HOTS & Value Based Questions: Introduction to Trigonometry

# HOTS & Value Based Questions: Introduction to Trigonometry Notes | Study Mathematics (Maths) Class 10 - Class 10

## Document Description: HOTS & Value Based Questions: Introduction to Trigonometry for Class 10 2022 is part of Mathematics (Maths) Class 10 preparation. The notes and questions for HOTS & Value Based Questions: Introduction to Trigonometry have been prepared according to the Class 10 exam syllabus. Information about HOTS & Value Based Questions: Introduction to Trigonometry covers topics like HOTS, Value-based Questions and HOTS & Value Based Questions: Introduction to Trigonometry Example, for Class 10 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for HOTS & Value Based Questions: Introduction to Trigonometry.

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HOTS

Q1. What is the maximum value of

Hint: ∵    = 3 sin θ
Since the maximum value of ‘sin θ’ is 1
∴  the maximum value of 3 sin θ is 3 × 1 i.e. 3

⇒  the maximum value of  is 3.

Q2. If sin θ = 1/3,  then find the value of 9 cot2θ + 9.

Hint: cot2 θ = cosec2 θ – 1

∴ 9 cot2θ + 9 = 9(8) + 9 = 72 + 9 = 81

Q3. If 4 tan θ = 3, then find the value of

Hint:

Q4. If sin α = 1/2 and cos β = 1/2 then find the value of (α + β).

Hint:

Q5. If sin θ + cos θ = √3 , find the value of tan θ + cot θ .

Hint: sin θ + cos θ = 3 ⇒ (sin θ + cos θ)2 = 3
⇒ sin2 θ + cos2 θ + 2 sin θ . cos θ = 3
⇒ 1 + 2 sin θ . cos θ = 3 ⇒ 2 sin θ . cos θ = 2    [∴ sin2θ + cos2θ = 1]

⇒ sin θ . cos θ =1 ⇒  1 =

⇒

Thus, tanθ + cotθ = 1

Q6. cos (A+B) = 1/2 and sin (A–B) = 1/2 ; 0° < (A + B) < 90° and (A – B) > 0°. What are the values of ∠A and ∠B?

Hint:

...(1)

...(2)

Adding (1) and (2), 2A = 90 ⇒ A = 45
From (1) 45° + B = 60°  ⇒   B = 60° – 45° = 15°
Thus, ∠A = 45° and ∠B = 15°

Value-based Questions

Q1. A group of students plan to put up a banner in favour of respect towards girls and women, against a wall. They placed a ladder against the wall such that its foot is at a distance of 2.5 m from the wall and its top reaches a window 6 m above the ground.

(i) Find the length of the ladder.
(ii) Which mathematical concept is used in this problem?
(iii) By putting up a banner in favour of respect to women, which value is depicted by the group of students?

Sol. (i) Let AB be the ladder and CA be the wall with the window at A. Also,
BC = 2.5 m
CA = 6m
∴ In rt ΔACB, we have
AB2 = BC2 + CA2 [Using Pythagoras Theorem]
= (2.5)2 + (6)2
= 6.25 + 36 = 42.25

⇒

Thus, the length of the ladder is 6.5 m.
(ii) Triangles (Pythagoras Theorem)
(iii) Creating positive awareness in public towards regards to women.

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