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Distance Travelled Notes - Class 11

Document Description: Distance Travelled for Class 11 2022 is part of Class 11 preparation. The notes and questions for Distance Travelled have been prepared according to the Class 11 exam syllabus. Information about Distance Travelled covers topics like and Distance Travelled Example, for Class 11 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Distance Travelled.

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A particle projected upwards with v = 20ms find time when the distance travelled is twice the displacemen?
Ref: https://edurev.in/question/568976/A-particle-projected-upwards-with-v-20ms-find-time

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Distance Travelled Notes - Class 11


Let it happen at a height of x meters.

Distance = twice |displacement|

=> H + (H-x) = 2 * x

=> 2H = 3x

=> x = 2/3 H

Now, v = u + at (where v is final velocity, u is initial velocity, a is acceleration and t is time). We know v is zero at max height and u = 20m/s. Assuming acceleration due to gravity is 10m/s^2, we get

0 = 20 - 10t

=> t = 2

i.e. takes two seconds to reach max height.

Again, S = ut + 1/2at^2 (where S = distance). Substituting, we get

H = (20 * 2 ) - 1/2(10 * 2^2)

=> H = 20

thus x = 2/3H = 40/3

Now we just need to find out how long it takes for an object dropped from rest to fall a distance of H-x = 20 - 40/3 = 20/3

Using the equation S = ut + 1/2at^2, we get t = 2/root3

Thus, 2 seconds to get to max height and 2/root3 secs to fall, giving a total time requirement of 2 + 2/root3

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