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# Constraint and Reaction Forces and Moments (Part - 2) Civil Engineering (CE) Notes | EduRev

## Civil Engineering (CE) : Constraint and Reaction Forces and Moments (Part - 2) Civil Engineering (CE) Notes | EduRev

The document Constraint and Reaction Forces and Moments (Part - 2) Civil Engineering (CE) Notes | EduRev is a part of the Civil Engineering (CE) Course Introduction to Dynamics and Vibrations- Notes, Videos, MCQs.
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2.4.5 Contact Forces

Contacts are actually a bit more complex than our glib discussion of your interaction with a slippery floor might suggest.

The nature of the forces acting at a contact depends on three things:

(1) Whether the contact is lubricated, i.e. whether friction acts at the contact
(2) Whether there is significant rolling resistance at the contact
(3) Whether the contact is conformal, or nonconformal.

A detailed discussion of friction forces will be left until later. For now, we will consider only two limiting cases (a) fully lubricated (frictionless) contacts; and (b) ideally rough (infinite friction) contacts.

Rolling resistance will not be considered at all in this course.

Forces acting at frictionless nonconformal contacts

A contact is said to be nonconformal if the two objects initially touch at a point. The contact between any two convex surfaces is always nonconformal. Examples include contact between two balls, a ball and a flat surface, or contact between two non-parallel cylinders.

The simplest approximation to the forces acting at a non-conformal lubricated contact states that

(1) Each solid is subjected to a force at the contact point;
(2) The forces between the two solids are repulsive; this requires NA > 0 and NB > 0 for both examples illustrated in the picture;
(3) The direction of the forces are along the line connecting the centers of curvature of the two contacting surfaces;
(4) The moments acting on each solid at the contact point are negligible.

Three rules that help to establish the direction of frictionless contact forces are:

Forces acting at rough (infinite friction) nonconformal contacts

A rough nonconformal contact behaves somewhat like a pinned joint. There can be no relative motion of the contacting surfaces, therefore there must be three components of reaction force acting on both contacting solids. Unlike a pin joint, however, the contact can only sustain a repulsive normal force. This means that the components of force shown in the picture must satisf NA > 0. If the normal force is zero (eg when the two surfaces are about to separate), the tangential forces TA1 = TA2 = 0 as well.

The contacting solids can rotate freely relative to one another. Therefore there must be no moment acting on the contacting solids at the point of contact.

Usually the forces acting at a rough contact are represented by components acting perpendicular and parallel to the contacting surfaces, as shown in the picture above. If you do this, itâ€™s easy to enforce the NA > 0 constraint. But if itâ€™s more convenient, you can treat the contact just like a pin joint, and express the reaction forces in any arbitrary basis, as shown in the picture below.

Thereâ€™s a minor disadvantage to doing this â€“ itâ€™s not easy to check whether the normal force between the surface is repulsive. You can do it using vectors â€“ for the picture shown the normal force is repulsive if

Forces acting at frictionless conformal contacts

A contact is said to be conformal if two objects initially contact over a finite area. Examples include contact between the face of a cube and a flat surface; contact between the flat end of a cylinder and a flat surface; or a circular pin inside a matching circular hole.

Two conformal solids are actually subjected to a pressure over the area where they are in contact. Itâ€™s really hard to calculate the pressure distribution (you have to model the deformation of the two contacting solids), so instead we replace the pressure by a statically equivalent force.

If the two contacting surfaces are flat, then

(1) The reaction force can be modeled as a single force, with no moment
(2) The force can act anywhere within the area of contact (its actual position is determined by force and moment balance)
(3) The force must be perpendicular to the two surfaces
(4) The force acts to repel the two solids.

You can of course make really weird conformal contacts â€“ like a jigsaw connection â€“ that can completely prevent both relative translation and rotation of the contacting solids. In this case the contact behaves just like a clamped joint.

Forces acting at ideally rough (infinite friction) conformal contacts

No relative motion can occur at the contact. There must therefore be three components of force acting on each solid.

The forces can act anywhere within the area of contact â€“ (its actual position is determined by force and moment balance)

The component of force acting normal to the surface must be repulsive.

2.4.6 Some short-cuts for drawing free body diagrams in systems containing components with negligible mass

The safest procedure in solving any statics or dynamics problem is to set up and solve equations of motion for every different part of the structure or machine. There are two particularly common structural or machine elements that can be treated using short-cuts. These are (i) Two force members in a structure; and (ii) A freely rotating wheel in a machine.

A Two-force member is a component or structural member that

1. is connected only to two ball-and socket type joints (in 3D) or pin joints (in 2D).
2. has negligible weight

Weâ€™ve seen an example already in one of the Mickey Mouse examples â€“ itâ€™s shown again in the picture to remind you. Member BC is a two-force member, because its weight is negligible, and it has only two pin joints connecting it to other members. Member AB is not a two-force member â€“ partly because itâ€™s weight is not negligible, but also because Mickey exerts a force on the member.

The following rules are very helpful

• Only one component of reaction force acts at the joints on a 2-force member
• The reaction force component acts along a line connecting the two joints.

Itâ€™s trivial to show this â€“ if forces act on a body at only two points, and the body is in static equilibrium, then the forces have to be equal and opposite, and must also act along the same line, to ensure that both forces and moments are balanced.

A generic 2 force member is shown in the figure. Note that a 2-force member doesnâ€™t have to be straight, though it often is.

By convention, a positive reaction force is normally taken to pull at each end of the member, as shown. Equal and opposite reaction forces must act on whatever is connected to the two force member.

Forces on a freely rotating wheel with negligible weight: Wheels are so ubiquitous that itâ€™s worth developing a short-cut to deal with them. The picture shows a generic 2D wheel, mounted onto an axle with a frictionless bearing. The contact between wheel and ground is assumed to be ideally rough (infinite friction).

For a freely rotating 2D wheel, there is only one component of reaction force at the contact between the ground and the wheel.

The picture shows a free body diagram for a 2D wheel mounted on a frictionless bearing.

Since only two forces act on the wheel (the force at the axle, and the contact force), it behaves just like a 2 force member. The two forces must be equal and opposite, and must act along the same line. Moreover, the contact force must satisfy RAy > 0.

For a freely rotating 3D wheel, there are 2 components of reaction force acting at the contact between the wheel and ground. One component acts perpendicular to the ground; the other acts parallel to the ground and perpendicular to the direction of motion of the wheel (i.e. parallel to the projection of the wheelâ€™s axle on the ground) .

The picture below shows all the forces and moments acting on a freely rotating 3D wheel. The reactions that act on the axle are also shown.

A view from in front of the wheel shows the directions of the forces and moments more clearly

The forces and moments shown are the only nonzero components of reaction force.

The missing force and moment components can be shown to be zero by considering force and moment balance for the wheel. The details are left as an exercise.

Finally, a word of caution.

You can only use these shortcuts if:
1. The wheelâ€™s weight in negligible;
2. The wheel rotates freely (no bearing friction, and nothing driving the wheel);
3. There is only one contact point on the wheel.

If any of these conditions are violated you must solve the problem by applying all the proper reaction forces at contacts and bearings, and drawing a separate free body diagram for the wheel.

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## Introduction to Dynamics and Vibrations- Notes, Videos, MCQs

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