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Page 1 JEE Advanced Previous Year Questions (2021-2023): General Organic Chemistry 2023 Single Correct Type JEE Advanced 2023 Paper 1 Online Q1. Match the reactions in List-I with the features of their products in List-II and choose the correct option. Page 2 JEE Advanced Previous Year Questions (2021-2023): General Organic Chemistry 2023 Single Correct Type JEE Advanced 2023 Paper 1 Online Q1. Match the reactions in List-I with the features of their products in List-II and choose the correct option. ?? . ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? B. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? C. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? D. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? Ans: (B) Page 3 JEE Advanced Previous Year Questions (2021-2023): General Organic Chemistry 2023 Single Correct Type JEE Advanced 2023 Paper 1 Online Q1. Match the reactions in List-I with the features of their products in List-II and choose the correct option. ?? . ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? B. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? C. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? D. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? Ans: (B) 2021 Numerical Type JEE Advanced 2021 Paper 1 Online Q1. The maximum number of possible isomers (including stereoisomers) which may be formed on mono-bromination of 1-methylcyclohex-1-ene using ???? ?? and ???? light is Ans: 13 Monobromination of 1-methyl cyclohex-1-ene in presence of UV-light gives following products ( 1 achiral and 6 optically active (*) compounds). So, total 13 products are formed ( 1 + 6 + 6 enantiomers) Radicals formed are Page 4 JEE Advanced Previous Year Questions (2021-2023): General Organic Chemistry 2023 Single Correct Type JEE Advanced 2023 Paper 1 Online Q1. Match the reactions in List-I with the features of their products in List-II and choose the correct option. ?? . ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? B. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? C. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? D. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? Ans: (B) 2021 Numerical Type JEE Advanced 2021 Paper 1 Online Q1. The maximum number of possible isomers (including stereoisomers) which may be formed on mono-bromination of 1-methylcyclohex-1-ene using ???? ?? and ???? light is Ans: 13 Monobromination of 1-methyl cyclohex-1-ene in presence of UV-light gives following products ( 1 achiral and 6 optically active (*) compounds). So, total 13 products are formed ( 1 + 6 + 6 enantiomers) Radicals formed are JEE Advanced 2021 Paper 2 Online Q2. The amount of energy required to break a bond is same as the amount of energy released when the same bond is formed. In gaseous state, the energy required for homolytic cleavage of a bond is called Bond Dissociation Energy (BDE) or Bond Strength. BDE is affected by s- character of the bond and the stability of the radicals formed. Shorter bonds are typically stronger bonds. BDEs for some bonds are given below : Correct match of the ?? - ?? bonds (shown in bold) in Column ?? with their BDE in Column ?? is Column J Molecule Column K BDE (kcal mol -?? ) (P) ?? - ?? ?? (???? ?? ) ?? (i) 132 (Q) ?? - ???? ?? ???? (ii) 110 (R) ?? - ???? = ???? ?? (iii) 95 (S) ?? - ?? = ???? (iv) 88 Page 5 JEE Advanced Previous Year Questions (2021-2023): General Organic Chemistry 2023 Single Correct Type JEE Advanced 2023 Paper 1 Online Q1. Match the reactions in List-I with the features of their products in List-II and choose the correct option. ?? . ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? B. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? C. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? D. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? Ans: (B) 2021 Numerical Type JEE Advanced 2021 Paper 1 Online Q1. The maximum number of possible isomers (including stereoisomers) which may be formed on mono-bromination of 1-methylcyclohex-1-ene using ???? ?? and ???? light is Ans: 13 Monobromination of 1-methyl cyclohex-1-ene in presence of UV-light gives following products ( 1 achiral and 6 optically active (*) compounds). So, total 13 products are formed ( 1 + 6 + 6 enantiomers) Radicals formed are JEE Advanced 2021 Paper 2 Online Q2. The amount of energy required to break a bond is same as the amount of energy released when the same bond is formed. In gaseous state, the energy required for homolytic cleavage of a bond is called Bond Dissociation Energy (BDE) or Bond Strength. BDE is affected by s- character of the bond and the stability of the radicals formed. Shorter bonds are typically stronger bonds. BDEs for some bonds are given below : Correct match of the ?? - ?? bonds (shown in bold) in Column ?? with their BDE in Column ?? is Column J Molecule Column K BDE (kcal mol -?? ) (P) ?? - ?? ?? (???? ?? ) ?? (i) 132 (Q) ?? - ???? ?? ???? (ii) 110 (R) ?? - ???? = ???? ?? (iii) 95 (S) ?? - ?? = ???? (iv) 88 A. P - iii, Q - iv, R - ii, S - i B. P - i, Q - ii, R - iii, S - iv C. P - iii, Q - ii, R - i, S - iv D. P - ii, Q - i, R - iv, S – ii Ans: (A) A more stable radical means lesser the bond dissociation energy. Radicals formed are Radical formed from Q(PhCH 2 - H) is most stable due to resonance. Stability of free radical decreases with increase in % s-character. P radical ? sp 3 ? % s-character 25% R radical ? sp 2 ? % s-character 33% S radical ? sp ? % s-character 50% Thus, order of stability of free radical is Q > P > R > S Order of bond dissociation energy is ?? > ?? > ?? > ?? JEE Advanced 2021 Paper 2 Online Q3.The amount of energy required to break a bond is same as the amount of energy released when the same bond is formed. In gaseous state, the energy required for homolytic cleavage of a bond is called Bond Dissociation Energy (BDE) or Bond Strength. BDE is affected by s- character of the bond and the stability of the radicals formed. Shorter bonds are typically stronger bonds. BDEs for some bonds are given below : ???? - ???? (?? ) ? ???? (?? ) · + ???? (?? ) · ?? ?? ° = ???????????? ?????? -??Read More
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