NCERT Solutions - Coordinate Geometry

# NCERT Solutions - Coordinate Geometry Notes | Study Mathematics (Maths) Class 9 - Class 9

## Document Description: NCERT Solutions - Coordinate Geometry for Class 9 2022 is part of Mathematics (Maths) Class 9 preparation. The notes and questions for NCERT Solutions - Coordinate Geometry have been prepared according to the Class 9 exam syllabus. Information about NCERT Solutions - Coordinate Geometry covers topics like Exercise 3.1, Exercise 3.2, Exercise 3.3 and NCERT Solutions - Coordinate Geometry Example, for Class 9 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for NCERT Solutions - Coordinate Geometry.

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Exercise 3.1

Q.1. How will you describe the position of a table lamp on your study table to another person?

The above figure is a 3-D shows a study table, on which a study lamp is placed.
Now let us consider only the top surface of the table which becomes a 2-D rectangle figure.

From the Figure Above,

• Consider the lamp on the table as a point
• Consider the table as a 2-D plane.

The table has a shorter side (20 cm) and a longer side (30 cm).

• Let us measure the distance of the lamp from the shorter side and the longer side.
• Let us assume
• Distance of the lamp from the shorter side is 5 cm.
• Distance of the lamp from the longer side is 5 cm.

Therefore, we can conclude that the position of the lamp on the table can be described with respect to the order of the axes as (5,15).

Q.2. (Street Plan): A city has two main roads which cross each other at the center of the city.
These two roads are along the North–South direction and East– West direction.
All the other streets of the city run parallel to these roads and are 200 m apart. There are 5 streets in each direction. Using 1cm = 200 m, draw a model of the city on your notebook. Represent the roads/streets by single lines. There are many cross- streets in your model. A particular cross-street is made by two streets, one running in the North–South direction and another in the East– West direction. Each cross street is referred to in the following manner:
If the 2nd street running in the North–South direction and 5th in the East–West direction meet at some crossing, then we will call this cross-street (2, 5).
Using this convention, find:
(i) How many cross - streets can be referred to as (4, 3).
(ii) How many cross - streets can be referred to as (3, 4).

Let us draw two perpendicular lines as the two main roads of the city that cross each other at the center. Let us mark them as North–South and East–West.

As given in the question, let us take the scale as 1cm = 200 m.
Draw five streets that are parallel to both the main roads (which intersect), to get the given below figure.
Street plan is as shown in the figure:

(i) There is only one cross street, which can be referred as (4, 3).
(ii) There is only one cross street, which can be referred as (3, 4).

Exercise 3.2

Q.1. Write the answer of each of the following questions:
(i) What is the name of horizontal and the vertical lines drawn to determine the position of any point in the Cartesian plane?
(ii) What is the name of each part of the plane formed by these two lines?
(iii) Write the name of the point where these two lines intersect.

(i) The horizontal line that is drawn to determine the position of any point in the Cartesian plane is called as x-axis. The vertical line that is drawn to determine the position of any point in the Cartesian plane is called as y-axis.

(ii) The name of each part of the plane that is formed by x-axis and y-axis is called as quadrant.

(iii) The point, where the x-axis and the y-axis intersect is called as origin (O).

Q.2. See the given figure, and write the following:
(i) The coordinates of B.
(ii) The coordinates of C.
(iii) The point identified by the coordinates (–3, –5).
(iv) The point identified by the coordinates (2, –4).
(v) The abscissa of the point D.
(vi) The ordinate of the point H.
(vii) The coordinates of the point L.
(viii) The coordinates of the point M.

From the Figure above,
(i) The co-ordinates of point B is the distance of point B from x-axis and y-axis.

Therefore, the co-ordinates of point B are (–5, 2).
(ii) The co-ordinates of point C is the distance of point C from x-axis and y-axis.

Therefore, the co-ordinates of point C are (5, –5).
(iii) The point that represents the co-ordinates (–3, –5) is E.
(iv) The point that represents the co-ordinates (2, –4) is G.
(v) The abscissa of point D is the distance of point D from the y-axis. Therefore, the abscissa of point D is 6.
(vi) The ordinate of point H is the distance of point H from the x-axis. Therefore, the abscissa of point H is –3.
(vii) The co-ordinates of point L in the above figure is the distance of point L from x-axis and y-axis. Therefore, the co-ordinates of point L are (0, 5).
(viii) The co-ordinates of point M in the above figure is the distance of point M from x-axis and y-axis. Therefore, the co-ordinates of point M are (–3, 0).

Exercise 3.3

Q.1. In which quadrant or on which axis do each of the points ( –2, 4), (3, –1), (–1, 0), (1, 2) and (–3, –5) lie? Verify your answer by locating them on the Cartesian plane.

To determine the quadrant or axis of the points (–2, 4), (3, –1), (–1, 0), (1, 2) and (–3, –5).Plot the points (–2, 4), (3, –1), (–1, 0), (1, 2) and (–3, –5) on the graph, to get

From the figure above, we can conclude that the points

• Point (–2, 4) lie in 2nd quadrant.
• Point (3, –1) lie in 4th quadrant.
• Point (–1, 0) lie on the negative x-axis.
• Point (1, 2) lie in 1st quadrant.
• Point (–3, –5) lie in 3rd quadrant.

Q.2. Plot the points (x, y) given in the following table on the plane, choosing suitable units of distance on the axes.

Given,

Draw x-axis and y-axis as the co-ordinate axes and mark their point of intersection O as the Origin (0, 0).
In order to plot the points given in the table provided above,

• Let us mark the first point as A (–2, 8)
• Take 2 units on the negative x-axis and then 8 units on positive y-axis.
• Let us mark the second point as B (–1, 7)
• Take -1 unit on negative x-axis and then 7 units on positive y-axis.
• Let us mark the third point as C (0, –1.25),
• Take 1.25 units below x-axis on negative y-axis.
• Let us mark the fourth point as D (1, 3)
• Take 1 unit on positive x-axis and then 3 units on positive y-axis.
• Let us mark the fifth point as E (3, –1)
• Take 3 units on positive x-axis and then move -1 unit on negative x-axis.

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