Mathematics Exam  >  Mathematics Notes  >  Mathematics for IIT JAM, GATE, CSIR NET, UGC NET  >  Connectedness and Compactness (Part - 2) - Topology, CSIR-NET Mathematical Sciences

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3.2 CONNECTEDNESS IN CLOSURE SPACES

In this section we introduce and study connectedness..

Definition 3.2.1

(X,c) is said to be disconnected if it can be written as two disjoint nonempty subsets A and B such that cA U cB=X, cA ∩ cB = φ and cA and cB are nonempty. A space which is not disconnected is said to be connected.

Example 3.2.2 

X = {a,b,c}

c can be defined on X such that

c {a}={a,b}, c{b}=c{c}=c{b,c}={b,c}, c{a,b}=c{a,c}=cX=X, cφ=φ)

Then c is a closure operation on X.

Here (X,c) is connected because we can not find nonempty subsets A and B such that cA U cB=X and cA ∩ cB=φ.

Definition 3.2.3

(X,c) is said to be feebly disconnected if it can be written as two disjoint nonempty subsets A and B such that A U cB=cA U B=X and cA ∩ B=φ=A ∩ cB.

Note 3.2.4

It is clear that (X,c) is disconnected implies (X,c) is feebly disconnected. The following example shows that the converse is not true.

Example 3.2.5 

X={a,b,c}

c{a}={a,c},c{b}=c{c}=c{b,c}={b,c},c{a,b}=c{a,c}=cX=X,cφ=φ

c is a closure operation on X.

Here (X,c) is feebly disconnected, but not disconnected.

Result 3.2.6

(x,t) is disconnected ⇒ (X,c) is disconnected.

Proof

(X,t) is disconnected implies that it is the union of two disjoint nonempty subsets A and B such that clA U clB=X, clA ∩ clB=φ and clA, clB are nonempty. clA∩clB=φ). So cA ∩cB=φ. That is (X,c) is disconnected.

Note 3.2.7 .

(X,t) is connected need not imply that (X,c) is connected.

Example

X={a,b,c} . Let c be a closure operation defined on X in such a way that

c {a} = {a},c {b}= {b ,c},c {c} = c {a .b} = c {b ,c}= c X = X , φ=φ

(X,t)={X,φ,{b,c}}

Here (X,c) is disconnected, but (X,t) is connected.

Remark

Connectedness of a subspace Y of (X,c) can be defined in the same manner.

Note 3.2.8

Let (X,c) be a closure space and Y be a connected subset o f (X,c). Then cY need not be connected.

Example 3.2.9 

X={a,b,c,d,e}

Let c be defined on X such that

c{a }= {a},c{b }= {a,b ,c},c{c}= {b ,c},c{d }= {b ,c,d},

c{a,b}=c{a,c}=c{b,c}=c{a,b,c}={a,b,c},

c{c,d}={b,c,d}, c{a,d}=c{b,d}=c{a,b,d}=c{a,c,d}=c{b,c,d}=c{a,b,c,d}={a,b,c,d},

c {e}= c {a,e}= c {b,e}= c {c,e}:= c {d,e}= c {a,b,e}= c {a,c,e}= c {a,d,e}= c {b,c,e}= c {c,d,e}

=c{b,d,e}=c{a,b,d,e}=c{a,c,d,e}=c{b,c,d,e}=cX=X,cφ=φ

Here Y={b,c} is connected.

cY={a,b,c}; if c' isthe induced closure operation on cY, then

c'{a}={a},c'{c}={b,c},c'{b}:=;c,{a,b}=c'{b,c}=c'{a,c}=c'cY=cY. 

cY is disconnected.

Note 3.2.10

If cA and cB form a separation of X and if Y is a connected subset of X, then Y need not be entirely within either cA or cB.

Example 3.2.11

X={a,b,c}

Let c be a closure operation defined on X such that

c{a}={a},c{b}={b,c} c{c}={a,c},c{a,b}=c{b,c}=cX=X,c{a,c}={a,c}.

Y={a,c} is connected

Note 3.2.12

The image of a connected space under a c -c' morphism need not be connected. 

Example

Let X-{a,b,c,d,e}. A closure operation c is defined on X as in Example 3.2.9 

Let Y={a,b,c} c' be defined on Y such that

c'{a}={a},c'{b}={b,c},c'{c}=c'{a,b}=c'{b,c}=c'{a,c}=c'X=X c'φ=φ.

Let f be a map from (X,c) into (Y,c') defined in such a way that f(a)=a, f(b)=c, f(c)-b, 

f(d)=c, f(e)=c

Here f is a c-c' moiphism. But f(X) is disconnected.

Result 3.2.13

Suppose c1 is a closure operator on Y with degree k and f is a c-c, morphism from (X,c) to (Y,c1). If c1k(A) and c1k(B) form a separation of Y , then c(f-1(c1k(A)) and c(f-1(c1k(B)) form a separation on X.

Proof

Connectedness and Compactness (Part - 2) - Topology, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET
Connectedness and Compactness (Part - 2) - Topology, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET
Connectedness and Compactness (Part - 2) - Topology, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET
Connectedness and Compactness (Part - 2) - Topology, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET

Result 3.2.14

Let (X,c) be connected and f is a c-c1 morphism from (X,c) on to (Y,c,1). Then (Y,t1) is connected.

Proof

Since f(cA) ⊂ c1 f(A) ⊂ cl1 f(A), f being c -c1 morphism and we get f is c - cl1 morphism. Suppose cl1 A and cl1 B form a separation on Y. Then cl1A U cl1 B=Y and cl1 A ∩ cl1B=φ. f-1 (cl1A) U f -1(cl1B)= X and f-1(cl1A) ∩ f-1(cl1 (B)=φ . By th e above result c(f-1 (cl1(A)) and c(f-1(cl1B)) form a separation on X. This is a contradiction . Hence (Y,t) is connected.

3.3 PATHWISE AND LOCAL CONNECTEDNESS

In this section we define and study pathwise connectedness and local connnectedness.

Definition 3.3.1

A space (X,c) is pathwise connected if and only if for any two points x and y in X, there is a cl1 -c morphism f : I → X such that f(o) =x and f (l) = y where cl1 is the usual closure on I, f is called a path from x to y.

Result 3.3.2

(X,c) is pathwise connected implies (X,t) is pathwise connected.

Proof

If (X,c) is pathwise connected, then for any two points x and y in X there is a cl1- c morphism f : I → X such that f(0)=x and f(l) = y . If f is cl1-c morphism ,then f is cl1-cl morphism. Therefore (X,t) is pathwise connected.

Note 3.3.3

The converse of the above result is not true.

Note 3.3.4

Pathwise connected space need not be a connected space .

Definition 3.3.5

A space X is said to be locally connected at x if for every neighbourhood U of x, there is a connected neighbourhood V of x contained in U. If X is locally connected at each of its points, then X is said to be locally connected.

Definintion 3.3.6

A space X is said to be locally path connected at x if for every neighbourhood U of x, there is a path connected neighbourhood V of x contained in U. If X is locally path connected at each of its points, then it is said to be locally path connected.

Note 3.3.7

A space (X,c) is locally connected need not imply that (X,t) is locally connected and vice-versa.

A parallel study of the above concepts in the set up of closure spaces is interesting; however we are not attempting it in this thesis.

3.4. COMPACTNESS AND CONNECTEDNESS IN MONOTONE SPACES

Definition 3.4.1

Let (X,c*) be a monotone space. F be a proper filter on X and x be an element of X. We shall say that x is a cluster point of F in (X,c*) if x belongs to ∩{c*F : F∈F}. That is each neighbourhood of x intersects each F ∈ F.

Definition 3.4.2

A monotone space (X,c*) is said to be compact, if every proper filter of sets on X has a cluster point in X.

Remark 3.4.3

It is clear that if (X,c*) is compact, then (X,c) is compact but the converse is not true.

Result 3.4.4

Any image under a c-c* morphism of a compact monotone space (X,c*) onto a monotone space (Y,c*) is compact.

The proof is similar to the Proof of 41 A - 15 in [CE2] .

Result 3.4.5

Every closed subspace of a compact monotone space is compact.

The proof is similar to the Proof of 41 A - 10 in [CE2].

Result 3.4.6

If (Y, c') is a com pact subspace of a Hausdorff monotone space (X ,c*),then Y is closed in X.

The proof is similar to the Proof of 41 A-l 1 in [CE2].

Definition 3.4.7

A monotone space (X,c*) is said to be discomiected if it can be written as two disjoint nonempty subsets A and B such that c*A U c*B = X, c*A ∩ c*B=φ. A space which is not disconnected is said to be connected.

Remark 3.4.8

(X,c) is disconnected implies (X,c*) is disconnected,and the converse is not true. 

Example 3.4. 9 

X={a,b,c}

cbe defined on X such that

c*{a}={a},c*{b}={b,c}, c*{c}={b,c}, c*{a,b}=c*{b,c}=c{a,c}=c*X=X,c*φ=φ

c* is a monotone operator.

(X,c*) is disconnected. But (X,c) is connected.

The document Connectedness and Compactness (Part - 2) - Topology, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET is a part of the Mathematics Course Mathematics for IIT JAM, GATE, CSIR NET, UGC NET.
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FAQs on Connectedness and Compactness (Part - 2) - Topology, CSIR-NET Mathematical Sciences - Mathematics for IIT JAM, GATE, CSIR NET, UGC NET

1. What is the definition of connectedness in topology?
Ans. In topology, a topological space is said to be connected if it cannot be divided into two non-empty open sets that are disjoint and whose union is the entire space.
2. What is the definition of compactness in topology?
Ans. In topology, a topological space is said to be compact if every open cover of the space has a finite subcover. In other words, for every collection of open sets that covers the space, there exists a finite subcollection that also covers the space.
3. What is the relationship between connectedness and compactness?
Ans. Compactness is a stronger property than connectedness. Every compact space is connected, but not every connected space is compact. In other words, compactness implies connectedness, but connectedness does not imply compactness.
4. Can a disconnected space be compact?
Ans. No, a disconnected space cannot be compact. By definition, a disconnected space can be divided into two non-empty open sets that are disjoint. If such a space were also compact, then each of these two sets would be an open cover of the space, but there would be no finite subcover, contradicting the definition of compactness.
5. Are there any examples of spaces that are both connected and compact?
Ans. Yes, there are examples of spaces that are both connected and compact. One such example is the closed interval [0, 1] in the real numbers with the standard topology. Another example is the unit sphere in n-dimensional Euclidean space, denoted as Sn. These spaces satisfy both the criteria of connectedness and compactness.
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