JEE Main 2020 Answer Key Chemistry - Evening Shift (08-01-2020) JEE Notes | EduRev

JEE : JEE Main 2020 Answer Key Chemistry - Evening Shift (08-01-2020) JEE Notes | EduRev

 Page 1


      
 
      
    
    
     
 
                       
 
 
 
PAGE # 1 
 
 
PART : CHEMISTRY 
 
SECTION – 1 : (Maximum Marks : 80) 
Straight Objective Type   (lh/ks oLrqfu"B izdkj) 
This section contains 20 multiple choice questions. Each question has 4 choices (1), (2), (3) and (4) for its 
answer, out of which Only One is correct. 
bl [k.M esa 20 cgq&fodYih iz'u gSaA izR;sd iz'u ds 4 fodYi (1), (2), (3) rFkk (4) gSa] ftuesa ls flQZ ,d lgh gSA 
 
1. Correct bond energy order of following is- 
 fuEu dk lgh cU/k ÅtkZ Øe gS & 
 (1) C –Cl > C –Br > C – ? > C –F     (2) C –F < C –Cl < C –Br < C – ?   
 (3) C –F > C –Cl > C –Br > C – ? ? ? ? (4) C – ? < C –Br < C –F < C –Cl  
Ans. (3)      
Sol. Bond energy ? 
length Bond
1
   
 cU/k ÅtkZ ? 
yEckbZ cU/k
1
  
 
2.  Determine Bohr's radius of Li
2+
 ion for n = 2. Given (Bohr's radius of H-atom = a0)  
 n = 2 ds fy, Li
2+
 vk;u dh cksgj ÅtkZ dk fu/kkZj.k dhft,A fn;k gS (H-ijek.kq dh cksgj f=kT;k = a0) 
 (1) 
4
a 3
0
  (2) 
3
a 4
0
  (3) 
3
a
0
   (4) 
9
a 16
0
  
Ans. (2)  
Sol. r = 
Z
n a
2
0
  
 For Li
2+
 ds fy, r = 
3
) 2 ( a
2
0
 = 
3
a 4
0
  
 
3. Given the following reaction sequence  
  
 
A +N2 nitride  
(B) 
H2O 
NH3 
CuSO4 
Blue Colour 
 
 A & B are respectively  
fuEu vfHkfØ;k vuqØe fn;k x;k gS  
  
 
A +N2 ukbVªkbM 
(B) 
H2O 
NH3 
CuSO4 
uhyk jax 
 
 A rFkk B Øe'k% gS 
 (1) Mg, Mg3N2 
 (2) Na Na3N 
 (3) Mg Mg(NO3)2 
(4) Na NaNO3  
Ans. (1) 
Sol. 
2
HO
2 3 2 2 3
3Mg N Mg N Mg(OH) NH
(B)
? ? ? ? ? ? ? ? ?
 
 
Page 2


      
 
      
    
    
     
 
                       
 
 
 
PAGE # 1 
 
 
PART : CHEMISTRY 
 
SECTION – 1 : (Maximum Marks : 80) 
Straight Objective Type   (lh/ks oLrqfu"B izdkj) 
This section contains 20 multiple choice questions. Each question has 4 choices (1), (2), (3) and (4) for its 
answer, out of which Only One is correct. 
bl [k.M esa 20 cgq&fodYih iz'u gSaA izR;sd iz'u ds 4 fodYi (1), (2), (3) rFkk (4) gSa] ftuesa ls flQZ ,d lgh gSA 
 
1. Correct bond energy order of following is- 
 fuEu dk lgh cU/k ÅtkZ Øe gS & 
 (1) C –Cl > C –Br > C – ? > C –F     (2) C –F < C –Cl < C –Br < C – ?   
 (3) C –F > C –Cl > C –Br > C – ? ? ? ? (4) C – ? < C –Br < C –F < C –Cl  
Ans. (3)      
Sol. Bond energy ? 
length Bond
1
   
 cU/k ÅtkZ ? 
yEckbZ cU/k
1
  
 
2.  Determine Bohr's radius of Li
2+
 ion for n = 2. Given (Bohr's radius of H-atom = a0)  
 n = 2 ds fy, Li
2+
 vk;u dh cksgj ÅtkZ dk fu/kkZj.k dhft,A fn;k gS (H-ijek.kq dh cksgj f=kT;k = a0) 
 (1) 
4
a 3
0
  (2) 
3
a 4
0
  (3) 
3
a
0
   (4) 
9
a 16
0
  
Ans. (2)  
Sol. r = 
Z
n a
2
0
  
 For Li
2+
 ds fy, r = 
3
) 2 ( a
2
0
 = 
3
a 4
0
  
 
3. Given the following reaction sequence  
  
 
A +N2 nitride  
(B) 
H2O 
NH3 
CuSO4 
Blue Colour 
 
 A & B are respectively  
fuEu vfHkfØ;k vuqØe fn;k x;k gS  
  
 
A +N2 ukbVªkbM 
(B) 
H2O 
NH3 
CuSO4 
uhyk jax 
 
 A rFkk B Øe'k% gS 
 (1) Mg, Mg3N2 
 (2) Na Na3N 
 (3) Mg Mg(NO3)2 
(4) Na NaNO3  
Ans. (1) 
Sol. 
2
HO
2 3 2 2 3
3Mg N Mg N Mg(OH) NH
(B)
? ? ? ? ? ? ? ? ?
 
 
      
 
      
    
    
     
 
                       
 
 
 
PAGE # 2 
 
 
4. Correct order of magnetic moment (spin only) for the following complexes  
 fuEu ladqyksa ds fy,] pqEcdh; vk?kw.kZ ¼dsoy pØ.k½ dk lgh Øe gS& 
 (a) [Pd(PPh3)2Cl2]    (b) [Ni(CO)4]  
 (c) [Ni(CN)4]
2 –   
   (d) [Ni(H2O)6]
2+
  
 (1) a = b = c < d     (2) a < b < c < d  
 (3) a > b > c > d     (4) a = b > c > d  
Ans. (1)  
Sol. [Pd(PPh3)2Cl2]   Pd
2+
 = 4d
8
   M = 0  
 [Ni(CO)4]    Ni = 3d
8
4s
2
(SFL)  M = 0  
 [Ni(CN)4]
2 –
   Ni
2+
 = 3d
8
 (SFL)  M = 0  
 [Ni(H2O)6]
2+
   Ni
2+
 = 3d
8
 (WFL) 
1 , 1
g
2 , 2 , 2
g 2
e , t So, unpaired electron is 2  
 [Ni(H2O)6]
2+
   Ni
2+
 = 3d
8
 (WFL) 
1 , 1
g
2 , 2 , 2
g 2
e , t blfy,] v;qfXer bysDVªkWu 2 gSA 
M = 8 BM  
 
5. Determine total number of neutrons in three isotopes of hydrogen. 
 gkbMªkstu ds rhu leLFkkfudks esa U;wVªkWuksa dh dqy la[;k dk fu/kkZj.k dhft,A  
 (1) 1   (2) 2   (3) 3    (4) 4 
Ans. (3) 
Sol.    
1
1
H 
2
1
H(D) 
3
1
H(T)  
 Number of neutrons  0 + 1 + 2 = 3 
 U;wVªkWuksa dh la[;k  0 + 1 + 2 = 3 
 
6. 
 
1/T 
log k 
a 
d 
b 
c 
    
Compare Ea (activation energy) for a, b, c and d.  
a, b, c rFkk d ds fy, Ea (lfØ;.k ÅtkZZ) dh rqyuk dhft,A 
 (1) Eb > Ec > Ed > Ea     (2) Ea > Ed > Ec > Eb  
 (3) Ec > Eb > Ea > Ed    (4) Ed > Ea > Eb > Ec  
Ans. (1)  
Sol. log k = log A – 
RT 303 . 2
E
a
  
 slope <+ky = –
R 303 . 2
E
a
 ? Eb > Ec > Ed > Ea  
 
7. Which of the following exhibit both Frenkel & Schottky defect? 
 fuEu esa ls dkSu Ýsady rFkk 'kkWV~dh nksuksa =kqfV iznf'kZr djrk gS\ 
 (1) AgBr  (2) KCl   (3) CsCl  (4) ZnS 
Ans. (1)  
Sol. Only AgBr can exhibit both Schottky and Frenkel defect. 
 dsoy AgBr 'kkWV~dh rFkk Ýsady nksuksa =kqfV iznf'kZr dj ldrk gSA 
     
Page 3


      
 
      
    
    
     
 
                       
 
 
 
PAGE # 1 
 
 
PART : CHEMISTRY 
 
SECTION – 1 : (Maximum Marks : 80) 
Straight Objective Type   (lh/ks oLrqfu"B izdkj) 
This section contains 20 multiple choice questions. Each question has 4 choices (1), (2), (3) and (4) for its 
answer, out of which Only One is correct. 
bl [k.M esa 20 cgq&fodYih iz'u gSaA izR;sd iz'u ds 4 fodYi (1), (2), (3) rFkk (4) gSa] ftuesa ls flQZ ,d lgh gSA 
 
1. Correct bond energy order of following is- 
 fuEu dk lgh cU/k ÅtkZ Øe gS & 
 (1) C –Cl > C –Br > C – ? > C –F     (2) C –F < C –Cl < C –Br < C – ?   
 (3) C –F > C –Cl > C –Br > C – ? ? ? ? (4) C – ? < C –Br < C –F < C –Cl  
Ans. (3)      
Sol. Bond energy ? 
length Bond
1
   
 cU/k ÅtkZ ? 
yEckbZ cU/k
1
  
 
2.  Determine Bohr's radius of Li
2+
 ion for n = 2. Given (Bohr's radius of H-atom = a0)  
 n = 2 ds fy, Li
2+
 vk;u dh cksgj ÅtkZ dk fu/kkZj.k dhft,A fn;k gS (H-ijek.kq dh cksgj f=kT;k = a0) 
 (1) 
4
a 3
0
  (2) 
3
a 4
0
  (3) 
3
a
0
   (4) 
9
a 16
0
  
Ans. (2)  
Sol. r = 
Z
n a
2
0
  
 For Li
2+
 ds fy, r = 
3
) 2 ( a
2
0
 = 
3
a 4
0
  
 
3. Given the following reaction sequence  
  
 
A +N2 nitride  
(B) 
H2O 
NH3 
CuSO4 
Blue Colour 
 
 A & B are respectively  
fuEu vfHkfØ;k vuqØe fn;k x;k gS  
  
 
A +N2 ukbVªkbM 
(B) 
H2O 
NH3 
CuSO4 
uhyk jax 
 
 A rFkk B Øe'k% gS 
 (1) Mg, Mg3N2 
 (2) Na Na3N 
 (3) Mg Mg(NO3)2 
(4) Na NaNO3  
Ans. (1) 
Sol. 
2
HO
2 3 2 2 3
3Mg N Mg N Mg(OH) NH
(B)
? ? ? ? ? ? ? ? ?
 
 
      
 
      
    
    
     
 
                       
 
 
 
PAGE # 2 
 
 
4. Correct order of magnetic moment (spin only) for the following complexes  
 fuEu ladqyksa ds fy,] pqEcdh; vk?kw.kZ ¼dsoy pØ.k½ dk lgh Øe gS& 
 (a) [Pd(PPh3)2Cl2]    (b) [Ni(CO)4]  
 (c) [Ni(CN)4]
2 –   
   (d) [Ni(H2O)6]
2+
  
 (1) a = b = c < d     (2) a < b < c < d  
 (3) a > b > c > d     (4) a = b > c > d  
Ans. (1)  
Sol. [Pd(PPh3)2Cl2]   Pd
2+
 = 4d
8
   M = 0  
 [Ni(CO)4]    Ni = 3d
8
4s
2
(SFL)  M = 0  
 [Ni(CN)4]
2 –
   Ni
2+
 = 3d
8
 (SFL)  M = 0  
 [Ni(H2O)6]
2+
   Ni
2+
 = 3d
8
 (WFL) 
1 , 1
g
2 , 2 , 2
g 2
e , t So, unpaired electron is 2  
 [Ni(H2O)6]
2+
   Ni
2+
 = 3d
8
 (WFL) 
1 , 1
g
2 , 2 , 2
g 2
e , t blfy,] v;qfXer bysDVªkWu 2 gSA 
M = 8 BM  
 
5. Determine total number of neutrons in three isotopes of hydrogen. 
 gkbMªkstu ds rhu leLFkkfudks esa U;wVªkWuksa dh dqy la[;k dk fu/kkZj.k dhft,A  
 (1) 1   (2) 2   (3) 3    (4) 4 
Ans. (3) 
Sol.    
1
1
H 
2
1
H(D) 
3
1
H(T)  
 Number of neutrons  0 + 1 + 2 = 3 
 U;wVªkWuksa dh la[;k  0 + 1 + 2 = 3 
 
6. 
 
1/T 
log k 
a 
d 
b 
c 
    
Compare Ea (activation energy) for a, b, c and d.  
a, b, c rFkk d ds fy, Ea (lfØ;.k ÅtkZZ) dh rqyuk dhft,A 
 (1) Eb > Ec > Ed > Ea     (2) Ea > Ed > Ec > Eb  
 (3) Ec > Eb > Ea > Ed    (4) Ed > Ea > Eb > Ec  
Ans. (1)  
Sol. log k = log A – 
RT 303 . 2
E
a
  
 slope <+ky = –
R 303 . 2
E
a
 ? Eb > Ec > Ed > Ea  
 
7. Which of the following exhibit both Frenkel & Schottky defect? 
 fuEu esa ls dkSu Ýsady rFkk 'kkWV~dh nksuksa =kqfV iznf'kZr djrk gS\ 
 (1) AgBr  (2) KCl   (3) CsCl  (4) ZnS 
Ans. (1)  
Sol. Only AgBr can exhibit both Schottky and Frenkel defect. 
 dsoy AgBr 'kkWV~dh rFkk Ýsady nksuksa =kqfV iznf'kZr dj ldrk gSA 
     
      
 
      
    
    
     
 
                       
 
 
 
PAGE # 3 
 
 
8. Given: fn;k gS&  
 
P4 + NaOH + H2O    
PH3 + A 
HCl 
B 
  
 Basicity of B is:  
 B dh {kkjh;rk gS& 
 (1) 1   (2) 2   (3) 3   (4) 4 
Ans. (1) 
Sol.  
P4 + NaOH + H2O    
PH3 + NaH2PO2 
HCl 
H3PO2 
 
 Basicity {kkjh;rk = 1 
 
9. Which reaction does not occurs in the blast furnace in the metallurgy of Fe 
 dkSulh vfHkfØ;k Fe ds /kkrqdeZ esa okR;k Hkêh esa lEiUu ugha gksrh gS\   
 (a) CaO + SiO2 ? ? ? CaSiO3 
 (b) Fe2O3 + CO ? ? ? Fe3O4 + CO2 
 (c) FeO + SiO2 ? ? ? FeSiO3 
 (d) FeO 
?
? ? ? Fe + 
1
2
O2 
 (1) a & b  (2) a,b & c   (3) c & d  (4) a, b, c, d  
Ans. (3) 
Sol. Theory based lS)kfUrd  
 
10. Correct order of radius of elements is: 
 rRoksa dh f=kT;k dk lgh Øe gS & 
 C, O, F, Cl, Br 
 (1) Br > Cl > C > O > F    (2) Br < Cl < C < O < F 
 (3) Cl < C < O < F < Br    (4) C > F > O > Br > Cl  
Ans. (1) 
Sol.
 
 
C N O F 
Size decreases 
Cl 
Br 
Size increases 
 
 
C N O F 
vkdkj ?kVrk gS 
Cl 
Br 
vkdkj c<+rk gS 
 
 
 
11. Amongs the following which will show geometrical isomerism.  
 fuEu esa ls dkSu T;kfefr; leko;ork n'kkZ;sxk\ 
 (a) [Ni(NH3)5Cl]
+
  (b) [Ni(NH3)4ClBr]  (c) [Ni(NH3)3Cl]
+  
(d) [Ni(NH3)2(NO2)2]  
 (1) b, d   (2) a, b    (3) a, b & c  (4) a, b, c & d  
Ans. (1)  
Sol. Ma4bc can show 2 G.I.  
 Ma2b2 can show 2 G.I.  
 (Square planar)  
Ma4bc, 2 G.I. n'kkZ ldrk gSA 
 Ma2b2, 2 G.I. n'kkZ ldrk gSA 
 (oxZ leryh;)  
Page 4


      
 
      
    
    
     
 
                       
 
 
 
PAGE # 1 
 
 
PART : CHEMISTRY 
 
SECTION – 1 : (Maximum Marks : 80) 
Straight Objective Type   (lh/ks oLrqfu"B izdkj) 
This section contains 20 multiple choice questions. Each question has 4 choices (1), (2), (3) and (4) for its 
answer, out of which Only One is correct. 
bl [k.M esa 20 cgq&fodYih iz'u gSaA izR;sd iz'u ds 4 fodYi (1), (2), (3) rFkk (4) gSa] ftuesa ls flQZ ,d lgh gSA 
 
1. Correct bond energy order of following is- 
 fuEu dk lgh cU/k ÅtkZ Øe gS & 
 (1) C –Cl > C –Br > C – ? > C –F     (2) C –F < C –Cl < C –Br < C – ?   
 (3) C –F > C –Cl > C –Br > C – ? ? ? ? (4) C – ? < C –Br < C –F < C –Cl  
Ans. (3)      
Sol. Bond energy ? 
length Bond
1
   
 cU/k ÅtkZ ? 
yEckbZ cU/k
1
  
 
2.  Determine Bohr's radius of Li
2+
 ion for n = 2. Given (Bohr's radius of H-atom = a0)  
 n = 2 ds fy, Li
2+
 vk;u dh cksgj ÅtkZ dk fu/kkZj.k dhft,A fn;k gS (H-ijek.kq dh cksgj f=kT;k = a0) 
 (1) 
4
a 3
0
  (2) 
3
a 4
0
  (3) 
3
a
0
   (4) 
9
a 16
0
  
Ans. (2)  
Sol. r = 
Z
n a
2
0
  
 For Li
2+
 ds fy, r = 
3
) 2 ( a
2
0
 = 
3
a 4
0
  
 
3. Given the following reaction sequence  
  
 
A +N2 nitride  
(B) 
H2O 
NH3 
CuSO4 
Blue Colour 
 
 A & B are respectively  
fuEu vfHkfØ;k vuqØe fn;k x;k gS  
  
 
A +N2 ukbVªkbM 
(B) 
H2O 
NH3 
CuSO4 
uhyk jax 
 
 A rFkk B Øe'k% gS 
 (1) Mg, Mg3N2 
 (2) Na Na3N 
 (3) Mg Mg(NO3)2 
(4) Na NaNO3  
Ans. (1) 
Sol. 
2
HO
2 3 2 2 3
3Mg N Mg N Mg(OH) NH
(B)
? ? ? ? ? ? ? ? ?
 
 
      
 
      
    
    
     
 
                       
 
 
 
PAGE # 2 
 
 
4. Correct order of magnetic moment (spin only) for the following complexes  
 fuEu ladqyksa ds fy,] pqEcdh; vk?kw.kZ ¼dsoy pØ.k½ dk lgh Øe gS& 
 (a) [Pd(PPh3)2Cl2]    (b) [Ni(CO)4]  
 (c) [Ni(CN)4]
2 –   
   (d) [Ni(H2O)6]
2+
  
 (1) a = b = c < d     (2) a < b < c < d  
 (3) a > b > c > d     (4) a = b > c > d  
Ans. (1)  
Sol. [Pd(PPh3)2Cl2]   Pd
2+
 = 4d
8
   M = 0  
 [Ni(CO)4]    Ni = 3d
8
4s
2
(SFL)  M = 0  
 [Ni(CN)4]
2 –
   Ni
2+
 = 3d
8
 (SFL)  M = 0  
 [Ni(H2O)6]
2+
   Ni
2+
 = 3d
8
 (WFL) 
1 , 1
g
2 , 2 , 2
g 2
e , t So, unpaired electron is 2  
 [Ni(H2O)6]
2+
   Ni
2+
 = 3d
8
 (WFL) 
1 , 1
g
2 , 2 , 2
g 2
e , t blfy,] v;qfXer bysDVªkWu 2 gSA 
M = 8 BM  
 
5. Determine total number of neutrons in three isotopes of hydrogen. 
 gkbMªkstu ds rhu leLFkkfudks esa U;wVªkWuksa dh dqy la[;k dk fu/kkZj.k dhft,A  
 (1) 1   (2) 2   (3) 3    (4) 4 
Ans. (3) 
Sol.    
1
1
H 
2
1
H(D) 
3
1
H(T)  
 Number of neutrons  0 + 1 + 2 = 3 
 U;wVªkWuksa dh la[;k  0 + 1 + 2 = 3 
 
6. 
 
1/T 
log k 
a 
d 
b 
c 
    
Compare Ea (activation energy) for a, b, c and d.  
a, b, c rFkk d ds fy, Ea (lfØ;.k ÅtkZZ) dh rqyuk dhft,A 
 (1) Eb > Ec > Ed > Ea     (2) Ea > Ed > Ec > Eb  
 (3) Ec > Eb > Ea > Ed    (4) Ed > Ea > Eb > Ec  
Ans. (1)  
Sol. log k = log A – 
RT 303 . 2
E
a
  
 slope <+ky = –
R 303 . 2
E
a
 ? Eb > Ec > Ed > Ea  
 
7. Which of the following exhibit both Frenkel & Schottky defect? 
 fuEu esa ls dkSu Ýsady rFkk 'kkWV~dh nksuksa =kqfV iznf'kZr djrk gS\ 
 (1) AgBr  (2) KCl   (3) CsCl  (4) ZnS 
Ans. (1)  
Sol. Only AgBr can exhibit both Schottky and Frenkel defect. 
 dsoy AgBr 'kkWV~dh rFkk Ýsady nksuksa =kqfV iznf'kZr dj ldrk gSA 
     
      
 
      
    
    
     
 
                       
 
 
 
PAGE # 3 
 
 
8. Given: fn;k gS&  
 
P4 + NaOH + H2O    
PH3 + A 
HCl 
B 
  
 Basicity of B is:  
 B dh {kkjh;rk gS& 
 (1) 1   (2) 2   (3) 3   (4) 4 
Ans. (1) 
Sol.  
P4 + NaOH + H2O    
PH3 + NaH2PO2 
HCl 
H3PO2 
 
 Basicity {kkjh;rk = 1 
 
9. Which reaction does not occurs in the blast furnace in the metallurgy of Fe 
 dkSulh vfHkfØ;k Fe ds /kkrqdeZ esa okR;k Hkêh esa lEiUu ugha gksrh gS\   
 (a) CaO + SiO2 ? ? ? CaSiO3 
 (b) Fe2O3 + CO ? ? ? Fe3O4 + CO2 
 (c) FeO + SiO2 ? ? ? FeSiO3 
 (d) FeO 
?
? ? ? Fe + 
1
2
O2 
 (1) a & b  (2) a,b & c   (3) c & d  (4) a, b, c, d  
Ans. (3) 
Sol. Theory based lS)kfUrd  
 
10. Correct order of radius of elements is: 
 rRoksa dh f=kT;k dk lgh Øe gS & 
 C, O, F, Cl, Br 
 (1) Br > Cl > C > O > F    (2) Br < Cl < C < O < F 
 (3) Cl < C < O < F < Br    (4) C > F > O > Br > Cl  
Ans. (1) 
Sol.
 
 
C N O F 
Size decreases 
Cl 
Br 
Size increases 
 
 
C N O F 
vkdkj ?kVrk gS 
Cl 
Br 
vkdkj c<+rk gS 
 
 
 
11. Amongs the following which will show geometrical isomerism.  
 fuEu esa ls dkSu T;kfefr; leko;ork n'kkZ;sxk\ 
 (a) [Ni(NH3)5Cl]
+
  (b) [Ni(NH3)4ClBr]  (c) [Ni(NH3)3Cl]
+  
(d) [Ni(NH3)2(NO2)2]  
 (1) b, d   (2) a, b    (3) a, b & c  (4) a, b, c & d  
Ans. (1)  
Sol. Ma4bc can show 2 G.I.  
 Ma2b2 can show 2 G.I.  
 (Square planar)  
Ma4bc, 2 G.I. n'kkZ ldrk gSA 
 Ma2b2, 2 G.I. n'kkZ ldrk gSA 
 (oxZ leryh;)  
      
 
      
    
    
     
 
                       
 
 
 
PAGE # 4 
 
 
12. Assertion: pH of water increases on increasing temperature. 
 Reason: H2O ? H
+ 
+ OH
–
 is an exothermic process. 
 (1) Both assertion and reason are correct and reason is correct explanation of assertion. 
 (2) Both assertion and reason are correct and reason is not correct explanation of assertion. 
 (3) Assertion is true & reason is false. 
 (4) Both assertion and reason are incorrect. 
 dFku: ty dh pH rki c<+kus ij c<+rh gSA  
 dkj.k: H2O ? H
+ 
+ OH
–
 ,d Å"ek{ksih izØe gSA 
 (1) nksuksa dFku rFkk dkj.k lgh gS] rFkk dkj.k dFku dk lgh Li"Vhdj.k gSA 
 (2) nksuksa dFku rFkk dkj.k lgh gS] rFkk dkj.k dFku dk lgh Li"Vhdj.k ugha gSA 
 (3) dFku lR; gS rFkk dkj.k vlR; gSA  
 (4) nksuksa dFku rFkk dkj.k xyr gSA 
Ans. (4) 
Sol. Theory Based lS)kfUrd   
 
13. Assertion: It has been found that for hydrogenation reaction the catalytic activity increases from group-
5 to group-11 metals with maximum activity being shown by groups 7-9 elements of the periodic table. 
 Reason: For 7-9 group elements adsorption rate is maximum.  
 (1) Both assertion and reason are correct and reason is correct explanation of assertion. 
 (2) Both assertion and reason are correct and reason is not correct explanation of assertion. 
 (3) Assertion is true & reason is false. 
 (4) Both are incorrect 
 dFku: ;g ik;k x;k fd gkbMªkstuhdj.k vfHkfØ;k ds fy, mRizsjdh; lfØ;rk lewg-5 ls vkorZ lkj.kh ds lewg 7-9 
rRo }kjk n'kkZ;h x;h vf/kdre lfØ;rk ;qDr lewg-11 dh /kkrqvksa rd c<+rh gSA 
 dkj.k: 7-9 lewg ds rRoksa ds fy, vf/k'kks"k.k nj vf/kdre gksrh gS  
 (1) nksuksa dFku rFkk dkj.k lgh gS] rFkk dkj.k dFku dk lgh Li"Vhdj.k gSA 
 (2) nksuksa dFku rFkk dkj.k lgh gS] rFkk dkj.k dFku dk lgh Li"Vhdj.k ugha gSA 
 (3) dFku lR; gS rFkk dkj.k vlR; gSA  
 (4) nksuksa dFku rFkk dkj.k xyr gSA 
Ans. (1)  
Sol. Theory Based  lS)kfUrd 
 
14. The major product of the following reactions is  
 fuEufyf[kr vfHkfØ;k dk eq[; mRikn gSA   
 
O 
CH3 
|| 
H3O
+ 
      
(1) 
 
O 
CH3 
|| 
OH 
  (2) 
 
O 
CH3 
|| 
HO 
(3) 
 
OH 
CH3 
?
?
 (4) 
 
CH3 
OH 
HO 
 
Ans. (3) 
Sol. 
 
O 
CH3 
|| 
H3O
+ 
 
OH 
CH3 
?
?
(Aromatic) (,sjksesfVd) 
Page 5


      
 
      
    
    
     
 
                       
 
 
 
PAGE # 1 
 
 
PART : CHEMISTRY 
 
SECTION – 1 : (Maximum Marks : 80) 
Straight Objective Type   (lh/ks oLrqfu"B izdkj) 
This section contains 20 multiple choice questions. Each question has 4 choices (1), (2), (3) and (4) for its 
answer, out of which Only One is correct. 
bl [k.M esa 20 cgq&fodYih iz'u gSaA izR;sd iz'u ds 4 fodYi (1), (2), (3) rFkk (4) gSa] ftuesa ls flQZ ,d lgh gSA 
 
1. Correct bond energy order of following is- 
 fuEu dk lgh cU/k ÅtkZ Øe gS & 
 (1) C –Cl > C –Br > C – ? > C –F     (2) C –F < C –Cl < C –Br < C – ?   
 (3) C –F > C –Cl > C –Br > C – ? ? ? ? (4) C – ? < C –Br < C –F < C –Cl  
Ans. (3)      
Sol. Bond energy ? 
length Bond
1
   
 cU/k ÅtkZ ? 
yEckbZ cU/k
1
  
 
2.  Determine Bohr's radius of Li
2+
 ion for n = 2. Given (Bohr's radius of H-atom = a0)  
 n = 2 ds fy, Li
2+
 vk;u dh cksgj ÅtkZ dk fu/kkZj.k dhft,A fn;k gS (H-ijek.kq dh cksgj f=kT;k = a0) 
 (1) 
4
a 3
0
  (2) 
3
a 4
0
  (3) 
3
a
0
   (4) 
9
a 16
0
  
Ans. (2)  
Sol. r = 
Z
n a
2
0
  
 For Li
2+
 ds fy, r = 
3
) 2 ( a
2
0
 = 
3
a 4
0
  
 
3. Given the following reaction sequence  
  
 
A +N2 nitride  
(B) 
H2O 
NH3 
CuSO4 
Blue Colour 
 
 A & B are respectively  
fuEu vfHkfØ;k vuqØe fn;k x;k gS  
  
 
A +N2 ukbVªkbM 
(B) 
H2O 
NH3 
CuSO4 
uhyk jax 
 
 A rFkk B Øe'k% gS 
 (1) Mg, Mg3N2 
 (2) Na Na3N 
 (3) Mg Mg(NO3)2 
(4) Na NaNO3  
Ans. (1) 
Sol. 
2
HO
2 3 2 2 3
3Mg N Mg N Mg(OH) NH
(B)
? ? ? ? ? ? ? ? ?
 
 
      
 
      
    
    
     
 
                       
 
 
 
PAGE # 2 
 
 
4. Correct order of magnetic moment (spin only) for the following complexes  
 fuEu ladqyksa ds fy,] pqEcdh; vk?kw.kZ ¼dsoy pØ.k½ dk lgh Øe gS& 
 (a) [Pd(PPh3)2Cl2]    (b) [Ni(CO)4]  
 (c) [Ni(CN)4]
2 –   
   (d) [Ni(H2O)6]
2+
  
 (1) a = b = c < d     (2) a < b < c < d  
 (3) a > b > c > d     (4) a = b > c > d  
Ans. (1)  
Sol. [Pd(PPh3)2Cl2]   Pd
2+
 = 4d
8
   M = 0  
 [Ni(CO)4]    Ni = 3d
8
4s
2
(SFL)  M = 0  
 [Ni(CN)4]
2 –
   Ni
2+
 = 3d
8
 (SFL)  M = 0  
 [Ni(H2O)6]
2+
   Ni
2+
 = 3d
8
 (WFL) 
1 , 1
g
2 , 2 , 2
g 2
e , t So, unpaired electron is 2  
 [Ni(H2O)6]
2+
   Ni
2+
 = 3d
8
 (WFL) 
1 , 1
g
2 , 2 , 2
g 2
e , t blfy,] v;qfXer bysDVªkWu 2 gSA 
M = 8 BM  
 
5. Determine total number of neutrons in three isotopes of hydrogen. 
 gkbMªkstu ds rhu leLFkkfudks esa U;wVªkWuksa dh dqy la[;k dk fu/kkZj.k dhft,A  
 (1) 1   (2) 2   (3) 3    (4) 4 
Ans. (3) 
Sol.    
1
1
H 
2
1
H(D) 
3
1
H(T)  
 Number of neutrons  0 + 1 + 2 = 3 
 U;wVªkWuksa dh la[;k  0 + 1 + 2 = 3 
 
6. 
 
1/T 
log k 
a 
d 
b 
c 
    
Compare Ea (activation energy) for a, b, c and d.  
a, b, c rFkk d ds fy, Ea (lfØ;.k ÅtkZZ) dh rqyuk dhft,A 
 (1) Eb > Ec > Ed > Ea     (2) Ea > Ed > Ec > Eb  
 (3) Ec > Eb > Ea > Ed    (4) Ed > Ea > Eb > Ec  
Ans. (1)  
Sol. log k = log A – 
RT 303 . 2
E
a
  
 slope <+ky = –
R 303 . 2
E
a
 ? Eb > Ec > Ed > Ea  
 
7. Which of the following exhibit both Frenkel & Schottky defect? 
 fuEu esa ls dkSu Ýsady rFkk 'kkWV~dh nksuksa =kqfV iznf'kZr djrk gS\ 
 (1) AgBr  (2) KCl   (3) CsCl  (4) ZnS 
Ans. (1)  
Sol. Only AgBr can exhibit both Schottky and Frenkel defect. 
 dsoy AgBr 'kkWV~dh rFkk Ýsady nksuksa =kqfV iznf'kZr dj ldrk gSA 
     
      
 
      
    
    
     
 
                       
 
 
 
PAGE # 3 
 
 
8. Given: fn;k gS&  
 
P4 + NaOH + H2O    
PH3 + A 
HCl 
B 
  
 Basicity of B is:  
 B dh {kkjh;rk gS& 
 (1) 1   (2) 2   (3) 3   (4) 4 
Ans. (1) 
Sol.  
P4 + NaOH + H2O    
PH3 + NaH2PO2 
HCl 
H3PO2 
 
 Basicity {kkjh;rk = 1 
 
9. Which reaction does not occurs in the blast furnace in the metallurgy of Fe 
 dkSulh vfHkfØ;k Fe ds /kkrqdeZ esa okR;k Hkêh esa lEiUu ugha gksrh gS\   
 (a) CaO + SiO2 ? ? ? CaSiO3 
 (b) Fe2O3 + CO ? ? ? Fe3O4 + CO2 
 (c) FeO + SiO2 ? ? ? FeSiO3 
 (d) FeO 
?
? ? ? Fe + 
1
2
O2 
 (1) a & b  (2) a,b & c   (3) c & d  (4) a, b, c, d  
Ans. (3) 
Sol. Theory based lS)kfUrd  
 
10. Correct order of radius of elements is: 
 rRoksa dh f=kT;k dk lgh Øe gS & 
 C, O, F, Cl, Br 
 (1) Br > Cl > C > O > F    (2) Br < Cl < C < O < F 
 (3) Cl < C < O < F < Br    (4) C > F > O > Br > Cl  
Ans. (1) 
Sol.
 
 
C N O F 
Size decreases 
Cl 
Br 
Size increases 
 
 
C N O F 
vkdkj ?kVrk gS 
Cl 
Br 
vkdkj c<+rk gS 
 
 
 
11. Amongs the following which will show geometrical isomerism.  
 fuEu esa ls dkSu T;kfefr; leko;ork n'kkZ;sxk\ 
 (a) [Ni(NH3)5Cl]
+
  (b) [Ni(NH3)4ClBr]  (c) [Ni(NH3)3Cl]
+  
(d) [Ni(NH3)2(NO2)2]  
 (1) b, d   (2) a, b    (3) a, b & c  (4) a, b, c & d  
Ans. (1)  
Sol. Ma4bc can show 2 G.I.  
 Ma2b2 can show 2 G.I.  
 (Square planar)  
Ma4bc, 2 G.I. n'kkZ ldrk gSA 
 Ma2b2, 2 G.I. n'kkZ ldrk gSA 
 (oxZ leryh;)  
      
 
      
    
    
     
 
                       
 
 
 
PAGE # 4 
 
 
12. Assertion: pH of water increases on increasing temperature. 
 Reason: H2O ? H
+ 
+ OH
–
 is an exothermic process. 
 (1) Both assertion and reason are correct and reason is correct explanation of assertion. 
 (2) Both assertion and reason are correct and reason is not correct explanation of assertion. 
 (3) Assertion is true & reason is false. 
 (4) Both assertion and reason are incorrect. 
 dFku: ty dh pH rki c<+kus ij c<+rh gSA  
 dkj.k: H2O ? H
+ 
+ OH
–
 ,d Å"ek{ksih izØe gSA 
 (1) nksuksa dFku rFkk dkj.k lgh gS] rFkk dkj.k dFku dk lgh Li"Vhdj.k gSA 
 (2) nksuksa dFku rFkk dkj.k lgh gS] rFkk dkj.k dFku dk lgh Li"Vhdj.k ugha gSA 
 (3) dFku lR; gS rFkk dkj.k vlR; gSA  
 (4) nksuksa dFku rFkk dkj.k xyr gSA 
Ans. (4) 
Sol. Theory Based lS)kfUrd   
 
13. Assertion: It has been found that for hydrogenation reaction the catalytic activity increases from group-
5 to group-11 metals with maximum activity being shown by groups 7-9 elements of the periodic table. 
 Reason: For 7-9 group elements adsorption rate is maximum.  
 (1) Both assertion and reason are correct and reason is correct explanation of assertion. 
 (2) Both assertion and reason are correct and reason is not correct explanation of assertion. 
 (3) Assertion is true & reason is false. 
 (4) Both are incorrect 
 dFku: ;g ik;k x;k fd gkbMªkstuhdj.k vfHkfØ;k ds fy, mRizsjdh; lfØ;rk lewg-5 ls vkorZ lkj.kh ds lewg 7-9 
rRo }kjk n'kkZ;h x;h vf/kdre lfØ;rk ;qDr lewg-11 dh /kkrqvksa rd c<+rh gSA 
 dkj.k: 7-9 lewg ds rRoksa ds fy, vf/k'kks"k.k nj vf/kdre gksrh gS  
 (1) nksuksa dFku rFkk dkj.k lgh gS] rFkk dkj.k dFku dk lgh Li"Vhdj.k gSA 
 (2) nksuksa dFku rFkk dkj.k lgh gS] rFkk dkj.k dFku dk lgh Li"Vhdj.k ugha gSA 
 (3) dFku lR; gS rFkk dkj.k vlR; gSA  
 (4) nksuksa dFku rFkk dkj.k xyr gSA 
Ans. (1)  
Sol. Theory Based  lS)kfUrd 
 
14. The major product of the following reactions is  
 fuEufyf[kr vfHkfØ;k dk eq[; mRikn gSA   
 
O 
CH3 
|| 
H3O
+ 
      
(1) 
 
O 
CH3 
|| 
OH 
  (2) 
 
O 
CH3 
|| 
HO 
(3) 
 
OH 
CH3 
?
?
 (4) 
 
CH3 
OH 
HO 
 
Ans. (3) 
Sol. 
 
O 
CH3 
|| 
H3O
+ 
 
OH 
CH3 
?
?
(Aromatic) (,sjksesfVd) 
      
 
      
    
    
     
 
                       
 
 
 
PAGE # 5 
 
 
15. Find the final major product of the following reactions- 
fuEufyf[kr vfHkfØ;k vuqØe dk eq[; mRikn gS& 
 
CH3 —C     CH —CH2 —CH3 
CH(CH3)2 
B 2H 6 
A 
H 2O 2, OH 
– 
dil H 2SO 4 
B 
heat 
 
 (1) 
 
CH3 —C —CH2 —CH2 —CH3 
C(CH3)2 
  
(2) 
 
CH3 —C     CH —CH2 —CH3 
CH(CH3)2 
 
(3) 
 
CH3 —CH —CH 
 
CH —CH3 
CH(CH3)2 
  
(4) 
 
CH2 
 
C —CH2 —CH2 —CH3 
CH(CH3)2 
 
Ans. (1) 
Sol.
 
CH3 —C     CH —CH2 —CH3 
CH(CH3)2 
B 2H 6 
CH3 —C —CH —CH2 —CH3 
H 2O 2, OH 
– 
 
| 
| 
CH(CH3)2 
H 
| 
OH 
CH3 —C —CH2 —CH2 —CH3 
C(CH3)2 
dil H 2SO 4, ? 
 
 
 
16. There are two compounds A and B of molecular formula C9H18O3. A has higher boiling point than B. 
What are the possible structures of A and B?        
 nks ;kSfxd A rFkk B dk v.kqlw=k C9H18O3 gSA ;kSfxd A dk DoFkukad fcUnq B ls T;knk gS rks A rFkk B dh lajpuk 
gksxhA        
(1) 
 
CH3O 
OCH3 
OH 
OH 
OH HO 
A 
B 
  
(2) 
 CH3O 
OH 
OH HO 
OCH3 
OCH3 
A 
B 
  
(3) 
 
CH3O 
OCH3 
OH 
OH HO 
OCH3 
A 
B 
  
(4) 
 OCH3 
OCH3 OH 
OH HO 
HO 
A 
B 
 
Ans. (2) 
Sol. In (A), extensive inter-molecular H-bonding is possible while in (B) there is no Inter-molecular H-
bonding. 
(A) esa foLrh.kZ varj v.kqd H-caèk ik;k tkrk gS tcfd (B) esa dksbZ vUrj v.kqd H-caèk ugh ik;k tkrk gSA 
 
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