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MCQ (with Solutions): Comparing Quantities | Mathematics (Maths) Class 8 PDF Download

Q1: A class has 30 girls and 40 boys. What is ratio of number of girls to total students in class?
(a) 3/7
(b) 4/7
(c) 3/4
(d) 4/3

View Answer

Ans: (a)
A class has 30 girls and 40 boys. So total number of students in the class is 70. The ration of number of girls to total students in the class is
MCQ (with Solutions): Comparing Quantities | Mathematics (Maths) Class 8

Q2: 40% of group likes tea as a beverage. What is the ratio of people liking tea as a beverage in the group?
(a) 3/7
(b) 2/5
(c) 2/10
(d) 4/3

View Answer

Ans: (b)
40% of group likes tea as a beverage. Ratio of people liking tea as a beverage in the group is
MCQ (with Solutions): Comparing Quantities | Mathematics (Maths) Class 8

Q3: Train travels at 45 kmph and bus travels at 30 kmph. What is the ratio of speed of train with respect to bus?
(a) 3/7
(b) 2/5
(c) 3/2
(d) 5/2

View Answer

Ans: (c)
Train travels with 45 kmph and bus travels at 30 kmph. The ratio of speed of train with respect to speed of bus is
MCQ (with Solutions): Comparing Quantities | Mathematics (Maths) Class 8

Q4: Train travels at 45 kmph and bus travels at 30 kmph. What is the ratio of speed of bus with respect to train?
(a) 3/7
(b) 2/3
(c) 3/2
(d) 5/2

View Answer

Ans: (c)
Train travels with 45 kmph and bus travels at 30 kmph. The ratio of speed of bus with respect to speed of train is
MCQ (with Solutions): Comparing Quantities | Mathematics (Maths) Class 8

Q5: Rakesh has Rs. 50 and Karan has Rs. 1.5. Find the ratio of money with Rakesh and money with Karan.
(a) 3/100
(b) 100/3
(c) 3/500
(d) 500/2

View Answer

Ans: (b)
Rakesh has Rs. 50 and Karan has Rs. 1.5.
Ratio of money with Rakesh and money with Karan is
MCQ (with Solutions): Comparing Quantities | Mathematics (Maths) Class 8

Q6: Rakesh has Rs. 10 and Karan has 10 paise. Find the ratio of money with Rakesh and money with Karan.
(a) 1/100
(b) 100/1
(c) 10/500
(d) 5/2

View Answer

Ans: (b)
Rakesh has Rs. 10 and Karan has 10 paisa. To derive ratio, quantities should be in converted to same unit. Here, one quantity is in rupees and other in paisa. We will convert both the quantities to paisa to derive ratio.
Ratio of money with Rakesh and money with Karan is
MCQ (with Solutions): Comparing Quantities | Mathematics (Maths) Class 8

Q7: Kiran has Rs. 140 left after using 65% of total money she had on shopping. Find total money with Kiran before shopping.
(a) Rs. 100
(b) Rs. 500
(c) Rs. 350
(d) Rs. 400

View Answer

Ans: (d)
Kiran has Rs. 140 left after using 65% of total money she had on shopping. Let the total money with Kiran be Rs. X.
∴ 140 = Total money – 65% of total money
∴ 140 = (100 – 65)% of total money
∴ 140 = 35% of X.
MCQ (with Solutions): Comparing Quantities | Mathematics (Maths) Class 8
∴ X = 400
Thus, total money with Kiran before shopping is Rs. 400.

Q8: Ticket to Rameshwar by train is Rs. 1200 and ticket to Delhi is Rs. 900 from Mumbai. What is the ratio of cost to reach Delhi with respect to Rameshwar from Mumbai?
(a) 3/4
(b) 3/5
(c) 4/3
(d) 5/2

View Answer

Ans: (a)
Ticket to Rameshwar by train is Rs. 1200 and ticket to Delhi is Rs. 900 from Mumbai. The ratio of ticket to Delhi with respect to ticket to Rameshwar is
MCQ (with Solutions): Comparing Quantities | Mathematics (Maths) Class 8

Q9: Sam is 78 kg and Sameer is 91 kg. Find the ratio of weight of Sam and Sameer.
(a) 3/7
(b) 7/6
(c) 3/7
(d) 6/7

View Answer

Ans: (d)
Sam is 78 kg and Sameer is 91 kg. The ratio of weight of Sam and Sameer is
MCQ (with Solutions): Comparing Quantities | Mathematics (Maths) Class 8

Q10: Satish has 15 kg sugar and Ray has 250 gm. Find the ratio of sugar with of Satish and Ray.
(a) 3/25
(b) 60/1
(c)1/60
(d) 15/25

View Answer

Ans: (b)
Satish has 15 kg of sugar and Ray has 250 gm. We must have both quantities in the same unit. 15 kg converted to grams is 15000gm. The ratio of sugar with Satish and Ray is
MCQ (with Solutions): Comparing Quantities | Mathematics (Maths) Class 8

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FAQs on MCQ (with Solutions): Comparing Quantities - Mathematics (Maths) Class 8

1. What is the difference between simple interest and compound interest?

Ans. Simple interest is calculated only on the principal amount, while compound interest is calculated on the principal amount as well as the interest accumulated over previous periods.

2. How can we calculate the amount after a certain period with compound interest?

Ans. The formula to calculate the amount after a certain period with compound interest is A = P(1 + r/n)^(nt), where A is the total amount, P is the principal amount, r is the rate of interest, n is the number of times interest is compounded per year, and t is the number of years.

3. What is the formula to calculate the compound interest?

Ans. The formula to calculate compound interest is CI = P(1 + r/n)^(nt) - P, where CI is the compound interest, P is the principal amount, r is the rate of interest, n is the number of times interest is compounded per year, and t is the number of years.

4. How can we compare the prices of two items with different quantities and prices?

Ans. To compare the prices of two items with different quantities and prices, we can calculate the price per unit for each item by dividing the total price by the quantity. Then, we can compare the price per unit to determine which item offers better value for money.

5. Is it better to choose a higher interest rate with simple interest or compound interest?

Ans. It is better to choose a higher interest rate with compound interest as it allows for interest to be calculated on the interest earned in previous periods, resulting in higher returns compared to simple interest.

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