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Mutual Inductance Notes | Study Physics For JEE - JEE

Document Description: Mutual Inductance for JEE 2022 is part of Electromagnetic Induction for Physics For JEE preparation. The notes and questions for Mutual Inductance have been prepared according to the JEE exam syllabus. Information about Mutual Inductance covers topics like and Mutual Inductance Example, for JEE 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Mutual Inductance.

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10. MUTUAL INDUCTANCE

Consider two coils P and S placed close to each other as shown in the figure. When the current passing through a coil increases or decreases, the magnetic flux linked with the other coil also changes and an induced e.m.f. is developed in it. This phenomenon is known as mutual induction. This coil in which current is passed is known as primary and the other in which e.m.f. is developed is called as secondary.

Let the current through the primary coil at any instant be i1. Then the magnetic flux Mutual Inductance Notes | Study Physics For JEE - JEE in the secondary at any time will be proportional to i1 i.e., Mutual Inductance Notes | Study Physics For JEE - JEE is directly proportional to i1

Therefore the induced e.m.f. in secondary

when i1 changes is given by

Mutual Inductance Notes | Study Physics For JEE - JEE i.e., Mutual Inductance Notes | Study Physics For JEE - JEE

Mutual Inductance Notes | Study Physics For JEE - JEE = Mutual Inductance Notes | Study Physics For JEE - JEE ⇒ Mutual Inductance Notes | Study Physics For JEE - JEE = M i1            Mutual Inductance Notes | Study Physics For JEE - JEE

where M is the constant of proportionality and is known as mutual inductance of two coils. It is defined as the e.m.f. induced in the secondary coil by unit rate of change of current in the primary coil. The unit of mutual inductance is henry (H).

10.1 Mutual Inductance of a Pair of Solenoids one Surrounding the other coil

Figure shows a coil of N2 turns and radius R2 surrounding a long solenoid of length l1, radius R1 and number of turns N1.

Mutual Inductance Notes | Study Physics For JEE - JEE

To calculate mutual inductance M between them, let us assume a current i1 through the inner solenoid S1

There is no magnetic field outside the solenoid and the field inside has magnitude,

Mutual Inductance Notes | Study Physics For JEE - JEE

and is directed parallel to the solenoid's axis. The magnetic flux Mutual Inductance Notes | Study Physics For JEE - JEE through the surrounding coil is, therefore,

Mutual Inductance Notes | Study Physics For JEE - JEE

Now, Mutual Inductance Notes | Study Physics For JEE - JEE

Notice that M is independent of the radius R2 of the surrounding coil. This is because solenoid's magnetic field is confined to its interior.

Brain Teaser

What is the meaning of the statement "The coefficient of mutual inductance for a pair of coils is large" ?

Note : Mutual Inductance Notes | Study Physics For JEE - JEE

Mutual Inductance Notes | Study Physics For JEE - JEE For two coils in series if mutual inductance is considered then

Leq = L1 + L2 ± 2M

Ex.48 Find the mutual inductance of two concentric coils of radii a1 and a(a1 << a2) if the planes of coils are same.

Mutual Inductance Notes | Study Physics For JEE - JEE

Sol. Let a current i flow in coil of radius a2.

Magnetic field at the centre of coil =

or M i = Mutual Inductance Notes | Study Physics For JEE - JEE or Mutual Inductance Notes | Study Physics For JEE - JEE

Ex.49 Solve the above question, if the planes of coil are perpendicular.

Sol. Let a current i flow in the coil of radius a1. The magnetic field at the centre of this coil will now be parallel to the plane of smaller coil and hence no flux will pass through it, hence M = 0

Ex.50 Solve the above problem if the planes of coils make θ angle with each other.

Sol. If i current flows in the larger coil, magnetic field produced at the centre will be perpendicular to the plane of larger coil.

Now the area vector of smaller coil which is perpendicular to the plane of smaller coil will make an angle θ with the magnetic field.

Thus flux = Mutual Inductance Notes | Study Physics For JEE - JEE. πa12 cos θ

or M = Mutual Inductance Notes | Study Physics For JEE - JEE

Ex.51 Find the mutual inductance between two rectangular loops, shown in figure.

Mutual Inductance Notes | Study Physics For JEE - JEE

Sol. Let current i flow in the loop having ∞-by long sides. Consider a segment of width dx at a distance x as shown flux through the regent

Mutual Inductance Notes | Study Physics For JEE - JEE

dMutual Inductance Notes | Study Physics For JEE - JEEMutual Inductance Notes | Study Physics For JEE - JEE

⇒ Mutual Inductance Notes | Study Physics For JEE - JEE = Mutual Inductance Notes | Study Physics For JEE - JEE

Mutual Inductance Notes | Study Physics For JEE - JEE

Ex.52 Figure shows two concentric coplanar coils with radii a and b (a << b). A current i = 2t flows in the smaller loop. Neglecting self inductance of larger loop

Mutual Inductance Notes | Study Physics For JEE - JEE

(a) Find the mutual inductance of the two coils

(b) Find the emf induced in the larger coil

(c) If the resistance of the larger loop is R find the current in it as a function of time

Sol. (a) To find mutual inductance, it does not matter in which coil we consider current and in which flux is calculated (Reciprocity theorem) Let current i be flowing in the larger coil. Magnetic field at the centre = Mutual Inductance Notes | Study Physics For JEE - JEE.

flux through the smaller coil = Mutual Inductance Notes | Study Physics For JEE - JEE

Therefore, M = Mutual Inductance Notes | Study Physics For JEE - JEE

(ii) |emf induced in larger coil| = Mutual Inductance Notes | Study Physics For JEE - JEE

Mutual Inductance Notes | Study Physics For JEE - JEE = Mutual Inductance Notes | Study Physics For JEE - JEE

(iii) current in the larger coil = Mutual Inductance Notes | Study Physics For JEE - JEE

Ex.53 If the current in the inner loop changes according to i = 2t2 then, find the current in the capacitor as a function of time.

Mutual Inductance Notes | Study Physics For JEE - JEE

Sol. M = Mutual Inductance Notes | Study Physics For JEE - JEE

|emf induced in larger coil| = Mutual Inductance Notes | Study Physics For JEE - JEE

e = Mutual Inductance Notes | Study Physics For JEE - JEE = Mutual Inductance Notes | Study Physics For JEE - JEE    Mutual Inductance Notes | Study Physics For JEE - JEE

Applying KVL : -

+e - Mutual Inductance Notes | Study Physics For JEE - JEE - iR = 0 ⇒ Mutual Inductance Notes | Study Physics For JEE - JEE - -iR = 0

differentiate wrt time : Mutual Inductance Notes | Study Physics For JEE - JEE - Mutual Inductance Notes | Study Physics For JEE - JEE - Mutual Inductance Notes | Study Physics For JEE - JEEon solving it i = Mutual Inductance Notes | Study Physics For JEE - JEE

11. Series Combination of Inductors

Mutual Inductance Notes | Study Physics For JEE - JEE = Mutual Inductance Notes | Study Physics For JEE - JEE

Therefore, V = V1 + V2

Mutual Inductance Notes | Study Physics For JEE - JEE

L = L1 + L2 +.................

Parallel Combination of inductor

i = i1 + i2 ⇒ Mutual Inductance Notes | Study Physics For JEE - JEE     Mutual Inductance Notes | Study Physics For JEE - JEE

Mutual Inductance Notes | Study Physics For JEE - JEE

Mutual Inductance Notes | Study Physics For JEE - JEE

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