Q1. State whether the following statements are true or false. Justify your answers.
(i) Every irrational number is a real number.
Ans: True
Reason: Irrational Numbers – A number is said to be irrational, if it cannot be written in the p/q, where p and q are integers and q ≠ 0.
i.e., Irrational numbers = π, e, √3, 5+√2, 6.23146…. , 0.101001001000….
Real numbers – The collection of both rational and irrational numbers are known as real numbers.
i.e., Real numbers = √2, √5, 56 , 0.102…
Every irrational number is a real number, however, every real number is not an irrational number.
(ii) Every point on the number line is of the form √m where m is a natural number.
Ans: False
Reason: The statement is false since as per the rule, a negative number cannot be expressed as square roots.
E.g., √9 =3 is a natural number.
But √2 = 1.414 is not a natural number.
Similarly, we know that there are negative numbers on the number line but when we take the root of a negative number it becomes a complex number and not a natural number.
E.g., √7 = 7i, where i = √1
The statement that every point on the number line is of the form √m, where m is a natural number is false.
(iii) Every real number is an irrational number.
Ans: False
Reason: The statement is false, the real numbers include both irrational and rational numbers. Therefore, every real number cannot be an irrational number.
Real numbers – The collection of both rational and irrational numbers are known as real numbers.
i.e., Real numbers = √2, √5, , 0.102…
Irrational Numbers – A number is said to be irrational if it cannot be written in the p/q, where p and q are integers and q ≠ 0.
i.e., Irrational numbers = π, e, √3, 5+√2, 6.23146…. , 0.101001001000….
Every irrational number is a real number, however, every real number is not irrational.
Q2. Are the square roots of all positive integers irrational? If not, give an example of the square root of a number that is a rational number.
Ans: No, the square roots of all positive integers are not irrational.
For example,
√4 = 2 is rational.
√9 = 3 is rational.
Hence, the square roots of positive integers 4 and 9 are not irrational. ( 2 and 3, respectively).
Q3. Show how √5 can be represented on the number line.
Ans:
Step 1: Let line AB be of 2 unit on a number line.
Step 2: At B, draw a perpendicular line BC of length 1 unit.
Step 3: Join CA
Step 4: Now, ABC is a right angled triangle. Applying Pythagoras theorem,
AB^{2 }+ BC^{2} = CA^{2}
2^{2 }+ 1^{2} = CA^{2} = 5
⇒ CA = √5 . Thus, CA is a line of length √5 unit.
Step 5: Taking CA as a radius and A as a center draw an arc touching the number line. The point at which number line get intersected by arc is at √5 distance from 0 because it is a radius of the circle whose center was A.
Thus, √5 is represented on the number line as shown in the figure.
√5 on number line
Q4. Classroom activity (Constructing the ‘square root spiral’) : Take a large sheet of paper and construct the ‘square root spiral’ in the following fashion. Start with a point O and draw a line segment OP_{1} of unit length. Draw a line segment P_{1} P_{2} perpendicular to OP_{1} of unit length (see Fig. 1.9). Now draw a line segment P_{2} P_{3} perpendicular to OP_{2} . Then draw a line segment P_{3} P_{4} perpendicular to OP_{3}.
Continuing in this manner, you can get the line segment P_{n–1}P_{n} by drawing a line segment of unit length perpendicular to OP_{n–1}. In this manner, you will have created the points P_{2} , P_{3} ,...., P_{n} ,... ., and joined them to create a beautiful spiral depicting √2, √3, √4, ....
Ans:
Step 1: Mark a point O on the paper. Here, O will be the center of the square root spiral.
Step 2: From O, draw a straight line, OA, of 1cm horizontally.
Step 3: From A, draw a perpendicular line, AB, of 1 cm.
Step 4: Join OB. Here, OB will be of √2
Step 5: Now, from B, draw a perpendicular line of 1 cm and mark the end point C.
Step 6: Join OC. Here, OC will be of √3
Step 7: Repeat the steps to draw √4, √5, √6….
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