Table of contents | |
What is Remainder? | |
Finding Remainders Using Long Division | |
How to Represent Remainder? | |
Basic Remainder Theorem | |
Concept of Negative Remainder |
Remainders is a very crucial concept since numerous questions from Quantitative Aptitude section require the concepts of remainder to solve them. Most of the candidates have already studied this concept in their elementary schools and can solve the related questions. Here is a lesson on Remainders to help the candidates revise the topic in an efficient way.
Example: Suppose 9 is divided by 2.
In this case, N = 9, x = 2, 2 × 4 = 8, which is 1 less than 9. hence Q = 4 and R = (9-8) = 1 . Hence, 9 = 4 × 2 + 1.
Thus, the remainder is 3. A remainder can also be a 0. The remainder on dividing 10 by 2, 18 by 3, or 35 by 7, is equal to 0. Here are some other examples of remainders.
Division | Remainder |
35/6 | 5 |
42/8 | 2 |
121/11 | 0 |
118/12 | 10 |
120/17 | 1 |
We can represent the remainder of the division in two ways.
The basic remainder theorem is based on the product of individual remainders.
If R is the remainder of an expression( p*q*r)/X, and pR, qR and rR are the remainders when p,q and r are respectively divided by X, then it can be said that ((pR × qR × rR ))/X, will give the same remainder as given by (p*q*r)/X.
Let’s understand this with the help of some examples.
1. Find the remainder when (361*363) is divided by 12.
Steps:
2. Find the remainder when 106 is divided by 7 i.e. (106/7)R.
Solution.
106=103 x 103
Thus (106/7)R = (103/7 × 103/7)R = ((6 * 6)/7)R = (36/7)R = 1.
So the remainder is 1.
“Remainder when the product of some numbers is divided by the requisite number is the product of individual remainders of the numbers”– This is Basic Remainder Theorem put across in words.
Example: 10/11 remainder is +10 itself. It can also be written as 10-11= -1 Similarly, 32/10 remainder is +2 or -8
Let’s express the solution for questions 31 above, in another way- based on the concept of negative remainder.
Thus (106/7)R = (103/7 × 103/7)R = ((-1 * -1)/7)R = (1/7)R = 1.
Let’s see why this happens:
If the numbers N1, N2, N3 give remainders of R1, R2, R3 with quotients Q1, Q2, Q3 when divided by a common divisor D.
N1 = DQ1 + R1 N2 = DQ2 + R2 N3 = DQ3 + R3
Multiplying = N1 × N2 × N3
= (DQ1 + R1) × (DQ2 + R2) × (DQ3 + R3)
= D(some number) + (R1 × R2 × R3) = first part is divisible by D,
Hence you need to check for the individual remainders only.
108 videos|103 docs|114 tests
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1. What is a remainder in mathematics? |
2. How can we find remainders using long division? |
3. What is the basic remainder theorem? |
4. How do we represent remainders in mathematics? |
5. Can remainders be negative? |
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