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a_{n} = a_{1} + (n  1)d
EduRev's Tip:
⇒ 1^{3} + 2^{3} + 3^{3} ... + n^{3} =
Sum of first n odd numbers
⇒ 1 + 3 + 5 … + (2n  1) = n^{2}
Sum of first n even numbers
⇒ 2 + 4 + 6 ... 2n = n(n  1)
If you have to consider 3 terms in an AP, consider {ad,a,a+d}. If you have to consider 4 terms, consider {a3d,ad,a+d,a+3d}
If all terms of an AP are multiplied with k or divided with k, the resultant series will also be an AP with the common difference dk or d/k respectively.
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