Hydrostatic Forces Civil Engineering (CE) Notes | EduRev

Topic wise GATE Past Year Papers for Civil Engineering

Civil Engineering (CE) : Hydrostatic Forces Civil Engineering (CE) Notes | EduRev

The document Hydrostatic Forces Civil Engineering (CE) Notes | EduRev is a part of the Civil Engineering (CE) Course Topic wise GATE Past Year Papers for Civil Engineering.
All you need of Civil Engineering (CE) at this link: Civil Engineering (CE)

Question 1. A sector gate is provided on a spillway as shown in the figure. Assuming g = 10 m/s2, the resultant force per meter length (expressed in kN/m) on the gate will be_______ .     [2016 : 2 Marks, Set-I]
Hydrostatic Forces Civil Engineering (CE) Notes | EduRev
Solution:
Hydrostatic Forces Civil Engineering (CE) Notes | EduRev
Hydrostatic Forces Civil Engineering (CE) Notes | EduRev

Question 2. A triangular gate with a base width of 2 m and a height of 1.5 m lies in a vertical plane. The top vertex of the gate is 1.5 m below the surface of a tank which contains oil of specific gravity 0.8. Considering the density of water and acceleration due to gravity to be 1000 kg/m3 and 9.81 m/s2, respectively, the hydrostatic force (in kN) exerted by the oil on the gate is _________ .     [2015 : 2 Marks, Set-II]
Solution:

Hydrostatic Forces Civil Engineering (CE) Notes | EduRev
Hydrostatic Forces Civil Engineering (CE) Notes | EduRev

Question 3. Three rigid buckets, shown as in the figures (1), (2) and (3), are of identical heights and base areas. Further, assume that each of these buckets have negligible mass and are full of water. The weight of water in these buckets are denoted as W1,  W2, and W3 respectively. Also, let the force of water on the base of the bucket be denoted as F1, F2, and F3 respectively. The option giving an accurate description of the system physics is    [2014 : 2 Marks, Set-I]
Hydrostatic Forces Civil Engineering (CE) Notes | EduRev
(a) W2 = W1 = W3 and F2 > F1 > F
(b) W2 > W1 > W3 and F2 > F1 > F
(c) W2 = W1 = W3 and F1 = F2 = F
(d) W2 > W1 > W3 and F1 = F2 = F
Answer: 
(d)
Solution: 
Bucket → identical height → identical base area
Hydrostatic Forces Civil Engineering (CE) Notes | EduRev
=> w2> w1> w
Force on the base in each case will be equal to = Hydrostatic Forces Civil Engineering (CE) Notes | EduRev
Hence, F1 = P2 = F3

Offer running on EduRev: Apply code STAYHOME200 to get INR 200 off on our premium plan EduRev Infinity!

Related Searches

practice quizzes

,

study material

,

Viva Questions

,

past year papers

,

shortcuts and tricks

,

Previous Year Questions with Solutions

,

Exam

,

mock tests for examination

,

Hydrostatic Forces Civil Engineering (CE) Notes | EduRev

,

MCQs

,

Semester Notes

,

ppt

,

pdf

,

Extra Questions

,

video lectures

,

Hydrostatic Forces Civil Engineering (CE) Notes | EduRev

,

Important questions

,

Hydrostatic Forces Civil Engineering (CE) Notes | EduRev

,

Summary

,

Sample Paper

,

Free

,

Objective type Questions

;