D & F- BLOCK ELEMENTS - Sample Objective Test, Chemistry, Class 12 Notes | EduRev

: D & F- BLOCK ELEMENTS - Sample Objective Test, Chemistry, Class 12 Notes | EduRev

 Page 1


1 
Anjana Chemistry Notes 
OBJECTIVE TEST  
DATE: 31 AUG         MAX. MARKS: 92 
           TIME: 1HR 
TOPICS: D & F- BLOCK ELEMENTS  
 
SECTION – I 
MCQS : SINGLE OPTION CORRECT 
Q1. FeCr
2
O
4
 ? ? ?
I
 NaCrO
4
 ? ? ?
II
 Cr
2
O
3
 ? ? ?
III
 Cr I, II and III are 
 I      II    III 
(a)  Na
2
CO
3
/air, ? NH
4
Cl, ? Al  
(b)  NaOH/air, ? C, heat  C, heat  
(c)  Na
2
CO
3
/air, ? C, heat  C, heat  
(d)  NaOH/air, heat  Al, heat  C, heat  
 
Q2. The dissolution of V
2
O
5
 in 30% H
2
O
2
 gives  
(a) V(O
2
)
4
3
-
   (b) VO(O
2
)
2
-
   (c) V
2
O
3
   (d) VO
2
-
  
Q3. Acidified solution of chromic acid on treatment with hydrogen peroxide yields.  
(a) CrO
5
 + H
2
O      (b) H
2
Cr
2
O
7
 + H
2
O + O
2
  
(c) Cr
2
O
3
 + H
2
O + O
2
     (d) CrO
3
 + H
2
O + O
2
  
Q4. (NH
4
)
2
Cr
2
O
7
 on heating liberates a gas. The same gas will be obtained by  
(a) heating NH
4
NO
2
     (b) heating NH
4
NO
3
 
(c) treating Mg
3
N
2
 with H
2
O    (d) heating H
2
O
2
 on NaNO
2
  
Q5. White vitriol has the formula  
(a) CaSO
4
.2H
2
O     (b) CuSO
4
.5H
2
O  
(c) ZnSO
4
.7H
2
O      (d) FeSO
4
.7H
2
O  
Q6. The stability of complexes of Cu
2+
, Ni
2+
, Co
2+
 and Fe
2+
 varies in the order  
(a) Cu
2+
 > Ni
2+
 > Co
2+
 > Fe
2+
    (b) Cu
2+
 > Fe
2+
 > Ni
2+
 > Co
2+
  
(c) Ni
2+
 > Co
2+
 > Fe
2+
 > Cu
2+
    (d) Cu
2+
 < Ni
2+
 < Co
2+
 < Fe
2+
  
Q7. Four successive member of the first row transition elements are listed below with their atomic numbers. 
Which one of them is expected to have the highest third ionization enthalpy?  
(a) Vanadium (Z = 23)     (b) Manganese (Z = 25)  
(c) Chromium (Z = 24)     (d) Iron (Z = 26)  
Q8. Which of the following nitrates on strong heating leaves the metal as the residue?  
(a) AgNO
3
   (b) Pb(NO
3
)
2
   (c) Cu(NO
3
)
2
   (d) Al(NO
3
)
3
  
 
 ANJANA CHEMISTRY CLASSES SCO-42 SEC-20 C, Contact: 9464010111/ talk2anjana@gmail.com , Chandigarh  
Page 2


1 
Anjana Chemistry Notes 
OBJECTIVE TEST  
DATE: 31 AUG         MAX. MARKS: 92 
           TIME: 1HR 
TOPICS: D & F- BLOCK ELEMENTS  
 
SECTION – I 
MCQS : SINGLE OPTION CORRECT 
Q1. FeCr
2
O
4
 ? ? ?
I
 NaCrO
4
 ? ? ?
II
 Cr
2
O
3
 ? ? ?
III
 Cr I, II and III are 
 I      II    III 
(a)  Na
2
CO
3
/air, ? NH
4
Cl, ? Al  
(b)  NaOH/air, ? C, heat  C, heat  
(c)  Na
2
CO
3
/air, ? C, heat  C, heat  
(d)  NaOH/air, heat  Al, heat  C, heat  
 
Q2. The dissolution of V
2
O
5
 in 30% H
2
O
2
 gives  
(a) V(O
2
)
4
3
-
   (b) VO(O
2
)
2
-
   (c) V
2
O
3
   (d) VO
2
-
  
Q3. Acidified solution of chromic acid on treatment with hydrogen peroxide yields.  
(a) CrO
5
 + H
2
O      (b) H
2
Cr
2
O
7
 + H
2
O + O
2
  
(c) Cr
2
O
3
 + H
2
O + O
2
     (d) CrO
3
 + H
2
O + O
2
  
Q4. (NH
4
)
2
Cr
2
O
7
 on heating liberates a gas. The same gas will be obtained by  
(a) heating NH
4
NO
2
     (b) heating NH
4
NO
3
 
(c) treating Mg
3
N
2
 with H
2
O    (d) heating H
2
O
2
 on NaNO
2
  
Q5. White vitriol has the formula  
(a) CaSO
4
.2H
2
O     (b) CuSO
4
.5H
2
O  
(c) ZnSO
4
.7H
2
O      (d) FeSO
4
.7H
2
O  
Q6. The stability of complexes of Cu
2+
, Ni
2+
, Co
2+
 and Fe
2+
 varies in the order  
(a) Cu
2+
 > Ni
2+
 > Co
2+
 > Fe
2+
    (b) Cu
2+
 > Fe
2+
 > Ni
2+
 > Co
2+
  
(c) Ni
2+
 > Co
2+
 > Fe
2+
 > Cu
2+
    (d) Cu
2+
 < Ni
2+
 < Co
2+
 < Fe
2+
  
Q7. Four successive member of the first row transition elements are listed below with their atomic numbers. 
Which one of them is expected to have the highest third ionization enthalpy?  
(a) Vanadium (Z = 23)     (b) Manganese (Z = 25)  
(c) Chromium (Z = 24)     (d) Iron (Z = 26)  
Q8. Which of the following nitrates on strong heating leaves the metal as the residue?  
(a) AgNO
3
   (b) Pb(NO
3
)
2
   (c) Cu(NO
3
)
2
   (d) Al(NO
3
)
3
  
 
 ANJANA CHEMISTRY CLASSES SCO-42 SEC-20 C, Contact: 9464010111/ talk2anjana@gmail.com , Chandigarh  
2 
Anjana Chemistry Notes 
Q9. Lanthanoids are  
(a) 14 elements in the sixth period (atomic no. 90 to 103) that are filling 4f sublevel  
(b) 14 elements in the seventh period (atomic number = 90 to 103) that are filling, 5f sublevel 
(c)  14 elements in the sixth period (atomic number = 58 to 71) that are filling the 4f sublevel 
(d) 14 elements in the seventh period (atomic number = 50 to 71) that are filling 4fg sublevel.  
Q10. Calomel (Hg
2
Cl
2
) on reaction with NH
4
OH gives  
(a) HgNH
2
Cl      (b) NH
2
 – Hg – Hg – Cl   
(c) Hg
2
O      (d) HgO  
Q11. KMnO
4
 reacts with ferrous sulphate according to the equation  
MnO
4
-
 + 5Fe
2+
 + 8H
+
 ?? Mn
2+
 + 5Fe
3+
 + 4H
2
O.  
Here 10 mLof 0.1 M KMnO
4
 is equivalent to  
 (a) 30 mL of 0.3 M FeSO
4
    (b) 40 mL of 0.1 M FeSO
4
 
 (c) 20 mL of 0.1 M FeSO
4
    (d) 50 mL of 0.1 M FeSO
4
  
 
SECTION – II 
MCQS : MORE THAN ONE CORRECT OPTION 
Q12. Which of the following statement are correct when a mixture of NaCl and K
2
Cr
2
O
7
 is gently warmed with 
conc. H
2
SO
4
?  
(a) A deep red vapour is evolved  
(b) The vapour when passed into NaOH solution gives a yellow solution of Na
2
CrO
4
  
(c) Chlorine gas is evolved  
(d) Chromyl chloride is formed  
Q13. Zinc is the only metal in group – 12 which show amphoteric properties and is soluble on alkaline forming 
(a) Na
2
[Zn(OH)
4
]     (b) Na[Zn(OH)
3
 . (H
2
O)
3
] 
(c) Na[Zn(OH)
3
 . (H
2
O)]    (d) Na
4
[Zn(OH)
6
]  
Q14. A solution of colourless salt X on boiling with excess NaOH produces a non-flammable gas. The gas evolution 
ceases after sometime upon addition of Zn dust to the same solution, the gas evolution restarts. The colourless 
salt(s) X is/are  
(a) NH
4
NO
3
   (b) NH
4
NO
2
   (c) NH
4
Cl   (d) (NH
4
)
2
SO
4
  
 
SECTION – III 
COMPREHENSION 
When an electron from a lower energy d orbital is excited to a higher energy d orbital, the energy of excitation 
corresponds to the frequency of light absorbed. This frequency generally lies in the visible region. The colour observed 
corresponds to the complementary colour of the light absorbed. The frequency of the light absorbed is determined by 
the nature of the ligand.  
 ANJANA CHEMISTRY CLASSES SCO-42 SEC-20 C, Contact: 9464010111/ talk2anjana@gmail.com , Chandigarh  
Page 3


1 
Anjana Chemistry Notes 
OBJECTIVE TEST  
DATE: 31 AUG         MAX. MARKS: 92 
           TIME: 1HR 
TOPICS: D & F- BLOCK ELEMENTS  
 
SECTION – I 
MCQS : SINGLE OPTION CORRECT 
Q1. FeCr
2
O
4
 ? ? ?
I
 NaCrO
4
 ? ? ?
II
 Cr
2
O
3
 ? ? ?
III
 Cr I, II and III are 
 I      II    III 
(a)  Na
2
CO
3
/air, ? NH
4
Cl, ? Al  
(b)  NaOH/air, ? C, heat  C, heat  
(c)  Na
2
CO
3
/air, ? C, heat  C, heat  
(d)  NaOH/air, heat  Al, heat  C, heat  
 
Q2. The dissolution of V
2
O
5
 in 30% H
2
O
2
 gives  
(a) V(O
2
)
4
3
-
   (b) VO(O
2
)
2
-
   (c) V
2
O
3
   (d) VO
2
-
  
Q3. Acidified solution of chromic acid on treatment with hydrogen peroxide yields.  
(a) CrO
5
 + H
2
O      (b) H
2
Cr
2
O
7
 + H
2
O + O
2
  
(c) Cr
2
O
3
 + H
2
O + O
2
     (d) CrO
3
 + H
2
O + O
2
  
Q4. (NH
4
)
2
Cr
2
O
7
 on heating liberates a gas. The same gas will be obtained by  
(a) heating NH
4
NO
2
     (b) heating NH
4
NO
3
 
(c) treating Mg
3
N
2
 with H
2
O    (d) heating H
2
O
2
 on NaNO
2
  
Q5. White vitriol has the formula  
(a) CaSO
4
.2H
2
O     (b) CuSO
4
.5H
2
O  
(c) ZnSO
4
.7H
2
O      (d) FeSO
4
.7H
2
O  
Q6. The stability of complexes of Cu
2+
, Ni
2+
, Co
2+
 and Fe
2+
 varies in the order  
(a) Cu
2+
 > Ni
2+
 > Co
2+
 > Fe
2+
    (b) Cu
2+
 > Fe
2+
 > Ni
2+
 > Co
2+
  
(c) Ni
2+
 > Co
2+
 > Fe
2+
 > Cu
2+
    (d) Cu
2+
 < Ni
2+
 < Co
2+
 < Fe
2+
  
Q7. Four successive member of the first row transition elements are listed below with their atomic numbers. 
Which one of them is expected to have the highest third ionization enthalpy?  
(a) Vanadium (Z = 23)     (b) Manganese (Z = 25)  
(c) Chromium (Z = 24)     (d) Iron (Z = 26)  
Q8. Which of the following nitrates on strong heating leaves the metal as the residue?  
(a) AgNO
3
   (b) Pb(NO
3
)
2
   (c) Cu(NO
3
)
2
   (d) Al(NO
3
)
3
  
 
 ANJANA CHEMISTRY CLASSES SCO-42 SEC-20 C, Contact: 9464010111/ talk2anjana@gmail.com , Chandigarh  
2 
Anjana Chemistry Notes 
Q9. Lanthanoids are  
(a) 14 elements in the sixth period (atomic no. 90 to 103) that are filling 4f sublevel  
(b) 14 elements in the seventh period (atomic number = 90 to 103) that are filling, 5f sublevel 
(c)  14 elements in the sixth period (atomic number = 58 to 71) that are filling the 4f sublevel 
(d) 14 elements in the seventh period (atomic number = 50 to 71) that are filling 4fg sublevel.  
Q10. Calomel (Hg
2
Cl
2
) on reaction with NH
4
OH gives  
(a) HgNH
2
Cl      (b) NH
2
 – Hg – Hg – Cl   
(c) Hg
2
O      (d) HgO  
Q11. KMnO
4
 reacts with ferrous sulphate according to the equation  
MnO
4
-
 + 5Fe
2+
 + 8H
+
 ?? Mn
2+
 + 5Fe
3+
 + 4H
2
O.  
Here 10 mLof 0.1 M KMnO
4
 is equivalent to  
 (a) 30 mL of 0.3 M FeSO
4
    (b) 40 mL of 0.1 M FeSO
4
 
 (c) 20 mL of 0.1 M FeSO
4
    (d) 50 mL of 0.1 M FeSO
4
  
 
SECTION – II 
MCQS : MORE THAN ONE CORRECT OPTION 
Q12. Which of the following statement are correct when a mixture of NaCl and K
2
Cr
2
O
7
 is gently warmed with 
conc. H
2
SO
4
?  
(a) A deep red vapour is evolved  
(b) The vapour when passed into NaOH solution gives a yellow solution of Na
2
CrO
4
  
(c) Chlorine gas is evolved  
(d) Chromyl chloride is formed  
Q13. Zinc is the only metal in group – 12 which show amphoteric properties and is soluble on alkaline forming 
(a) Na
2
[Zn(OH)
4
]     (b) Na[Zn(OH)
3
 . (H
2
O)
3
] 
(c) Na[Zn(OH)
3
 . (H
2
O)]    (d) Na
4
[Zn(OH)
6
]  
Q14. A solution of colourless salt X on boiling with excess NaOH produces a non-flammable gas. The gas evolution 
ceases after sometime upon addition of Zn dust to the same solution, the gas evolution restarts. The colourless 
salt(s) X is/are  
(a) NH
4
NO
3
   (b) NH
4
NO
2
   (c) NH
4
Cl   (d) (NH
4
)
2
SO
4
  
 
SECTION – III 
COMPREHENSION 
When an electron from a lower energy d orbital is excited to a higher energy d orbital, the energy of excitation 
corresponds to the frequency of light absorbed. This frequency generally lies in the visible region. The colour observed 
corresponds to the complementary colour of the light absorbed. The frequency of the light absorbed is determined by 
the nature of the ligand.  
 ANJANA CHEMISTRY CLASSES SCO-42 SEC-20 C, Contact: 9464010111/ talk2anjana@gmail.com , Chandigarh  
3 
Anjana Chemistry Notes 
Q15. The colourless species is  
(a) VCl
3
      (b) VOSO
4
 
(c) Na
3
VO
4
      (d) [V(H
2
O)
6
SO
4
].H
2
O  
Q16. An aqueous solution of FeSO
4
, Al
2
(SO
4
)
3
 and chrome alum is heated with excess of Na
2
O
2
 and filtered. The 
material obtained are  
(a) a colourless filtrate and a green residue  (b) a yellow filtrate and a green residue  
(c) a yellow filtrate and a brown residue   (d) a green filtrate and a brown residue  
Q17. Which of the following pair of compounds is expected to exhibit same colour in aqueous solution?  
(a) FeCl
2
, CuCl
2
   (b) VOCl
2
, CuCl
2
 (c) VOCl
2
, FeCl
2
  (d) FeCl
2
, MnCl
2
  
 
SECTION – IV 
INTEGER TYPE QUESTIONS 
Q18. All lanthanoides react easily with water to give solution giving +x ions, the principle oxidation state of 
lanthanides is +x. Here, x is  
Q19. The number of ions formed on dissolving one molecule of FeSO
4
. (NH
4
)
2
 SO
4
. 6H
2
O are  
Q20. Number of salts among the following that will give metal on heating is  
Zn(NO
3
)
2
, AgNO
3
, Cu(NO
3
)
2
, Hg(NO
3
)
2
  
Q21. When SO
2
 is passed in an acidified K
2
Cr
2
O
7
 solution, the oxidation state of sulphur is changed to  
Q22. The oxidation state of chromium in the final produced formed by the reaction between KI and acidified 
K
2
Cr
2
O
7
 soluiton is  
Q23. The number of water molecule(s) directly bonded to the metal centre of CusO
4
.5H
2
O is   
 
 
 
 ANJANA CHEMISTRY CLASSES SCO-42 SEC-20 C, Contact: 9464010111/ talk2anjana@gmail.com , Chandigarh  
Page 4


1 
Anjana Chemistry Notes 
OBJECTIVE TEST  
DATE: 31 AUG         MAX. MARKS: 92 
           TIME: 1HR 
TOPICS: D & F- BLOCK ELEMENTS  
 
SECTION – I 
MCQS : SINGLE OPTION CORRECT 
Q1. FeCr
2
O
4
 ? ? ?
I
 NaCrO
4
 ? ? ?
II
 Cr
2
O
3
 ? ? ?
III
 Cr I, II and III are 
 I      II    III 
(a)  Na
2
CO
3
/air, ? NH
4
Cl, ? Al  
(b)  NaOH/air, ? C, heat  C, heat  
(c)  Na
2
CO
3
/air, ? C, heat  C, heat  
(d)  NaOH/air, heat  Al, heat  C, heat  
 
Q2. The dissolution of V
2
O
5
 in 30% H
2
O
2
 gives  
(a) V(O
2
)
4
3
-
   (b) VO(O
2
)
2
-
   (c) V
2
O
3
   (d) VO
2
-
  
Q3. Acidified solution of chromic acid on treatment with hydrogen peroxide yields.  
(a) CrO
5
 + H
2
O      (b) H
2
Cr
2
O
7
 + H
2
O + O
2
  
(c) Cr
2
O
3
 + H
2
O + O
2
     (d) CrO
3
 + H
2
O + O
2
  
Q4. (NH
4
)
2
Cr
2
O
7
 on heating liberates a gas. The same gas will be obtained by  
(a) heating NH
4
NO
2
     (b) heating NH
4
NO
3
 
(c) treating Mg
3
N
2
 with H
2
O    (d) heating H
2
O
2
 on NaNO
2
  
Q5. White vitriol has the formula  
(a) CaSO
4
.2H
2
O     (b) CuSO
4
.5H
2
O  
(c) ZnSO
4
.7H
2
O      (d) FeSO
4
.7H
2
O  
Q6. The stability of complexes of Cu
2+
, Ni
2+
, Co
2+
 and Fe
2+
 varies in the order  
(a) Cu
2+
 > Ni
2+
 > Co
2+
 > Fe
2+
    (b) Cu
2+
 > Fe
2+
 > Ni
2+
 > Co
2+
  
(c) Ni
2+
 > Co
2+
 > Fe
2+
 > Cu
2+
    (d) Cu
2+
 < Ni
2+
 < Co
2+
 < Fe
2+
  
Q7. Four successive member of the first row transition elements are listed below with their atomic numbers. 
Which one of them is expected to have the highest third ionization enthalpy?  
(a) Vanadium (Z = 23)     (b) Manganese (Z = 25)  
(c) Chromium (Z = 24)     (d) Iron (Z = 26)  
Q8. Which of the following nitrates on strong heating leaves the metal as the residue?  
(a) AgNO
3
   (b) Pb(NO
3
)
2
   (c) Cu(NO
3
)
2
   (d) Al(NO
3
)
3
  
 
 ANJANA CHEMISTRY CLASSES SCO-42 SEC-20 C, Contact: 9464010111/ talk2anjana@gmail.com , Chandigarh  
2 
Anjana Chemistry Notes 
Q9. Lanthanoids are  
(a) 14 elements in the sixth period (atomic no. 90 to 103) that are filling 4f sublevel  
(b) 14 elements in the seventh period (atomic number = 90 to 103) that are filling, 5f sublevel 
(c)  14 elements in the sixth period (atomic number = 58 to 71) that are filling the 4f sublevel 
(d) 14 elements in the seventh period (atomic number = 50 to 71) that are filling 4fg sublevel.  
Q10. Calomel (Hg
2
Cl
2
) on reaction with NH
4
OH gives  
(a) HgNH
2
Cl      (b) NH
2
 – Hg – Hg – Cl   
(c) Hg
2
O      (d) HgO  
Q11. KMnO
4
 reacts with ferrous sulphate according to the equation  
MnO
4
-
 + 5Fe
2+
 + 8H
+
 ?? Mn
2+
 + 5Fe
3+
 + 4H
2
O.  
Here 10 mLof 0.1 M KMnO
4
 is equivalent to  
 (a) 30 mL of 0.3 M FeSO
4
    (b) 40 mL of 0.1 M FeSO
4
 
 (c) 20 mL of 0.1 M FeSO
4
    (d) 50 mL of 0.1 M FeSO
4
  
 
SECTION – II 
MCQS : MORE THAN ONE CORRECT OPTION 
Q12. Which of the following statement are correct when a mixture of NaCl and K
2
Cr
2
O
7
 is gently warmed with 
conc. H
2
SO
4
?  
(a) A deep red vapour is evolved  
(b) The vapour when passed into NaOH solution gives a yellow solution of Na
2
CrO
4
  
(c) Chlorine gas is evolved  
(d) Chromyl chloride is formed  
Q13. Zinc is the only metal in group – 12 which show amphoteric properties and is soluble on alkaline forming 
(a) Na
2
[Zn(OH)
4
]     (b) Na[Zn(OH)
3
 . (H
2
O)
3
] 
(c) Na[Zn(OH)
3
 . (H
2
O)]    (d) Na
4
[Zn(OH)
6
]  
Q14. A solution of colourless salt X on boiling with excess NaOH produces a non-flammable gas. The gas evolution 
ceases after sometime upon addition of Zn dust to the same solution, the gas evolution restarts. The colourless 
salt(s) X is/are  
(a) NH
4
NO
3
   (b) NH
4
NO
2
   (c) NH
4
Cl   (d) (NH
4
)
2
SO
4
  
 
SECTION – III 
COMPREHENSION 
When an electron from a lower energy d orbital is excited to a higher energy d orbital, the energy of excitation 
corresponds to the frequency of light absorbed. This frequency generally lies in the visible region. The colour observed 
corresponds to the complementary colour of the light absorbed. The frequency of the light absorbed is determined by 
the nature of the ligand.  
 ANJANA CHEMISTRY CLASSES SCO-42 SEC-20 C, Contact: 9464010111/ talk2anjana@gmail.com , Chandigarh  
3 
Anjana Chemistry Notes 
Q15. The colourless species is  
(a) VCl
3
      (b) VOSO
4
 
(c) Na
3
VO
4
      (d) [V(H
2
O)
6
SO
4
].H
2
O  
Q16. An aqueous solution of FeSO
4
, Al
2
(SO
4
)
3
 and chrome alum is heated with excess of Na
2
O
2
 and filtered. The 
material obtained are  
(a) a colourless filtrate and a green residue  (b) a yellow filtrate and a green residue  
(c) a yellow filtrate and a brown residue   (d) a green filtrate and a brown residue  
Q17. Which of the following pair of compounds is expected to exhibit same colour in aqueous solution?  
(a) FeCl
2
, CuCl
2
   (b) VOCl
2
, CuCl
2
 (c) VOCl
2
, FeCl
2
  (d) FeCl
2
, MnCl
2
  
 
SECTION – IV 
INTEGER TYPE QUESTIONS 
Q18. All lanthanoides react easily with water to give solution giving +x ions, the principle oxidation state of 
lanthanides is +x. Here, x is  
Q19. The number of ions formed on dissolving one molecule of FeSO
4
. (NH
4
)
2
 SO
4
. 6H
2
O are  
Q20. Number of salts among the following that will give metal on heating is  
Zn(NO
3
)
2
, AgNO
3
, Cu(NO
3
)
2
, Hg(NO
3
)
2
  
Q21. When SO
2
 is passed in an acidified K
2
Cr
2
O
7
 solution, the oxidation state of sulphur is changed to  
Q22. The oxidation state of chromium in the final produced formed by the reaction between KI and acidified 
K
2
Cr
2
O
7
 soluiton is  
Q23. The number of water molecule(s) directly bonded to the metal centre of CusO
4
.5H
2
O is   
 
 
 
 ANJANA CHEMISTRY CLASSES SCO-42 SEC-20 C, Contact: 9464010111/ talk2anjana@gmail.com , Chandigarh  
4 
Anjana Chemistry Notes 
SOLUTION 
SECTION – I 
MCQS : SINGLE OPTION CORRECT 
Q1. (a) 
 FeCr
2
O
4
 + 
I
3 2
CO Na + 
Air
2
O ? ? ? ?
Heat
 2Na
2
CrO
4
 + Cr 2 O Al Al 2 CrO Cl NH
3 2
III
3
Heat
II
4
+ ? ? ? + ? ? ? ? .  
Q2. (b)   
 V
2
O
5
 + 2H
2
O
2
 ? ? ? ? ?
- O H
2
 2VO
2
(OH)
2
 ? ? ? ? ?
2 2
O H 2
 VO(O
2
)
2
-
 + 3H
2
O  
Q3. (a)   
 K
2
Cr
2
O
7
 + H
2
SO
4
 + 4H
2
O
2
 ?? K
2
SO
4
 + 2CrO
5
 + 5H
2
O  
Q4. (a)  
 (NH
4
)
2
Cr
2
O
7
 ? ? ? ?
heat
 Cr
2
O
3
 + N
2
 + 4H
2
O   
 NH
4
NO
2
 ? ? N
2
 + 2H
2
O  
 NH
4
NO
3
 ? ? N
2
O + 2H
2
O  
 Mg
3
N
2
 + H
2
O ?? 3Mg(OH)
2
 + 2NH
3
  
 2NaNO
2
 + H
2
O
2
 ?? Na
2
O
2
 + 2HNO
2
 
N
2
 gas is liberated by heating (NH
4
)
2
Cr
2
O
7
 and the same gas i.e., N
2
 is liberated by heating NH
4
NO
2
. In all 
other cases N
2
 is not a product.  
Q5. (c)  
Q6.  (a)   
 Smaller cation form more stable complexes.  
 Ionic radii : Fe
2+
 > Co
2+
 > Ni
2+
 > Cu
2+
  
 ? Stability : Fe
2+
 < Co
2+
 < Ni
2+
 < Cu
2+
 
Q7. (b)  
Mn
2+
 has most stable configuration, i.e., 3d
5
 (all the five d-orbitals are singly occupied). Hence, to remove 
electron from Mn
2+
 ion requires more energy, i.e., the third ionization enthalpy of manganese is highest.  
Q8.  (a)  
 AgNO
3
 on heating strongly gives Ag metal.  
 2AgNO
3
 ? ? ? ? ? ?
heat d Re
 2 Ag + 2NO
3
 + O
2
 
Q9. (c)  
As sixth period can accommodate only 18 elements in the table, 14 members of 4f series (atomic number          
58 to 71) are separately accommodated in a horizontal row below the periodic table. These are called as 
lanthanides.  
Q10. (a) 
 Hg
2
Cl
2
 + 2NH
4
OH ? ? 
 
 ANJANA CHEMISTRY CLASSES SCO-42 SEC-20 C, Contact: 9464010111/ talk2anjana@gmail.com , Chandigarh  
Page 5


1 
Anjana Chemistry Notes 
OBJECTIVE TEST  
DATE: 31 AUG         MAX. MARKS: 92 
           TIME: 1HR 
TOPICS: D & F- BLOCK ELEMENTS  
 
SECTION – I 
MCQS : SINGLE OPTION CORRECT 
Q1. FeCr
2
O
4
 ? ? ?
I
 NaCrO
4
 ? ? ?
II
 Cr
2
O
3
 ? ? ?
III
 Cr I, II and III are 
 I      II    III 
(a)  Na
2
CO
3
/air, ? NH
4
Cl, ? Al  
(b)  NaOH/air, ? C, heat  C, heat  
(c)  Na
2
CO
3
/air, ? C, heat  C, heat  
(d)  NaOH/air, heat  Al, heat  C, heat  
 
Q2. The dissolution of V
2
O
5
 in 30% H
2
O
2
 gives  
(a) V(O
2
)
4
3
-
   (b) VO(O
2
)
2
-
   (c) V
2
O
3
   (d) VO
2
-
  
Q3. Acidified solution of chromic acid on treatment with hydrogen peroxide yields.  
(a) CrO
5
 + H
2
O      (b) H
2
Cr
2
O
7
 + H
2
O + O
2
  
(c) Cr
2
O
3
 + H
2
O + O
2
     (d) CrO
3
 + H
2
O + O
2
  
Q4. (NH
4
)
2
Cr
2
O
7
 on heating liberates a gas. The same gas will be obtained by  
(a) heating NH
4
NO
2
     (b) heating NH
4
NO
3
 
(c) treating Mg
3
N
2
 with H
2
O    (d) heating H
2
O
2
 on NaNO
2
  
Q5. White vitriol has the formula  
(a) CaSO
4
.2H
2
O     (b) CuSO
4
.5H
2
O  
(c) ZnSO
4
.7H
2
O      (d) FeSO
4
.7H
2
O  
Q6. The stability of complexes of Cu
2+
, Ni
2+
, Co
2+
 and Fe
2+
 varies in the order  
(a) Cu
2+
 > Ni
2+
 > Co
2+
 > Fe
2+
    (b) Cu
2+
 > Fe
2+
 > Ni
2+
 > Co
2+
  
(c) Ni
2+
 > Co
2+
 > Fe
2+
 > Cu
2+
    (d) Cu
2+
 < Ni
2+
 < Co
2+
 < Fe
2+
  
Q7. Four successive member of the first row transition elements are listed below with their atomic numbers. 
Which one of them is expected to have the highest third ionization enthalpy?  
(a) Vanadium (Z = 23)     (b) Manganese (Z = 25)  
(c) Chromium (Z = 24)     (d) Iron (Z = 26)  
Q8. Which of the following nitrates on strong heating leaves the metal as the residue?  
(a) AgNO
3
   (b) Pb(NO
3
)
2
   (c) Cu(NO
3
)
2
   (d) Al(NO
3
)
3
  
 
 ANJANA CHEMISTRY CLASSES SCO-42 SEC-20 C, Contact: 9464010111/ talk2anjana@gmail.com , Chandigarh  
2 
Anjana Chemistry Notes 
Q9. Lanthanoids are  
(a) 14 elements in the sixth period (atomic no. 90 to 103) that are filling 4f sublevel  
(b) 14 elements in the seventh period (atomic number = 90 to 103) that are filling, 5f sublevel 
(c)  14 elements in the sixth period (atomic number = 58 to 71) that are filling the 4f sublevel 
(d) 14 elements in the seventh period (atomic number = 50 to 71) that are filling 4fg sublevel.  
Q10. Calomel (Hg
2
Cl
2
) on reaction with NH
4
OH gives  
(a) HgNH
2
Cl      (b) NH
2
 – Hg – Hg – Cl   
(c) Hg
2
O      (d) HgO  
Q11. KMnO
4
 reacts with ferrous sulphate according to the equation  
MnO
4
-
 + 5Fe
2+
 + 8H
+
 ?? Mn
2+
 + 5Fe
3+
 + 4H
2
O.  
Here 10 mLof 0.1 M KMnO
4
 is equivalent to  
 (a) 30 mL of 0.3 M FeSO
4
    (b) 40 mL of 0.1 M FeSO
4
 
 (c) 20 mL of 0.1 M FeSO
4
    (d) 50 mL of 0.1 M FeSO
4
  
 
SECTION – II 
MCQS : MORE THAN ONE CORRECT OPTION 
Q12. Which of the following statement are correct when a mixture of NaCl and K
2
Cr
2
O
7
 is gently warmed with 
conc. H
2
SO
4
?  
(a) A deep red vapour is evolved  
(b) The vapour when passed into NaOH solution gives a yellow solution of Na
2
CrO
4
  
(c) Chlorine gas is evolved  
(d) Chromyl chloride is formed  
Q13. Zinc is the only metal in group – 12 which show amphoteric properties and is soluble on alkaline forming 
(a) Na
2
[Zn(OH)
4
]     (b) Na[Zn(OH)
3
 . (H
2
O)
3
] 
(c) Na[Zn(OH)
3
 . (H
2
O)]    (d) Na
4
[Zn(OH)
6
]  
Q14. A solution of colourless salt X on boiling with excess NaOH produces a non-flammable gas. The gas evolution 
ceases after sometime upon addition of Zn dust to the same solution, the gas evolution restarts. The colourless 
salt(s) X is/are  
(a) NH
4
NO
3
   (b) NH
4
NO
2
   (c) NH
4
Cl   (d) (NH
4
)
2
SO
4
  
 
SECTION – III 
COMPREHENSION 
When an electron from a lower energy d orbital is excited to a higher energy d orbital, the energy of excitation 
corresponds to the frequency of light absorbed. This frequency generally lies in the visible region. The colour observed 
corresponds to the complementary colour of the light absorbed. The frequency of the light absorbed is determined by 
the nature of the ligand.  
 ANJANA CHEMISTRY CLASSES SCO-42 SEC-20 C, Contact: 9464010111/ talk2anjana@gmail.com , Chandigarh  
3 
Anjana Chemistry Notes 
Q15. The colourless species is  
(a) VCl
3
      (b) VOSO
4
 
(c) Na
3
VO
4
      (d) [V(H
2
O)
6
SO
4
].H
2
O  
Q16. An aqueous solution of FeSO
4
, Al
2
(SO
4
)
3
 and chrome alum is heated with excess of Na
2
O
2
 and filtered. The 
material obtained are  
(a) a colourless filtrate and a green residue  (b) a yellow filtrate and a green residue  
(c) a yellow filtrate and a brown residue   (d) a green filtrate and a brown residue  
Q17. Which of the following pair of compounds is expected to exhibit same colour in aqueous solution?  
(a) FeCl
2
, CuCl
2
   (b) VOCl
2
, CuCl
2
 (c) VOCl
2
, FeCl
2
  (d) FeCl
2
, MnCl
2
  
 
SECTION – IV 
INTEGER TYPE QUESTIONS 
Q18. All lanthanoides react easily with water to give solution giving +x ions, the principle oxidation state of 
lanthanides is +x. Here, x is  
Q19. The number of ions formed on dissolving one molecule of FeSO
4
. (NH
4
)
2
 SO
4
. 6H
2
O are  
Q20. Number of salts among the following that will give metal on heating is  
Zn(NO
3
)
2
, AgNO
3
, Cu(NO
3
)
2
, Hg(NO
3
)
2
  
Q21. When SO
2
 is passed in an acidified K
2
Cr
2
O
7
 solution, the oxidation state of sulphur is changed to  
Q22. The oxidation state of chromium in the final produced formed by the reaction between KI and acidified 
K
2
Cr
2
O
7
 soluiton is  
Q23. The number of water molecule(s) directly bonded to the metal centre of CusO
4
.5H
2
O is   
 
 
 
 ANJANA CHEMISTRY CLASSES SCO-42 SEC-20 C, Contact: 9464010111/ talk2anjana@gmail.com , Chandigarh  
4 
Anjana Chemistry Notes 
SOLUTION 
SECTION – I 
MCQS : SINGLE OPTION CORRECT 
Q1. (a) 
 FeCr
2
O
4
 + 
I
3 2
CO Na + 
Air
2
O ? ? ? ?
Heat
 2Na
2
CrO
4
 + Cr 2 O Al Al 2 CrO Cl NH
3 2
III
3
Heat
II
4
+ ? ? ? + ? ? ? ? .  
Q2. (b)   
 V
2
O
5
 + 2H
2
O
2
 ? ? ? ? ?
- O H
2
 2VO
2
(OH)
2
 ? ? ? ? ?
2 2
O H 2
 VO(O
2
)
2
-
 + 3H
2
O  
Q3. (a)   
 K
2
Cr
2
O
7
 + H
2
SO
4
 + 4H
2
O
2
 ?? K
2
SO
4
 + 2CrO
5
 + 5H
2
O  
Q4. (a)  
 (NH
4
)
2
Cr
2
O
7
 ? ? ? ?
heat
 Cr
2
O
3
 + N
2
 + 4H
2
O   
 NH
4
NO
2
 ? ? N
2
 + 2H
2
O  
 NH
4
NO
3
 ? ? N
2
O + 2H
2
O  
 Mg
3
N
2
 + H
2
O ?? 3Mg(OH)
2
 + 2NH
3
  
 2NaNO
2
 + H
2
O
2
 ?? Na
2
O
2
 + 2HNO
2
 
N
2
 gas is liberated by heating (NH
4
)
2
Cr
2
O
7
 and the same gas i.e., N
2
 is liberated by heating NH
4
NO
2
. In all 
other cases N
2
 is not a product.  
Q5. (c)  
Q6.  (a)   
 Smaller cation form more stable complexes.  
 Ionic radii : Fe
2+
 > Co
2+
 > Ni
2+
 > Cu
2+
  
 ? Stability : Fe
2+
 < Co
2+
 < Ni
2+
 < Cu
2+
 
Q7. (b)  
Mn
2+
 has most stable configuration, i.e., 3d
5
 (all the five d-orbitals are singly occupied). Hence, to remove 
electron from Mn
2+
 ion requires more energy, i.e., the third ionization enthalpy of manganese is highest.  
Q8.  (a)  
 AgNO
3
 on heating strongly gives Ag metal.  
 2AgNO
3
 ? ? ? ? ? ?
heat d Re
 2 Ag + 2NO
3
 + O
2
 
Q9. (c)  
As sixth period can accommodate only 18 elements in the table, 14 members of 4f series (atomic number          
58 to 71) are separately accommodated in a horizontal row below the periodic table. These are called as 
lanthanides.  
Q10. (a) 
 Hg
2
Cl
2
 + 2NH
4
OH ? ? 
 
 ANJANA CHEMISTRY CLASSES SCO-42 SEC-20 C, Contact: 9464010111/ talk2anjana@gmail.com , Chandigarh  
5 
Anjana Chemistry Notes 
  
Q11. (d)  
In the reaction  
MnO
4
-
 + 5Fe
2+
 + 8H
+
 ?? Mn
2+
 + 5Fe
3+
 + 4H
2
O  
5 times quantity of Fe
2+
 consumed. Therefore, 5 times of FeSO
4
 will be equivalent to 50 mL.  
 
SECTION – II 
MCQS : MORE THAN ONE CORRECT OPTION 
Q12. (a, b, d)  
 K
2
Cr
2
O
7
 + 6H
2
SO
4
 + 4NaCl ? ?  
 2KHSO
4
 + 4NaHSO
4
 + O H 3 Cl CrO 2
2
) vapours d (Re
chloride Chromyl
2 2
+
-
 
 4NaOH + CrO
2
Cl ? ? 
.) ln so Yellow (
4 2
CrO Na + 2NaCl + 2H
2
O  
Q13. (a, b, c)   
Zn reacts with NaOH to form zincate ions and metazincate ion and H
2
. The zincate and metazincates are 
represented as  
[Zn(OH)
4
]
2
-
, [Zn(OH)
3
(H
2
O)
3
]
-
, [Zn(OH)
3
H
2
O]
-
  
Q14. (a, b)  
 
] X [
3 4
NO NH + NaOH ? ? 
gas flammable Non
3
NH
-
+ NaNO
3
 + H
2
O  
 NaNO
3
 + 4Zn + 7NaOH ?? 4Na
2
ZnO
2
 + NH
3
 + 2H
2
O  
 
] X [
2 4
NO NH + NaOH ? ? NH
3
 + NaNO
2
 + H
2
O  
 3Zn + 5NaOH + NaNO
2
 ?? 3Na
2
ZnO
2
 + NH
3
 + H
2
O  
SECTION – III 
COMPREHENSION 
Q15. (c) 
 Na
3
VO
4
 contains vanadium in +5 oxidation state which has vacant d-orbitals and is thus colourless.  
Q16. (c)  
FeSO
4
 first gets oxidized to Fe
2
(SO
4
)
3
 and then gets precipitated as brown ppt. of Fe(OH)
3
. Whereas ppt. of 
Al(OH)
3
 and Cr(OH)
3
 dissolves forming colourless and yellow solutions of NaAlO
2
 and Na
2
CrO
4
 
respectively, Fe(OH)
3
 remains undissolved.  
 
Hg 
NH
2
 
Cl 
Black  
+ Hg + NH
4
Cl + 2H
2
O  
 ANJANA CHEMISTRY CLASSES SCO-42 SEC-20 C, Contact: 9464010111/ talk2anjana@gmail.com , Chandigarh  
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