we see
the first slab first slab this is the
first lab and this is the second slab if
we will see this first slab then RT h1
is equal to k1 k1 a and the same that
should be seen for this second slab RTS
2 is equal to B 2 K 2 a so this is this
is all about thermal resistance now once
we get the thermal resistance for this
lab we can easily find out the heat
transfer or rate of heat transfer
through this slab right so we know Q is
equal to Q is equal to D 1 minus D
things by the total resistance B 1 K 1 a
plus P 2 K 2 a right so this is the
total heat transfer rate now if it is
heat transfer rate and the unit of this
is what all right now cushion may be
asked that heat transfer rate okay let
me write first heat transfer rate per
unit area that means what per meter
square or sometimes we said W per meter
square right
so if quotient in the question is like
this what we should do we'll have to
transfer this area to this side that
means Q by a is equal to t1 minus t2 by
B 1 by K 1 plus B 2 by K 2 that's it
so this is the formula for finding out
heat transfer rate per area and this is
the formula for finding out heat
transfer rate for any composite slab for
composite slab only you need to invert
this and this is all about finding out
heat transfer rate through composite
slab well in my next in the last I mean
in this video only I'm going to share
with you a question which questions
already asked engaged 2006 I hope you
can read the question right so that's it
2006 okay
so in this portion what we have given
exactly we need to understand first we
are we have given a composite slab that
is important because we need to think
about composite slab
I have already shared with you what is
composite slab and now I will I'm going
to share with you how to solve the
question right away that's why if
anywhere you will get cushion related to
these you can solve the question quite
easily so first of all we have to draw a
composite slab so I have already to the
position so you need to read the
question first right so because you know
you don't know what about this tempo is
level now on that right so already they
have been asked that this side is W so
so this is David I'm just marking with
red line that's what you can identify
this is that we thought they said is
double and this side is single right now
the temperature is like this t1 and T I
and t2 here in the question will have
given di is equal to t1 plus DP by P
that means average average of these two
right so based on this diagram based on
this diagram what we have to do we have
to draw the resistance I mean the metal
diagram you must say okay Network once
you will come to know how to tow a
thermal circuit or you can social
network diagram the thermal circuit I
must say that because this is the
technical name of this thermal circuit
once you will come to know how to draw a
thermal circuit then the solve the
problem solve in a lawsuit or thinking
all much better for you ok I mean the
you can easily solve the question you
don't have any problem not this problem
once you will come to know how to draw a
thermal circuit so it's simple first
start here because you are having one
only one resistance here one type of
okay now second and then another
material because this is a composite
slab of two two that's why we have drawn
thermal circuit like this
here temperature one here temperature I
say temperature fridge here here we are
having something right
you know Q is equal to minus ka DT by DX
right this is the formula for four years
ago I mean this is a four tips law and
we have been studied couple of times
maybe have also gone through this
formula okay but here D X is me and all
those things are same here changing
temperature that means if I would say
from here to here what I have to write
for here for in this case T 1 minus TI
by be a by K a so the resistance would
be like this here to be because
thickness is here to be by K B K is
thermal conduction so suppose that this
is K 1 this is K 2 so k1 a right now for
this is B by K 2 a B by K 2 a okay now
let's go I'll go for the question okay
so this quotient will have given that
will have already a month off some dr.
we have to find out a relation like this
okay
so for this we don't need to find out
any numerical values so the thing is
that we the probability of doing mistake
is very less but here what is the case
here heat transfer it here in the first
lab is equal to it does parade in the
second slab so we can write the equation
like this Q is equal to t1 minus TI y to
be k1 K is equal to TI minus t2 by B by
K 2
okay now as we know T I is equal to t1
plus t2 by two because we have all day
live in this condition in the question
right so we have to put values TI and TI
here only
so let's write e1 minus TI t 1 plus t 2
by 2 and here also to be by k1 is equal
to t1 plus t2 by 2 minus t2 by b k2 e
now we will solve this quotient but we
caught here would be caught here that is
important that is important right so
what we got here after solving this we
can say I mean this down this idea to t1
minus t1 plus t2 right and t1 plus t2
minus 2 D 2 y 2 right so this is the
question I mean you know after what we
are getting here what we are getting
here these terms these two terms are
same okay so so what happened what
happen okay so and as you know if we
solve case and this what we want to get
this let me write so clapping will
happen to t1 minus T 1 minus T 2 by 2 so
here what will be meaning T 1 minus T 2
by 2 so let me first okay on the face
that's what we share with you
it's not so what we can write here that
is 1 minus T 2 T 1 minus T 2 by 2 B so
to give to be by K 1 a for the first or
a second second one is what here this
let me share with you so this is the we
have to simplify this one right so T 1
plus T 2 minus 2 T 2 by 2 so it will
happen T 1 minus T 2 by 2 so I can write
the same equation here T 1 minus T 2 by
2 divided by 2 so it will be by K 2 e so
this will this will cancel out now what
we can write to be 1 K 1 e and V by K 2
cross multiplication it will go cross
multiplication we are going to get like
this right now
AE cancel out be we cancel out so what
we can write Q 1 is equal to 2 K 2 what
we can write k 1 is equal to 2 K 2 so
this is how we can solve quotient if you
will get quotient come for composite
slab ok I hope you understand the
question as well as concept behind it
thanks for watching see you soon in my
next video bye
Related Exams
About this Video
|
4.76/5 Rating |
|
Dec 22, 2024 Last updated |
Video Description: Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE for Mechanical Engineering 2024 is part of Topper Handwritten Notes & Videos for GATE ME preparation.
The notes and questions for Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE have been prepared according to the Mechanical Engineering exam syllabus.
Information about Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE covers all important topics for Mechanical Engineering 2024 Exam.
Find important definitions, questions, notes, meanings, examples, exercises and tests below for Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE.
Introduction of Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE in English is available as part of our Topper Handwritten Notes & Videos for GATE ME for Mechanical Engineering & Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE in
Hindi for Topper Handwritten Notes & Videos for GATE ME course. Download more important topics related with notes, lectures and mock test series for
Mechanical Engineering Exam by signing up for free.
Description
Video Lecture & Questions for Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE Video Lecture | Topper Handwritten Notes & Videos for GATE ME - Mechanical Engineering full syllabus preparation | Free video for Mechanical Engineering exam to prepare for Topper Handwritten Notes & Videos for GATE ME.
Information about Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE
Here you can find the meaning of Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE defined & explained in the simplest way possible.
Besides explaining types of Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE theory, EduRev gives you an ample number of questions to practice Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE tests,
examples and also practice Mechanical Engineering tests.
|
59 videos|204 docs
|
|
Explore Courses for Mechanical Engineering exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
Mechanical Engineering
,Heat and Mass Transfer
,Heat and Mass Transfer
,Previous Year Questions with Solutions
,GATE Video Lecture | Topper Handwritten Notes & Videos for GATE ME
,Mechanical Engineering
,Mechanical Engineering
,Summary
,shortcuts and tricks
,GATE Video Lecture | Topper Handwritten Notes & Videos for GATE ME
,Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14
,study material
,Exam
,Sample Paper
,Viva Questions
,GATE Video Lecture | Topper Handwritten Notes & Videos for GATE ME
,Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14
,ppt
,Extra Questions
,Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14
,Semester Notes
,Objective type Questions
,past year papers
,video lectures
,MCQs
,practice quizzes
,Free
,Heat and Mass Transfer
,mock tests for examination
,Important questions
,
Study Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE on the App
Students of Mechanical Engineering can study Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE,
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of Conduction Through Composite Wall Heat Transfer HMT Tutorial- 14, Heat and Mass Transfer, Mechanical Engineering, GATE is prepared as per the latest Mechanical Engineering syllabus.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup