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# NCERT Solutions Chapter 9 - Rational Numbers, Maths, Class 7 | EduRev Notes

## Class 7 : NCERT Solutions Chapter 9 - Rational Numbers, Maths, Class 7 | EduRev Notes

The document NCERT Solutions Chapter 9 - Rational Numbers, Maths, Class 7 | EduRev Notes is a part of the Class 7 Course Mathematics (Maths) Class 7.
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Exercise 9.1

Q1. List five rational numbers between:

(i) -1 and 0
Ans: Let us write -1 and 0 as rational numbers with denominator 6. Therefore, five rational numbers between -1 and 0 would be (ii) -2 and -1
Ans: Let us write -2 and -1 as rational numbers with denominator 6. Therefore, Five rational numbers between -2 and -1 would be (iii) Ans: Let us write as rational numbers with the same denominators. Therefore, five rational numbers between would be (iv) Ans: Let us write as rational numbers with the same denominators. Therefore, five rational numbers between would be Q2. Write four more rational numbers in each of the following patterns:

(i) Ans: Therefore, the next four rational numbers of this pattern would be (ii) Ans: Therefore, the next four rational numbers of this pattern would be (iii) Ans: Therefore, the next four rational numbers of this pattern would be (iv) Ans: Therefore, the next four rational numbers of tins pattern would be Q3. Give four rational numbers equivalent to:

(i) -2/7
Ans: Therefore, four equivalent rational numbers are (ii) 5/-3

Ans: Therefore, four equivalent rational numbers are (iii) 4/9

Ans: Therefore, four equivalent rational numbers are Q4. Draw the number line and represent the following rational numbers on it:

(i) 3/4
Ans: (ii) -5/8
Ans: (iii)  -7/4
Ans: (iv) 7/8
Ans: Q5. The points P, Q, R, S, T, U, A and B on the number line are such that, TR = RS = SU and AP = PQ = QB. Name the rational numbers represented by P, Q, R and S. Ans:
Therefore, Similarly Thus, the rational numbers represented P, Q, R and S are respectively.

Q6. Which of the following pairs represent the same rational numbers:

(i) Ans: [Converting into lowest term] (ii) Ans: [Converting into lowest term] (iii) Ans: [Converting into lowest term] (iv) Ans: [Converting into lowest term] (v) Ans: [Converting into lowest term] (vi) Ans: [Converting into lowest term] (vii) Ans: [Converting into lowest terra] Q7. Rewrite the following rational numbers in the simplest form:

(i) -8/6
Ans:
The given rational numbers can be simplified further,
Then,
= -4/3 … [∵ Divide both numerator and denominator by 2]

(ii) 25/45
Ans:
The given rational numbers can be simplified further,
Then,
= 5/9 … [∵ Divide both numerator and denominator by 5]

(iii) -44/72
Ans:
The given rational numbers can be simplified further,
Then,
= -11/18 … [∵ Divide both numerator and denominator by 4]

(iv) -8/10
Ans:
The given rational numbers can be simplified further,
Then,
= -4/5 … [∵ Divide both numerator and denominator by 2]

Q8. Fill in the boxes with the correct symbol out of <, > and =:

(i) Ans: The LCM of the denominators 7 and 3 is 21
∴ (-5/7) = [(-5 × 3)/ (7 × 3)] = (-15/21)
And (2/3) = [(2 × 7)/ (3 × 7)] = (14/21)
Now, -15 < 14
So,
(-15/21) < (14/21)
Hence, -5/7 [<] 2/3

(ii) Ans: The LCM of the denominators 5 and 7 is 35
∴ (-4/5) = [(-4 × 7)/ (5 × 7)] = (-28/35)
And (-5/7) = [(-5 × 5)/ (7 × 5)] = (-25/35)
Now, -28 < -25
So,
(-28/35) < (- 25/35)
Hence, -4/5 [<] -5/7

(iii) Ans: 14/-16 can be simplified further,
Then,
7/-8 … [∵ Divide both numerator and denominator by 2]
So,
(-7/8) = (-7/8)
Hence, -7/8 [=] 14/-16

(iv) Ans: The LCM of the denominators 5 and 4 is 20
∴ (-8/5) = [(-8 × 4)/ (5 × 4)] = (-32/20)
And (-7/4) = [(-7 × 5)/ (4 × 5)] = (-35/20)
Now, -32 > – 35
So,
(-32/20) > (- 35/20)
Hence, -8/5 [>] -7/4

(v) Ans: The LCM of the denominators 3 and 4 is 12
∴ (-1/3) = [(-1 × 4)/ (3 × 4)] = (-4/12)
And (-1/4) = [(-1 × 3)/ (4 × 3)] = (-3/12)
Now, -4 < – 3
So,
(-4/12) < (- 3/12)
Hence, 1/-3 [<] -1/4

(vi) Ans: Since, (-5/11) = (-5/11)
Hence, 5/-11 [=] -5/11

(vii) Ans: Since every negative rational number is less than 0.
We have:
= 0 [>] -7/6

Q9. Which is greater in each of the following:

(i) Ans: The LCM of the denominators 3 and 2 is 6
(2/3) = [(2 × 2)/ (3 × 2)] = (4/6)
And (5/2) = [(5 × 3)/ (2 × 3)] = (15/6)
Now, 4 < 15
So, (4/6) < (15/6)
∴ 2/3 < 5/2
Hence, 5/2 is greater.

(ii) Ans: The LCM of the denominators 6 and 3 is 6
∴ (-5/6) = [(-5 × 1)/ (6 × 1)] = (-5/6)
And (-4/3) = [(-4 × 2)/ (3 × 2)] = (-12/6)
Now, -5 > -12
So, (-5/6) > (- 12/6)
∴ -5/6 > -12/6
Hence, – 5/6 is greater.

(iii) Ans: The LCM of the denominators 4 and 3 is 12
∴ (-3/4) = [(-3 × 3)/ (4 × 3)] = (-9/12)
And (-2/3) = [(-2 × 4)/ (3 × 4)] = (-8/12)
Now, -9 < -8 So, (-9/12) < (- 8/12)
∴ -3/4 < 2/-3
Hence, 2/-3 is greater.

(iv) Ans: The given fraction is like friction,
So, -¼ < ¼
Hence ¼ is greater,

(v) Ans: First we have to convert mixed fraction into improper fraction, = -23/7 = -19/5
Then, The LCM of the denominators 7 and 5 is 35
∴ (-23/7) = [(-23 × 5)/ (7 × 5)] = (-115/35)
And (-19/5) = [(-19 × 7)/ (5 × 7)] = (-133/35)
Now, -115 > -133 So, (-115/35) > (- 133/35) > Hence, is greater.

Q10. Write the following rational numbers in ascending order:

(i)  -3/5, -2/5, -1/5
Ans:
The given rational numbers are in form of like fraction,
Hence, (-3/5)< (-2/5) < (-1/5)

(ii) -1/3, -2/9, -4/3
Ans:
To convert the given rational numbers into like fraction we have to find LCM,
LCM of 3, 9, and 3 is 9
Now,
(-1/3)= [(-1 × 3)/ (3 × 9)] = (-3/9)
(-2/9)= [(-2 × 1)/ (9 × 1)] = (-2/9)
(-4/3)= [(-4 × 3)/ (3 × 3)] = (-12/9)
Clearly, (-12/9) < (-3/9) < (-2/9)
Hence, (-4/3) < (-1/3) < (-2/9)

(iii) -3/7, -3/2, -3/4
Ans:
To convert the given rational numbers into like fraction we have to find LCM,
LCM of 7, 2, and 4 is 28
Now, (-3/7)= [(-3 × 4)/ (7 × 4)] = (-12/28)
(-3/2)= [(-3 × 14)/ (2 × 14)] = (-42/28)
(-3/4)= [(-3 × 7)/ (4 × 7)] = (-21/28)
Clearly, (-42/28) < (-21/28) < (-12/28)
Hence, (-3/2) < (-3/4) < (-3/7)

Exercise 9.2

Q1. Find the sum:

(i) Ans: We have:
= (5/4) – (11/4) = [(5 – 11)/4] … [∵ denominator is same in both the rational numbers]
= (-6/4)
= -3/2 … [∵ Divide both numerator and denominator by 3]

(ii) Ans: Take the LCM of the denominators of the given rational numbers.
LCM of 3 and 5 is 15 Express each of the given rational numbers with the above LCM as the common denominator.
Now, (5/3) = [(5 × 5)/ (3 × 5)] = (25/15)
(3/5) = [(3 × 3)/ (5 × 3)] = (9/15)
Then,
= (25/15) + (9/15) … [∵ denominator is same in both the rational numbers]
= (25 + 9)/15 = 34/15

(iii) Ans: Take the LCM of the denominators of the given rational numbers.
LCM of 10 and 15 is 30 Express each of the given rational numbers with the above LCM as the common denominator.
Now,
(-9/10)= [(-9 × 3)/ (10 × 3)] = (-27/30)
(22/15)= [(22 × 2) / (15 × 2)] = (44/30)
Then, = (-27/30) + (44/30) … [∵ denominator is same in both the rational numbers]
= (-27 + 44)/30
= (17/30)

(iv) Ans: We have, = 3/11 + 5/9
Take the LCM of the denominators of the given rational numbers.
LCM of 11 and 9 is 99
Express each of the given rational numbers with the above LCM as the common denominator.
Now,
(3/11) = [(3 × 9)/ (11 × 9)] = (27/99)
(5/9) = [(5 × 11)/ (9 × 11)] = (55/99)
Then,
= (27/99) + (55/99) … [∵ denominator is same in both the rational numbers]
= (27 + 55)/99
= (82/99)

(v) Ans: We have = -8/19 – 2/57
Take the LCM of the denominators of the given rational numbers.
LCM of 19 and 57 is 57
Express each of the given rational numbers with the above LCM as the common denominator.
Now,
(-8/19)= [(-8 × 3)/ (19 × 3)] = (-24/57) (-2/57)= [(-2 × 1)/ (57 × 1)] = (-2/57)
Then,
= (-24/57) – (2/57) … [∵ denominator is same in both the rational numbers]
= (-24 – 2)/57 = (-26/57)

(vi) Ans: We know that any number or fraction is added to zero the answer will be the same number or fraction.
Hence,
= -2/3 + 0
= -2/3

(vi) Ans: [L.C.M. of 3 and 5 is 15] Q2. Find:

(i) Ans: Take the LCM of the denominators of the given rational numbers.
LCM of 24 and 36 is 72
Express each of the given rational numbers with the above LCM as the common denominator.
Now,
(7/24)= [(7 × 3)/ (24 × 3)] = (21/72)
(17/36)= [(17 × 2)/ (36 × 2)] = (34/72)
Then,
= (21/72) – (34/72) … [∵ denominator is same in both the rational numbers]
= (21 – 34)/72 = (-13/72)

(ii) Ans: We can also write -6/21 = -2/7
= 5/63 – (-2/7)
We have, = 5/63 + 2/7
Take the LCM of the denominators of the given rational numbers.
LCM of 63 and 7 is 63
Express each of the given rational numbers with the above LCM as the common denominator.
Now,
(5/63)= [(5 × 1)/ (63 × 1)] = (5/63)
(2/7)= [(2 × 9)/ (7 × 9)] = (18/63)
Then, = (5/63) + (18/63) … [∵ denominator is same in both the rational numbers]
= (5 + 18)/63 = 23/63

(iii) Ans: We have, = -6/13 + 7/15
LCM of 13 and 15 is 195
Express each of the given rational numbers with the above LCM as the common denominator.
Now,
(-6/13)= [(-6 × 15)/ (13 × 15)] = (-90/195)
(7/15)= [(7 × 13)/ (15 × 13)] = (91/195)
Then, = (-90/195) + (91/195) … [∵ denominator is same in both the rational numbers]
= (-90 + 91)/195
= (1/195)

(iv) Ans: Take the LCM of the denominators of the given rational numbers.
LCM of 8 and 11 is 88
Express each of the given rational numbers with the above LCM as the common denominator.
Now,
(-3/8)= [(-3 × 11)/ (8 × 11)] = (-33/88)
(7/11)= [(7 × 8)/ (11 × 8)] = (56/88)
Then, = (-33/88) – (56/88) … [∵ denominator is same in both the rational numbers]
= (-33 – 56)/88
= (-89/88)
(v) Ans:
First we have to convert the mixed fraction into improper fraction, = -19/9
We have, -19/9 – 6
Take the LCM of the denominators of the given rational numbers.
LCM of 9 and 1 is 9
Express each of the given rational numbers with the above LCM as the common denominator.
Now,
(-19/9)= [(-19 × 1)/ (9 × 1)] = (-19/9)
(6/1)= [(6 × 9)/ (1 × 9)] = (54/9)
Then, = (-19/9) – (54/9) … [∵ denominator is same in both the rational numbers]
= (-19 – 54)/9
= (-73/9)

Q3. Find the product:

(i) (9/2) × (-7/4)
Ans:
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
The above question can be written as
(9/2) × (-7/4)
We have,
= (9 × -7) / (2 × 4)
= -63/8

(ii) (3/10) × (-9)
Ans:
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
The above question can be written as
(3/10) × (-9/1)
We have,
= (3 × -9)/ (10×1)
= -27/10

(iii) (-6/5) × (9/11)
Ans:
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
We have,
= (-6 × 9) / (5 × 11)
= -54/55

(iv) (3/7) × (-2/5)
Ans:
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
We have,
= (3 × -2) / (7 × 5)
= -6/35

(v) (3/11) × (2/5)
Ans:
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
We have,
= (3 × 2) / (11 × 5)
= 6/55

(vi) (3/-5) × (-5/3)
Ans:
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
We have,
= (3 × -5) / (-5 × 3)
On simplifying, = (1 × -1)/ (-1 × 1)
= -1/-1 = 1

Q4. Find the value of:

(i) (-4) ÷ (2/3)
Ans:
We have,
= (-4/1) × (3/2) … [∵ reciprocal of (2/3) is (3/2)]
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
= (-4 × 3) / (1 × 2) = (-2 × 3) / (1 × 1) = -6

(ii) (-3/5) ÷ 2
Ans:
We have,
= (-3/5) × (1/2) … [∵ reciprocal of (2/1) is (1/2)]
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
= (-3 × 1) / (5 × 2)
= -3/10

(iii) (-4/5) ÷ (-3)
Ans:
We have,
= (-4/5) × (1/-3) … [∵ reciprocal of (-3) is (1/-3)]
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
= (-4× (1)) / (5× (-3))
= -4/-15 = 4/15

(iv) (-1/8) ÷ 3/4
Ans:
We have,
= (-1/8) × (4/3) … [∵ reciprocal of (3/4) is (4/3)]
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
= (-1 × 4) / (8 × 3)
= (-1 × 1) / (2 × 3) = -1/6

(v) (-2/13) ÷ 1/7
Ans:
We have,
= (-2/13) × (7/1) … [∵ reciprocal of (1/7) is (7/1)]
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
= (-2 × 7) / (13 × 1)
= -14/13

(vi) (-7/12) ÷ (-2/13)
Ans:
We have, = (-7/12) × (13/-2) … [∵ reciprocal of (-2/13) is (13/-2)]
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
= (-7× 13) / (12× (-2))
= -91/-24 = 91/24

(vii) (3/13) ÷ (-4/65)
Ans:
We have, = (3/13) × (65/-4) … [∵ reciprocal of (-4/65) is (65/-4)]
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
= (3 × 65) / (13 × (-4))
= 195/-52 = -15/4

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## Mathematics (Maths) Class 7

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