All Courses
Get the App Signup / Login
Sign in Open App
JEE Exam  >  JEE Notes  >  Mathematics (Maths) for JEE Main & Advanced  >  Hyperbola: JEE Mains Previous Year Questions (2021-2024)

Hyperbola: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced PDF Download

Download, print and study this document offline
Please wait while the PDF view is loading
 Page 1


JEE Mains Previous Year Questions 
(2021-2024): Hyperbola 
2024 
Q1: For ?? < ?? < ?? / ?? , if the eccentricity of the hyperbola ?? ?? - ?? ?? ?? ???? ???? ?? ? ?? = ?? is v ?? times 
eccentricity of the ellipse ?? ?? ?? ???? ???? ?? ? ?? + ?? ?? = ?? , then the value of ?? is : 
A. 
?? ?? 
B. 
?? ?? ????
 
C. 
?? ?? 
D. 
?? ??              [JEE Main 2024 (Online) 1st February Morning Shift] 
Ans: (c) 
Explanation: Currently no explanation available 
Q2: If the foci of a hyperbola are same as that of the ellipse 
?? ?? ?? +
?? ?? ????
= ?? and the eccentricity of the 
hyperbola is 
????
?? times the eccentricity of the ellipse, then the smaller focal distance of the point 
( v ?? ,
????
?? v
?? ?? ) on the hyperbola, is equal to 
A. ???? v
?? ?? -
?? ?? 
B. ?? v
?? ?? +
?? ?? 
C. ?? v
?? ?? -
?? ?? 
D. ???? v
?? ?? -
????
??             [JEE Main 2024 (Online) 31st January Morning Shift] 
Ans: (c) 
x
2
9
+
y
2
25
= 1
a = 3 , b = 5
e =
v
1 -
9
25
=
4
5
? foci = ( 0 , ± be ) = ( 0 , ± 4 )
? ? e
H
=
4
5
×
15
8
=
3
2
 
Let equation hyperbola 
Page 2


JEE Mains Previous Year Questions 
(2021-2024): Hyperbola 
2024 
Q1: For ?? < ?? < ?? / ?? , if the eccentricity of the hyperbola ?? ?? - ?? ?? ?? ???? ???? ?? ? ?? = ?? is v ?? times 
eccentricity of the ellipse ?? ?? ?? ???? ???? ?? ? ?? + ?? ?? = ?? , then the value of ?? is : 
A. 
?? ?? 
B. 
?? ?? ????
 
C. 
?? ?? 
D. 
?? ??              [JEE Main 2024 (Online) 1st February Morning Shift] 
Ans: (c) 
Explanation: Currently no explanation available 
Q2: If the foci of a hyperbola are same as that of the ellipse 
?? ?? ?? +
?? ?? ????
= ?? and the eccentricity of the 
hyperbola is 
????
?? times the eccentricity of the ellipse, then the smaller focal distance of the point 
( v ?? ,
????
?? v
?? ?? ) on the hyperbola, is equal to 
A. ???? v
?? ?? -
?? ?? 
B. ?? v
?? ?? +
?? ?? 
C. ?? v
?? ?? -
?? ?? 
D. ???? v
?? ?? -
????
??             [JEE Main 2024 (Online) 31st January Morning Shift] 
Ans: (c) 
x
2
9
+
y
2
25
= 1
a = 3 , b = 5
e =
v
1 -
9
25
=
4
5
? foci = ( 0 , ± be ) = ( 0 , ± 4 )
? ? e
H
=
4
5
×
15
8
=
3
2
 
Let equation hyperbola 
x
2
 A
2
-
y
2
 B
2
= - 1
? ? B · e
H
= 4 ? ? B =
8
3
? ? A
2
= B
2
( e
H
2
- 1 ) =
64
9
(
9
4
- 1 ) ? A
2
=
80
9
? ?
x
2
80
9
-
y
2
64
9
= - 1
 Directrix : y = ±
B
e
H
= ±
16
9
PS = e · PM =
3
2
|
14
3
·
v
2
5
-
16
9
|
? = 7
v
2
5
-
8
3
 
Q3: Let ?? be a point on the hyperbola ?? :
?? ?? ?? -
?? ?? ?? = ?? , in the first quadrant such that the area of 
triangle formed by ?? and the two foci of ?? is ?? v ???? . Then, the square of the distance of ?? from the 
origin is 
A. 26 
B. 22 
C. 20 
D. 18         [JEE Main 2024 (Online) 30th January Evening Shift] 
Ans: (b) 
 
 
Page 3


JEE Mains Previous Year Questions 
(2021-2024): Hyperbola 
2024 
Q1: For ?? < ?? < ?? / ?? , if the eccentricity of the hyperbola ?? ?? - ?? ?? ?? ???? ???? ?? ? ?? = ?? is v ?? times 
eccentricity of the ellipse ?? ?? ?? ???? ???? ?? ? ?? + ?? ?? = ?? , then the value of ?? is : 
A. 
?? ?? 
B. 
?? ?? ????
 
C. 
?? ?? 
D. 
?? ??              [JEE Main 2024 (Online) 1st February Morning Shift] 
Ans: (c) 
Explanation: Currently no explanation available 
Q2: If the foci of a hyperbola are same as that of the ellipse 
?? ?? ?? +
?? ?? ????
= ?? and the eccentricity of the 
hyperbola is 
????
?? times the eccentricity of the ellipse, then the smaller focal distance of the point 
( v ?? ,
????
?? v
?? ?? ) on the hyperbola, is equal to 
A. ???? v
?? ?? -
?? ?? 
B. ?? v
?? ?? +
?? ?? 
C. ?? v
?? ?? -
?? ?? 
D. ???? v
?? ?? -
????
??             [JEE Main 2024 (Online) 31st January Morning Shift] 
Ans: (c) 
x
2
9
+
y
2
25
= 1
a = 3 , b = 5
e =
v
1 -
9
25
=
4
5
? foci = ( 0 , ± be ) = ( 0 , ± 4 )
? ? e
H
=
4
5
×
15
8
=
3
2
 
Let equation hyperbola 
x
2
 A
2
-
y
2
 B
2
= - 1
? ? B · e
H
= 4 ? ? B =
8
3
? ? A
2
= B
2
( e
H
2
- 1 ) =
64
9
(
9
4
- 1 ) ? A
2
=
80
9
? ?
x
2
80
9
-
y
2
64
9
= - 1
 Directrix : y = ±
B
e
H
= ±
16
9
PS = e · PM =
3
2
|
14
3
·
v
2
5
-
16
9
|
? = 7
v
2
5
-
8
3
 
Q3: Let ?? be a point on the hyperbola ?? :
?? ?? ?? -
?? ?? ?? = ?? , in the first quadrant such that the area of 
triangle formed by ?? and the two foci of ?? is ?? v ???? . Then, the square of the distance of ?? from the 
origin is 
A. 26 
B. 22 
C. 20 
D. 18         [JEE Main 2024 (Online) 30th January Evening Shift] 
Ans: (b) 
 
 
?? 2
9
-
?? 2
4
= 1
?? 2
= 9 , ?? 2
= 4
?? 2
= ?? 2
( ?? 2
- 1 ) ? ?? 2
= 1 +
?? 2
?? 2
?? 2
= 1 +
4
9
=
13
9
?? =
v 13
3
? ?? 1
?? 2
= 2ae = 2 × 3 ×
v
13
3
= 2 v 13
 
Area of ? PS
1
 S
2
=
1
2
× ?? × S
1
 S
2
= 2 v 13 
? ?
1
2
× ?? × ( 2 v 13 ) = 2 v 13 ? ?? = 2
?? 2
9
-
?? 2
4
= 1 ?
?? 2
9
- 1 = 1 ? ?? 2
= 18 ? ?? = 3 v 2
 
Distance of P from origin = v ?? 2
+ ?? 2
 
= v 18 + 4 = v 22 
Q4: 4Let ?? ?? be the eccentricity of the hyperbola 
?? ?? ????
-
?? ?? ?? = ?? and ?? ?? be the eccentricity of the ellipse 
?? ?? ?? ?? +
?? ?? ?? ?? = ?? , ?? > ?? , which passes through the foci of the hyperbola. If ?? ?? ?? ?? = ?? , then the length of the 
chord of the ellipse parallel to the ?? -axis and passing through ( ?? , ?? ) is : 
A. 
?? v ?? ?? 
B. ?? v ?? 
C. ?? v ?? 
D. 
???? v ?? ??    [JEE Main 2024 (Online) 27th January Evening Shift] 
Ans: (d) 
Explanation: Currently no explanation available 
Q5: Let the foci and length of the latus rectum of an ellipse 
?? ?? ?? ?? +
?? ?? ?? ?? = ?? , ?? > ?????? ( ± ?? , ?? ) and v ???? , 
respectively. Then, the square of the eccentricity of the hyperbola 
?? ?? ?? ?? -
?? ?? ?? ?? ?? ?? = ?? equals      [JEE Main 
2024 (Online) 31st January Morning Shift] 
Ans:  51 
Page 4


JEE Mains Previous Year Questions 
(2021-2024): Hyperbola 
2024 
Q1: For ?? < ?? < ?? / ?? , if the eccentricity of the hyperbola ?? ?? - ?? ?? ?? ???? ???? ?? ? ?? = ?? is v ?? times 
eccentricity of the ellipse ?? ?? ?? ???? ???? ?? ? ?? + ?? ?? = ?? , then the value of ?? is : 
A. 
?? ?? 
B. 
?? ?? ????
 
C. 
?? ?? 
D. 
?? ??              [JEE Main 2024 (Online) 1st February Morning Shift] 
Ans: (c) 
Explanation: Currently no explanation available 
Q2: If the foci of a hyperbola are same as that of the ellipse 
?? ?? ?? +
?? ?? ????
= ?? and the eccentricity of the 
hyperbola is 
????
?? times the eccentricity of the ellipse, then the smaller focal distance of the point 
( v ?? ,
????
?? v
?? ?? ) on the hyperbola, is equal to 
A. ???? v
?? ?? -
?? ?? 
B. ?? v
?? ?? +
?? ?? 
C. ?? v
?? ?? -
?? ?? 
D. ???? v
?? ?? -
????
??             [JEE Main 2024 (Online) 31st January Morning Shift] 
Ans: (c) 
x
2
9
+
y
2
25
= 1
a = 3 , b = 5
e =
v
1 -
9
25
=
4
5
? foci = ( 0 , ± be ) = ( 0 , ± 4 )
? ? e
H
=
4
5
×
15
8
=
3
2
 
Let equation hyperbola 
x
2
 A
2
-
y
2
 B
2
= - 1
? ? B · e
H
= 4 ? ? B =
8
3
? ? A
2
= B
2
( e
H
2
- 1 ) =
64
9
(
9
4
- 1 ) ? A
2
=
80
9
? ?
x
2
80
9
-
y
2
64
9
= - 1
 Directrix : y = ±
B
e
H
= ±
16
9
PS = e · PM =
3
2
|
14
3
·
v
2
5
-
16
9
|
? = 7
v
2
5
-
8
3
 
Q3: Let ?? be a point on the hyperbola ?? :
?? ?? ?? -
?? ?? ?? = ?? , in the first quadrant such that the area of 
triangle formed by ?? and the two foci of ?? is ?? v ???? . Then, the square of the distance of ?? from the 
origin is 
A. 26 
B. 22 
C. 20 
D. 18         [JEE Main 2024 (Online) 30th January Evening Shift] 
Ans: (b) 
 
 
?? 2
9
-
?? 2
4
= 1
?? 2
= 9 , ?? 2
= 4
?? 2
= ?? 2
( ?? 2
- 1 ) ? ?? 2
= 1 +
?? 2
?? 2
?? 2
= 1 +
4
9
=
13
9
?? =
v 13
3
? ?? 1
?? 2
= 2ae = 2 × 3 ×
v
13
3
= 2 v 13
 
Area of ? PS
1
 S
2
=
1
2
× ?? × S
1
 S
2
= 2 v 13 
? ?
1
2
× ?? × ( 2 v 13 ) = 2 v 13 ? ?? = 2
?? 2
9
-
?? 2
4
= 1 ?
?? 2
9
- 1 = 1 ? ?? 2
= 18 ? ?? = 3 v 2
 
Distance of P from origin = v ?? 2
+ ?? 2
 
= v 18 + 4 = v 22 
Q4: 4Let ?? ?? be the eccentricity of the hyperbola 
?? ?? ????
-
?? ?? ?? = ?? and ?? ?? be the eccentricity of the ellipse 
?? ?? ?? ?? +
?? ?? ?? ?? = ?? , ?? > ?? , which passes through the foci of the hyperbola. If ?? ?? ?? ?? = ?? , then the length of the 
chord of the ellipse parallel to the ?? -axis and passing through ( ?? , ?? ) is : 
A. 
?? v ?? ?? 
B. ?? v ?? 
C. ?? v ?? 
D. 
???? v ?? ??    [JEE Main 2024 (Online) 27th January Evening Shift] 
Ans: (d) 
Explanation: Currently no explanation available 
Q5: Let the foci and length of the latus rectum of an ellipse 
?? ?? ?? ?? +
?? ?? ?? ?? = ?? , ?? > ?????? ( ± ?? , ?? ) and v ???? , 
respectively. Then, the square of the eccentricity of the hyperbola 
?? ?? ?? ?? -
?? ?? ?? ?? ?? ?? = ?? equals      [JEE Main 
2024 (Online) 31st January Morning Shift] 
Ans:  51 
 focii = ( ± 5 , 0 ) ;
2 ?? 2
?? = v 50
?? = 5 ? ?? 2
=
5 v 2 ?? 2
?? 2
= ?? 2
( 1 - ?? 2
) =
5 v 2 ?? 2
? ? a ( 1 - e
2
) =
5 v 2
2
? ?
5
e
( 1 - e
2
) =
5 v 2
2
? ? v 2 - v 2 e
2
= e
? ? v 2 e
2
+ e - v 2 = 0
? ? v 2 e
2
+ 2e - e - v 2 = 0
? ? v 2 e ( e + v 2 ) - 1 ( 1 + v 2 ) = 0
? ? ( e + v 2 ) ( v 2 e - 1 ) = 0
? ? e ? - v 2 ; e =
1
v 2
x
2
 b
2
-
y
2
a
2
 b
2
= 1 ? a = 5 v 2
?? = 5
?? 2
?? 2
= ?? 2
( ?? 1
2
- 1 ) ? ?? 1
2
= 51
 
Q6: Let the latus rectum of the hyperbola 
?? ?? ?? -
?? ?? ?? ?? = ?? subtend an angle of 
?? ?? at the centre of the 
hyperbola. If ?? ?? is equal to 
?? ?? ( ?? + v ?? ) , where ?? and ?? are coprime numbers, then ?? ?? + ?? ?? + ?? ?? is 
equal to       [JEE Main 2024 (Online) 30th January Morning Shift] 
Ans: 182 
LR subtends 60
°
 at centre 
 
Page 5


JEE Mains Previous Year Questions 
(2021-2024): Hyperbola 
2024 
Q1: For ?? < ?? < ?? / ?? , if the eccentricity of the hyperbola ?? ?? - ?? ?? ?? ???? ???? ?? ? ?? = ?? is v ?? times 
eccentricity of the ellipse ?? ?? ?? ???? ???? ?? ? ?? + ?? ?? = ?? , then the value of ?? is : 
A. 
?? ?? 
B. 
?? ?? ????
 
C. 
?? ?? 
D. 
?? ??              [JEE Main 2024 (Online) 1st February Morning Shift] 
Ans: (c) 
Explanation: Currently no explanation available 
Q2: If the foci of a hyperbola are same as that of the ellipse 
?? ?? ?? +
?? ?? ????
= ?? and the eccentricity of the 
hyperbola is 
????
?? times the eccentricity of the ellipse, then the smaller focal distance of the point 
( v ?? ,
????
?? v
?? ?? ) on the hyperbola, is equal to 
A. ???? v
?? ?? -
?? ?? 
B. ?? v
?? ?? +
?? ?? 
C. ?? v
?? ?? -
?? ?? 
D. ???? v
?? ?? -
????
??             [JEE Main 2024 (Online) 31st January Morning Shift] 
Ans: (c) 
x
2
9
+
y
2
25
= 1
a = 3 , b = 5
e =
v
1 -
9
25
=
4
5
? foci = ( 0 , ± be ) = ( 0 , ± 4 )
? ? e
H
=
4
5
×
15
8
=
3
2
 
Let equation hyperbola 
x
2
 A
2
-
y
2
 B
2
= - 1
? ? B · e
H
= 4 ? ? B =
8
3
? ? A
2
= B
2
( e
H
2
- 1 ) =
64
9
(
9
4
- 1 ) ? A
2
=
80
9
? ?
x
2
80
9
-
y
2
64
9
= - 1
 Directrix : y = ±
B
e
H
= ±
16
9
PS = e · PM =
3
2
|
14
3
·
v
2
5
-
16
9
|
? = 7
v
2
5
-
8
3
 
Q3: Let ?? be a point on the hyperbola ?? :
?? ?? ?? -
?? ?? ?? = ?? , in the first quadrant such that the area of 
triangle formed by ?? and the two foci of ?? is ?? v ???? . Then, the square of the distance of ?? from the 
origin is 
A. 26 
B. 22 
C. 20 
D. 18         [JEE Main 2024 (Online) 30th January Evening Shift] 
Ans: (b) 
 
 
?? 2
9
-
?? 2
4
= 1
?? 2
= 9 , ?? 2
= 4
?? 2
= ?? 2
( ?? 2
- 1 ) ? ?? 2
= 1 +
?? 2
?? 2
?? 2
= 1 +
4
9
=
13
9
?? =
v 13
3
? ?? 1
?? 2
= 2ae = 2 × 3 ×
v
13
3
= 2 v 13
 
Area of ? PS
1
 S
2
=
1
2
× ?? × S
1
 S
2
= 2 v 13 
? ?
1
2
× ?? × ( 2 v 13 ) = 2 v 13 ? ?? = 2
?? 2
9
-
?? 2
4
= 1 ?
?? 2
9
- 1 = 1 ? ?? 2
= 18 ? ?? = 3 v 2
 
Distance of P from origin = v ?? 2
+ ?? 2
 
= v 18 + 4 = v 22 
Q4: 4Let ?? ?? be the eccentricity of the hyperbola 
?? ?? ????
-
?? ?? ?? = ?? and ?? ?? be the eccentricity of the ellipse 
?? ?? ?? ?? +
?? ?? ?? ?? = ?? , ?? > ?? , which passes through the foci of the hyperbola. If ?? ?? ?? ?? = ?? , then the length of the 
chord of the ellipse parallel to the ?? -axis and passing through ( ?? , ?? ) is : 
A. 
?? v ?? ?? 
B. ?? v ?? 
C. ?? v ?? 
D. 
???? v ?? ??    [JEE Main 2024 (Online) 27th January Evening Shift] 
Ans: (d) 
Explanation: Currently no explanation available 
Q5: Let the foci and length of the latus rectum of an ellipse 
?? ?? ?? ?? +
?? ?? ?? ?? = ?? , ?? > ?????? ( ± ?? , ?? ) and v ???? , 
respectively. Then, the square of the eccentricity of the hyperbola 
?? ?? ?? ?? -
?? ?? ?? ?? ?? ?? = ?? equals      [JEE Main 
2024 (Online) 31st January Morning Shift] 
Ans:  51 
 focii = ( ± 5 , 0 ) ;
2 ?? 2
?? = v 50
?? = 5 ? ?? 2
=
5 v 2 ?? 2
?? 2
= ?? 2
( 1 - ?? 2
) =
5 v 2 ?? 2
? ? a ( 1 - e
2
) =
5 v 2
2
? ?
5
e
( 1 - e
2
) =
5 v 2
2
? ? v 2 - v 2 e
2
= e
? ? v 2 e
2
+ e - v 2 = 0
? ? v 2 e
2
+ 2e - e - v 2 = 0
? ? v 2 e ( e + v 2 ) - 1 ( 1 + v 2 ) = 0
? ? ( e + v 2 ) ( v 2 e - 1 ) = 0
? ? e ? - v 2 ; e =
1
v 2
x
2
 b
2
-
y
2
a
2
 b
2
= 1 ? a = 5 v 2
?? = 5
?? 2
?? 2
= ?? 2
( ?? 1
2
- 1 ) ? ?? 1
2
= 51
 
Q6: Let the latus rectum of the hyperbola 
?? ?? ?? -
?? ?? ?? ?? = ?? subtend an angle of 
?? ?? at the centre of the 
hyperbola. If ?? ?? is equal to 
?? ?? ( ?? + v ?? ) , where ?? and ?? are coprime numbers, then ?? ?? + ?? ?? + ?? ?? is 
equal to       [JEE Main 2024 (Online) 30th January Morning Shift] 
Ans: 182 
LR subtends 60
°
 at centre 
 
? ? t a n ? 30
°
=
b
2
/ a
ae
=
b
2
a
2
e
=
1
v 3
? ? e =
v 3 b
2
9
 
Also, e
2
= 1 +
b
2
9
? 1 +
b
2
9
=
3 b
4
81
 
? ? ?? 4
= 3 ?? 2
+ 27
? ? ?? 4
- 3 ?? 2
- 27 = 0
? ? ?? 2
=
3
2
( 1 + v 13 )
? ? l = 3 , m = 2 , n = 13
? ? l
2
+ m
2
+ n
2
= 182
Read More
209 videos|443 docs|143 tests
Join Course for Free

Top Courses for JEE

Related Exams
JEE
About this Document
4.94/5 Rating
Dec 22, 2024 Last updated
Document Description: Hyperbola: JEE Mains Previous Year Questions (2021-2024) for JEE 2024 is part of Mathematics (Maths) for JEE Main & Advanced preparation. The notes and questions for Hyperbola: JEE Mains Previous Year Questions (2021-2024) have been prepared according to the JEE exam syllabus. Information about Hyperbola: JEE Mains Previous Year Questions (2021-2024) covers topics like and Hyperbola: JEE Mains Previous Year Questions (2021-2024) Example, for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Hyperbola: JEE Mains Previous Year Questions (2021-2024).
Introduction of Hyperbola: JEE Mains Previous Year Questions (2021-2024) in English is available as part of our Mathematics (Maths) for JEE Main & Advanced for JEE & Hyperbola: JEE Mains Previous Year Questions (2021-2024) in Hindi for Mathematics (Maths) for JEE Main & Advanced course. Download more important topics related with notes, lectures and mock test series for JEE Exam by signing up for free. JEE: Hyperbola: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced
Description
Full syllabus notes, lecture & questions for Hyperbola: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced - JEE | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) for JEE Main & Advanced | Best notes, free PDF download
Information about Hyperbola: JEE Mains Previous Year Questions (2021-2024)
In this doc you can find the meaning of Hyperbola: JEE Mains Previous Year Questions (2021-2024) defined & explained in the simplest way possible. Besides explaining types of Hyperbola: JEE Mains Previous Year Questions (2021-2024) theory, EduRev gives you an ample number of questions to practice Hyperbola: JEE Mains Previous Year Questions (2021-2024) tests, examples and also practice JEE tests
209 videos|443 docs|143 tests
Join Course for Free
Download as PDF
Explore Courses for JEE exam

Top Courses for JEE

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Related Searches

Hyperbola: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced

,

mock tests for examination

,

Important questions

,

video lectures

,

Exam

,

Hyperbola: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced

,

shortcuts and tricks

,

past year papers

,

study material

,

pdf

,

Extra Questions

,

ppt

,

Semester Notes

,

MCQs

,

Summary

,

practice quizzes

,

Objective type Questions

,

Hyperbola: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced

,

Sample Paper

,

Previous Year Questions with Solutions

,

Free

,

Viva Questions

;
Additional Information about Hyperbola: JEE Mains Previous Year Questions (2021-2024) for JEE Preparation

Hyperbola: JEE Mains Previous Year Questions (2021-2024) Free PDF Download

The Hyperbola: JEE Mains Previous Year Questions (2021-2024) is an invaluable resource that delves deep into the core of the JEE exam. These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective. With the help of these notes, you can grasp complex subjects quickly, revise important points easily, and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner, allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material, or toppers' notes, this PDF has got you covered. Download the Hyperbola: JEE Mains Previous Year Questions (2021-2024) now and kickstart your journey towards success in the JEE exam.

Importance of Hyperbola: JEE Mains Previous Year Questions (2021-2024)

The importance of Hyperbola: JEE Mains Previous Year Questions (2021-2024) cannot be overstated, especially for JEE aspirants. This document holds the key to success in the JEE exam. It offers a detailed understanding of the concept, providing invaluable insights into the topic. By knowing the concepts well in advance, students can plan their preparation effectively. Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.

Hyperbola: JEE Mains Previous Year Questions (2021-2024) Notes

Hyperbola: JEE Mains Previous Year Questions (2021-2024) Notes offer in-depth insights into the specific topic to help you master it with ease. This comprehensive document covers all aspects related to Hyperbola: JEE Mains Previous Year Questions (2021-2024). It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation. Practice papers and question papers enable you to assess your progress effectively. Additionally, the paper analysis provides valuable tips for tackling the exam strategically. Access to Toppers' notes gives you an edge in understanding complex concepts. Whether you're a beginner or aiming for advanced proficiency, Hyperbola: JEE Mains Previous Year Questions (2021-2024) Notes on EduRev are your ultimate resource for success.

Hyperbola: JEE Mains Previous Year Questions (2021-2024) JEE

The "Hyperbola: JEE Mains Previous Year Questions (2021-2024) JEE Questions" guide is a valuable resource for all aspiring students preparing for the JEE exam. It focuses on providing a wide range of practice questions to help students gauge their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation. The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level. Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.

Study Hyperbola: JEE Mains Previous Year Questions (2021-2024) on the App

Students of JEE can study Hyperbola: JEE Mains Previous Year Questions (2021-2024) alongwith tests & analysis from the EduRev app, which will help them while preparing for their exam. Apart from the Hyperbola: JEE Mains Previous Year Questions (2021-2024), students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc. The EduRev App will make your learning easier as you can access it from anywhere you want. The content of Hyperbola: JEE Mains Previous Year Questions (2021-2024) is prepared as per the latest JEE syllabus.
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup