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**Exercise 2.3 ****Ques 1****:**** ****Find****:**** ****(i) ****1/4 of (a) 1/4 (b) 3/5 (c) 4/3(ii) 1/7 of (a) 2/9 (b) 6/5 (c) 3/10**

(b)

(c)

**(ii) (a) (b) (c) **

(ii)

(iii)

(iv)

(v)

(vi)

(vii)

**Ans****:****(i) (ii) (iii) (iv) (v) (vi) (vii) **

**(i) (ii) (iii) (iv) (v) (vi) (vii) **

(ii)

(iii)

(iv)

(v)

(vi)

(vii)

(ii)

â‡’

â‡’

â‡’

**(ii)â‡’â‡’â‡’**

Saili planted 4 saplings in a row, then number of gap in saplings = 3

Therefore,

The distance between the first and the last saplings

Thus the distance between the first and the last saplings is

She reads entire book in 6 days.

Now, total hours taken by her to read the entire book

Thus, 10 hours were required by her to read the book.

In litres of petrol, car covers the distance =

Thus, the car will cover 44 km distance.

(ii) The simplest form

(ii)

(iii)

(iii)

(iv)

(v)

(ii)

(iii)

(iv)

(v)

(vi)

(ii)

(iii)

(iv)

(v)

(vi)

(vii)

(viii)

âˆµ

âˆ´

(ii)

(iii)

(iv)

(v)

âˆµ 100 cm = 1 meter

âˆ´ 1 cm = 1/100 meter

â‡’ 5 cm = 5/100 = 0.05 meter

Now,

âˆ´ 1000 meters = 1 kilometers

âˆ´ 1 meters = 1/1000 kilometer

â‡’ 0.05 meter = 0.05/1000 = 0.00005 kilometer

âˆµ 10 mm = 1 cm

âˆ´ 1 mm = 1/10 cm

â‡’ 35 mm = 35/100 = 3.5 cm

Now, âˆµ 100 cm = 1 meter

âˆ´ 1 cm = 1/100 meter

â‡’ 3.5 cm = 3.5/100 = 0.035 meter

Again,

âˆµ 1000 meters = 1 kilometers

âˆ´ 1 meter = 1/1000 kilometers

â‡’ 0.035 meter = 0.035/1000 = 0.000035 kilometer

Let us consider, 1000 g = 1 kg

â‡’**(i) ****(ii)** **(iii)** 4kg 8 g = = 5 kg + 0.008 kg = 4.005 kg**Ques 5: ****Write the following decimal numbers in the expanded form: ****(i) 20.03 ****(ii) 2.03 ****(iii) 200.03 ****(iv) 2.034 ****Ans: ****(i) (ii) (iii) (iv) **

Distance travelled by Dinesh when he went from place A to place B = 7.5 km and from place B to C = 12.7 km.

Total distance covered by Dinesh = AB + BC

= 7.5 + 12.7

= 20.2 km

Total distance covered by Ayub = AD + DC

= 9.3 + 11.8

= 21.1 km

On comparing the total distance of Ayub and Dinesh,

21.1 km > 20.2 km

Therefore, Ayub covered more distance by 21.1 â€“ 20.2 = 0.9 km = 900 m**Ques 8: ****Shyam bought 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas. Who bought more fruits? ****Ans: **Total weight of fruits bought by Shyam = 5 kg 300 g + 3 kg 250 g = 8 kg 550 g

Total weight of fruits bought by Sarala = 4 kg 800 g + 4 kg 150 g = 8 kg 950 g

On comparing the quantity of fruits, 8 kg 550 g < 8 kg 950 g

Therefore, Sarala bought more fruits.**Ques: ****How much less is 28 km than 42.6 km? ****Ans: **We have to find the difference of 42.6 km and 28 km.

Difference = 42.6 â€“ 28.0 = 14.6 km

Therefore 14.6 km less is 28 km than 42.6 km.

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