Maths Olympiad Model Practice Test Paper - 1 | Mathematics Olympiad Class 4 PDF Download

Ans: (d) 
Word formed from the given letters is 'TUESDAY'.

Ans: (c) 
If one more butterfly is added on the left of butterfly 1, then 7 butterflies are on the left of butterfly 7.

Ans: (a) 
Shekhar is 2nd from the left.

Ans: (c)

• The letters given are T, I, I, C, L, H.
• To form a meaningful word, we need to find the correct order of the numbers.
• Option (c) gives us the order 5, 3, 1, 4, 6, 2, which corresponds to the letters L, I, T, C, H, I.
• This arrangement spells the word "LICHT," which is a valid English word.

Ans: (d)

• Understanding the terms: In this question, the words are swapped. The 'Nose' is actually the part used for breathing, but it is called 'Foot' in this scenario.
• Identifying the correct part: Since 'Nose' is called 'Foot', the correct answer to the question about breathing is 'Foot'.
• Conclusion: Therefore, the answer is (d) Foot, as it represents the 'Nose' in this context.

Ans:  (c) 
Letters of word are written in reverse order to get the decoded word. So, code for PAPER is REPAP.

Ans: (d) 
49 comes in table of 7.

Ans: (b) 
The given numbers are arranged in ascending order,
158 283 321 438 467 641 764 952
So, 438 is fourth from the left.

Ans: (a) 
According to Robin : 17, 18, 19 , 20
According to his father : 19
According to both common days is 19th October
Hence, Ritika's birthday was on 19th October.

Ans: (b)
The pattern is as follows:

Ans: (a)

• To find the multiples of 15 between 95 and 185, we first identify the smallest multiple of 15 greater than 95. This is 105 (15 x 7).
• Next, we find the largest multiple of 15 less than 185, which is 180 (15 x 12).
• Now, we list the multiples of 15 from 105 to 180: 105, 120, 135, 150, 165, 180.
• Counting these gives us a total of 6 multiples of 15 in that range.

Ans: (c)

Ans: (c)
1 year = 12 months  
Annual income = ₹ 9876 × 12  
= ₹ 1,18,512 

Ans: (b)
1782 × 56 = 99,792  When 99,792 
Round off to nearest  thousands = 1,00,000

Ans: (b)
Number of crates needed  = 990 ÷ 18 = 55

Ans: (a)
Number of people each bus  carry = 4600 ÷ 100 = 46 

Ans: (c)
12th multiple of 12 = 12 × 12 = 144 

Ans: (d)
1 × 12 = 12  
2 × 6 = 12  
3 × 4 = 12 
So, factors of 12 are: 1, 2, 3, 4, 6, 12.

Ans: (a)  
Since 2 divides 22 exactly, i.e.,  
22 ÷ 2 = 11 (Remainder = 0)  
So, 2 is a factor of 22.

Ans: (d)
1 × 28 = 28  
2 × 14 = 28  
4 × 7 = 28  
So, factors of 28 are: 1, 2, 4, 7, 14 and 28.

Ans: (a)

• To find the total population, we need to add the number of men, women, and children together.
• The calculation is: 4758 (men) + 3978 (women) + 2650 (children).
• This gives us 11386 as the total population of the village.
• Thus, the correct answer is (a) 11386.

Ans: (d)

• Last year, Kartik was 18, so this year he is 19 years old.
• Swastik is twice Kartik's age, making him 38 years old now.
• In five years, Swastik will be 38 + 5 = 43 years old.
• Thus, the correct answer is 43 years.

Ans: (b)

• The shape described has 4 sides and none of them are of the same length.
• This means it cannot be a rectangle or a square, as those shapes have equal sides or pairs of equal sides.
• A quadrilateral is a general term for any 4-sided shape, which fits the description given.
• A pentagon has 5 sides, so it does not apply here.

Ans: (c)

• First, convert all measurements to centimeters for easier addition: 225 m 18 cm = 22500 cm + 18 cm = 22518 cm, 212 m 20 cm = 21200 cm + 20 cm = 21220 cm, and 140 m 5 cm = 14000 cm + 5 cm = 14005 cm.
• Now, add these values together: 22518 cm + 21220 cm + 14005 cm = 57743 cm.
• Convert the total back to meters and centimeters: 57743 cm = 577 m 43 cm.
• Thus, the total length of cloth Mrs. Sharma bought from all the shops is 577 m 43 cm.

Ans: (a)

• To find the distance Kashi covered, we first need to calculate the perimeter of the playground.
• The perimeter is given by the formula: Perimeter = 2 × (Length + Width).
• Here, Length = 150 m and Width = 80 m, so Perimeter = 2 × (150 + 80) = 2 × 230 = 460 m.
• Kashi went around the playground 5 times, so the total distance is 5 × 460 m = 2300 m, which is equal to 2 km 300 m.

Ans: (b)
If the last two digits of a number are  divisible by 4, then the number is divisible  by 4.  Here, last two digits of 1832 are divisible  by 4. 

Ans: (c)
Factors of 35 are: 1, 5, 7, 35  
Factors of 28 are: 1, 2, 4, 7, 14, 28  
Factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24,  48  
Factors of 16 are: 1, 2, 4, 8, 16  
So, 48 has highest number of factors.

Ans: (d)
Since, 7 × 17 = 119 and 119 ÷  119 = 1  
So, 119 is multiple of 7 as well as factor of  119.

Ans: (c)
Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48  Out of these factors number which is  greater than 5 but not multiple of 4 is 6.  
So, G = 6.  Kindle Edition.

Ans: (c)
28 + x = 28 + 4 = 32 and 24 + x = 24 + 4 = 28  
So, out of the given options, 4 is the greatest number which divides 32 and 28 without leaving any remainder.

Ans: (d)
Numbers between 100 and  130 which are multiples of 5 are: 105, 110,  115, 120, 125.  
Numbers between 100 and 130 which is  multiple of 25 is: 125.  
Common Multiple of 5 and 25 between 100 and 130 is 125.  
125 is also the factor of 125.  
So, product of digits = 1 × 2 × 5 = 10. 

Ans: (c)
Let number be x.  So, 5x + 209= 364 
5x = 364 – 209  
5x = 155  
x = 155 ÷ 5  = 31  
Now, 3 times of number is 3 × 31 = 93.  
Thus, with respect to number 93  statements 1 and 2 both are correct as 85 < 91 < 95 and 3 × 31 = 93. 

Ans: (c)
Let number of red marbles = x  
So, number of green marbles = 5x  
x + 5x = 1230  
6x = 1230  
x = 1230 ÷ 6 =205  
Thus, number of green marbles = 5 × 205  = 1025  
1/5 of green marbles =  1/5  × 1025 = 205  
So, number of marbles left = 1025 – 205  = 820  

Ans: (a)
Diameter = 2 × radius  
New Diameter = 2 × (2 × radius)  
= 4 × radius  
Thus, New Diameter is increased by 4 cm.

Ans: (c)
First odd prime number = 3  
Thus, radius = 3  
Therefore, diameter = 2 × radius  
= 2 × 3  
= 6 units