Courses

# Important Formulae of Modern Physics - I NEET Notes | EduRev

## DC Pandey (Questions & Solutions) of Physics: NEET

Created by: Ciel Knowledge

## NEET : Important Formulae of Modern Physics - I NEET Notes | EduRev

``` Page 1

Modern Physics – I
Important Formulae
1.  Bohr's Theory
(i) Bohr's theory is applicable for hydrogen and hydrogen like atoms/ions. For such type
of atoms/ions number of electron is one. Although atomic numbers may be different,
eg,  For
1
H
1
, atomic number Z = 1
For He
+
, atomic number Z =2 and
For Li
+2
, atomic number Z = 3 .
But for all three number of electron is one.
(ii) In nth orbit

2
n 2
0
mv 1 (e)(Ze) nh
. and L mvr
t 4 r 2
? ? ?
? ? ?

After solving these two equations we will get following results
(a)
2
n1
r and r
Zm
??
(b)
0
Z
v and v m
n
??
(c)
2
2
Z
E and E m
n
??
(d)
H
1
r 0.529 ? Å

(e)
H6
1
c
v 2.2 10 m / s
137
? ? ?
(f)
H
1
E 13.6eV ??
(g) K = |E| and U = 2E
(iii) Energy of a photon
hc
E ?
?
.
After substituting values of h and c, we get

o
12375
E(in eV)
(in A)
?
?

(iv) Hydrogen spectrum

Page 2

Modern Physics – I
Important Formulae
1.  Bohr's Theory
(i) Bohr's theory is applicable for hydrogen and hydrogen like atoms/ions. For such type
of atoms/ions number of electron is one. Although atomic numbers may be different,
eg,  For
1
H
1
, atomic number Z = 1
For He
+
, atomic number Z =2 and
For Li
+2
, atomic number Z = 3 .
But for all three number of electron is one.
(ii) In nth orbit

2
n 2
0
mv 1 (e)(Ze) nh
. and L mvr
t 4 r 2
? ? ?
? ? ?

After solving these two equations we will get following results
(a)
2
n1
r and r
Zm
??
(b)
0
Z
v and v m
n
??
(c)
2
2
Z
E and E m
n
??
(d)
H
1
r 0.529 ? Å

(e)
H6
1
c
v 2.2 10 m / s
137
? ? ?
(f)
H
1
E 13.6eV ??
(g) K = |E| and U = 2E
(iii) Energy of a photon
hc
E ?
?
.
After substituting values of h and c, we get

o
12375
E(in eV)
(in A)
?
?

(iv) Hydrogen spectrum

(v) In first orbit of hydrogen atom,
E = -13.6eV, K = 13.6eV and U=-272eV
Similarly, in second orbit,
E = -3.4 eV, K = 3.4 eV and U = -6.8 eV
(vi) n = 1 is ground state, n = 2 is first excited state and n = 3 is second excited state.
(vii) If an electron jumps from n
1
state to n
2
(< n
1
) state, then wavelength of photon
emitted in this process will be given by,

12
nn
hc
EE ??
?

or
12
o
nn
12375
(in A)
(E E )in eV
??
?

Here,
1
2
n 2
1
13.6 Z
E eV
n
??
?
and
2
2
n 2
2
13.6 Z
E eV
n
??
?
(viii) Rhc = 1 Rydberg = 13.6 eV
(ix) R = Rydberg constant = 1.09 × 10
7
m
-1

(x) As n increases
(a) Angular momentum, time period, potential energy and total energy will
increase.
(b) Speed, kinetic energy and frequency will decrease.
(xi) Total number of emission lines from nth state to ground state are,
n(n 1)
2
?
.
2.  Matter Wave or de-Broglie Wave
(i) Every matter particle having some linear momentum is associated with a wave called
matter wave or de-Broglie wave.
(ii) Wavelength of this wave is given by

h h h h
mv 2Km 2qVm
? ? ? ? ?
?

(iii) For an electron,
o
150
(in A)
V(in volt)
??
3.  Electromagnetic Waves
(i) EM-waves have dual nature. Particle as well as a wave.
(ii) Interference, diffraction or polarization can be explained by wave nature of EM
waves. Photoelectric effect, Compton effect etc is explained by particle nature of EM
waves.
Page 3

Modern Physics – I
Important Formulae
1.  Bohr's Theory
(i) Bohr's theory is applicable for hydrogen and hydrogen like atoms/ions. For such type
of atoms/ions number of electron is one. Although atomic numbers may be different,
eg,  For
1
H
1
, atomic number Z = 1
For He
+
, atomic number Z =2 and
For Li
+2
, atomic number Z = 3 .
But for all three number of electron is one.
(ii) In nth orbit

2
n 2
0
mv 1 (e)(Ze) nh
. and L mvr
t 4 r 2
? ? ?
? ? ?

After solving these two equations we will get following results
(a)
2
n1
r and r
Zm
??
(b)
0
Z
v and v m
n
??
(c)
2
2
Z
E and E m
n
??
(d)
H
1
r 0.529 ? Å

(e)
H6
1
c
v 2.2 10 m / s
137
? ? ?
(f)
H
1
E 13.6eV ??
(g) K = |E| and U = 2E
(iii) Energy of a photon
hc
E ?
?
.
After substituting values of h and c, we get

o
12375
E(in eV)
(in A)
?
?

(iv) Hydrogen spectrum

(v) In first orbit of hydrogen atom,
E = -13.6eV, K = 13.6eV and U=-272eV
Similarly, in second orbit,
E = -3.4 eV, K = 3.4 eV and U = -6.8 eV
(vi) n = 1 is ground state, n = 2 is first excited state and n = 3 is second excited state.
(vii) If an electron jumps from n
1
state to n
2
(< n
1
) state, then wavelength of photon
emitted in this process will be given by,

12
nn
hc
EE ??
?

or
12
o
nn
12375
(in A)
(E E )in eV
??
?

Here,
1
2
n 2
1
13.6 Z
E eV
n
??
?
and
2
2
n 2
2
13.6 Z
E eV
n
??
?
(viii) Rhc = 1 Rydberg = 13.6 eV
(ix) R = Rydberg constant = 1.09 × 10
7
m
-1

(x) As n increases
(a) Angular momentum, time period, potential energy and total energy will
increase.
(b) Speed, kinetic energy and frequency will decrease.
(xi) Total number of emission lines from nth state to ground state are,
n(n 1)
2
?
.
2.  Matter Wave or de-Broglie Wave
(i) Every matter particle having some linear momentum is associated with a wave called
matter wave or de-Broglie wave.
(ii) Wavelength of this wave is given by

h h h h
mv 2Km 2qVm
? ? ? ? ?
?

(iii) For an electron,
o
150
(in A)
V(in volt)
??
3.  Electromagnetic Waves
(i) EM-waves have dual nature. Particle as well as a wave.
(ii) Interference, diffraction or polarization can be explained by wave nature of EM
waves. Photoelectric effect, Compton effect etc is explained by particle nature of EM
waves.
(iii) E,B and c
??
?
are mutually perpendicular.
(iv) E B c ??
??
?

(v) E and B oscillate in same phase.
eg,   B
x
= B
0
sin( ?t

- ky) then
E
Z
= E
0
sin ( ?t

- ky)
(vi)
12
2 f ,T
f
?
? ? ? ? ?
?

(vii)
0
0
E
c
B
?
(viii) Properties of a photon
(a) E = hf =
hc
?

(b)E (in eV) =
o
12375
(in A) ?

(c) Momentum of photon
Eh
p
c
??
?

(d) Dynamic mass,
2
E
m
c
?
(ix) ?-rays, X-rays, UV rays, visible light, infrared rays, micro waves, radio waves.
In moving from left to right, energy and frequency of wave decrease but wavelength
increases.
(i) These are electromagnetic waves of high energy, high frequency and low wavelength.
(ii) Wavelength of X-rays lies in the range of 1Å to 100 Å.
(iii) Cut off wavelength of X-ray spectrum is given by

o
min
12375
(in A)
V(in volt)
??
(iv) Moseley's law for X-ray spectrum is
v (z b) ??
Here, the constant b depends on the series
b = 1 for K-series and b = 7.4 f or L-series
(v)
Page 4

Modern Physics – I
Important Formulae
1.  Bohr's Theory
(i) Bohr's theory is applicable for hydrogen and hydrogen like atoms/ions. For such type
of atoms/ions number of electron is one. Although atomic numbers may be different,
eg,  For
1
H
1
, atomic number Z = 1
For He
+
, atomic number Z =2 and
For Li
+2
, atomic number Z = 3 .
But for all three number of electron is one.
(ii) In nth orbit

2
n 2
0
mv 1 (e)(Ze) nh
. and L mvr
t 4 r 2
? ? ?
? ? ?

After solving these two equations we will get following results
(a)
2
n1
r and r
Zm
??
(b)
0
Z
v and v m
n
??
(c)
2
2
Z
E and E m
n
??
(d)
H
1
r 0.529 ? Å

(e)
H6
1
c
v 2.2 10 m / s
137
? ? ?
(f)
H
1
E 13.6eV ??
(g) K = |E| and U = 2E
(iii) Energy of a photon
hc
E ?
?
.
After substituting values of h and c, we get

o
12375
E(in eV)
(in A)
?
?

(iv) Hydrogen spectrum

(v) In first orbit of hydrogen atom,
E = -13.6eV, K = 13.6eV and U=-272eV
Similarly, in second orbit,
E = -3.4 eV, K = 3.4 eV and U = -6.8 eV
(vi) n = 1 is ground state, n = 2 is first excited state and n = 3 is second excited state.
(vii) If an electron jumps from n
1
state to n
2
(< n
1
) state, then wavelength of photon
emitted in this process will be given by,

12
nn
hc
EE ??
?

or
12
o
nn
12375
(in A)
(E E )in eV
??
?

Here,
1
2
n 2
1
13.6 Z
E eV
n
??
?
and
2
2
n 2
2
13.6 Z
E eV
n
??
?
(viii) Rhc = 1 Rydberg = 13.6 eV
(ix) R = Rydberg constant = 1.09 × 10
7
m
-1

(x) As n increases
(a) Angular momentum, time period, potential energy and total energy will
increase.
(b) Speed, kinetic energy and frequency will decrease.
(xi) Total number of emission lines from nth state to ground state are,
n(n 1)
2
?
.
2.  Matter Wave or de-Broglie Wave
(i) Every matter particle having some linear momentum is associated with a wave called
matter wave or de-Broglie wave.
(ii) Wavelength of this wave is given by

h h h h
mv 2Km 2qVm
? ? ? ? ?
?

(iii) For an electron,
o
150
(in A)
V(in volt)
??
3.  Electromagnetic Waves
(i) EM-waves have dual nature. Particle as well as a wave.
(ii) Interference, diffraction or polarization can be explained by wave nature of EM
waves. Photoelectric effect, Compton effect etc is explained by particle nature of EM
waves.
(iii) E,B and c
??
?
are mutually perpendicular.
(iv) E B c ??
??
?

(v) E and B oscillate in same phase.
eg,   B
x
= B
0
sin( ?t

- ky) then
E
Z
= E
0
sin ( ?t

- ky)
(vi)
12
2 f ,T
f
?
? ? ? ? ?
?

(vii)
0
0
E
c
B
?
(viii) Properties of a photon
(a) E = hf =
hc
?

(b)E (in eV) =
o
12375
(in A) ?

(c) Momentum of photon
Eh
p
c
??
?

(d) Dynamic mass,
2
E
m
c
?
(ix) ?-rays, X-rays, UV rays, visible light, infrared rays, micro waves, radio waves.
In moving from left to right, energy and frequency of wave decrease but wavelength
increases.
(i) These are electromagnetic waves of high energy, high frequency and low wavelength.
(ii) Wavelength of X-rays lies in the range of 1Å to 100 Å.
(iii) Cut off wavelength of X-ray spectrum is given by

o
min
12375
(in A)
V(in volt)
??
(iv) Moseley's law for X-ray spectrum is
v (z b) ??
Here, the constant b depends on the series
b = 1 for K-series and b = 7.4 f or L-series
(v)
(vi)
(vii)
22
12
1 1 1
(Z b)R
nn
??
? ? ?
??
?
??

Here, n
1
< n
2

(viii) Continuous X-Ray spectrum

Here,
o
min
12375
(in A)
V(in volt)
?? = cut-off wavelength.
(ix)
This is actual spectrum of X-rays including continuous and characteristic X-rays.
5.  Photoelectric Effect
(i) K
max
=
2
max
1
mv
2
=E - W = hf - hf
0
= eV
0
=
0
hc hc
?
??

(ii) Graphs K
max
= hf - W

Slope
1
= Slope
2
= Planck's constant f
01
= Threshold frequency of metal-1
f
02
= Threshold frequency of metal-2
W
1
= Work function of metal-1 and
Page 5

Modern Physics – I
Important Formulae
1.  Bohr's Theory
(i) Bohr's theory is applicable for hydrogen and hydrogen like atoms/ions. For such type
of atoms/ions number of electron is one. Although atomic numbers may be different,
eg,  For
1
H
1
, atomic number Z = 1
For He
+
, atomic number Z =2 and
For Li
+2
, atomic number Z = 3 .
But for all three number of electron is one.
(ii) In nth orbit

2
n 2
0
mv 1 (e)(Ze) nh
. and L mvr
t 4 r 2
? ? ?
? ? ?

After solving these two equations we will get following results
(a)
2
n1
r and r
Zm
??
(b)
0
Z
v and v m
n
??
(c)
2
2
Z
E and E m
n
??
(d)
H
1
r 0.529 ? Å

(e)
H6
1
c
v 2.2 10 m / s
137
? ? ?
(f)
H
1
E 13.6eV ??
(g) K = |E| and U = 2E
(iii) Energy of a photon
hc
E ?
?
.
After substituting values of h and c, we get

o
12375
E(in eV)
(in A)
?
?

(iv) Hydrogen spectrum

(v) In first orbit of hydrogen atom,
E = -13.6eV, K = 13.6eV and U=-272eV
Similarly, in second orbit,
E = -3.4 eV, K = 3.4 eV and U = -6.8 eV
(vi) n = 1 is ground state, n = 2 is first excited state and n = 3 is second excited state.
(vii) If an electron jumps from n
1
state to n
2
(< n
1
) state, then wavelength of photon
emitted in this process will be given by,

12
nn
hc
EE ??
?

or
12
o
nn
12375
(in A)
(E E )in eV
??
?

Here,
1
2
n 2
1
13.6 Z
E eV
n
??
?
and
2
2
n 2
2
13.6 Z
E eV
n
??
?
(viii) Rhc = 1 Rydberg = 13.6 eV
(ix) R = Rydberg constant = 1.09 × 10
7
m
-1

(x) As n increases
(a) Angular momentum, time period, potential energy and total energy will
increase.
(b) Speed, kinetic energy and frequency will decrease.
(xi) Total number of emission lines from nth state to ground state are,
n(n 1)
2
?
.
2.  Matter Wave or de-Broglie Wave
(i) Every matter particle having some linear momentum is associated with a wave called
matter wave or de-Broglie wave.
(ii) Wavelength of this wave is given by

h h h h
mv 2Km 2qVm
? ? ? ? ?
?

(iii) For an electron,
o
150
(in A)
V(in volt)
??
3.  Electromagnetic Waves
(i) EM-waves have dual nature. Particle as well as a wave.
(ii) Interference, diffraction or polarization can be explained by wave nature of EM
waves. Photoelectric effect, Compton effect etc is explained by particle nature of EM
waves.
(iii) E,B and c
??
?
are mutually perpendicular.
(iv) E B c ??
??
?

(v) E and B oscillate in same phase.
eg,   B
x
= B
0
sin( ?t

- ky) then
E
Z
= E
0
sin ( ?t

- ky)
(vi)
12
2 f ,T
f
?
? ? ? ? ?
?

(vii)
0
0
E
c
B
?
(viii) Properties of a photon
(a) E = hf =
hc
?

(b)E (in eV) =
o
12375
(in A) ?

(c) Momentum of photon
Eh
p
c
??
?

(d) Dynamic mass,
2
E
m
c
?
(ix) ?-rays, X-rays, UV rays, visible light, infrared rays, micro waves, radio waves.
In moving from left to right, energy and frequency of wave decrease but wavelength
increases.
(i) These are electromagnetic waves of high energy, high frequency and low wavelength.
(ii) Wavelength of X-rays lies in the range of 1Å to 100 Å.
(iii) Cut off wavelength of X-ray spectrum is given by

o
min
12375
(in A)
V(in volt)
??
(iv) Moseley's law for X-ray spectrum is
v (z b) ??
Here, the constant b depends on the series
b = 1 for K-series and b = 7.4 f or L-series
(v)
(vi)
(vii)
22
12
1 1 1
(Z b)R
nn
??
? ? ?
??
?
??

Here, n
1
< n
2

(viii) Continuous X-Ray spectrum

Here,
o
min
12375
(in A)
V(in volt)
?? = cut-off wavelength.
(ix)
This is actual spectrum of X-rays including continuous and characteristic X-rays.
5.  Photoelectric Effect
(i) K
max
=
2
max
1
mv
2
=E - W = hf - hf
0
= eV
0
=
0
hc hc
?
??

(ii) Graphs K
max
= hf - W

Slope
1
= Slope
2
= Planck's constant f
01
= Threshold frequency of metal-1
f
02
= Threshold frequency of metal-2
W
1
= Work function of metal-1 and
W
2
= Work function of metal-2
From the equation K
max
=hf -W, we can see that K
max
versus f graph is a straight line with
positive slope h (a universal constant) and negative intercept W (varies metal to metal).

Slope
1
= Slope
2
=
h
e
= a universal constant
From the equation,
0
hW
Vf
ee
??
??
??
??
,

we can see that stopping potential V
0
versus
frequency f graph is a straight line with positive slope
h
e
and negative slope
W
e
.
(iii) Threshold wavelength
0
hc
W
??
(iv) Threshold frequency
0
W
f
h
?
(v) Photoelectric current versus potential graph

Saturation current I
2
depends upon number of photons incident on metallic plate per sec
and stopping potential depends on the frequency of incident photons.
(vi) For photoemission to take place,
E ? W, ? = ?
0

and
(vii) Kinetic energy of photoelectrons varies between 0 and K
max
.
```
Offer running on EduRev: Apply code STAYHOME200 to get INR 200 off on our premium plan EduRev Infinity!

210 docs

,

,

,

,

,

,

,

,

,

,

,

,

,

,

,

,

,

,

,

,

,

;