Match the Following of The d- and f-Block Elements & Coordination Compounds, Past year QuesJEE Adv. JEE Notes | EduRev

Class 12 Chemistry 35 Years JEE Mains &Advance Past yr Paper

Created by: Abhishek Kapoor

JEE : Match the Following of The d- and f-Block Elements & Coordination Compounds, Past year QuesJEE Adv. JEE Notes | EduRev

The document Match the Following of The d- and f-Block Elements & Coordination Compounds, Past year QuesJEE Adv. JEE Notes | EduRev is a part of the JEE Course Class 12 Chemistry 35 Years JEE Mains &Advance Past yr Paper.
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DIRECTIONS (Q. No. 1 and 2) : Each question contains statements given in two columns, which have to be matched. The statements in Column-I are labelled A, B, C and D, while the statements in Column-II are labelled p, q, r, s and t. Any given statement in Column-I can have correct matching with ONE OR MORE statement(s) in Column-II. The appropriate bubbles corresponding to the answers to these questions have to be darkened as illustrated in the following example :

If the correct matches are A-p, s and t; B-q and r; C-p and q; and D-s then the correct darkening of bubbles will look like the given.

Match the Following of The d- and f-Block Elements & Coordination Compounds, Past year QuesJEE Adv. JEE Notes | EduRev

 

Q.1. Match the complexes in Column I with their properties listed in Column II.

Column I                                           Column II

(A) [Co(NH3)4(H2O)2]Cl2                (p) geometrical isomers

(B) [Pt(NH3)2Cl2]                              (q) paramagnetic

(C) [Co(H2O)5Cl]Cl                           (r) diamagnetic

(D) [Ni(H2O)6]Cl2                              (s) metal ion with +2 oxidation state

Ans. (A - p, q, s); (B - p, r, s); (C - q, s); (D - q, s)

Solution. In [Co(NH3)4(H2O)2]2+, Co is in + 2 state having 3d7 configuration, which makes it paramagentic due to odd electrons. Moreover, it is an octahedral complex showing cis-trans isomerism w.r.t., H2O.

Match the Following of The d- and f-Block Elements & Coordination Compounds, Past year QuesJEE Adv. JEE Notes | EduRev

(B) : (p), (r) and (s) 

In [Pt (NH3)Cl2], Pt is in + 2 state with configuration 5d8.
Since NHis a strong field ligand, it will pair all the electrons making the complex diamagnetic. Moreover, it is a square planar complex showing cis-trans isomerism.
Match the Following of The d- and f-Block Elements & Coordination Compounds, Past year QuesJEE Adv. JEE Notes | EduRev

(C) : (q) and (s) In [Co(H2O)5Cl]Cl, Co is in + 2 state with 3d7 configuration making it paramagnetic.

(D) : (q) and (s) In [Ni(H2O)6]Cl2, Ni is in + 2 state with 3d8 configuration. It is attached with weak field ligands, therefore it is paramagnetic.


Q.2. Match each of the reactions given in Column I with the corresponding product(s) given in Column II.

ColumnI                                                         Column II

(A) Cu + dil HNO3                                           (p) NO

(B) Cu + conc HNO3                                        (q) NO2

(C) Zn + dil HNO3                                            (r) N2O

(D) Zn + conc HNO3                                         (s) Cu (NO3)2

                                                                          (t) Zn(NO3)2

Ans. (A - p, s); (B - q, s); (C - r, t); (D - q, t)

Solution. 

Match the Following of The d- and f-Block Elements & Coordination Compounds, Past year QuesJEE Adv. JEE Notes | EduRev
Match the Following of The d- and f-Block Elements & Coordination Compounds, Past year QuesJEE Adv. JEE Notes | EduRev
Match the Following of The d- and f-Block Elements & Coordination Compounds, Past year QuesJEE Adv. JEE Notes | EduRev
Match the Following of The d- and f-Block Elements & Coordination Compounds, Past year QuesJEE Adv. JEE Notes | EduRev


DIRECTIONS (Q. No. 3) : Following question has matching lists. The codes for the list have choices (a), (b), (c) and (d) out of which ONLY ONE is correct.

Q.3. Match each coordination compound in List-I with an appropriate pair of characteristics from List- II and select the correct answer using the code given below the lists.

{en = H2NCH2CH2NH2; atomic numbers : Ti = 22; Cr = 24; Co = 27; Pt = 78}

List-I                                                         List-II

P. [Cr(NH3)4Cl2]Cl                                   1. Paramagnetic and exhibits ionisation isomerism

Q. [Ti(H2O)5Cl](NO3)2                             2. Diamagnetic and exhibits cis-trans isomerism

R. [Pt(en)(NH3)Cl]NO3                            3. Paramagnetic and exhibits cis-trans isomerism

S. [Co(NH3)4(NO3)2]NO3                       4. Diamagnetic and exhibits ionisation isomerism

Match the Following of The d- and f-Block Elements & Coordination Compounds, Past year QuesJEE Adv. JEE Notes | EduRev

Ans. (b)

Solution. 

 

Complex

Magnetic character

Isomerism

P, [Cr(NH3)4Cl2]Cl

Cr3+ is d3, hence paramagnetic

cis-trans

Q, [Ti(H2O)5Cl](NO3)2

Ti3 + is d1, hence paramagnetic.

ionization

R, [Pt(en)(NH3)Cl]NO3

Pt 2+ is d8, complex is square planar, all electrons are paired, hence diamagnetic

ionization

S, [Co(NH3)4(NO3)2]NO3

Co3+ is d6, all electrons are paired due to strong ligands, hence diamagnetic

cis-trans

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