Class 8 Exam > Class 8 Notes > Mathematics (Maths) Class 8 > Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2
Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 | Mathematics (Maths) Class 8 PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
EXERCISE 21.2 PAGE NO: 21.15
1. Find the volume in cubic metres (cu. m) of each of the cuboids whose dimensions
are:
(i) length = 12 m, breadth = 10 m, height = 4.5 m
(ii) length = 4 m, breadth = 2.5m, height = 50 cm
(iii) length = 10m, breadth = 25 dm, height = 25 cm.
Solution:
(i) Given details are,
Length of a cuboid = 12 m
Breadth of a cuboid = 10m
Height of a cuboid = 4.5 m
By using the formula
Volume of cuboid = l × b × h
= 12 × 10 × 4.5
= 540 m
3
(ii) Given details are,
Length of a cuboid = 4 m
Breadth of a cuboid = 2.5 m
Height of a cuboid = 50 cm = 0.50m
By using the formula
Volume of a cuboid = l × b × h
= 4 × 2.5 × 0.50
= 5 m
3
(iii) Given details are,
Length of a cuboid = 10m
Breadth of a cuboid = 25 dm = 2.5 m
Height of a cuboid = 25 cm = 0.25 m
By using the formula
Volume of a cuboid = l × b × h
= 10 × 2.5 × 0.25
= 6.25 m
3
2. Find the volume in cubic decimetre of each of the cubes whose side is
(i) 1.5 m
(ii) 75cm
(iii) 2 dm 5 cm
Page 2
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
EXERCISE 21.2 PAGE NO: 21.15
1. Find the volume in cubic metres (cu. m) of each of the cuboids whose dimensions
are:
(i) length = 12 m, breadth = 10 m, height = 4.5 m
(ii) length = 4 m, breadth = 2.5m, height = 50 cm
(iii) length = 10m, breadth = 25 dm, height = 25 cm.
Solution:
(i) Given details are,
Length of a cuboid = 12 m
Breadth of a cuboid = 10m
Height of a cuboid = 4.5 m
By using the formula
Volume of cuboid = l × b × h
= 12 × 10 × 4.5
= 540 m
3
(ii) Given details are,
Length of a cuboid = 4 m
Breadth of a cuboid = 2.5 m
Height of a cuboid = 50 cm = 0.50m
By using the formula
Volume of a cuboid = l × b × h
= 4 × 2.5 × 0.50
= 5 m
3
(iii) Given details are,
Length of a cuboid = 10m
Breadth of a cuboid = 25 dm = 2.5 m
Height of a cuboid = 25 cm = 0.25 m
By using the formula
Volume of a cuboid = l × b × h
= 10 × 2.5 × 0.25
= 6.25 m
3
2. Find the volume in cubic decimetre of each of the cubes whose side is
(i) 1.5 m
(ii) 75cm
(iii) 2 dm 5 cm
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
Solution:
(i) Given details are,
Side of cube = 1.5m = 15 dm
So, Volume of cube = 15
3
= 3375 dm
3
(ii) Given details are,
Side of cube = 75cm = 7.5 dm
So, Volume of cube = 7.5
3
= 421.875 dm
3
(iii) Given details are,
Side of cube = 2dm 5cm = 2.5 dm
So, Volume of cube = 2.5
3
= 15.625 dm
3
3. How much clay is dug out in digging a well measuring 3 m by 2 m by 5 m?
Solution:
Given details are,
Dimensions of well = 3m × 2m × 5m
So,
Volume of clay dug out from well is = l × b × h
= 3 × 2 × 5
= 30 m
3
4. What will be the height of a cuboid of volume 168 m
3
, if the area of its base is 28
m
2
?
Solution:
Given details are,
Volume of a cuboid = 168 m
3
Area of base = l × b = 28m
2
Let height of cuboid be ‘h’ m
We know that,
Volume = l × b × h
h = volume/ l × b
= 168/28
= 6m
? Height of cuboid is 6 m
5. A tank is 8 m long, 6 m broad and 2 m high. How much water can it contain?
Solution:
Given details are,
Page 3
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
EXERCISE 21.2 PAGE NO: 21.15
1. Find the volume in cubic metres (cu. m) of each of the cuboids whose dimensions
are:
(i) length = 12 m, breadth = 10 m, height = 4.5 m
(ii) length = 4 m, breadth = 2.5m, height = 50 cm
(iii) length = 10m, breadth = 25 dm, height = 25 cm.
Solution:
(i) Given details are,
Length of a cuboid = 12 m
Breadth of a cuboid = 10m
Height of a cuboid = 4.5 m
By using the formula
Volume of cuboid = l × b × h
= 12 × 10 × 4.5
= 540 m
3
(ii) Given details are,
Length of a cuboid = 4 m
Breadth of a cuboid = 2.5 m
Height of a cuboid = 50 cm = 0.50m
By using the formula
Volume of a cuboid = l × b × h
= 4 × 2.5 × 0.50
= 5 m
3
(iii) Given details are,
Length of a cuboid = 10m
Breadth of a cuboid = 25 dm = 2.5 m
Height of a cuboid = 25 cm = 0.25 m
By using the formula
Volume of a cuboid = l × b × h
= 10 × 2.5 × 0.25
= 6.25 m
3
2. Find the volume in cubic decimetre of each of the cubes whose side is
(i) 1.5 m
(ii) 75cm
(iii) 2 dm 5 cm
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
Solution:
(i) Given details are,
Side of cube = 1.5m = 15 dm
So, Volume of cube = 15
3
= 3375 dm
3
(ii) Given details are,
Side of cube = 75cm = 7.5 dm
So, Volume of cube = 7.5
3
= 421.875 dm
3
(iii) Given details are,
Side of cube = 2dm 5cm = 2.5 dm
So, Volume of cube = 2.5
3
= 15.625 dm
3
3. How much clay is dug out in digging a well measuring 3 m by 2 m by 5 m?
Solution:
Given details are,
Dimensions of well = 3m × 2m × 5m
So,
Volume of clay dug out from well is = l × b × h
= 3 × 2 × 5
= 30 m
3
4. What will be the height of a cuboid of volume 168 m
3
, if the area of its base is 28
m
2
?
Solution:
Given details are,
Volume of a cuboid = 168 m
3
Area of base = l × b = 28m
2
Let height of cuboid be ‘h’ m
We know that,
Volume = l × b × h
h = volume/ l × b
= 168/28
= 6m
? Height of cuboid is 6 m
5. A tank is 8 m long, 6 m broad and 2 m high. How much water can it contain?
Solution:
Given details are,
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
Dimensions of a tank = 8m × 6m × 2m
We know that,
Volume of tank = l × b × h
= 8 × 6 × 2
= 96 m
3
= 96000 litres
? The tank can contain 96000 litres of water.
6. The capacity of a certain cuboidal tank is 50000 litres of water. Find the breadth
of the tank, if its height and length are 10 m and 2.5 m respectively.
Solution:
Given details are,
Capacity (volume) of cuboidal tank is = 50000 litre = 50 m
3
Height of tank = 10 m
Length of tank = 2.5 m
Let breadth of tank be ‘b’ m
We know that,
Volume = l × b × h
b = volume / (l × h)
= 50/(10×2.5)
= 2m
? Breadth of tank is 2m
7. A rectangular diesel tanker is 2m long, 2m wide and 40cm deep. How many litres
of diesel can it hold?
Solution:
Given details are,
Length of a tanker = 2m
Breadth of a tanker = 2m
Height of a tanker = 40cm = 0.4m
So, Dimensions of rectangular diesel tank = 2m × 2m × 0.4m
Volume of tank (amount of diesel it can hold) = l × b × h
= 2 × 2 × 0.4
= 1.6m
3
= 1600 litres
? A rectangular diesel tanker can hold 1600 litres of diesel.
8. The length, breadth and height of a room are 5 m, 4.5 m and 3 m respectively.
Find the volume of the air it contains.
Page 4
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
EXERCISE 21.2 PAGE NO: 21.15
1. Find the volume in cubic metres (cu. m) of each of the cuboids whose dimensions
are:
(i) length = 12 m, breadth = 10 m, height = 4.5 m
(ii) length = 4 m, breadth = 2.5m, height = 50 cm
(iii) length = 10m, breadth = 25 dm, height = 25 cm.
Solution:
(i) Given details are,
Length of a cuboid = 12 m
Breadth of a cuboid = 10m
Height of a cuboid = 4.5 m
By using the formula
Volume of cuboid = l × b × h
= 12 × 10 × 4.5
= 540 m
3
(ii) Given details are,
Length of a cuboid = 4 m
Breadth of a cuboid = 2.5 m
Height of a cuboid = 50 cm = 0.50m
By using the formula
Volume of a cuboid = l × b × h
= 4 × 2.5 × 0.50
= 5 m
3
(iii) Given details are,
Length of a cuboid = 10m
Breadth of a cuboid = 25 dm = 2.5 m
Height of a cuboid = 25 cm = 0.25 m
By using the formula
Volume of a cuboid = l × b × h
= 10 × 2.5 × 0.25
= 6.25 m
3
2. Find the volume in cubic decimetre of each of the cubes whose side is
(i) 1.5 m
(ii) 75cm
(iii) 2 dm 5 cm
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
Solution:
(i) Given details are,
Side of cube = 1.5m = 15 dm
So, Volume of cube = 15
3
= 3375 dm
3
(ii) Given details are,
Side of cube = 75cm = 7.5 dm
So, Volume of cube = 7.5
3
= 421.875 dm
3
(iii) Given details are,
Side of cube = 2dm 5cm = 2.5 dm
So, Volume of cube = 2.5
3
= 15.625 dm
3
3. How much clay is dug out in digging a well measuring 3 m by 2 m by 5 m?
Solution:
Given details are,
Dimensions of well = 3m × 2m × 5m
So,
Volume of clay dug out from well is = l × b × h
= 3 × 2 × 5
= 30 m
3
4. What will be the height of a cuboid of volume 168 m
3
, if the area of its base is 28
m
2
?
Solution:
Given details are,
Volume of a cuboid = 168 m
3
Area of base = l × b = 28m
2
Let height of cuboid be ‘h’ m
We know that,
Volume = l × b × h
h = volume/ l × b
= 168/28
= 6m
? Height of cuboid is 6 m
5. A tank is 8 m long, 6 m broad and 2 m high. How much water can it contain?
Solution:
Given details are,
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
Dimensions of a tank = 8m × 6m × 2m
We know that,
Volume of tank = l × b × h
= 8 × 6 × 2
= 96 m
3
= 96000 litres
? The tank can contain 96000 litres of water.
6. The capacity of a certain cuboidal tank is 50000 litres of water. Find the breadth
of the tank, if its height and length are 10 m and 2.5 m respectively.
Solution:
Given details are,
Capacity (volume) of cuboidal tank is = 50000 litre = 50 m
3
Height of tank = 10 m
Length of tank = 2.5 m
Let breadth of tank be ‘b’ m
We know that,
Volume = l × b × h
b = volume / (l × h)
= 50/(10×2.5)
= 2m
? Breadth of tank is 2m
7. A rectangular diesel tanker is 2m long, 2m wide and 40cm deep. How many litres
of diesel can it hold?
Solution:
Given details are,
Length of a tanker = 2m
Breadth of a tanker = 2m
Height of a tanker = 40cm = 0.4m
So, Dimensions of rectangular diesel tank = 2m × 2m × 0.4m
Volume of tank (amount of diesel it can hold) = l × b × h
= 2 × 2 × 0.4
= 1.6m
3
= 1600 litres
? A rectangular diesel tanker can hold 1600 litres of diesel.
8. The length, breadth and height of a room are 5 m, 4.5 m and 3 m respectively.
Find the volume of the air it contains.
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
Solution:
Given details are,
Length of a room = 5m
Breadth of a room = 4.5m
Height of a room = 3m
So, Dimensions of a room are = 5m × 4.5m × 3m
Volume of air = l × b × h
= 5 × 4.5 × 3
= 67.5m
3
? The room contains 67.5m
3
volume of the air.
9. A water tank is 3 m long, 2 m broad and 1 m deep. How many litres of water can
it hold?
Solution:
Given details are,
Length of water tank = 3m
Breadth of water tank = 2m
Height of water tank = 1m
So, Dimensions of water tank is = 3m × 2m × 1m
Volume the water tank can hold = l × b × h
= 3 × 2 × 1
= 6m
3
= 6000 litres
? The water tank can hold 6000 litres of water.
10. How many planks each of which is 3 m long, 15 cm broad and 5 cm thick can be
prepared from a wooden block 6 m long, 75 cm broad and 45 cm thick?
Solution:
Given details are,
Dimensions of one plank = 3m × 15cm × 5cm = 300cm × 15cm × 5cm
Dimensions of wooden block = 6m × 75cm × 45cm = 600cm × 75cm × 45cm
We know that,
Number of planks that can be prepared = volume of wooden block / volume of one plank
= (600 × 75 × 45) / (300 × 15 × 5)
= 90 planks
? 90 planks are required to prepare the block.
11. How many bricks each of size 25 cm × 10 cm × 8 cm will be required to build a
wall 5 m long, 3 m high and 16 cm thick, assuming that the volume of sand and
Page 5
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
EXERCISE 21.2 PAGE NO: 21.15
1. Find the volume in cubic metres (cu. m) of each of the cuboids whose dimensions
are:
(i) length = 12 m, breadth = 10 m, height = 4.5 m
(ii) length = 4 m, breadth = 2.5m, height = 50 cm
(iii) length = 10m, breadth = 25 dm, height = 25 cm.
Solution:
(i) Given details are,
Length of a cuboid = 12 m
Breadth of a cuboid = 10m
Height of a cuboid = 4.5 m
By using the formula
Volume of cuboid = l × b × h
= 12 × 10 × 4.5
= 540 m
3
(ii) Given details are,
Length of a cuboid = 4 m
Breadth of a cuboid = 2.5 m
Height of a cuboid = 50 cm = 0.50m
By using the formula
Volume of a cuboid = l × b × h
= 4 × 2.5 × 0.50
= 5 m
3
(iii) Given details are,
Length of a cuboid = 10m
Breadth of a cuboid = 25 dm = 2.5 m
Height of a cuboid = 25 cm = 0.25 m
By using the formula
Volume of a cuboid = l × b × h
= 10 × 2.5 × 0.25
= 6.25 m
3
2. Find the volume in cubic decimetre of each of the cubes whose side is
(i) 1.5 m
(ii) 75cm
(iii) 2 dm 5 cm
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
Solution:
(i) Given details are,
Side of cube = 1.5m = 15 dm
So, Volume of cube = 15
3
= 3375 dm
3
(ii) Given details are,
Side of cube = 75cm = 7.5 dm
So, Volume of cube = 7.5
3
= 421.875 dm
3
(iii) Given details are,
Side of cube = 2dm 5cm = 2.5 dm
So, Volume of cube = 2.5
3
= 15.625 dm
3
3. How much clay is dug out in digging a well measuring 3 m by 2 m by 5 m?
Solution:
Given details are,
Dimensions of well = 3m × 2m × 5m
So,
Volume of clay dug out from well is = l × b × h
= 3 × 2 × 5
= 30 m
3
4. What will be the height of a cuboid of volume 168 m
3
, if the area of its base is 28
m
2
?
Solution:
Given details are,
Volume of a cuboid = 168 m
3
Area of base = l × b = 28m
2
Let height of cuboid be ‘h’ m
We know that,
Volume = l × b × h
h = volume/ l × b
= 168/28
= 6m
? Height of cuboid is 6 m
5. A tank is 8 m long, 6 m broad and 2 m high. How much water can it contain?
Solution:
Given details are,
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
Dimensions of a tank = 8m × 6m × 2m
We know that,
Volume of tank = l × b × h
= 8 × 6 × 2
= 96 m
3
= 96000 litres
? The tank can contain 96000 litres of water.
6. The capacity of a certain cuboidal tank is 50000 litres of water. Find the breadth
of the tank, if its height and length are 10 m and 2.5 m respectively.
Solution:
Given details are,
Capacity (volume) of cuboidal tank is = 50000 litre = 50 m
3
Height of tank = 10 m
Length of tank = 2.5 m
Let breadth of tank be ‘b’ m
We know that,
Volume = l × b × h
b = volume / (l × h)
= 50/(10×2.5)
= 2m
? Breadth of tank is 2m
7. A rectangular diesel tanker is 2m long, 2m wide and 40cm deep. How many litres
of diesel can it hold?
Solution:
Given details are,
Length of a tanker = 2m
Breadth of a tanker = 2m
Height of a tanker = 40cm = 0.4m
So, Dimensions of rectangular diesel tank = 2m × 2m × 0.4m
Volume of tank (amount of diesel it can hold) = l × b × h
= 2 × 2 × 0.4
= 1.6m
3
= 1600 litres
? A rectangular diesel tanker can hold 1600 litres of diesel.
8. The length, breadth and height of a room are 5 m, 4.5 m and 3 m respectively.
Find the volume of the air it contains.
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
Solution:
Given details are,
Length of a room = 5m
Breadth of a room = 4.5m
Height of a room = 3m
So, Dimensions of a room are = 5m × 4.5m × 3m
Volume of air = l × b × h
= 5 × 4.5 × 3
= 67.5m
3
? The room contains 67.5m
3
volume of the air.
9. A water tank is 3 m long, 2 m broad and 1 m deep. How many litres of water can
it hold?
Solution:
Given details are,
Length of water tank = 3m
Breadth of water tank = 2m
Height of water tank = 1m
So, Dimensions of water tank is = 3m × 2m × 1m
Volume the water tank can hold = l × b × h
= 3 × 2 × 1
= 6m
3
= 6000 litres
? The water tank can hold 6000 litres of water.
10. How many planks each of which is 3 m long, 15 cm broad and 5 cm thick can be
prepared from a wooden block 6 m long, 75 cm broad and 45 cm thick?
Solution:
Given details are,
Dimensions of one plank = 3m × 15cm × 5cm = 300cm × 15cm × 5cm
Dimensions of wooden block = 6m × 75cm × 45cm = 600cm × 75cm × 45cm
We know that,
Number of planks that can be prepared = volume of wooden block / volume of one plank
= (600 × 75 × 45) / (300 × 15 × 5)
= 90 planks
? 90 planks are required to prepare the block.
11. How many bricks each of size 25 cm × 10 cm × 8 cm will be required to build a
wall 5 m long, 3 m high and 16 cm thick, assuming that the volume of sand and
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
cement used in the construction is negligible?
Solution:
Given details are,
Size of one brick = 25cm × 10cm × 8cm
Dimensions of wall = 5m × 3m × 16cm = 500 cm × 300 cm × 16cm
We know that,
Number of bricks required to build a wall = volume of wall / volume of one brick
= (500×300×16) / (25×10×8)
= 1200 bricks
? 1200 bricks are required to build the wall.
12. A village, having a population of 4000, required 150 litres water per head per
day. It has a tank which is 20 m long, 15 m broad and 6 m high. For how many days
will the water of this tank last?
Solution:
Given details are,
Population of village = 4000
Dimensions of water tank = 20m × 15m × 6m
Water required per head per day = 150 litres
Total requirement of water per day = 150 × 4000 = 600000 litres
Volume of water tank = l × b × h
= 20 × 15 × 6
= 1800m
3
= 1800000 litres
We know that,
Number of days water last in the tank = volume of tank / total requirement
= 1800000/600000
= 3 days
? Water in the tank last for 3 days.
13. A rectangular field is 70 m long and 60 m broad. A well of dimensions 14 m × 8
m × 6 m is dug outside the field and the earth dug-out from this well is spread
evenly on the field. How much will the earth level rise?
Solution:
Given details are,
Dimensions of rectangular field = 70m × 60m
Dimensions of well = 14m × 8m × 6m
Amount of earth dug out from well (volume) = l × b × h
= 14 × 8 × 6 = 672m
3
Read More
|
79 videos|408 docs|31 tests
|
Related Exams
About this Document
|
4.76/5 Rating |
|
Nov 23, 2024 Last updated |
Document Description: Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 for Class 8 2024 is part of Mathematics (Maths) Class 8 preparation.
The notes and questions for Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 have been prepared according to the Class 8 exam syllabus. Information about Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 covers topics
like and Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 Example, for Class 8 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2.
Introduction of Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 in English is available as part of our Mathematics (Maths) Class 8
for Class 8 & Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 in Hindi for Mathematics (Maths) Class 8 course.
Download more important topics related with notes, lectures and mock test series for Class 8
Exam by signing up for free. Class 8: Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 | Mathematics (Maths) Class 8
Description
Full syllabus notes, lecture & questions for Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 | Mathematics (Maths) Class 8 - Class 8 | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 8 | Best notes, free PDF download
Information about Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2
In this doc you can find the meaning of Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 defined & explained in the simplest way possible. Besides explaining types of
Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 theory, EduRev gives you an ample number of questions to practice Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 tests, examples and also practice Class 8
tests
|
Explore Courses for Class 8 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
Semester Notes
,Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 | Mathematics (Maths) Class 8
,Summary
,past year papers
,Exam
,study material
,Objective type Questions
,Viva Questions
,MCQs
,ppt
,Sample Paper
,Important questions
,Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 | Mathematics (Maths) Class 8
,mock tests for examination
,Free
,shortcuts and tricks
,practice quizzes
,Extra Questions
,Previous Year Questions with Solutions
,video lectures
,Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 | Mathematics (Maths) Class 8
;
Additional Information about Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 for Class 8 Preparation
Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 Free PDF Download
The Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 is an invaluable resource that delves deep into the core of the Class 8 exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 now and kickstart your journey towards success in the Class 8 exam.
Importance of Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2
The importance of Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 cannot be overstated, especially for Class 8 aspirants.
This document holds the key to success in the Class 8 exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 Notes
Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2.
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 Notes on EduRev are your ultimate resource for success.
Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 Class 8 Questions
The "Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 Class 8 Questions" guide is a valuable resource for all aspiring students preparing for the
Class 8 exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 on the App
Students of Class 8 can study Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2,
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.2 is prepared as per the latest Class 8 syllabus.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup