If a=b^2x, b=c^2y, c=a^2z then find the value of xyz Notes - Class 8
a=b^2x {^ means "to the power"}
=(c^2y)^2x
=c^4xy
Therefore, a=c^4xy
=(a^2z)^4xy
=a^8xyz
Then, a=a^8xyz
Therefore, xyz=1a/8a{a and a cancel}
=1/8
ANS=1/8
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