JEE Advanced Previous Year Questions (2021-2023): Ray Optics and Optical Instruments | Physics for JEE Main & Advanced PDF Download

 Page 1


 
2023 
Numerical Type  
JEE Advanced 2023 Paper 1 Online 
Q1: An optical arrangement consists of two concave mirrors ?? ?? and ?? ?? , and a 
convex lens ?? with a common principal axis, as shown in the figure. The focal 
length of ?? is ???? ???? . The radii of curvature of ?? ?? and ?? ?? are ???? ???? and ???? ???? , 
respectively. The distance between ?? and ?? ?? is ???? ???? . A point object ?? is placed 
at the mid-point between ?? and ?? ?? on the axis. When the distance between ?? and 
?? ?? is /?? ???? , one of the images coincides with ?? . The value of ?? is 
 
Ans: 80 or 150 or 220 
Case-1 : if ?? st 
 refraction on lens : 
 
Page 2


 
2023 
Numerical Type  
JEE Advanced 2023 Paper 1 Online 
Q1: An optical arrangement consists of two concave mirrors ?? ?? and ?? ?? , and a 
convex lens ?? with a common principal axis, as shown in the figure. The focal 
length of ?? is ???? ???? . The radii of curvature of ?? ?? and ?? ?? are ???? ???? and ???? ???? , 
respectively. The distance between ?? and ?? ?? is ???? ???? . A point object ?? is placed 
at the mid-point between ?? and ?? ?? on the axis. When the distance between ?? and 
?? ?? is /?? ???? , one of the images coincides with ?? . The value of ?? is 
 
Ans: 80 or 150 or 220 
Case-1 : if ?? st 
 refraction on lens : 
 
Given that the object is positioned at the focal point, the resulting light rays will transition 
to a parallel alignment. 
Upon the first reflection at Mirror ?? 1
 : 
As the incoming light rays are parallel, the resultant image will be formed at the focal 
point. 
II  
nd 
 refraction from L: - 
u = -( d - 10) 
f = 10 cm 
1
v
-
1
?? =
1
f
 
1
v
+
1
 d - 10
=
1
10
 
1
v
=
1
10
-
1
( d - 10)
 
This ?? will be object for ?? 2
, and image should be at 10 cm 
-
1
( 20 - ?? )
-
1
10
= -
1
12
 
1
12
-
1
10
=
1
20 - ?? 
-
2
120
=
1
20 - ?? 
20 - ?? = -60 
?? = 80 cm 
From equation (i), we get 
1
80
=
1
10
-
1
?? - 10
 
1
?? - 10
=
1
10
-
1
80
 
1
?? - 10
=
80 - 10
800
=
70
800
 
?? - 10 =
80
7
? ?? = 10 +
80
7
=
150
7
 
Page 3


 
2023 
Numerical Type  
JEE Advanced 2023 Paper 1 Online 
Q1: An optical arrangement consists of two concave mirrors ?? ?? and ?? ?? , and a 
convex lens ?? with a common principal axis, as shown in the figure. The focal 
length of ?? is ???? ???? . The radii of curvature of ?? ?? and ?? ?? are ???? ???? and ???? ???? , 
respectively. The distance between ?? and ?? ?? is ???? ???? . A point object ?? is placed 
at the mid-point between ?? and ?? ?? on the axis. When the distance between ?? and 
?? ?? is /?? ???? , one of the images coincides with ?? . The value of ?? is 
 
Ans: 80 or 150 or 220 
Case-1 : if ?? st 
 refraction on lens : 
 
Given that the object is positioned at the focal point, the resulting light rays will transition 
to a parallel alignment. 
Upon the first reflection at Mirror ?? 1
 : 
As the incoming light rays are parallel, the resultant image will be formed at the focal 
point. 
II  
nd 
 refraction from L: - 
u = -( d - 10) 
f = 10 cm 
1
v
-
1
?? =
1
f
 
1
v
+
1
 d - 10
=
1
10
 
1
v
=
1
10
-
1
( d - 10)
 
This ?? will be object for ?? 2
, and image should be at 10 cm 
-
1
( 20 - ?? )
-
1
10
= -
1
12
 
1
12
-
1
10
=
1
20 - ?? 
-
2
120
=
1
20 - ?? 
20 - ?? = -60 
?? = 80 cm 
From equation (i), we get 
1
80
=
1
10
-
1
?? - 10
 
1
?? - 10
=
1
10
-
1
80
 
1
?? - 10
=
80 - 10
800
=
70
800
 
?? - 10 =
80
7
? ?? = 10 +
80
7
=
150
7
 
?? = 150 
Case-2 : If 1
st 
 reflection on mirror ?? 2
 : 
 
For m
2
 
1
 V
1
+
1
-10
=
1
-12
 
V
1
= 60 cm 
Then refraction on lens L 
u
2
= 80 cm 
1
 V
2
-
1
-60
=
1
10
 
V
2
=
80
7
 
Then reflection on m
2
 
Either ?? 2
 is at centre (normal incidence) 
d =
220
7
 
n
7
=
220
7
 
n = 220 
?? 2
 is at pole of ?? 2
 
Page 4


 
2023 
Numerical Type  
JEE Advanced 2023 Paper 1 Online 
Q1: An optical arrangement consists of two concave mirrors ?? ?? and ?? ?? , and a 
convex lens ?? with a common principal axis, as shown in the figure. The focal 
length of ?? is ???? ???? . The radii of curvature of ?? ?? and ?? ?? are ???? ???? and ???? ???? , 
respectively. The distance between ?? and ?? ?? is ???? ???? . A point object ?? is placed 
at the mid-point between ?? and ?? ?? on the axis. When the distance between ?? and 
?? ?? is /?? ???? , one of the images coincides with ?? . The value of ?? is 
 
Ans: 80 or 150 or 220 
Case-1 : if ?? st 
 refraction on lens : 
 
Given that the object is positioned at the focal point, the resulting light rays will transition 
to a parallel alignment. 
Upon the first reflection at Mirror ?? 1
 : 
As the incoming light rays are parallel, the resultant image will be formed at the focal 
point. 
II  
nd 
 refraction from L: - 
u = -( d - 10) 
f = 10 cm 
1
v
-
1
?? =
1
f
 
1
v
+
1
 d - 10
=
1
10
 
1
v
=
1
10
-
1
( d - 10)
 
This ?? will be object for ?? 2
, and image should be at 10 cm 
-
1
( 20 - ?? )
-
1
10
= -
1
12
 
1
12
-
1
10
=
1
20 - ?? 
-
2
120
=
1
20 - ?? 
20 - ?? = -60 
?? = 80 cm 
From equation (i), we get 
1
80
=
1
10
-
1
?? - 10
 
1
?? - 10
=
1
10
-
1
80
 
1
?? - 10
=
80 - 10
800
=
70
800
 
?? - 10 =
80
7
? ?? = 10 +
80
7
=
150
7
 
?? = 150 
Case-2 : If 1
st 
 reflection on mirror ?? 2
 : 
 
For m
2
 
1
 V
1
+
1
-10
=
1
-12
 
V
1
= 60 cm 
Then refraction on lens L 
u
2
= 80 cm 
1
 V
2
-
1
-60
=
1
10
 
V
2
=
80
7
 
Then reflection on m
2
 
Either ?? 2
 is at centre (normal incidence) 
d =
220
7
 
n
7
=
220
7
 
n = 220 
?? 2
 is at pole of ?? 2
 
d -
80
7
= 0 
d =
80
7
 
n
7
=
80
7
 
n = 80 
 
 
 
 
 
 
 
 
 
 
 
 
Page 5


 
2023 
Numerical Type  
JEE Advanced 2023 Paper 1 Online 
Q1: An optical arrangement consists of two concave mirrors ?? ?? and ?? ?? , and a 
convex lens ?? with a common principal axis, as shown in the figure. The focal 
length of ?? is ???? ???? . The radii of curvature of ?? ?? and ?? ?? are ???? ???? and ???? ???? , 
respectively. The distance between ?? and ?? ?? is ???? ???? . A point object ?? is placed 
at the mid-point between ?? and ?? ?? on the axis. When the distance between ?? and 
?? ?? is /?? ???? , one of the images coincides with ?? . The value of ?? is 
 
Ans: 80 or 150 or 220 
Case-1 : if ?? st 
 refraction on lens : 
 
Given that the object is positioned at the focal point, the resulting light rays will transition 
to a parallel alignment. 
Upon the first reflection at Mirror ?? 1
 : 
As the incoming light rays are parallel, the resultant image will be formed at the focal 
point. 
II  
nd 
 refraction from L: - 
u = -( d - 10) 
f = 10 cm 
1
v
-
1
?? =
1
f
 
1
v
+
1
 d - 10
=
1
10
 
1
v
=
1
10
-
1
( d - 10)
 
This ?? will be object for ?? 2
, and image should be at 10 cm 
-
1
( 20 - ?? )
-
1
10
= -
1
12
 
1
12
-
1
10
=
1
20 - ?? 
-
2
120
=
1
20 - ?? 
20 - ?? = -60 
?? = 80 cm 
From equation (i), we get 
1
80
=
1
10
-
1
?? - 10
 
1
?? - 10
=
1
10
-
1
80
 
1
?? - 10
=
80 - 10
800
=
70
800
 
?? - 10 =
80
7
? ?? = 10 +
80
7
=
150
7
 
?? = 150 
Case-2 : If 1
st 
 reflection on mirror ?? 2
 : 
 
For m
2
 
1
 V
1
+
1
-10
=
1
-12
 
V
1
= 60 cm 
Then refraction on lens L 
u
2
= 80 cm 
1
 V
2
-
1
-60
=
1
10
 
V
2
=
80
7
 
Then reflection on m
2
 
Either ?? 2
 is at centre (normal incidence) 
d =
220
7
 
n
7
=
220
7
 
n = 220 
?? 2
 is at pole of ?? 2
 
d -
80
7
= 0 
d =
80
7
 
n
7
=
80
7
 
n = 80 
 
 
 
 
 
 
 
 
 
 
 
 
2022 
JEE Advanced 2022 Paper 2 Online 
Q1. Consider a configuration of ?? identical units, each consisting of three layers. 
The first layer is a column of air of height ?? =
?? ?? ???? , and the second and third 
layers are of equal thickness ?? = 
v ?? -?? ?? ???? , and refractive indices ?? ?? = v
?? ?? and 
?? ?? = v ?? , respectively. A light source 0 is placed on the top of the first unit, as 
shown in the figure. A ray of light from 0 is incident on the second layer of the first 
unit at an angle of ?? = ????
°
 to the normal. For a specific value of ?? , the ray of light 
emerges from the bottom of the configuration at a distance ?? =
?? v ?? ???? , as shown in 
the figure. The value of ?? is 
 
Ans: 4