Class 9 Exam  >  Class 9 Notes  >  Mathematics (Maths) Class 9  >  Worksheet Solutions: Heron’s Formula

Heron’s Formula Class 9 Worksheet Maths Chapter 10

Multiple Choice Questions

Q1: The difference between sides at right angles in a right angled triangle is 14 cm. The area of the triangle is 120 cm2. The perimeter of the triangle is
(a) 80
(b) 45
(c) 60
(d) 64
Ans: 
(c)
Let y be one of the at right angle ,then another side will be y-14
Now we know that
A = (1/2)BH
120 = (1/2)y(y - 14)
y- 14y - 240
(y - 24)(y + 10) = 0
y = 24
So other side is 10
From pythogrous theorem
Heron’s Formula Class 9 Worksheet Maths Chapter 10
So perimeter will be =10+24+26=60 cm

Q2: ABCD is a trapezium with AB  = 10cm, AD = 5 cm, BC = 4 cm and DC = 7 cm?
Heron’s Formula Class 9 Worksheet Maths Chapter 10Find the area of the ABCD
(a) 34 cm2
(b) 28cm2
(c) 20 cm2
(d) None of these
Ans:
(a)
BC is the altitude between the two parallel sides AB and DC
So Area of trapezium will be given by
Heron’s Formula Class 9 Worksheet Maths Chapter 10

Q3: Find the area and perimeter of the right angle triangle whose hypotenuse is 5 cm and Base is 4 cm
(a) 6 cm2 ,12 cm
(b) 12 cm2 ,14 cm
(c) 4 cm2, 6 cm
(d) 12 cm2 ,6 cm
Ans:
(a)
By pythogorous theorem
Heron’s Formula Class 9 Worksheet Maths Chapter 10
So Area =(1/2) XBase X height = 6 cm2
Perimeter = 5 + 4 + 3 = 12 cm

Q4: In an isosceles triangle ?ABC with AB = AC = 13 cm. D is mid point on BC. Also BC=10 cm
Which of the following is true?
(a) Area of Triangle ABD and ADC are equal
(b) Area of triangle ABD is 30 cm2
(c) Area of triangle ABC is 60 cm2
(d) All the above
Ans: 
(d)
ABD an ADC are congruent triangle, So Area of Triangle ABD and ADC are equal
Also From pythogorous theorem, AD will be given as
Heron’s Formula Class 9 Worksheet Maths Chapter 10
So Area of triangle ABC = (1/2)X base X height = 60 cm2 

Q5: A triangle and a parallelogram have the same base and the same area. The sides of the triangle are 26 cm and 30 cm and parallelogram stands on the base 28 cm. calculate the height of the parallelogram
(a) 12 cm
(b) 14 cm
(c) 10cm
(d) 13 cm
Ans:
(a)
For triangle, all the sides are given, calculating the area using Heron formula
A = 336 cm2
Now for parallelogram, Area is given by
A = Base X Altitude
336 = 28 X H
Or H = 12 cm

True / False

Q1: Heron formula for area of triangle is not valid of all triangles
Ans: 
False

Q2: If each side of the triangles is tripled, the area will becomes 9 times.
Ans: 
True

Q3: Base and corresponding altitude of the parallelogram are 8 and 5 cm respectively. Area of parallelogram is 40 cm2.
Ans: 
True

Q4: If each side of triangle is doubled, the perimeter will become 4 times.
Ans: False

Q5: If p is the perimeter of the triangle of sides a,b,c ,the area of triangle is.
Heron’s Formula Class 9 Worksheet Maths Chapter 10
Ans: 
True

Q6: When two triangles are congruent, there areas are same.
Ans
True

Q7: Heron’s belongs to America.
Ans:
False

Q8:  If the side of the equilateral triangle is a rational number, the area would always be irrational number.
Ans:
 True

Concepts Questions

Q1: Triangle have sides as a=5 cm ,b=4 cm,c=3 cm
Ans: Heron’s Formula Class 9 Worksheet Maths Chapter 10
Area Heron’s Formula Class 9 Worksheet Maths Chapter 10

Q2: Equilateral triangle having side a=2 cm
Ans: Area of equilateral
Heron’s Formula Class 9 Worksheet Maths Chapter 10

Q3: Right angle triangle have base=4 cm and Height =3 cm
Ans: Area of triangle
A = (1/2)BH = 6cm2

Q4: Square whose diagonal is 10 cm
Ans: Area of square in terms diagonal
A = (1/2)d= 50cm2

Q5: Rectangle whose length and breath are 6 and 4 cm
Ans: Rectangle area is given by
A = LXB = 24cm2

Q6: Parallelogram whose two sides are 10 cm and 16 cm and diagonal is 14 cm
Ans: In parallelogram whose two sides and diagonal are given, Area is given by
Heron’s Formula Class 9 Worksheet Maths Chapter 10
Where Heron’s Formula Class 9 Worksheet Maths Chapter 10
So s=20cm
So A=80(3)1/2cm2 

Q7: Parallelogram whose base is 10 cm and height is 14 cm
Ans: Area is given by
A = Base X height = 10X14 = 140cm2

Q8: Rhombus of diagonals to 10 and 24 cm
Ans: Area is given by
A=(1/2)d1d= 120cm2

Q9: Two sides of trapezium are 36 and 24 cm and its altitude is
Ans: Area of trapezium is given by
A = (1/2)(Sum of parallel sides) Altitude
A = 360cm2

The document Heron’s Formula Class 9 Worksheet Maths Chapter 10 is a part of the Class 9 Course Mathematics (Maths) Class 9.
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FAQs on Heron’s Formula Class 9 Worksheet Maths Chapter 10

1. What is Heron's formula and how is it used?
Ans. Heron's formula is a mathematical formula that is used to find the area of a triangle when the lengths of all three sides are known. It states that the area of a triangle, denoted as A, is equal to the square root of the product of the semi-perimeter, denoted as s, and the difference between the semi-perimeter and the length of each side of the triangle. Mathematically, it can be expressed as A = √(s(s-a)(s-b)(s-c)), where a, b, and c are the lengths of the sides of the triangle.
2. How do you calculate the semi-perimeter of a triangle?
Ans. The semi-perimeter of a triangle is calculated by adding the lengths of all three sides of the triangle and then dividing the sum by 2. For example, if the lengths of the sides of a triangle are a, b, and c, the semi-perimeter, denoted as s, can be calculated as s = (a + b + c)/2.
3. Can Heron's formula be used to find the area of any triangle?
Ans. Yes, Heron's formula can be used to find the area of any triangle, whether it is an equilateral, isosceles, or scalene triangle. It is a general formula that works for all types of triangles as long as the lengths of all three sides are known.
4. What are the advantages of using Heron's formula to find the area of a triangle?
Ans. Heron's formula is advantageous in finding the area of a triangle because it does not require the measurement of the height of the triangle, unlike the traditional formula (Area = 0.5 * base * height). This makes it particularly useful when the height is not easily measurable or known. Additionally, Heron's formula works for all types of triangles, including those with unequal sides, unlike some other formulas that are specific to certain types of triangles.
5. How can Heron's formula be applied in real-life situations?
Ans. Heron's formula has various applications in real-life situations. For example, it can be used in architecture and construction to calculate the area of irregularly shaped land or the surface area of a triangular roof. It is also used in engineering and physics to determine the area of complex shapes that can be divided into triangles. Moreover, Heron's formula is utilized in navigation and surveying for calculating the area of irregularly shaped fields or land plots.
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