Q1:
Can you help Rihan and Sheetal find their answers?
Ans: We can draw infinite number of lines passing though a single point, so Rihan can draw infinite many points through this point.
From two points we can draw only 1 line passing through it, Sheetal can draw only 1 line though these two points.
Q2: Name the line segments in Fig. 2.4. Which of the five marked points are on exactly one of the line segments? Which are on two of the line segments?
Ans: Line segments in the given figure are LM, MP, PQ and QR.
Points on exactly one line segment
Points on two line segments
Result:
Q3: Name the rays shown in Fig. 2.5. Is T the starting point of each of these rays?
Ans:
In the given figure, there are two rays:
So yes, T is the starting point of both rays.
Q4: Draw a rough figure and write labels appropriately to illustrate each of the following:
a. meet at O.
Ans:
b. intersect at point M.
Ans:
c. Line I contains points E and F but not point D.
Ans:
d. Point P lies on AB.
Ans:
Q5: In Fig. 2.6, name:
a. Five points
Ans: The five points in the figure are D, E, O, C, and B.
b. A line
Ans: The line in the figure is .
c. Four rays
Ans: The four rays in the figure are
d. Five line segments
Ans: The five line segments in the figure are DE EO OC BO and DO.
Q6: Here is a ray (Fig. 2.7). It starts at O and passes through the point A. It also passes through the point B.
a. Can you also name it as ? Why?
Ans: Yes, the ray can also be named because the ray OA passes through point B as well. Rays are named starting from the initial point and passing through any other point on the ray. Since the ray starts at O and passes through both B and A, it can be named .
b. Can we write ? Why or why not?
Ans: No, we cannot write because rays are directional. The ray starts at point O and extends through A, so indicates the direction from O to A. Writing it as would imply the ray starts at A and goes towards O, which is incorrect in this context because O is the starting point.
Vidya has just opened her book. Let us observe her opening the cover of the book in different scenarios.
Q: Do you see angles being made in each ofthese cases? Can you mark their arms and vertex?
Ans: Yes, I can see the angles in each case. The arms of angles are marked with green colour and the vertices are marked with red dot in each case.
Q1: Can you find the angles in the given pictures? Draw the rays forming any one of the angles and name the vertex of the angle.
Ans:
In ∠BDC, Rays are Vertex is D.
In ∠POQ, Rays are Vertex is O.
In ∠EOF, Rays are Vertex is O.
In ∠ABC, Rays are Vertex is B.
Q2: Draw and label an angle with arms ST and SR.
Ans: Arms of ∠RST are ST and SR.
Steps:
Q3: Explain why ∠APC cannot be labelled as ∠P.
Ans: ∠APC is a combination of two angles ∠APB and LBPC. So, ∠APC cannot be labelled as ∠P because there are more than one angle at vertex P.
Q4: Name the angles marked in the given figure.
Ans: The angles marked in the figure are:
Q5: Mark any three points on your paper that are not on one line. Label them A, B, C. Draw all possible lines going through pairs of these points. How many lines do you get? Name them. How many angles can you name using A, B, C? Write them down, and mark each of them with a curve as in Fig. 2.9.
Ans:
We get three lines by joining pairs of these points. There are three angels ∠ABC, ∠ACB and ∠BAC formed using these points.
Q6: Now mark any four points on your paper so that no three of them are on one line. Label them A, B, C, D. Draw all possible lines going through pairs of these points. How many lines do you get? Name them. How many angles can you name using A, B, C, D? Write them all down, and mark each of them with a curve as in Fig. 2.9.
Ans: We get four lines by joining pairs of these points. There are 12 angels ∠ABC, ∠ADC, ∠DCB, ∠BAD, ∠BAC, ∠DAC, ∠ABD, ∠DBC, ∠ACB, ∠ACD, ∠BDC and ∠BDA formed using these points.
Q: Is it always easy to compare two angles?
Here are some angles. Label each of the angles. How will you compare them?
Ans:
To compare the angles in the image, I will place one angle over the other by tracing or using transparent paper to directly compare which angle is larger or smaller. If I place one arm of each angle one over another, it can be observed easily (by looking at other arm) that which one is lesser or greater. By using this method, I can accurately compare the angles in the figure.
Q: Where else do we use superimposition to compare?
Ans: Superimposition is commonly used in situations in real-life objects like Scissors, compasses or other tools that involve angles. We can superimpose angles formed by these objects (e.g., the angle between the blades of a pair of scissors) to compare which angle is larger or smaller.
Q1: Fold a rectangular sheet of paper, then draw a line along the fold created. Name and compare the angles formed between the fold and the sides of the paper. Make different angles by folding a rectangular sheet of paper and compare the angles. Which is the largest and smallest angle you made?
Ans:
The angles formed with line along the fold created are ∠AEF, ∠BEF, ∠DFE and ∠CFE, which are marked with 1, 2, 3 and 4. Out of these angles ∠AEF and ∠CFE are the larger ones whereas ∠BEF and ∠DFE are the smaller ones.
Q2: In each case, determine which angle is greater and why.
a. ∠AOB or ∠XOY
b. ∠AOB or ∠XOB
c. ∠XOB or ∠XOC
Discuss with your friends on how you decided which one is greater.
Ans:
a. ∠AOB > ∠XOY, because ∠XOY is contained in ∠AOB. It means ∠XOY is a part of ∠AOB.
b. ∠AOB > ∠XOB, because ∠XOB is contained in ∠AOB. It means ∠XOB is a part of ∠AOB.
c. ∠XOB = ∠XOC, because both the angles are formed with the same rays.
Q3: Which angle is greater: ∠XOY or ∠AOB? Give reasons.
Ans: ∠XOB > ∠AOB, because ∠AOB is contained in ∠XOB. It means ∠AOB is a part of ∠XOB.
Let us consider a straight angle ∠AOB. Observe that any ray divides it into two angles, ∠AOC and ∠COB.
Q: Is it possible to draw such that the two angles are equal to each other in size?
Ans: If the ray become perpendicular to AB, the two angles become equal to each other.
Q: If a straight angle is formed by half of a full turn, how much of a full turn will form a right angle?
Ans: If a straight angle is formed by half of a full turn, a right angle is formed by one-quarter (1/4) of a full turn.
Steps of conclusion:
Q1: How many right angles do the windows of your classroom contain? Do you see other right angles in your classroom?
Ans:
In my classroom, the windows typically contain several right angles, as the corners where the frames meet are usually 90 degrees. Every rectangular or square-shaped window has four right angles.
Besides windows, other objects in the classroom with right angles include the corners of the doors, the edges of the blackboard or whiteboard, the desks or tables and tiles on the floor or walls may also contain right angles as they are square and rectangular.
Q2: Join A to other grid points in the figure by a straight line to get a straight angle. What are all the different ways of doing it?
Ans: The different way to form straight angle:
Q3: Now join A to other grid points in the figure by a straight line to get a right angle. What are all the different ways of doing it?
Ans: The different way to form right angle:
Q4: Get a slanting crease on the paper. Now, try to get another crease that is perpendicular to the slanting crease.
a. How many right angles do you have now? Justify why the angles are exact right angles.
b. Describe how you folded the paper so that any other person who doesn’t know the process can simply follow your description to get the right angle.
Ans:
Crease 2 is perpendicular to crease 1.
a. We will get four right angles because on folding the a. paper to create a crease that is perpendicular to the first crease, the two creases intersect at a right angle, dividing the plane into four angles of 90º each.
b. 1. Take a piece of paper and fold it diagonally from one corner to opposite corner, thereby making a firm crease.
2. Now fold the paper again in such a way that the second crease becomes perpendicular to the first one.
3. Thus, we will have two creases intersecting at 90º angIe, forming four right angles.
Explanation: a. When you fold the paper to create a crease that is perpendicular to the first, the two creases intersect at a right angle, dividing the plane into four right angles of 90 degrees each.
b. The second fold must be made carefully, aligning the first crease with the edge of the paper to ensure the two creases are perpendicular. This guarantees that the angles formed are exactly 90 degrees.
Q1: Identify acute, right, obtuse, and straight angles in the previous figures.
Ans:
Q2: Make a few acute angles and a few obtuse angles. Draw them in different orientations.
Ans:
Q3: Do you know what the words acute and obtuse mean? Acute means sharp and obtuse means blunt. Why do you think these words have been chosen?
Ans: Yes, the words acute and obtuse in geometry have meanings that relate to their everyday usage:
Acute: The word acute means "sharp" in general English, which is why an acute angle is described this way. Acute angles are smaller than 90 degrees and visually appear "sharp" or narrow, like the tip of a knife or a point, which gives a sharp impression.
Obtuse: The word obtuse means "blunt" or "dull." An obtuse angle is greater than 90 degrees and appears wider or broader, which makes it look blunt or less sharp, much like a blunt object or a broad, dull edge.
These words have likely been chosen because of the visual resemblance of these angles to sharp and blunt objects, making it easier to associate their sizes with everyday concepts. Acute angles are sharp because they are narrow and pointed, while obtuse angles are blunt because they are wide and dull-looking.
Q4: Find out the number of acute angles in each of the figures below.
What will be the next figure and how many acute angles will it have? Do you notice any pattern in the numbers?
Ans:
The number of acute angles in figure 1 is 3, figure 2 is 12 and figure 3 is 21.
In next figure, the number of acute angles will be 30.
There is a pattern in number of acute angles each figure. The number of acute angles i next figure is 9 more than the previous figure.
Q: What is the measure of a straight angle in degrees? A straight angle is half of a full turn. As a full-turn is 360º, a half turn is 180º. What is the measure of a right angle in degrees? Two right angles together form a straight angle. As a straight angle measures 180º, a right angle measures 90º.Ans: The measure of a straight angle in degrees is 180º and the measure of a right angle in degrees is 90º.
Q: The circle has been divided into 1, 2, 3, 4, 5, 6, 8, 9 10 and 12 parts below. What are the degree measures of the resulting angles? Write the degree measures down near the indicated angles.
Ans:
Q: Write the measures of the following angles:
a. ∠KAL b. ∠WAL
c. ∠TAK
Answer: a. ∠KAL = 30º
b. ∠WAL = 50º
c. ∠TAK = 40º
Q: Name the different angles in the figure and write their measures.
Did you include angles such as ∠TOQ?
Which set of markings did you use - inner or outer?
What is the measure of ∠TOS?
Ans:
Yes, I have included angles such as ∠TOQ. I have used both set of markings - inner and outer, depending on angles. The mesure of ∠TOS = 35º.
Q: In Figure, we have ∠AOB = ∠BOC = ∠COD = ∠DOE = ∠EOF = ∠FOG = ∠GOH = ∠HOI = ____ Why?
Ans: ∠AOB = ∠BOC = ∠COD = ∠DOE = ∠EOF = ∠FOG = ∠GOH = ∠HOI = 22.5º.
The straight angle is divided into 8 equal parts, that is why, the measure of each angle is 180º/8 = 22.5º.
Q1: Find the degree measures of the following angles using your protractor.
Ans:
Q2: Find the degree measures of different angles in your classroom using our protractor.
Ans: 2. The degree measures of different angles in my classroom:
Corner of a Window Frame: 90º
Edge of a Desk: 90º
Poster Slant on a Wall: 45º
Book opened halfway: 180º
Door slightly opened: 30º
Chair Backrest: 120º
Q3: Find the degree measures for the angles given below. Check if your paper protractor can be used here!
Ans:
Q4: How can you find the degree measure of the angle given below using a protractor?
Ans: (i) Measure the smaller angle with the help of protractor.
(ii) On subtracting the smaller angle from 360º, we get the value of the required bigger angle.
Smaller angle = 100º
Required bigger angle = 360º - 100º = 260º
Explanation: The angle you are measuring appears to be an obtuse angle (greater than 90°). By following these steps, you can accurately determine the angle's degree.
Q5: Measure and write the degree measures for each of the following angles:
Ans:
Q6: Find the degree measures of ∠BXE, ∠CXE, ∠AXB, and ∠BXC.
Ans: ∠BXE = 115º
∠CXE = 85º
∠AXB = 65º
∠BXC = ∠AXC - ∠AXB = 35º
Q7: Find the degree measures of ∠PQR, ∠PQS, and ∠PQT.
Ans: ∠PQR = 45º
∠PQS = 100º
∠ PQT = 152º
Explanation: Each angle is measured by placing the protractor's center at the vertex Q and aligning one of the rays with the 0° mark on the protractor. The other ray's intersection with the protractor scale gives the degree measure. The sum of ∠PQR and ∠PQS should give you ∠PQT, as angles on a straight line add up.
Q8: Make the paper craft as per the given instructions. Then, unfold and open the paper fully. Draw lines on the creases made and measure the angles formed.
Ans:
Step 1: When we fold the square paper diagonally, we create two right angles (90º) at the bottom corners and a 45º angle at the top.
Step 2: After folding, the base Of the triangle is flat, forming 90º angles at the bottom corners, while the top vertex remains 45º.
Step 3: When we fold the base upwards, we create a small right angle (90º) at the corner where the base meets the triangle.
Step 4: Folding in the sides to form the ears creates acute angles near the top, likely around 30º to 45º.
Step 5: As we further fold the sides inwards, the angles in the triangular ears might get sharper, leaving acute angles close to 30º at the tips of the ears.
Step 6: The fold upwards creates another acute angle at the tip of the bunny's face, likely around 45º.
Step 7: The final fold sharpens the bottom, maintaining the 90º at the base and 45º to 60º near the ears.
Step 8: In the complete bunny face, we will have multiple angles:
The ears form acute angles (around 30º to 45º).
The face near the chin forms an obtuse angle, close to 120º.
The sides of the face are around 90º to 120º depending on the precision of the folds.
Q9: Measure all three angles of the triangle shown in Fig. 2.21 (a), and write the measures down near the respective angles. Now add up the three measures. What do you get? Do the same for the triangles in Fig. 2.21 (b) and (c). Try it for other triangles as well, and then make a conjecture for what happens in general!
Ans:
(a) ∠ACB = 70º ; ∠CAB = 45º ; ∠ABC= 65º
Sum of all angles of ΔABC = ∠ACB + ∠CAB + ∠ABC
= 95º + 45º + 50º
= 180º
(b) ∠ACB = 62º ; ∠CAB = 55º ; ∠ABC= 63º
Sum of all angles of ΔABC = ∠ACB + ∠CAB + ∠ABC
= 62º + 55º + 63º
= 180º
(c) ∠ACB = 97º ; ∠CAB = 30º ; ∠ABC = 53º
Sum of all angles of ΔABC = ∠ACB + ∠CAB + ∠ABC
= 97º + 30º + 53º
= 180º
We have conjectured from the given activity that the sum of all the angles of any given triangle is always 180º.
Q1: Angles in a clock:
a. The hands of a clock make different angles at different times. At 1 o’clock, the angle between the hands is 30°. Why?
b. What will be the angle at 2 o’clock? And at 4 o’clock? 6 o’clock?
c. Explore other angles made by the hands of a clock.
Ans: a. A clock is divided into 12 hours and has a total of 360º.
Each hour = 360º/12 = 30º.
Therefore, at 1 o'clock the hour hand is at 1 and minute hand is at 12, thereby making an angle of 30º.
b. Angle at 2 0'clock = 2 x 30º
= 60º
Angle at 4 0'clock = 4 x 30º
= 120º
Angle at 6 0'clock = 6 x 30º
= 180º
c. Angle at 3 0'clock = 3 x 30º
= 90º
Angle at 5 0'clock = 5 x 30º
= 15º
Angle at 7 0'clock = 7 x 30º
= 210º
Angle at 8 0'clock = 8 x 30º
= 240º
Angle at 9 0'clock = 9 x 30º
= 270º
Angle at 10 0'clock = 10 x 30º
= 300º
Angle at 11 0'clock = 11 x 30º
= 330º
Angle at 12 0'clock = 12 x 30º
= 360º
Q2: The angle of a door: Is it possible to express the amount by which a door is opened using an angle? What will be the vertex of the angle and what will be the arms of the angle?
Ans: Yes, it is possible to express the amount by which a door is opened by using an angle. The hinge of the door will be the vertex of the angle. The wall and the door will be the arms of the angle.
Q3: Vidya is enjoying her time on the swing. She notices that the greater the angle with which she starts the swinging, the greater is the speed she achieves on her swing. But where is the angle? Are you able to see any angle?
Ans:
Yes, we can see the angle and the angle is between the rope and the branch of the tree.
Q4: Here is a toy with slanting slabs attached to its sides; the greater the angles or slopes of the slabs, the faster the balls roll. Can angles be used to describe the slopes of the slabs? What are the arms of each angle? Which arm is visible and which is not?
Ans:
Yes, angles can be used to describe the slopes of the slabs. The slanting slab and invisible line perpendicular to the sides of the toy are two arms of each angle.
The slanting slab is visible and the line perpendicular to the sides of the toy are invisible.
Q5: Observe the images below where there is an insect and its rotated version. Can angles be used to describe the amount of rotation? How? What will be the arms of the angle and the vertex? Hint: Observe the horizontal line touching the insects.
Ans: Yes, angles can be used to describe the amount of the rotation by observing the initial and the final position of the insect.
The horizontal line and the insect itself will be the arms of the angle. The vertex will be the back end of the insect.
Q1: In Fig. 2.23, list all the angles possible. Did you find them all? Now, guess the measures of all the angles. Then, measure the angles with a protractor. Record all your numbers in a table. See how close your guesses are to the actual measures.
Ans: All angles are ∠PAC, ∠ACL, ∠APL, ∠CLP, ∠RPL, ∠PLS, ∠LSR, ∠PRS, ∠BRS.
The guessed measurements were quite close to the actual measurements.
Q2: Use a protractor to draw angles having the following degree measures:
a. 110º
b. 40º
c. 75º
d. 112º
e. 134º
Ans:
Q3: Draw an angle whose degree measure is the same as the angle given below:
Also, write down the steps you followed to draw the angle.
Ans: The measurement of the given angle is 116º and it can be drawn by the following steps:
(i) Draw .
(ii) Place the centre point of the protractor on O and align to the zero line.
(iii) Now starting from 0º count up to 116º and mark a point B at the label 116º.
(iv) Using a ruler join the point O and B.
∠AOB = 116º is the required angle.
Q1: In each of the below grids, join A to other grid points in the figure by a straight line to get:
a. An acute angle
b. An obtuse angle
c. A reflex angle
Mark the intended angles with curves to specify the angles. One has been done for you.
Ans:
a. An acute angle
b. An obtuse angle
c. A reflex angle
Q2: Use a protractor to find the measure of each angle. Then classify each angle as acute, obtuse, right, or reflex.
a. ∠PTR
b. ∠PTQ
c. ∠PTW
d. ∠WTP
Ans:
a. ∠PTR = 30º
b. ∠PTQ = 60º
c. ∠PTW = 104º
d. ∠WTP = 360º - ∠PTW
= 360º - 104º
= 256º.
Q: In this figure, ∠TER = 80º. What is the measure of ∠BET? What is the measure of ∠SET?
Ans: ∠BET = 100º
∠SET = 10º
Q1: Draw angles with the following degree measures:
a. 140°
b. 82°
c. 195°
d. 70°
e. 35°
Ans:
Q2: Estimate the size of each angle and then measure it with a protractor:
Ans:
Q3: Make any figure with three acute angles, one right angle, and two obtuse angles.
Ans:
3 Acute angles = ∠COD, ∠BOC, ∠BOD
1 Right angle = ∠AOB
2 Obtuse angles = ∠AOC, ∠AOD.
Q4: Draw the letter ‘M’ such that the angles on the sides are 40° each and the angle in the middle is 60°.
Ans:
Explanation: Each side of the ‘M’ should form a 40° angle with the base, and the central angle at the top should be 60°.
Q5: Draw the letter ‘Y’ such that the three angles formed are 150°, 60°, and 150°.
Ans:
Explanation: The angles at the top should be wide (150°) while the central angle at the base should be narrower (60°).
Q6: The Ashoka Chakra has 24 spokes. What is the degree measure of the angle between two spokes next to each other? What is the largest acute angle formed between two spokes?
Ans: The Ashoka Chakra has 24 spokes and has a total of 360°.
Angle between two spokes = 360°/24 = 15°
The possible angles between two spokes are 15°, 30°, 45°, 60°, 75°.
Therefore, the largest acute angle formed between two spokes is 75°.
Explanation: Acute angles are less than 90°, and since the angle between each spoke is 15°, it is the largest acute angle.
Q7: Puzzle: I am an acute angle. If you double my measure, you get an acute angle. If you triple my measure, you will get an acute angle again. If you quadruple (four times) my measure, you will get an acute angle yet again! But if you multiply my measure by 5, you will get an obtuse angle. What are the possibilities for my measure?
Ans: The possibilities for your measure are 19°, 20°, 21°, 22°.
Explanation: An acute angle is less than 90°, so doubling, tripling, or quadrupling these values still results in an acute angle. However, multiplying by 5 gives 50°, 75°, and 90°, which makes 90° an obtuse angle in some cases.
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1. What are the different types of angles? |
2. How do you identify complementary angles? |
3. What is the sum of the angles in a triangle? |
4. How can you determine if two lines are parallel? |
5. How can you use the concept of alternate interior angles? |
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