NCERT Solutions Exercise 5.6: Continuity & Differentiability | Mathematics For JEE

Continuity & Differentiability

 Question 1:
 If x and y are connected parametrically by the equation, without eliminating the

Answer

Question 2: If x and y are connected parametrically by the equation, without eliminating the
 parameter, find .
 x = a cos θ, y = b cos θ

Answer
The given equations are x = a cos θ and y = b cos θ

Question 3: If x and y are connected parametrically by the equation, without eliminating the
 parameter, find .
 x = sin t, y = cos 2t

Answer
The given equations are x = sin t and y = cos 2t

Question 4:
 If x and y are connected parametrically by the equation, without eliminating the

.

Answer

Question 5: If x and y are connected parametrically by the equation, without eliminating the 

 Answer
The given equations are

Question 6: If x and y are connected parametrically by the equation, without eliminating the

Answer

The given equations are

Question 7: If x and y are connected parametrically by the equation, without eliminating the

parameter,  find  .

Answer

The given equations are

Question 8: If x and y are connected parametrically by the equation, without eliminating the

parameter, find 

Answer
The given equations are

 Question 9: If x and y are connected parametrically by the equation, without eliminating the
 parameter, find .

Answer

Question 10: If x and y are connected parametrically by the equation, without eliminating the

parameter, find  .

Answer


Question 11:
 If 

Answer

Hence, proved.