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A linear equation in two variables is an equation that can be expressed in the form Ax + By + C = 0, where A, B, and C are constants, and A and B are not both zero. |
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The slope-intercept form of a linear equation is y = mx + b, where m is the slope of the line and b is the y-intercept. |
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Rearranging the equation to slope-intercept form gives 2y = 4x - 8, or y = 2x - 4. The slope is 2. |
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If the two lines represented by the equations are parallel, they will never intersect, indicating no solution. |
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Solve the system: 2x + 3y = 6 and x - y = 1. Hint: Try substitution or elimination. |
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From x - y = 1, we find x = y + 1. Substituting into the first equation: 2(y + 1) + 3y = 6. This simplifies to 5y + 2 = 6, thus y = 4/5. Then, x = 1 + 4/5 = 9/5. The solution is (9/5, 4/5). |
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The graphical representation of a linear equation in two variables is a straight line. |
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The graphical method involves plotting the equations on a graph to find the point of intersection, which represents the solution. |
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The system can have one unique solution, no solution, or infinitely many solutions. |
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If the equations of two lines are identical, what type of solution does it imply? |
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If the equations are identical, it implies there are infinitely many solutions. |
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The elimination method is used to eliminate one variable by adding or subtracting the equations to solve for the other variable. |
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Find the solution for the system: 3x + 4y = 12 and x - 2y = -1. Hint: Consider elimination. |
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From x - 2y = -1, we find x = 2y - 1. Substituting into 3(2y - 1) + 4y = 12 gives 6y - 3 + 4y = 12. Simplifying gives 10y = 15, so y = 3/2. Then, x = 2(3/2) - 1 = 2. The solution is (2, 3/2). |
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Rearranging gives 2y = -5x + 10, or y = (-5/2)x + 5. The slope is -5/2 and the y-intercept is 5. |
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A consistent system of equations has at least one solution, either one unique solution or infinitely many solutions. |
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The substitution method involves solving one equation for one variable and substituting that expression into the other equation to find the solution. |
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Given the equations y = 2x + 3 and y = -x + 1, find the point of intersection. Hint: Set the equations equal to each other. |
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Setting 2x + 3 = -x + 1 gives 3x = -2, so x = -2/3. Substituting back, y = 2(-2/3) + 3 = 5/3. The point of intersection is (-2/3, 5/3). |
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The determinant method involves using Cramer's Rule, where you calculate determinants of matrices formed by the coefficients of the variables. |
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In this form, m represents the slope of the line, and b represents the y-coordinate where the line intersects the y-axis. |
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If two lines intersect at a single point, it indicates that the system of equations has a unique solution. |