Jee 2004 chemistry Solutions, Class 12, Chemistry JEE Notes | EduRev

JEE : Jee 2004 chemistry Solutions, Class 12, Chemistry JEE Notes | EduRev

 Page 1


FIITJEE Ltd. ICES House, Sarvapriya Vihar (Near Hauz Khas Bus  Term.), New Delhi - 16, Ph : 2686 5182, 26965626,  2685 4102, 26515949 Fax : 26513942 
F FI II IT TJ JE EE E  S So ol lu ut ti io on ns s  t to o  I II IT TJ JE EE E– –2 20 00 04 4  M Ma ai in ns s  P Pa ap pe er r  
C
C
h
h
e
e
m
m
i
i
s
s
t
t
r
r
y
y  
 
Time: 2 hours 
 
Note: Question number 1 to 10 carries 2 marks each and 11 to 20 carries 4 marks each. 
 
 
1. For the given reaction  
 A + B ?? ? Products  
 Following data were given  
 Initial conc. (m/L). Initial conc. (m/L) Initial rate [mL
-1
s
-1
 ] 
 [A]    [B]    
 0.1    0.1   0.05 
 0.2    0.1   0.1 
 0.1     0.2   0.05 
 a) Write the rate equation. 
 b) Calculate the rate constant.        
 
Sol. a) Let the order w.r.t A & B are x any y respectively  
  r = K[A]
x
 [B]
y
 
  0.05 = K[0.1]
x
 [0.1]
y
 
  0.1 = K[0.2]
x
 [0.1]
y
 
  or 2 = [2]
x
 
  x =1 
  0.05 = K[0.1]
x
 [0.1]
y
 
  0.05 = K[0.1]
x
 [0.2]
y
 
  1 = [2]
y
 
  y=0  
 b) rate equation = r = K[A] [B]
0
 
  0.1 = K[0.2] 
  K = 0.5 Sec
-1 
 
2. 100 ml of a liquid contained in an isolated container at a pressure of 1 bar. The pressure is steeply increased 
to 100 bar. The volume of the liquid is decreased by 1 ml at this constant pressure. Find the ?H & ?U. 
 
Sol. ?H =0,  ?q
p
 = ?U-W 
 W = PdV 
 = 100 ×1 atmmL  
 = 10
-2
 KJ = ?U 
 
3. Draw the shape of XeF
4
 and OSF
4
according to VSEPR theory. Show the lone pair of electrons on the 
central atom           
 
Sol.  
F
FF
F
Xe
(square planar)
(sp
3
d
2
)
F
O
F
S
F
F
(Trigonal bipyramidal)
(sp
3
d)
 
 
Page 2


FIITJEE Ltd. ICES House, Sarvapriya Vihar (Near Hauz Khas Bus  Term.), New Delhi - 16, Ph : 2686 5182, 26965626,  2685 4102, 26515949 Fax : 26513942 
F FI II IT TJ JE EE E  S So ol lu ut ti io on ns s  t to o  I II IT TJ JE EE E– –2 20 00 04 4  M Ma ai in ns s  P Pa ap pe er r  
C
C
h
h
e
e
m
m
i
i
s
s
t
t
r
r
y
y  
 
Time: 2 hours 
 
Note: Question number 1 to 10 carries 2 marks each and 11 to 20 carries 4 marks each. 
 
 
1. For the given reaction  
 A + B ?? ? Products  
 Following data were given  
 Initial conc. (m/L). Initial conc. (m/L) Initial rate [mL
-1
s
-1
 ] 
 [A]    [B]    
 0.1    0.1   0.05 
 0.2    0.1   0.1 
 0.1     0.2   0.05 
 a) Write the rate equation. 
 b) Calculate the rate constant.        
 
Sol. a) Let the order w.r.t A & B are x any y respectively  
  r = K[A]
x
 [B]
y
 
  0.05 = K[0.1]
x
 [0.1]
y
 
  0.1 = K[0.2]
x
 [0.1]
y
 
  or 2 = [2]
x
 
  x =1 
  0.05 = K[0.1]
x
 [0.1]
y
 
  0.05 = K[0.1]
x
 [0.2]
y
 
  1 = [2]
y
 
  y=0  
 b) rate equation = r = K[A] [B]
0
 
  0.1 = K[0.2] 
  K = 0.5 Sec
-1 
 
2. 100 ml of a liquid contained in an isolated container at a pressure of 1 bar. The pressure is steeply increased 
to 100 bar. The volume of the liquid is decreased by 1 ml at this constant pressure. Find the ?H & ?U. 
 
Sol. ?H =0,  ?q
p
 = ?U-W 
 W = PdV 
 = 100 ×1 atmmL  
 = 10
-2
 KJ = ?U 
 
3. Draw the shape of XeF
4
 and OSF
4
according to VSEPR theory. Show the lone pair of electrons on the 
central atom           
 
Sol.  
F
FF
F
Xe
(square planar)
(sp
3
d
2
)
F
O
F
S
F
F
(Trigonal bipyramidal)
(sp
3
d)
 
 
 
FIITJEE Ltd. ICES House, Sarvapriya Vihar (Near Hauz Khas Bus  Term.), New Delhi - 16, Ph : 2686 5182, 26965626,  2685 4102, 26515949 Fax : 26513942 
IIT-JEE 2004-M-2
4. The structure of D-Glucose is as follows  
 
CHO
HOH
H O H
HOH
OH H
O H
 
a) Draw the structure of L – Glucose. 
b) Give the reaction of L – Glucose with Tollens reagent.   
 
 
 
 
 
 
 
 
 
        
 
Sol.  
CHO
HOH
H O H
HOH
H O H
O H
(L glu cos e) -
HOH
H O H
HOH
H O H
O H
O
-
O
32
Ag(NH )
+
? ??? ?
 
 
 
5. a) Draw New mann`s projection for the less stable staggered form of butane.  
 b) Relatively less stability of the staggered form is due to  
  i) Torsional strain.  
  ii) Vander Waal’s strain.  
  iii) Combination of the above two.  
Sol.  a) 
CH
3
H
H
.
H
.
CH
3
.
H
 
   b) Less stability is due to Vander Waal’s strain  
 
6. Arrange the following oxides in the increasing order of Bronsted basicity. 
 
27 3 2 2 3
Cl O,BaO,SO ,CO,B O        
Sol. 
27 3 2 2 3
ClOSO CO BOBaO << < < 
 
7. AlF
3
 is insoluble in anhydrous HF but when little KF is added to the compound it becomes soluble. On 
addition of BF
3
 ,AlF
3
 is precipitated. Write the balanced chemical equations. 
 
Sol. 3KF + AlF
3
 ??? K
3
AlF
6
  
 K
3
AlF
6
 + 3BF
3
 ?? ? AlF
3
 + 3KBF
4
 
 
8. The crystal AB (rock salt structure) has molecular weight 6.023 y amu.  where y is  an arbitrary number in 
amu.. If the minimum distance between cation & anion is 
1/3
ynm and the observed density is 
3
20Kg / m . 
Find the   
 a) density in 
3
Kg / m and 
 b) type of defect 
Page 3


FIITJEE Ltd. ICES House, Sarvapriya Vihar (Near Hauz Khas Bus  Term.), New Delhi - 16, Ph : 2686 5182, 26965626,  2685 4102, 26515949 Fax : 26513942 
F FI II IT TJ JE EE E  S So ol lu ut ti io on ns s  t to o  I II IT TJ JE EE E– –2 20 00 04 4  M Ma ai in ns s  P Pa ap pe er r  
C
C
h
h
e
e
m
m
i
i
s
s
t
t
r
r
y
y  
 
Time: 2 hours 
 
Note: Question number 1 to 10 carries 2 marks each and 11 to 20 carries 4 marks each. 
 
 
1. For the given reaction  
 A + B ?? ? Products  
 Following data were given  
 Initial conc. (m/L). Initial conc. (m/L) Initial rate [mL
-1
s
-1
 ] 
 [A]    [B]    
 0.1    0.1   0.05 
 0.2    0.1   0.1 
 0.1     0.2   0.05 
 a) Write the rate equation. 
 b) Calculate the rate constant.        
 
Sol. a) Let the order w.r.t A & B are x any y respectively  
  r = K[A]
x
 [B]
y
 
  0.05 = K[0.1]
x
 [0.1]
y
 
  0.1 = K[0.2]
x
 [0.1]
y
 
  or 2 = [2]
x
 
  x =1 
  0.05 = K[0.1]
x
 [0.1]
y
 
  0.05 = K[0.1]
x
 [0.2]
y
 
  1 = [2]
y
 
  y=0  
 b) rate equation = r = K[A] [B]
0
 
  0.1 = K[0.2] 
  K = 0.5 Sec
-1 
 
2. 100 ml of a liquid contained in an isolated container at a pressure of 1 bar. The pressure is steeply increased 
to 100 bar. The volume of the liquid is decreased by 1 ml at this constant pressure. Find the ?H & ?U. 
 
Sol. ?H =0,  ?q
p
 = ?U-W 
 W = PdV 
 = 100 ×1 atmmL  
 = 10
-2
 KJ = ?U 
 
3. Draw the shape of XeF
4
 and OSF
4
according to VSEPR theory. Show the lone pair of electrons on the 
central atom           
 
Sol.  
F
FF
F
Xe
(square planar)
(sp
3
d
2
)
F
O
F
S
F
F
(Trigonal bipyramidal)
(sp
3
d)
 
 
 
FIITJEE Ltd. ICES House, Sarvapriya Vihar (Near Hauz Khas Bus  Term.), New Delhi - 16, Ph : 2686 5182, 26965626,  2685 4102, 26515949 Fax : 26513942 
IIT-JEE 2004-M-2
4. The structure of D-Glucose is as follows  
 
CHO
HOH
H O H
HOH
OH H
O H
 
a) Draw the structure of L – Glucose. 
b) Give the reaction of L – Glucose with Tollens reagent.   
 
 
 
 
 
 
 
 
 
        
 
Sol.  
CHO
HOH
H O H
HOH
H O H
O H
(L glu cos e) -
HOH
H O H
HOH
H O H
O H
O
-
O
32
Ag(NH )
+
? ??? ?
 
 
 
5. a) Draw New mann`s projection for the less stable staggered form of butane.  
 b) Relatively less stability of the staggered form is due to  
  i) Torsional strain.  
  ii) Vander Waal’s strain.  
  iii) Combination of the above two.  
Sol.  a) 
CH
3
H
H
.
H
.
CH
3
.
H
 
   b) Less stability is due to Vander Waal’s strain  
 
6. Arrange the following oxides in the increasing order of Bronsted basicity. 
 
27 3 2 2 3
Cl O,BaO,SO ,CO,B O        
Sol. 
27 3 2 2 3
ClOSO CO BOBaO << < < 
 
7. AlF
3
 is insoluble in anhydrous HF but when little KF is added to the compound it becomes soluble. On 
addition of BF
3
 ,AlF
3
 is precipitated. Write the balanced chemical equations. 
 
Sol. 3KF + AlF
3
 ??? K
3
AlF
6
  
 K
3
AlF
6
 + 3BF
3
 ?? ? AlF
3
 + 3KBF
4
 
 
8. The crystal AB (rock salt structure) has molecular weight 6.023 y amu.  where y is  an arbitrary number in 
amu.. If the minimum distance between cation & anion is 
1/3
ynm and the observed density is 
3
20Kg / m . 
Find the   
 a) density in 
3
Kg / m and 
 b) type of defect 
 
FIITJEE Ltd. ICES House, Sarvapriya Vihar (Near Hauz Khas Bus  Term.), New Delhi - 16, Ph : 2686 5182, 26965626,  2685 4102, 26515949 Fax : 26513942 
IIT-JEE 2004-M-3
Sol. a) Density
23 27
46.023 y
6.023 10 8 y 10
-
××
=
××××
 [Since a = 2y
1/3
] 
 
33
510g/m =× 
 
3
5Kg / m = 
b) Since the (density) calculated < density observed, it means the defect is metal excess defect. 
 
9. Which of the following is more acidic and why?  
 
NH
3
+
NH
3
+
F
,
 
 
Sol.  
NH
3
+
F
 
is more acidic due to – inductive effect of fluorine  
 
10. 7-bromo-1,3,5-cycloheptatriene exists as ionic species in aqueous solution while 5-bromo-1,3 
cyclopentadiene doesn’t ionise even in presence of Ag (aq),
+
Explain.   
    
Sol. 
Aromatic Ion 
(highly stable)
Ag aq.
?
?? ? ?
Br
Br
Ag
?
?? ? ?
Antiaromatic Ion
(highly unstable)
 
 
11. a) The schrodinger wave equation for hydrogen atoms is  
  ?
2s 
=
3/2
r/a
1/ 2
00
11 r
2e
aa 4(2 )
-
?? ? ?
-
?? ? ?
p
?? ? ?
 
  Where a
0
 is Bohr’s radius. Let the radial node in 2s be at r
0
. Then find r in terms of a
0
.   
 b) A base ball having mass 100 g moves with velocity 100 m/sec. Find out the value of wave length of 
base ball. 
 c) 
7 234
92
6
XY.
-a
-ß
?? ? ? Find out atomic number, mass number of Y and identify it.  
 
Sol. a) 
2
2s
? = probability of finding electrons at any place 
  ??
2
= 0 at node  
Read More
Offer running on EduRev: Apply code STAYHOME200 to get INR 200 off on our premium plan EduRev Infinity!

Complete Syllabus of JEE

JEE

Content Category

Related Searches

Previous Year Questions with Solutions

,

Class 12

,

Objective type Questions

,

pdf

,

ppt

,

past year papers

,

Exam

,

Chemistry JEE Notes | EduRev

,

Chemistry JEE Notes | EduRev

,

Important questions

,

study material

,

Semester Notes

,

Chemistry JEE Notes | EduRev

,

practice quizzes

,

Jee 2004 chemistry Solutions

,

MCQs

,

Class 12

,

Sample Paper

,

Free

,

Extra Questions

,

Jee 2004 chemistry Solutions

,

video lectures

,

Summary

,

shortcuts and tricks

,

Class 12

,

Jee 2004 chemistry Solutions

,

mock tests for examination

,

Viva Questions

;