The document NCERT Solutions(Part - 1) - Fractions and Decimals Class 7 Notes | EduRev is a part of the Class 7 Course Mathematics (Maths) Class 7.

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**Exercise 2.1**

**Q.1. Solve:****(i)****(ii)** **(iii) ****(iv)** **(v)** **(vi)** **(vii)** **Ans.****(i)****(ii) ** **(iii)** **(iv)** **(v)** **(vi)** **(vii) ** **Q.2.**** ****Arrange the following in descending order:****(ii)****Ans.****(i) **

[Converting into like fractions]**⇒ **

[Arranging in descending order]**⇒ **Therefore,

**(ii) **

[Converting into like fractions]

⇒

[Arranging in descending order]

⇒

Therefore,**Q.3.**** ****In a “magic square”, the sum of the numbers in each row, in each column and along the diagonals is the same. Is this a magic square?**

**Ans.**** **Sum of first row** **

Sum of second row

Sum of third row

Sum of first column

Sum of second column

Sum of third column

Sum of first diagonal [left to right)

Sum of second diagonal [left to right]

Since the sum of fractions in each row, in each column and along the diagonals are same, therefore it is a magic square.**Q.4.**** ****A rectangular sheet of paper is **** cm wide. Find its perimeter. ****Ans.**** ****Given**:** **The sheet of paper is in rectangular form.

Length of sheet** =** cm and Breadth of sheet cm

Perimeter of rectangle = 2 (length + breadth)

Thus, the perimeter of the rectangular sheet is **Q.5.** **Find the perimeter of ****(i) ΔABE ****(ii) the rectangle BCDE in this figure. ****Whose perimeter is greater?**

**Ans.****(i)** In ΔABE

The perimeter of ΔABE = AB + BE + AE

=

Thus, the perimeter of ΔABE iscm

**(ii)** In rectangle BCDE,

Perimeter of rectangle = 2 [length + breadth]

Thus, the perimeter of rectangle BCDE is

Comparing the perimeter of triangle and that of rectangle,

Therefore, the perimeter of triangle ABE is greater than that of rectangle BCDE.**Q.6.**** ****Salil wants to put a picture in a frame. The picture is ** **cm wide. To fit in the frame the picture cannot be more than cm wide. How much should the picture be trimmed?****Ans.****Given**: The width of the picture

and the width of picture frame

Therefore, the picture should be trimmed

Thus, the picture should be trimmed by **Q.7.**** ****Ritu ate 3/5 part of an apple and the remaining apple was eaten by her brother Somu. How much part of the apple did Somu eat? Who had the larger share? By how much? ****Ans.**** **The part of an apple eaten by Ritu = 3/5

The part of an apple eaten by Somu

Comparing the parts of apple eaten by both Ritu and Somu

Larger share will be more b

Thus, Ritu's part is 1/5 more than Somu’s part.**Q.8.**** ****Michael finished colouring a picture in 7/12 hour. Vaibhav finished colouring the same picture in 3/4 hour. Who worked longer? By what fraction was it longer? ****Ans.**** **Time taken by Michael to colour the picture = 7/2 hour

Time taken by Vaibhav to colour the picture = 3/4 hour

Converting both fractions in like fractions,

Here,

Thus, Vaibhav worked longer time.

Vaibhav worked longer time by

Thus, Vaibhav took 1/6 hour more than Michael.

**Exercise 2.2 **

**Q.1.**** ****Which of the drawings (a) to (d) show: **

**Ans.****Q.2.**** ****Some pictures (a) to (c) are given below. Tell which of them show:**

**Ans.****Q.3.**** ****Multiply and reduce to lowest form and convert into a mixed fraction: ****(i) ****(ii) ****(iii) ****(iv) ****(v) ****(vi) ****(vii) ****(viii) ****(ix) ****(x) ****Ans.****(i) (ii) (iii) (iv) (v) (vi) (vii) (viii) (ix) (x) **

**Ans.**

**Q.5.**** ****Find: ****(a) ****1/2 of (i) 24 (ii) 46(b) 2/3 of (i) 18 (ii) 27(c) 3/4 of (i) 16 (ii) 36 (d) 4/5 of (i) 20 (ii) 35**

(c) (i)

(d) (i)

(ii)

(ii)

(b) (i)

(ii)

Thus, Vidya drank 2 litres water from the bottle.**(ii)** Pratap consumed

Pratap consumed 3/5 of 5 litres water

Thus, Pratap drank 3/5 part of the total quantity of water.

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