NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

Mathematics (Maths) Class 12

JEE : NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

The document NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev is a part of the JEE Course Mathematics (Maths) Class 12.
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Continuity & Differentiability

 Question 1:
 If x and y are connected parametrically by the equation, without eliminating the

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev


Answer

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev


Question 2: If x and y are connected parametrically by the equation, without eliminating the
 parameter, find 
NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev.
 x = a cos θ, y = b cos θ


Answer
The given equations are x = a cos θ and y = b cos θ
NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev


Question 3: If x and y are connected parametrically by the equation, without eliminating the
 parameter, find 
NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev.
 x = sin t, y = cos 2t


Answer
The given equations are x = sin t and y = cos 2t

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

 

Question 4:
 If x and y are connected parametrically by the equation, without eliminating the
NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev.


Answer
NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev


Question 5: If x and y are connected parametrically by the equation, without eliminating the 
NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

 Answer
The given equations are

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

Question 6: If x and y are connected parametrically by the equation, without eliminating the

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev


Answer

The given equations are

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev


Question 7: If x and y are connected parametrically by the equation, without eliminating the

parameter,  find  NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev.


Answer

The given equations are

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

 

Question 8: If x and y are connected parametrically by the equation, without eliminating the

parameter, find NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev


Answer
The given equations are NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev


 Question 9: If x and y are connected parametrically by the equation, without eliminating the
 parameter, find 
NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev.



Answer

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

 


Question 10: If x and y are connected parametrically by the equation, without eliminating the

parameter, find  NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev.


Answer
NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

Question 11:
 If 
NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev


Answer
NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev
NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev

NCERT Solutions - Continuity & Differentiability, Exercise 5.6 JEE Notes | EduRev
Hence, proved.

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