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**a)****11.86 Ω****b)****10 Ω****c)****25 Ω****d)****11.18 Ω**

*As ladder is infinitely long. so choose repeating element and mark it as Req /Rnet.*

here choose 10 ohm- 10 ohm as repeating.

then connect that resistance in series with the element which chosen as Repeating ie across CD. Now solve first series combination

R1=(10 Req)

then connect that solved resistance in parallel across AB solve parallel combination

R2=(100 10Req)/(20 Req)

and equate with Req as (Resistance across AB=Resistance across CD).

Req=(100 10Req)/(20 Req)

solve this for Req you get quadratic equation

By solving we get Req=6.18ohm

Now solve the series combination to get final euivalant Resistance

final Req = 5 6.18=11.18 ohms

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