Introduction to Algebra - Objective Type Questions Class 6 Notes | EduRev

Mathematics (Maths) Class 6

Class 6 : Introduction to Algebra - Objective Type Questions Class 6 Notes | EduRev

 Page 1


 
 
 
 
 
 
Objective Type Questions                                                  PAGE: 8.13 
Mark the correct alternative in each of the following: 
 
1. 5 more than twice a number x is written as 
(a) 5 + x + 2 
(b) 2x + 5 
(c) 2x - 5 
(d) 5x + 2 
Solution: 
 
The option (b) is correct answer. 
5 more than twice a number x is written as 2x + 5. 
 
2. The quotient of x by 2 is added to 5 is written as 
(a) x/2 + 5 
(b) 2/x+5 
(c) (x+2)/ 5 
(d) x/ (2+5) 
Solution: 
 
The option (a) is correct answer. 
The quotient of x by 2 is added to 5 is written as x/2 + 5. 
 
3. The quotient of x by 3 is multiplied by y is written as 
(a) x/3y 
(b) 3x/y 
(c) 3y/x 
(d) xy/3 
Solution: 
 
The option (d) is correct answer. 
It can be written as 
x/3 × y = xy/3 
 
4. 9 taken away from the sum of x and y is 
(a) x + y - 9 
(b) 9 - (x+y) 
(c) x+y/ 9 
(d) 9/ x+y 
Solution: 
 
The option (a) is correct answer. 
9 taken away from the sum of x and y is x + y – 9. 
 
5. The quotient of x by y added to the product of x and y is written as 
(a) x/y + xy 
(b) y/x + xy 
(c) xy+x/ y 
(d) xy+y/ x 
Page 2


 
 
 
 
 
 
Objective Type Questions                                                  PAGE: 8.13 
Mark the correct alternative in each of the following: 
 
1. 5 more than twice a number x is written as 
(a) 5 + x + 2 
(b) 2x + 5 
(c) 2x - 5 
(d) 5x + 2 
Solution: 
 
The option (b) is correct answer. 
5 more than twice a number x is written as 2x + 5. 
 
2. The quotient of x by 2 is added to 5 is written as 
(a) x/2 + 5 
(b) 2/x+5 
(c) (x+2)/ 5 
(d) x/ (2+5) 
Solution: 
 
The option (a) is correct answer. 
The quotient of x by 2 is added to 5 is written as x/2 + 5. 
 
3. The quotient of x by 3 is multiplied by y is written as 
(a) x/3y 
(b) 3x/y 
(c) 3y/x 
(d) xy/3 
Solution: 
 
The option (d) is correct answer. 
It can be written as 
x/3 × y = xy/3 
 
4. 9 taken away from the sum of x and y is 
(a) x + y - 9 
(b) 9 - (x+y) 
(c) x+y/ 9 
(d) 9/ x+y 
Solution: 
 
The option (a) is correct answer. 
9 taken away from the sum of x and y is x + y – 9. 
 
5. The quotient of x by y added to the product of x and y is written as 
(a) x/y + xy 
(b) y/x + xy 
(c) xy+x/ y 
(d) xy+y/ x 
 
 
 
 
 
 
Solution: 
The option (a) is correct answer. 
The quotient of x by y added to the product of x and y is written as x/y + xy. 
 
6. a
2
b
3
 × 2ab
2
 is equal to 
(a) 2a
3
b
4
 
(b) 2a
3
b
5
 
(c) 2ab 
(d) a
3
b
5
 
Solution: 
 
The option (b) is correct answer. 
It can be written as 
a
2
b
3
 × 2ab
2
 = 2a
2
 × a × b
3
 × b
2
 = 2a
3
b
5
. 
 
7. 4a
2
b
3
 × 3ab
2
 × 5a
3
b is equal to 
(a) 60a
3
b
5
 
(b) 60a
6
b
5
 
(c) 60a
6
b
6
 
(d) a
6
b
6
 
Solution: 
 
The option (c) is correct answer. 
It can be written as 
4a
2
b
3
 × 3ab
2
 × 5a
3
b = 4 × 3 × 5 × a
2
 × a × a
3
 × b
3
 × b
2
 × b = 60a
6
b
6
 
 
8. If 2x
2
y and 3xy
2
 denote the length and breadth of a rectangle, then its area is 
(a) 6xy 
(b) 6x
2
y
2
 
(c) 6x
3
y
3
 
(d) x
3
y
3
 
Solution: 
 
The option (c) is correct answer. 
We know that area of a rectangle = length × breadth  
By substituting the values 
Area = 2x
2
y × 3xy
2
 = 6x
3
y
3
 
 
9. In a room there are x
2
 rows of chairs and each two contains 2x
2
 chairs. The total number of chairs in the 
room is 
(a) 2x
3
 
(b) 2x
4
 
(c) x
4
 
(d) x
4
/2 
Solution: 
 
The option (b) is correct answer. 
We know that 
Total number of chairs in the room = Number of rows × Number of chairs  
By substituting the values 
Page 3


 
 
 
 
 
 
Objective Type Questions                                                  PAGE: 8.13 
Mark the correct alternative in each of the following: 
 
1. 5 more than twice a number x is written as 
(a) 5 + x + 2 
(b) 2x + 5 
(c) 2x - 5 
(d) 5x + 2 
Solution: 
 
The option (b) is correct answer. 
5 more than twice a number x is written as 2x + 5. 
 
2. The quotient of x by 2 is added to 5 is written as 
(a) x/2 + 5 
(b) 2/x+5 
(c) (x+2)/ 5 
(d) x/ (2+5) 
Solution: 
 
The option (a) is correct answer. 
The quotient of x by 2 is added to 5 is written as x/2 + 5. 
 
3. The quotient of x by 3 is multiplied by y is written as 
(a) x/3y 
(b) 3x/y 
(c) 3y/x 
(d) xy/3 
Solution: 
 
The option (d) is correct answer. 
It can be written as 
x/3 × y = xy/3 
 
4. 9 taken away from the sum of x and y is 
(a) x + y - 9 
(b) 9 - (x+y) 
(c) x+y/ 9 
(d) 9/ x+y 
Solution: 
 
The option (a) is correct answer. 
9 taken away from the sum of x and y is x + y – 9. 
 
5. The quotient of x by y added to the product of x and y is written as 
(a) x/y + xy 
(b) y/x + xy 
(c) xy+x/ y 
(d) xy+y/ x 
 
 
 
 
 
 
Solution: 
The option (a) is correct answer. 
The quotient of x by y added to the product of x and y is written as x/y + xy. 
 
6. a
2
b
3
 × 2ab
2
 is equal to 
(a) 2a
3
b
4
 
(b) 2a
3
b
5
 
(c) 2ab 
(d) a
3
b
5
 
Solution: 
 
The option (b) is correct answer. 
It can be written as 
a
2
b
3
 × 2ab
2
 = 2a
2
 × a × b
3
 × b
2
 = 2a
3
b
5
. 
 
7. 4a
2
b
3
 × 3ab
2
 × 5a
3
b is equal to 
(a) 60a
3
b
5
 
(b) 60a
6
b
5
 
(c) 60a
6
b
6
 
(d) a
6
b
6
 
Solution: 
 
The option (c) is correct answer. 
It can be written as 
4a
2
b
3
 × 3ab
2
 × 5a
3
b = 4 × 3 × 5 × a
2
 × a × a
3
 × b
3
 × b
2
 × b = 60a
6
b
6
 
 
8. If 2x
2
y and 3xy
2
 denote the length and breadth of a rectangle, then its area is 
(a) 6xy 
(b) 6x
2
y
2
 
(c) 6x
3
y
3
 
(d) x
3
y
3
 
Solution: 
 
The option (c) is correct answer. 
We know that area of a rectangle = length × breadth  
By substituting the values 
Area = 2x
2
y × 3xy
2
 = 6x
3
y
3
 
 
9. In a room there are x
2
 rows of chairs and each two contains 2x
2
 chairs. The total number of chairs in the 
room is 
(a) 2x
3
 
(b) 2x
4
 
(c) x
4
 
(d) x
4
/2 
Solution: 
 
The option (b) is correct answer. 
We know that 
Total number of chairs in the room = Number of rows × Number of chairs  
By substituting the values 
 
 
Total number of chairs in the room = x
2
 × 2x
2
 = 2x
4
 
10. a
3
 × 2a
2
b × 3ab
5
 is equal to
(a) a
6
b
6
(b) 23a
6
b
6
(c) 6a
6
b
6
(d) None of these
Solution:
The option (c) is correct answer. 
It can be written as 
a
3
 × 2a
2
b × 3ab
5
 = 2 × 3 × a
3
 × a
2
 × a × b × b
5
 = 6a
6
b
6
 
Read More
Offer running on EduRev: Apply code STAYHOME200 to get INR 200 off on our premium plan EduRev Infinity!

Related Searches

Previous Year Questions with Solutions

,

Exam

,

Summary

,

Introduction to Algebra - Objective Type Questions Class 6 Notes | EduRev

,

ppt

,

mock tests for examination

,

Introduction to Algebra - Objective Type Questions Class 6 Notes | EduRev

,

shortcuts and tricks

,

Free

,

Introduction to Algebra - Objective Type Questions Class 6 Notes | EduRev

,

practice quizzes

,

video lectures

,

Semester Notes

,

study material

,

MCQs

,

pdf

,

Extra Questions

,

Sample Paper

,

Viva Questions

,

Objective type Questions

,

past year papers

,

Important questions

;