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**Question 1. In which quadrant or on which axis do each of the points (â€“2, 4) (3, â€“1), (â€“1, 0), (1, 2) and (â€“3, â€“5) lie? Verify your answer by locating them on the Cartesian plane.****Solution:** In the point (â€“2, 4), the abscissa is negative and the ordinate is positive.

âˆµ (â€“, +) belongs to 2nd quadrant.

âˆ´ (â€“2, 4) lies in the second quadrant.

The point (3, â€“1) is having +ve abscissa and â€“ve ordinate.

âˆ´ (3, â€“1) lies in the 4th quadrant.

The point (â€“1, 0) is having (â€“ve) abscissa and ordinate on the x-axis.

âˆ´ The point (â€“1, 0) lies on the negative x-axis.

The point (1, 2) is having the x-coordiante as well as y-coordinate +ve.

âˆ´ Point (1, 2) lies in the 1st quadrant.

The point (â€“3, â€“5) is having the abscissa as well as ordinate negative.

âˆ´ Point (â€“3, â€“5) lies in the 3rd quadrant.

These points are plotted in the Cartesian plane as shown in the following figure as A(â€“2, 4); B(3, â€“1); C(â€“1, 0); D(1, 2) and E(â€“3, â€“5).

**Question 2. Plot the points (x, y) given in the following table on the plane, choosing suitable units of distance on the axes.**

x | -2 | -1 | 0 | 1 | 3 |

y | 8 | 7 | -1.25 | 3 | -1 |

**Solution: **The given points are (â€“2, 8), (â€“1, 7), (0, â€“1.5), (1, 3) and (3, â€“1). To plot these points:

(i) We draw X'OX and YOY' as axes.

(ii) We choose suitable units of distance on the axes.

(iii) To plot (â€“2, 8), we start from O, take (â€“2) units on x-axis and then (+8) units on y-axis.

We mark the point as A(â€“2, 8).

(iv) To plot (â€“1, 7), we start from 0; take (â€“1) units on x-axis and then (+7) units on the yaxis. We mark the point as B(â€“1, 7).

(v) To plot (0, â€“1.25), we move along 1.25 units below the x-axis on the y-axis and mark the point as C(0, â€“1.25).

(vi) To plot (1, 3), we take (+1) unit on the x-axis and then (+3) units on the y-axis. We mark the point as D(1, 3).

(vii) To plot (3, â€“1), we take (+3) units on the x-axis and then (â€“1) unit on the y-axis. We mark the point E(3, â€“1).

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