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**Q.1. Find: ****(i) 64 ^{1/2} **

âˆ´ (64)

= 8

Thus, 64

âˆ´ (3

= 2

Thus, (32)

âˆ´ (125)

Thus, 125

âˆ´ (9)

Thus, 9

âˆ´ (32)

Thus, 32

âˆ´ (16)

Thus, 16

âˆ´ (125)

**(iv) **7^{1/2} . 8^{1/2}**Ans. ****(i)**

âˆµ a^{m} . a^{n} = a^{m+n}

âˆ´ 2^{2/3} . 2^{1/5} = 2^{2/3 + 1/5}^{}**(ii)**^{}^{}

Thus,

**(iii)**

Thus,

**(iv)**

âˆµ a^{m} . b^{m} = (ab)^{m}

âˆ´ 7^{1/2} . 8^{1/2} = (7 x 8)^{1/2} = (56)^{1/2}

Thus, 7^{1/2} . 8^{1/2 }= (56)^{1/2}

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