Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev

Class 12 Chemistry 35 Years JEE Mains &Advance Past yr Paper

Created by: Abhishek Kapoor

JEE : Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev

The document Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev is a part of the JEE Course Class 12 Chemistry 35 Years JEE Mains &Advance Past yr Paper.
All you need of JEE at this link: JEE

Direction : question contains statements given in two columns, which have to be matched. The statements in Column-I are labelled A, B, C and D, while the statements in Column-II are labelled p, q, r, s and t.

Q.

Match the reactions in Columns I with nature of the reactions/type of the products in Column II. Indicate your answer by darkening the appropriate bubbles of the 4 × 4 matrix given in the ORS.

Column IColumn II
Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev(p) redox reaction
 (q) one of the products has trigonal planar structure
 (r) dimeric bridged tetrahedral metal ion
 (s) disproportionation

 

Ans:  A - p, s); (B - r); (C - p, q); (D - p). 

Solution :  A→ p, s; The reaction is redox reaction because the O.N. of O in  Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev is – 0.5 and that in O2 is zero. In Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev is –1.0. It
involves reduction oxidation reaction. Since here a part of molecule is oxidised and a part is reduced so it is disproportionation.
B → r; The structure of  Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev is given below  
 

Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev

[NOTE : In any solution dichromate ions and chromate ions exist in equilibrium. In alkali solution, dichromate ions are converted into chromate ions and on acidification chromate ions are converted back into dichromate ion.]
C → p, q; The reaction is  Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev In involves change in O.N of Mn   Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev to
+ 2(in Mn2+), So Mn is reduced and NO2–  is oxidised to Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev  it is a redox reaction. The structure of Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev it is a redox reaction.
– (one of the products is trigonal planar)
D → p, It is a redox reaction

 

 

Direction : questions have matching lists. The codes for the lists have choices (a), (b), (c) and (d) out of which ONLY ONE is correct.

Q. 

An aqueous solution of X is added slowly to an aqueous solution of Y as shown in List I. The variation in conductivity of these reactions is given in List II. Match list I with List II and select the correct answer using the code given below the lists :                         (JEE Adv. 2013)

List IList II
Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev1. Conductivity decreases and then increases
2. Conductivity decreases and then does not change much
3. Conductivity increases and then does not change much
4. Conductivity does not change much and then increases

 

Codes: 

Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev

Ans: a

Solution :  (a) 
 (p)

Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev
Initially conductivity increases because on neutralisation ions are created. After that it becomes practically constant because X alone can
not form ions.

Q.

Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev

Number of ions in the solution remains constant as only AgNO3 precipitated as AgI. Thereafter conductance increases due to increase in number
of ions.

(R) Initially conductance decreases due to the decrease in the number of  Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev  ions as OH is getting replaced by CH3COO which has poorer conductivity
thereafter it slowly increases due to the increase in number of H+ ions.

(S) Initially it decreases due to decrease in H+ ions and then increases due to the increase in OH ions.

 

Q.

The standard reduction potential data at 25°C is given below : (JEE Adv. 2013)
 E°(Fe3+, Fe2+) = + 0.77 V; E°(Fe2+, Fe) = – 0.44 V; E°(Cu2+, Cu) = + 0.34 V; E°(Cu+, Cu) = + 0.52 V
 E°[O2(g) + 4H+ + 4e → 2H2O] = + 1.23 V; E°[O2(g) + 2H2O + 4e → 4OH] = + 0.40 V
 E°(Cr3+, Cr) = – 0.74 V; E°(Cr2+, Cr) = – 0.91 V

 

Match E° of the redox pair in List I with the values given in List II and select the correct answer using the code given below the lists :

List IList II
Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev1. – 0.18 V
2. – 0.4 V
3. – 0.04 V
4. – 0.83 V

Codes : 

Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev

Ans: d

Solution : 

Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev

 

Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev

 

Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev

Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev

Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev

Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev

Match the following of Electrochemistry, Past year Questions JEE Advance, Class 12, Chemistry JEE Notes | EduRev
– 0.74V, n = 3
x × 1 + 2 × (– 0.91) = 3 × (– 0.74)
x – 1.82 = – 2.22 ⇒ x = – 0.4V

Offer running on EduRev: Apply code STAYHOME200 to get INR 200 off on our premium plan EduRev Infinity!

Complete Syllabus of JEE

JEE

Dynamic Test

Content Category

Related Searches

Exam

,

Sample Paper

,

MCQs

,

Important questions

,

Chemistry JEE Notes | EduRev

,

Class 12

,

Extra Questions

,

Chemistry JEE Notes | EduRev

,

Summary

,

Free

,

Chemistry JEE Notes | EduRev

,

pdf

,

past year papers

,

video lectures

,

Previous Year Questions with Solutions

,

Past year Questions JEE Advance

,

mock tests for examination

,

Semester Notes

,

Match the following of Electrochemistry

,

practice quizzes

,

study material

,

Match the following of Electrochemistry

,

Past year Questions JEE Advance

,

ppt

,

Objective type Questions

,

Viva Questions

,

Class 12

,

Past year Questions JEE Advance

,

Match the following of Electrochemistry

,

Class 12

,

shortcuts and tricks

;