Negative Numbers and Integers - Exercise 5.2 Class 6 Notes | EduRev

Mathematics (Maths) Class 6

Class 6 : Negative Numbers and Integers - Exercise 5.2 Class 6 Notes | EduRev

 Page 1


 
 
 
 
 
 
Exercise 5.2                                                                               PAGE: 5.9 
1. Draw a number line and represent each of the following on it: 
(i) 5 + (-2) 
(ii) (-9) + 4 
(iii) (-3) + (-5) 
(iv) 6 + (-6) 
(v) (-1) + (-2) + 2 
(vi) (-2) + 7 + (-9) 
Solution: 
 
(i) 5 + (-2) 
 
From 0 move towards right of first five units to obtain + 5  
So the second number is – 2 so move 2 units towards left of + 5 we get + 3 
 
Therefore, 5 + (-2) = 3. 
 
(ii) (-9) + 4 
 
From 0 move towards left of nine units to obtain – 9 
So the second number is 4 so move 4 units towards right of – 9 we get – 5 
 
Therefore, (-9) + 4 = - 5. 
 
(iii) (-3) + (-5) 
 
From 0 move towards left of three units to obtain – 3 
So the second number is – 5 so move 5 units towards left of – 3 we get – 8 
 
Therefore, (-3) + (-5) = - 8. 
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Exercise 5.2                                                                               PAGE: 5.9 
1. Draw a number line and represent each of the following on it: 
(i) 5 + (-2) 
(ii) (-9) + 4 
(iii) (-3) + (-5) 
(iv) 6 + (-6) 
(v) (-1) + (-2) + 2 
(vi) (-2) + 7 + (-9) 
Solution: 
 
(i) 5 + (-2) 
 
From 0 move towards right of first five units to obtain + 5  
So the second number is – 2 so move 2 units towards left of + 5 we get + 3 
 
Therefore, 5 + (-2) = 3. 
 
(ii) (-9) + 4 
 
From 0 move towards left of nine units to obtain – 9 
So the second number is 4 so move 4 units towards right of – 9 we get – 5 
 
Therefore, (-9) + 4 = - 5. 
 
(iii) (-3) + (-5) 
 
From 0 move towards left of three units to obtain – 3 
So the second number is – 5 so move 5 units towards left of – 3 we get – 8 
 
Therefore, (-3) + (-5) = - 8. 
 
 
 
 
 
 
(iv) 6 + (-6) 
 
From zero move towards right of six units to obtain 6 
So the second number is – 6 so move 6 units towards left of 6 we get 0 
 
Therefore, 6 + (-6) = 0. 
 
(v) (-1) + (-2) + 2 
 
From zero move towards left of one unit to obtain – 1 
So the second number is – 2 so move 2 units towards left of – 1 we get – 3 
The third number is 2 so move 2 units towards right of – 3 we get – 1 
 
Therefore, (-1) + (-2) + 2 = - 1. 
 
(vi) (-2) + 7 + (-9) 
 
From zero move towards left of two units to obtain – 2 
So the second number is 7 so move 7 units towards right of – 2 we get 5 
The third number is – 9 so move 9 units towards left of 5 we get – 4 
 
Therefore, (-2) + 7 + (-9) = - 4. 
 
2. Find the sum of 
(i) -557 and 488 
(ii) -522 and -160 
(iii) 2567 and – 325 
(iv) -10025 and 139 
(v) 2547 and -2548 
(vi) 2884 and -2884 
Page 3


 
 
 
 
 
 
Exercise 5.2                                                                               PAGE: 5.9 
1. Draw a number line and represent each of the following on it: 
(i) 5 + (-2) 
(ii) (-9) + 4 
(iii) (-3) + (-5) 
(iv) 6 + (-6) 
(v) (-1) + (-2) + 2 
(vi) (-2) + 7 + (-9) 
Solution: 
 
(i) 5 + (-2) 
 
From 0 move towards right of first five units to obtain + 5  
So the second number is – 2 so move 2 units towards left of + 5 we get + 3 
 
Therefore, 5 + (-2) = 3. 
 
(ii) (-9) + 4 
 
From 0 move towards left of nine units to obtain – 9 
So the second number is 4 so move 4 units towards right of – 9 we get – 5 
 
Therefore, (-9) + 4 = - 5. 
 
(iii) (-3) + (-5) 
 
From 0 move towards left of three units to obtain – 3 
So the second number is – 5 so move 5 units towards left of – 3 we get – 8 
 
Therefore, (-3) + (-5) = - 8. 
 
 
 
 
 
 
(iv) 6 + (-6) 
 
From zero move towards right of six units to obtain 6 
So the second number is – 6 so move 6 units towards left of 6 we get 0 
 
Therefore, 6 + (-6) = 0. 
 
(v) (-1) + (-2) + 2 
 
From zero move towards left of one unit to obtain – 1 
So the second number is – 2 so move 2 units towards left of – 1 we get – 3 
The third number is 2 so move 2 units towards right of – 3 we get – 1 
 
Therefore, (-1) + (-2) + 2 = - 1. 
 
(vi) (-2) + 7 + (-9) 
 
From zero move towards left of two units to obtain – 2 
So the second number is 7 so move 7 units towards right of – 2 we get 5 
The third number is – 9 so move 9 units towards left of 5 we get – 4 
 
Therefore, (-2) + 7 + (-9) = - 4. 
 
2. Find the sum of 
(i) -557 and 488 
(ii) -522 and -160 
(iii) 2567 and – 325 
(iv) -10025 and 139 
(v) 2547 and -2548 
(vi) 2884 and -2884 
 
 
 
 
 
 
Solution: 
 
(i) -557 and 488 
We get 
-557 + 488 
It can be written as 
|-557| - |488| = 557 – 488 = 69. 
 
(ii) -522 and -160 
We get 
-522 + (-160) 
It can be written as 
-522 – 160 = - 682 
 
(iii) 2567 and – 325 
We get 
2567 + (-325)  
It can be written as 
2567 – 325 = 2242 
 
(iv) -10025 and 139 
We get 
-10025 + 139  
It can be written as 
-10025 + 139 = -9886 
 
(v) 2547 and -2548 
We get 
2547 + (-2548) 
It can be written as 
2547 – 2548 = -1 
 
(vi) 2884 and -2884 
We get 
2884 + (-2884) 
It can be written as 
2884 – 2884 = 0 
 
 
 
 
 
 
 
 
 
 
 
 
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