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# Negative Numbers and Integers - Exercise 5.2 Class 6 Notes | EduRev

## Class 6 : Negative Numbers and Integers - Exercise 5.2 Class 6 Notes | EduRev

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Exercise 5.2                                                                               PAGE: 5.9
1. Draw a number line and represent each of the following on it:
(i) 5 + (-2)
(ii) (-9) + 4
(iii) (-3) + (-5)
(iv) 6 + (-6)
(v) (-1) + (-2) + 2
(vi) (-2) + 7 + (-9)
Solution:

(i) 5 + (-2)

From 0 move towards right of first five units to obtain + 5
So the second number is – 2 so move 2 units towards left of + 5 we get + 3

Therefore, 5 + (-2) = 3.

(ii) (-9) + 4

From 0 move towards left of nine units to obtain – 9
So the second number is 4 so move 4 units towards right of – 9 we get – 5

Therefore, (-9) + 4 = - 5.

(iii) (-3) + (-5)

From 0 move towards left of three units to obtain – 3
So the second number is – 5 so move 5 units towards left of – 3 we get – 8

Therefore, (-3) + (-5) = - 8.
Page 2

Exercise 5.2                                                                               PAGE: 5.9
1. Draw a number line and represent each of the following on it:
(i) 5 + (-2)
(ii) (-9) + 4
(iii) (-3) + (-5)
(iv) 6 + (-6)
(v) (-1) + (-2) + 2
(vi) (-2) + 7 + (-9)
Solution:

(i) 5 + (-2)

From 0 move towards right of first five units to obtain + 5
So the second number is – 2 so move 2 units towards left of + 5 we get + 3

Therefore, 5 + (-2) = 3.

(ii) (-9) + 4

From 0 move towards left of nine units to obtain – 9
So the second number is 4 so move 4 units towards right of – 9 we get – 5

Therefore, (-9) + 4 = - 5.

(iii) (-3) + (-5)

From 0 move towards left of three units to obtain – 3
So the second number is – 5 so move 5 units towards left of – 3 we get – 8

Therefore, (-3) + (-5) = - 8.

(iv) 6 + (-6)

From zero move towards right of six units to obtain 6
So the second number is – 6 so move 6 units towards left of 6 we get 0

Therefore, 6 + (-6) = 0.

(v) (-1) + (-2) + 2

From zero move towards left of one unit to obtain – 1
So the second number is – 2 so move 2 units towards left of – 1 we get – 3
The third number is 2 so move 2 units towards right of – 3 we get – 1

Therefore, (-1) + (-2) + 2 = - 1.

(vi) (-2) + 7 + (-9)

From zero move towards left of two units to obtain – 2
So the second number is 7 so move 7 units towards right of – 2 we get 5
The third number is – 9 so move 9 units towards left of 5 we get – 4

Therefore, (-2) + 7 + (-9) = - 4.

2. Find the sum of
(i) -557 and 488
(ii) -522 and -160
(iii) 2567 and – 325
(iv) -10025 and 139
(v) 2547 and -2548
(vi) 2884 and -2884
Page 3

Exercise 5.2                                                                               PAGE: 5.9
1. Draw a number line and represent each of the following on it:
(i) 5 + (-2)
(ii) (-9) + 4
(iii) (-3) + (-5)
(iv) 6 + (-6)
(v) (-1) + (-2) + 2
(vi) (-2) + 7 + (-9)
Solution:

(i) 5 + (-2)

From 0 move towards right of first five units to obtain + 5
So the second number is – 2 so move 2 units towards left of + 5 we get + 3

Therefore, 5 + (-2) = 3.

(ii) (-9) + 4

From 0 move towards left of nine units to obtain – 9
So the second number is 4 so move 4 units towards right of – 9 we get – 5

Therefore, (-9) + 4 = - 5.

(iii) (-3) + (-5)

From 0 move towards left of three units to obtain – 3
So the second number is – 5 so move 5 units towards left of – 3 we get – 8

Therefore, (-3) + (-5) = - 8.

(iv) 6 + (-6)

From zero move towards right of six units to obtain 6
So the second number is – 6 so move 6 units towards left of 6 we get 0

Therefore, 6 + (-6) = 0.

(v) (-1) + (-2) + 2

From zero move towards left of one unit to obtain – 1
So the second number is – 2 so move 2 units towards left of – 1 we get – 3
The third number is 2 so move 2 units towards right of – 3 we get – 1

Therefore, (-1) + (-2) + 2 = - 1.

(vi) (-2) + 7 + (-9)

From zero move towards left of two units to obtain – 2
So the second number is 7 so move 7 units towards right of – 2 we get 5
The third number is – 9 so move 9 units towards left of 5 we get – 4

Therefore, (-2) + 7 + (-9) = - 4.

2. Find the sum of
(i) -557 and 488
(ii) -522 and -160
(iii) 2567 and – 325
(iv) -10025 and 139
(v) 2547 and -2548
(vi) 2884 and -2884

Solution:

(i) -557 and 488
We get
-557 + 488
It can be written as
|-557| - |488| = 557 – 488 = 69.

(ii) -522 and -160
We get
-522 + (-160)
It can be written as
-522 – 160 = - 682

(iii) 2567 and – 325
We get
2567 + (-325)
It can be written as
2567 – 325 = 2242

(iv) -10025 and 139
We get
-10025 + 139
It can be written as
-10025 + 139 = -9886

(v) 2547 and -2548
We get
2547 + (-2548)
It can be written as
2547 – 2548 = -1

(vi) 2884 and -2884
We get
2884 + (-2884)
It can be written as
2884 – 2884 = 0

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## Mathematics (Maths) Class 6

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