Table of contents | |
Interpreting Distance-Time Graphs | |
Constant Speed on a Distance-Time Graph | |
Changing Speed on a Distance-Time Graph | |
Gradient of a Distance-Time Graph |
A distance-time graph shows how the distance of an object moving in a straight line (from a starting position) varies over time:
This graph shows a moving object moving further away from its origin
Example: Ose decides to take a stroll to the park. He finds a bench in a quiet spot and takes a seat, picking up where he left off reading his book on Black Holes. After some time reading, Ose realises he lost track of time and runs home. A distance-time graph for his trip is drawn below:
(a) How long does Ose spend reading his book?
(b) Which of the labelled sections (A, B or C) represents Ose running home?
(c) What is the total distance travelled by Ose?
Part (a)
(i) Ose spends 40 minutes reading his book
(ii) The flat section of the line (section B) represents an object which is stationary - so section B
(iii) represents Ose sitting on the bench reading
(iv) This section lasts for 40 minutes - as shown in the graph belowPart (b)
(i) Section C represents Ose running home
(ii) The slope of the line in section C is steeper than the slope in section A
(iii) This means Ose was moving with a larger speed (running) in section CPart (c)
(i) The total distance travelled by Ose is 0.6 km
(ii) The total distance travelled by an object is given by the final point on the line - in this case, the line ends at 0.6 km on the distance axis. This is shown in the image below:
Exam Tip: Remember to check the units of variables measured on each axes. These may not always be in standard units - in our example, the unit of distance was km and the unit of time was minutes. Double check which units to use in your answer.
Exam Tip: Use the entire line, where possible, to calculate the gradient. Examiners tend to award credit if they see a large gradient triangle used - so remember to draw these directly on the graph itself!
Example: A distance-time graph is drawn below for part of a train journey. The train is travelling at a constant speed.
Calculate the speed of the train.
Step 1: Draw a large gradient triangle on the graph and label the magnitude of the rise and run
(i) The image below shows a large gradient triangle drawn with dashed lines
(ii) The rise and run magnitude is labelled, using the units as stated on each axisStep 2: Convert units for distance and time into standard units
(i) The distance travelled (rise) = 8 km = 8000 m
(ii) The time taken (run) = 6 mins = 360 sStep 3: State that speed is equal to the gradient of a distance-time graph
The gradient of a distance-time graph is equal to the speed of a moving object:Step 4: Substitute values in to calculate the speed
(i) speed = gradient = 8000 ÷ 360
(ii) speed = 22.2 m/s
124 videos|149 docs|37 tests
|
|
Explore Courses for Grade 10 exam
|