Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev

DC Pandey (Questions & Solutions) of Physics: NEET

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NEET : Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev

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Objective Questions (Level 1) 
Single Correct Option
Ques 1: A packet is released from a rising balloon accelerating upward with acceleration a. The acceleration of the stone just after the release is 
(a) a upward 
(b) g downward 
(c) (g - a) downward 
(d) (g + a) downward
Ans:  g downward
Sol: As the packet is detached from rising balloon its acceleration will be g in the downward direction.
Option (b) is correct.

Ques 2: A ball is thrown vertically upwards from the ground. If T1 and T2 are the respective time taken in going up and coming down, and the air resistance is not ignored, then 
(a) T1 > T2 
(b) T1 = T2 
(c) T1 < T2 
(d) nothing can be said
Ans: T1 < T2 
Sol: While going up:
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Using v2 = u2 + 2as
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
i.e., Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
While coming down
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Using Eq. (i) and Eq. (ii)
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
⇒ T2 > T1
Option (c) is correct.

Ques 3: The length of a seconds hand in watch is 1 cm. The change in velocity of its tip in 15 s is
(a) zero 
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Ans: Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Sol: Angular speed (ω) of seconds hand
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Speed of the tip of seconds hand
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev cm/s   [∵ v = rω and r = 1 cm]
As in 15s the seconds hand rotates through 90°, the change in velocity of its tip in 15 s will be
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Option (d) is correct.

Ques 4: A particle moving along a straight line travels half of the distance with uniform speed 30 ms-1 and the rem aining half of the distance with speed 60 ms-1. The average speed of the particle is 
(a) 45 ms-1 
(b) 42 ms-1 
(c) 40 ms-1 
(d) 50 ms-1
Ans: 40 ms-1
Sol: 
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Option (c) is correct.

Ques 5: A boat is moving with a velocity Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev with respect to ground. The water in the river is moving with a velocity Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev with respect to ground. The relative velocity of the boat with respect to water is
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
(d) zero
Sol: Relative velocity of boat w.r.t. water
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Option (b) is correct.

Ques 6: During the first 18 min of a 60 min trip, a car has an average speed of 11 ms 1. What should be the average speed for remaining 42 min so that car is having an average speed of 21 ms -1 for the entire trip ? 
(a) 25.3 ms-1 
(b) 29.2 ms-1 
(c) 31 ms-1 
(d) 35.6 ms-1
Ans: 25.3 ms-1 
Sol:
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev


Ques 7: A particle moves along a straight line. Its position at any instant is given by Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev where x is in metre and t in second. Find the acceleration of the particle at the instant when particle is at rest, 
(a) -16 ms-2 
(b) -32 ms-2 
(c) 32 ms-2 
(d) 16 ms-2
Ans: -32 ms-2 
Sol: 
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev

Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev  …(i)
∴ Particle is at rest when
32 - 8 t2 = 0
i.e., t = 2 s
Differentiating Eq. (i) w.r.t. time t
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
∴ a at time t = 2 s (when particle is at rest)
= - (16) x (2) = -32 m/s2 
Option (b) is correct.

Ques 8: A car starts from rest and accelerates at constant rate in a straight line. In the first second the car covers a distance of 2 m. The velocity of the car at the end of second (sec) will be 
(a) 4.0 ms-1 
(b) 8.0 ms-1 
(c) 16 ms-1 
(d) None of these
Ans: 8.0 ms-1 
Sol: For first one second
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
⇒ a = 4 m/s2 
Velocity at the end of next second
v = (4) x (2) = 8 m/s
Option (b) is correct.

Ques 9: A particle is moving along x-axis whose position is varying with time according to the relation x = - 3t + t3 where x is in metre and t is in second. The displacement of particle for t = 1 s to t = 3 s is 
(a) +16 m 
(b) -16 m 
(c) +20 m 
(d) -20 m
Ans: +20 m
Sol: x = - 3t + t3
∴ displacement at time t (= 1 s)
= - 3(1) + (1)3 = - 2 m
and displacement at time t (= 3 s)
= - 3(3) + (3)3 = 18 m
And as such displacement in the time interval (t = 1 s to t = 3 s)
= (18 m) - (- 2 m)
= + 20 m
Option (c) is correct.

Ques 10: The acceleration of a particle is increasing linearly with time t as bt. The particle starts from the origin with an initial velocity v0. The distance travelled by the particle in time t will be
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Ans: Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Sol: Acceleration α = bt
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
or  Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
or Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Now, at t = 0, v = v0
∴ C = v0
i.e., Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
or Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
or Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
or Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
At t = 0, s = 0,
∴ k = 0
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Option (a) is correct.

Ques 11: Water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap, the instant the first drop touches the ground. How far above the ground is the second drop at that instant, (g = 1 0 ms-2
(a) 1.25 m 
(b) 2.50 m 
(c) 3.75 m 
(d) 4.00 m
Ans: 3.75 m
Sol:Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev 
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
∴  Height of 2nd drop  from ground
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Option (c) is correct.

Ques 12: A stone is dropped from the top of a tower and one second later, a second stone is thrown vertically downward with a velocity 20 ms-1. The second stone will overtake the first after travelling a distance of (g = 10 ms-2
(a) 13 m 
(b) 15 m 
(c) 11.25 m 
(d) 19.5 m
Ans: 11.25 m
Sol: 
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
  [At time = t - 1]
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
or    t2 = 4 (t - 1) + (t2 - 2t + 1)
or    2t - 3 = 0
or Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
= 11.25 m
Option (c) is correct.

Ques 13: When a ball is thrown up vertically with velocity v0, it reaches a maximum height of h. If one wishes to triple the maximum height then the ball should be thrown with velocity
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
(b) 3 v0 
(c) 9 v0 
(d) 3/2 v0
Ans:Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Sol: Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev and u2 = 2g (3h)
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
or  u = v0√3
Option (a) is correct.

Ques 14: A particle moves in the x-y plane with velocity vx = 8t - 2 and vy = 2. If it passes through the point x = 14 and y = 4 at t = 2 s, the equation of the path is 
(a) x = y2 - y + 2
(b) x = y2 - 2
(c) x = y2 + y - 6
(d) None of these

Ans: x = y2 - y + 2
Sol:  vx = 8t - 2
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
or       ∫ dx = ∫ (8 t - 2) dt
or        x = 4t2 - 2t + k1
Now at t = 2,  x = 14
∴ 14 = 4 × 22 - (2) 2 + k1 
i.e.,        k1 = 2
Thus, x = 4 t2 - 2t + 2 …(i)
Further, vy = 2
i.e., Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
or ∫ dy = ∫ 2 dt
or  y = 2t + k2
Now, at t = 2, y = 4
∴ k2 = 0
Thus, y = 2t   …(ii)
Substituting t = y/2 in Eq. (i),
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
or   x = y2 - y + 2
Option (a) is correct.

Ques 15: The horizontal and vertical displacements of a particle moving along a curved line are given by x = 5t and y = 2t2 + 1. Time after which its velocity vector makes an angle o f 45° with the horizontal is 
(a) 0.5 s 
(b) 1 s 
(c) 2 s 
(d) 1.5 s
Ans: 1 s
Sol: x = 5t and y = 2t2 + t
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Now,  
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
⇒ t = 1 s
Option (b) is correct.

Ques 16: The height y and the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y = (8t - 5 t2) metre and x = 6t metre where t is in second. The velocity of projection is 
(a) 8 ms-1 
(b) 6 ms-1 
(c) 10 ms-1 
(d) data insufficient
Ans: 10 ms-1 
Sol: y = 8t - 5t2 and x = 6t
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
At t = 0
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
∴ Velocity of projection
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Option (c) is correct.

Ques 17: A ball is released from the top of a tower of height h metre. It takes T second to reach the ground. What is the position of the ball in T/3 second?
(a) h/9 metre from the ground
(b) (7h/9) metre from the ground
(c) (8h/9) metre from the ground
(d) (17h/18)metre form the ground
Ans: (8h/9) metre from the ground
Sol: 
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Option (c) is correct.

Ques 18: An ant is at a comer of a cubical room of side a. The ant can move with a constant speed u. The minimum time taken to reach the farthest comer of the cube is
(a) 3a/u 
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Ans: Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Sol: Distance of farthest corner from one corner
= a + a + a = 3 a
∴ Time taken = 3a/u
Option (a) is correct.

Ques 19: A lift starts from rest. Its acceleration is plotted against time. When it comes to rest its height above its starting point is
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
(a) 20 m
(b) 64 m
(c) 32 m
(d) 36 m

Ans: 64 m
Sol: Time-velocity graph of the given time-acceleration graph will be
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
∴ Height of lift above the starting point when it comes to rest
= Area under t-v graph
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Option (b) is correct.

Ques 20: A lift performs the first part of its ascent with uniform acceleration a and the remaining with uniform retardation 2a. If t is the time of ascent, find the depth of the shaft.
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Ans: Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Sol: 
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
In time interval t1
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
In time interval t2
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
i.e.,   t1 = 2t2
Now   t1 + t2 = t
∴  2t2 + t2 = t
or  t2 = t/3
Depth of shaft = Displacement of lift
Motion in One Dimension: JEE Main(Part- 5) - Physics, Solution by DC Pandey NEET Notes | EduRev
Option (b) is correct.

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