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Objective


To construct a square root spiral.

Materials Required

  • Adhesive
  • Geometry box
  • Marker
  • A piece of plywood

Prerequisite Knowledge

  • Concept of number line.
  • Concept of irrational numbers.
  • Pythagoras theorem.

Theory

  • A number line is a imaginary line whose each point represents a real number.
  • The numbers which cannot be expressed in the form p/q where q ≠ 0 and both p and q are integers, are called irrational numbers, e.g. √3, π, etc.
  • According to Pythagoras theorem, in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of other two sides containing right angle. ΔABC is a right angled triangle having right angle at B. (see Fig. 1.1)
    Lab Manual: Construct a Square Root Spiral | Lab Manuals for Class 9
  • Therefore, AC2 = AB2 +BC2

    where, AC = hypotenuse, AB = perpendicular and BC = base

Procedure

  • Take a piece of plywood having the dimensions 30 cm x 30 cm.
  • Draw a line segment PQ of length 1 unit by taking 2 cm as 1 unit, (see Fig. 1.2)
    Lab Manual: Construct a Square Root Spiral | Lab Manuals for Class 9
  • Construct a line QX perpendicular to the line segment PQ, by using compasses or a set square, (see Fig. 1.3)
    Lab Manual: Construct a Square Root Spiral | Lab Manuals for Class 9
  • From Q, draw an arc of 1 unit, which cut QX at C(say). (see Fig. 1.4)
    Lab Manual: Construct a Square Root Spiral | Lab Manuals for Class 9
  • Join PC.
  • Taking PC as base, draw a perpendicular CY to PC, by using compasses or a set square.
  • From C, draw an arc of 1 unit, which cut CY at D (say).
  • Join PD. (see Fig. 1.5)
    Lab Manual: Construct a Square Root Spiral | Lab Manuals for Class 9
  • Taking PD as base, draw a perpendicular DZ to PD, by using compasses or a set square.
  • From D, draw an arc of 1 unit, which cut DZ at E (say).
  • Join PE. (see Fig. 1.5)

Keep repeating the above process for sufficient number of times. Then, the figure so obtained is called a ‘square root spiral’.

Demonstration
In the Fig. 1.5, ΔPQC is a right angled triangle.
So, from Pythagoras theorem, we have PC2 = PQ2 + QC2

[∴ (Hypotenuse)2 = (Perpendicular)2 + (Base)2]
= 12 +12 = 2
⇒ PC = √2
Again, ΔPCD is also a right angled triangle.
So, from Pythagoras theorem,
PD2 =PC2 + CD2
= (√2)2 +(1)2 = 2 + 1 = 3
⇒ PD = √3
Similarly, we will have
PE= √4
⇒ PF=√5
⇒ PG = √6 and so on.

Observations
On actual measurement, we get
PC = …….. ,
PD = …….. ,
PE = …….. ,
PF = …….. ,
PG = …….. ,
√2 = PC = …. (approx.)
√3 = PD = …. (approx.)
√4 = PE = …. (approx.)
√5 = PF = …. (approx.)

Result
A square root spiral has been constructed.

Application
With the help of explained activity, existence of irrational numbers can be illustrated.

The document Lab Manual: Construct a Square Root Spiral | Lab Manuals for Class 9 is a part of the Class 9 Course Lab Manuals for Class 9.
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