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NCERT Solutions for Class 9 Maths - Ex 7.5 Triangles

Question 1. ABC is a triangle. Locate a point in the interior of ΔABC which is equidistant from all the vertices of ΔABC.
 Soultion:
Let us consider a ΔABC.
Draw ‘l’ the perpendicular bisector of AB.
Draw ‘m’ the perpendicular bisector of BC.
Let the two perpendicular bisectors ‘l’ and ‘m’ meet at O. ‘O’ is the required point which is equidistant from A, B and C.

NCERT Solutions for Class 9 Maths - Ex 7.5 Triangles

Note: If we draw a circle with centre ‘O’ and radius OB or OC, then it will pass through A, B and C.


Question 2. In a triangle, locate a point in its interior which is equidistant from all the sides of the triangle.
 Solution:
Let us consider a ΔABC.
Draw ‘l’ the bisector of ∠B.
Draw ‘m’ the bisector of ∠C.
Let the two bisectors l and m meet at O. Thus, ‘O’ is the required point which is equidistant from the sides of ΔABC.

NCERT Solutions for Class 9 Maths - Ex 7.5 Triangles

required point which is equidistant from the sides of ΔABC.
Note: If we draw OM ⊥ BC and draw a circle with O as centre and OM as radius, then the circle will touch the sides of the triangle.

NCERT Solutions for Class 9 Maths - Ex 7.5 Triangles
 

Question 3. In a huge park, people are concentrated at three points (see figure): A : where there are different slides and swings form children,

NCERT Solutions for Class 9 Maths - Ex 7.5 Triangles

B : near which a man-made lake is situated, C: which is near to a large parking and exit.
 Where should an ice cream parlour be set up so that maximum number of persons can approach it?
 Hint: The parlour should be equidistant from A, B and C.

Solution: Let us join A and B, and draw ‘l’ the perpendicular bisector of AB.

NCERT Solutions for Class 9 Maths - Ex 7.5 Triangles

Now, join B and C, and draw ‘m’ the perpendicular bisector of BC. Let the perpendicular bisectors ‘l’ and ‘m’ meet at ‘O’. The point ‘O’ is the required point where the ice cream parlour be set up.
Note: If we join ‘A’ and ‘C’, and draw the perpendicular bisectors, then it will also meet (or pass through) the point O.


Question 4. Complete the hexagonal and star shaped Rangolies [see Fig. (i) and (ii)] by filling them with as many equilateral triangles of side 1 cm as you can. Count the number of triangles in each case. Which has more triangles?

NCERT Solutions for Class 9 Maths - Ex 7.5 Triangles

Solution: It is an activity. We get the 150 equilateral triangles in the figure

(i) and 300 equilateral triangles in the figure

(ii). ∴ The figure

(ii) has more triangles.

The document NCERT Solutions for Class 9 Maths - Ex 7.5 Triangles is a part of the Class 9 Course Extra Documents & Tests for Class 9.
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FAQs on NCERT Solutions for Class 9 Maths - Ex 7.5 Triangles

1. What is the importance of studying triangles in class 9?
Ans. Studying triangles in class 9 is important as it forms the foundation for various mathematical concepts and geometrical principles. Triangles are one of the most basic and fundamental shapes, and understanding their properties helps in solving problems related to angles, sides, and areas of different shapes.
2. How many types of triangles are there?
Ans. There are several types of triangles based on their sides and angles. The three main types of triangles based on sides are equilateral triangle (all sides equal), isosceles triangle (two sides equal), and scalene triangle (no sides equal). Based on angles, triangles can be classified as acute-angled (all angles less than 90 degrees), obtuse-angled (one angle greater than 90 degrees), and right-angled (one angle equal to 90 degrees).
3. How can we determine if three given sides form a triangle?
Ans. To determine if three given sides form a triangle, we can apply the Triangle Inequality Theorem. According to this theorem, the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. If this condition is satisfied for all three sides, then the given lengths form a valid triangle. Otherwise, it is not possible to form a triangle with those side lengths.
4. What is the Pythagorean Theorem and how is it used in triangles?
Ans. The Pythagorean Theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. It can be represented as a^2 + b^2 = c^2, where 'c' is the hypotenuse and 'a' and 'b' are the other two sides. This theorem is extensively used in solving problems related to right-angled triangles, such as finding the length of an unknown side or determining if a triangle is right-angled.
5. How can we find the area of a triangle?
Ans. The area of a triangle can be found using various formulas depending on the given information. For example, if the lengths of the base and height of a triangle are known, the area can be calculated using the formula, Area = (1/2) * base * height. If the lengths of the three sides of a triangle are known, the area can be found using Heron's formula, which states that Area = √(s(s-a)(s-b)(s-c)), where 's' is the semi-perimeter of the triangle and 'a', 'b', and 'c' are the lengths of its sides.
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