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Integrated Rate Law Expression Of First Order - Chemical Kinetics Video Lecture - Chemistry

FAQs on Integrated Rate Law Expression Of First Order - Chemical Kinetics Video Lecture - Chemistry

1. What is the integrated rate law expression for a first-order reaction?
Ans. The integrated rate law expression for a first-order reaction is given by the equation: ln([A]t/[A]0) = -kt, where [A]t is the concentration of the reactant at time t, [A]0 is the initial concentration of the reactant, k is the rate constant, and t is the time.
2. How do you determine the rate constant in a first-order reaction using the integrated rate law expression?
Ans. To determine the rate constant in a first-order reaction using the integrated rate law expression, you can rearrange the equation as follows: k = -ln([A]t/[A]0)/t. Simply substitute the values of [A]t, [A]0, and t from an experimental data set into this equation to calculate the rate constant.
3. Can the integrated rate law expression for a first-order reaction be used to determine the reaction order?
Ans. No, the integrated rate law expression for a first-order reaction cannot be used to determine the reaction order. The integrated rate law expression itself assumes that the reaction is first-order. The determination of the reaction order requires analyzing the concentration-time data for multiple experiments with varying initial concentrations.
4. What are the units of the rate constant in a first-order reaction?
Ans. The units of the rate constant in a first-order reaction depend on the overall order of the reaction. For a first-order reaction, the units of the rate constant are usually expressed as reciprocal time units, such as s^-1 or min^-1.
5. How does the half-life of a first-order reaction change with the initial concentration of the reactant?
Ans. The half-life of a first-order reaction is independent of the initial concentration of the reactant. In a first-order reaction, the half-life remains constant regardless of the initial concentration. This means that regardless of how much reactant you start with, it will always take the same amount of time for the concentration to decrease to half of its initial value.
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