Heat Engine and Refrigerator, Refrigeration and Air Conditioning, Mechanical Engineering, GATE Video Lecture - Mechanical Engineering | Best Video for Mechanical Engineering

Martin and in this video tutorial I'm
going to share with you a question of
heat engine as well as refrigerator well
this is a question which in which you
need to focus on the quotient first and
you have to read the question with your
full concentration if you not give you
full concentration and probably you and
with getting the wrong answer of this
question right so what is about the
question let me share with you perhaps
are they have said that in this quotient
data a heat engine
this a T means hidden gem having an
efficiency of 70% is used to derive an
applicative that means this is the
quotient of combination of heat engine
as well as refrigerators remember that
so here suppose that this is a heat
engine
alright so rate engine just draw
whenever you are getting a question of
the engine repeater as well as heat form
just try to draw a diagram without
diagram to ability of solving the
question is I mean with maintaining
accuracy is little bit difficulty as per
my experience because till now I have
solved a more than a 100 questions in
refrigerator RFC an originator and air
conditioning thermodynamics less I'm
sharing with you alright so so here it
is not having an efficiency of 70
percent right so 70 percent efficiency
of this head engine now they send up you
to drive a refrigerator route Co B is
five GOP is five right energy absorbed
from low temperature reservoir by the
refrigerator for each kilo Joule of
energy absorbed from high temperature
source by engine that means so this is a
high temperature source
listed this is eight engine temperature
so they ask what is Q R is equal to if F
is equal to 1 kilojoules
they said this right so if this is 1
kilo Joule then how much Q R this desire
effect of the refrigerator this is the
device desire effect of refrigerator
right getting less temperature low
temperature bins
rounding is the Desertec tog
refrigerator right now here we will go
for the two equations based on the data
given in this quotient
what are those equation let me share
with you so what are those equation
basically we know that efficiency is
equal to what output by input but here
what output we are getting that output
is giving to the refrigerator for
getting this desire effect that means
these two this one is interrelated with
heat engine as well as refrigerator
that's why both of these refrigerator
and heat engine hidden generator both
are interconnected to each other are you
getting my point
so efficiency of the heat engine is
output by input that means this is is
equal to one so W is equal to what 1
point 70 so 70 kilo
this isn't joon-soo kilo Joule right so
W is equal to what we get vertically
point seven zero kilo Joule all right
now let's go for the refrigerator what
we have in case of refrigerator Co P of
refrigerator is equal to desire effect
QR by work input W now what is U P Co P
is 5 now what is Q our keyword we have
to find out what is W point seven zero
that means Q R is equal to five multiple
seven zero is equal to three point five
kilo do not know what because this is
given in judo is that they are not
relating with time that's why time it is
so the answer is work for this quotient
that is three point five kilo joule that
is awesome B is the right answer for
this quotient now within a few minutes
what you have learned the co P or P
danger especially the efficiency of heat
engine and CU p of refrigerator right so
I hope you understand something about
this total and yes if you will judge
want to get familiar with this type of
problem then I will share with you one
thing that is solved nobody
program there is no shortcut of it more
questions you will solve more similar
will become for solving numerical
problems all right thanks for watching
thank you very much of to see you again
in my next video dot well bye bye